Given that m∠abc=70° and m∠bcd=110°. Is it possible (consider all cases): Line AB intersects line CD?

Formula-

If a set has “n” elements, then the number of subset of the given set is 2n and the number of proper subsets of the given subset is given by 2n-1. Consider an example, If set A has the elements, A = {a, b}, then the proper subset of the given subset are { }, {a}, and {b}

Symbol that can be used-

The symbol "⊆" means "is a subset of". The symbol "⊂" means "is a proper subset of".

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Answer:

Answer:

Expanded form: 4,000,000 + 500,000 + 80,000 + 7,000 + 900 + 2 + 0.4 + 0.05 + 0.003

Word form: Four million, five hundred eighty-seven thousand, nine hundred two and four hundred fifty-three thousandths.

Answer:

A) It’s the First graph

Step-by-step explanation: hope this helps!

The graph corresponds to the inequality -2x - 3y < 6 is option A.

To estimate the value of x and y, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.

Given: -2x - 3y < 6

then -2x - 3y = 6

Put the value of y = 0, then

[tex]$-2x-3*0=6[/tex]

-2x = 6

x = -6/2 = -3 and

-2x - 3y = 6

Put the value of x = 0, then

[tex]$-2*0-3y=6[/tex]

-3y = 6

y = -6/3 = -2

The value of x = -3 and y = -2.

Therefore, the correct answer is option A.

To learn more about inequality refer to:

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Solution :

Let [tex]p_1[/tex] and [tex]p_2[/tex]  represents the proportions of the seeds which germinate among the seeds planted in the soil containing [tex]3\%[/tex] and [tex]5\%[/tex] mushroom compost by weight respectively.

To test the null hypothesis [tex]H_0: p_1=p_2[/tex] against the alternate hypothesis  [tex]H_1:p_1 \neq p_2[/tex] .

Let [tex]\hat p_1, \hat p_2[/tex] denotes the respective sample proportions and the [tex]n_1, n_2[/tex] represents the sample size respectively.

[tex]$\hat p_1 = \frac{74}{155} = 0.477419[/tex]

[tex]n_1=155[/tex]

[tex]$p_2=\frac{86}{155}=0.554839[/tex]

[tex]n_2=155[/tex]

The test statistic can be written as :

[tex]$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}[/tex]

which under [tex]H_0[/tex]  follows the standard normal distribution.

We reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance, if the P-value [tex]<0.05[/tex] or if [tex]|z_{obs}|>Z_{0.025}[/tex]

Now, the value of the test statistics = -1.368928

The critical value = [tex]\pm 1.959964[/tex]

P-value = [tex]$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$[/tex]

                                     [tex]$=2 \times 0.085667$[/tex]

                                     = 0.171335

Since the p-value > 0.05 and [tex]$|z_{obs}| \ngtr z_{critical} = 1.959964$[/tex], so we fail to reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the [tex]\text{proportion}[/tex] of the seeds that [tex]\text{germinate differs}[/tex] with the percent of the [tex]\text{mushroom compost}[/tex] in the soil.

9514 1404 393

Answer:

  see below

Step-by-step explanation:

  [tex]\text{A. point: }X\\\\\text{B. ray through Y: }\overrightarrow{XY}\\\\\text{C. line through Z: }\overleftrightarrow{XZ}\\\\\text{D. plane: plane } XYZ[/tex]

__

Additional comment

When you don't have the benefit of typesetting, you can refer to the geometry by name: ray XY, line XZ,

Answer:

Region C

Step-by-step explanation:

y ≤ ¼ x + 3 maps the areas C and D including the common boundary line

y ≥ -x + 5 maps the areas B and C including the common boundary line

The common area mapped is C plus its boundaries

This is a relative frequency question. Applying the concept, we get that the relative frequency of gluten free breads sold at store A compared to those sold at all stores combined is 0.1667.

Relative frequency:

The relative frequency of a to b is given by a divided by b.

In this question:

a: Gluten free breads sold at store A

b: Gluten free breads sold at all stores combined.

2 + 7 + 3 = 12 gluten free breads sold.

2 sold at store A, so:

[tex]\frac{2}{12} = \frac{1}{6} = 0.1667[/tex]

Thus, the relative frequency of gluten free breads sold at store A compared to those sold at all stores combined is 0.1667.

Another example of a problem involving relative frequency you can check at https://brainly.com/question/20630951

Relative Frequency:

The relative frequency of gluten-free breads sold at Store A compared to those sold at all the stores combined is:

= 0.167

Data and Calculations:

Gluten-Free Breads at Different Stores

                           Gluten-Free         Not Gluten-

                               Breads            Free Breads

Store A                        2                          4

Store B                        7                         10

Store C                       3                         12

Since we are only considering Gluten-Free Breads at the three stores, we take the relevant data to calculate and compare their frequencies as follows:

                           Gluten-Free        Relative

                               Breads         Frequency

Store A                        2                0.167 (2/12) = 17%

Store B                        7                0.583 (7/12) = 58%

Store C                       3                0.250 (3/12) = 25%

Total Gluten-free     12                 1 = 100%

Thus, the relative frequency of gluten-free breads sold at Store A compared to those sold at all the stores combined is 0.167.

Answer:

answer is

In empty set, n(A) = { }.

Answer:

Answer : 1/8.

Step-by-step explanation:

Hey there!

Please see the attached picture for your answer.

Hope it helps!

Find the sale price by multiplying the original price by 70% then add the two prices together to get the total.

