Given : AB = BC and BC = CD, AB = 3x - 1 and CD = 2x + 3 Prove: BC = 11 plz help me

Answer:

SOH-CAH-TOA

tan = opposite/adjacent

tan J = 15/20 = 3/4

Step-by-step explanation:

Hi there!

We know that the angles ∠B and ∠A are supplementary because they are both interior angles. Therefore:

180 = ∠A + ∠B

Rewrite:

180 = (6x - 48) + (4x + 38)

Combine like terms:

180 = 10x - 10

Solve for x:

190 = 10x

x = 19

Solve for ∠B by plugging in this value of x:

∠B = 4(19) + 38

∠B = 