799 x 0.70 = 559.30

549 x 0.70 = 384.30

Total: 559.30 + 384.30 = $943.60

Answer:

A∩B ={2;4}

Step-by-step explanation:

Chúc bạn học tốt

The length of the confidence interval is the margin of error, which is the ratio of the standard deviation and the square root of sample size. Hence, to reduce the length of confidence interval by half, Quadruple the sample size.

Recall :

Evaluating an hypothetical scenario :

Let standard deviation, σ = 2

Sample size = 50

Margin of Error = 2/√50 = 0.554

Using Quadruple of the sample size : (50 × 4) = 200 samples

(0.227 ÷ 0.554) = 0.5

Therefore, increasing the sample size, reduces the margin of error. Hence, using quadruple the sample size, will reduce the margin of error by half.

Learn more : https://brainly.com/question/13403969

the function that connects the point (0;1) with the point (-1;0) is the graph

Answer:

a multiple of 3.

Step-by-step explanation:

1x3=3

3x3=9

9x3=27

z = 3i / (-1 - i )

z = 3i / (-1 - i ) × (-1 + i ) / (-1 + i )

z = (3i × (-1 + i )) / ((-1)² - i ²)

z = (-3i + 3i ²) / ((-1)² - i ²)

z = (-3 - 3i ) / (1 - (-1))

z = (-3 - 3i ) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(z) and Im(z) are negative. But arctan only returns angles between -π/2 and π/2. So we have

arg(z) = arctan((-3/2)/(-3/2)) - π

arg(z) = arctan(1) - π

arg(z) = π/4 - π

arg(z) = -3π/4

where I'm taking arg(z) to have a range of -π < arg(z) ≤ π.

Answer:

[tex](4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7[/tex]

Step-by-step explanation:

Given

[tex](4x^3y^5)(3x^5y)^2[/tex]

Required

The equivalent expression

We have:

[tex](4x^3y^5)(3x^5y)^2[/tex]

Expand

[tex](4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2[/tex]

Further expand

[tex](4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2[/tex]

Apply laws of indices

[tex](4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7[/tex]

Answer:

he has 48 dollars left to spend on clothes

ANSWER

8-2........3/4 but you have you ADD some people dont know that 8-2= 6

and so 6/1 + 3/4 is 24/4

Step-by-step explanation:

the answer is regular octagon

i think

Answer:

Step-by-step explanation:

Assume the dish opens upwards. The cross-section through the vertex is a parabola. You know three points on the parabola: (0,0), (2,2), and (-2,2). Plug the points into y = ax² + bx + c to get a system of three equations where a=0.5, b=c=0.

Equation of parabola: y = 0.5x²

:::::

Vertex (0,0)

Focal length = 1/(4×0.5) = 0.5

Focus (0,0+0.5) = (0, 0.5)

Directrix y = 0-0.5 = -0.5

:::::

At endpoints of latus rectum, y = 0.5

x = ±√0.5 = ±√2/2

Focal width = 2×√2/2 = √2

:::::

Place antenna at focus, (9,2)

Answer:

x/8

Step-by-step explanation:

First, we are given "the quotient of...". This means that we are dividing something/something else. If two numbers are given in the phrase "something and something else", the first number given will be the something, and the second number will be the something else.

The first number listed is x. Therefore, we have

x/something else.

Next, we are given "and 8", so we have x/8 as our expression

Step-by-step explanation:

f(x)=log(x)

     =d(log(x)/dx)

=>y=1/x

Answer:

1/4

Step-by-step explanation:

x^2 - x

Take the coefficient of x

-1

Divide by 2

-1/2

Square it

(-1/2)^2 = 1/4

Add it

x^2 -x +1/4

Answer:

Step-by-step explanation: Hello! Do

Answer:

yes how can I help you???

Answer:

m = [tex]\frac{2K}{v^2}[/tex]

Step-by-step explanation:

Given mass (m ) varies directly as K and inversely as v² then the equation relating them is

m = [tex]\frac{kK}{v^2}[/tex] ← k is the constant of variation

To find k use the condition m = 10 when K = 80 and v = 4 , then

10 = [tex]\frac{80k}{4^2}[/tex] = [tex]\frac{80k}{16}[/tex] ( multiply both sides by 16 to clear the fraction )

160 = 80k ( divide both sides by 80 )

2 = k

m = [tex]\frac{2K}{v^2}[/tex] ← equation of variation

The expression of mass as a function of kinetic energy and velocity is m = 2K/V².

Expressions are defined as mathematical statements that have a minimum of two terms containing variables or numbers.

We have been given that the mass varies directly as the Kinetic energy (K) and inversely as the square of the velocity (V).

m ∝ K/V²

m = cK/V²

Here c is the constant of variation,

If the kinetic energy is 80 Joules and the velocity is 4 meters per second, then the mass is 10 kilograms.

We have to determine the value of c

Here m = 10 , K = 80 and V = 4 , then

Substitute the values in m =  cK/V²

10 = c(80)/4²

10 = c(80)/16

10 = 5c

c = 10/5

c = 2

Substitute the value of c = 2 in the equation of variation,

⇒ m = 2K/V²

Hence, the expression of mass as a function of kinetic energy and velocity is m = 2K/V².

Learn more about the expressions here:

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Answer:

6 (-5 + 6x)

Step-by-step explanation:

Rewrite the number 30 as 6×5 and 36 as 6×6

Factor out the common number, which is 6

so, 6 (-5 + 6x)

Answer:

-6(5-6x).

Just factor out -6 from the expression. Thank you!

Answer:

[tex]\sqrt{280}[/tex] = 2[tex]\sqrt{70}[/tex]

37^2 = 1369

33^2 =1089

1369-1089 = 280

Step-by-step explanation: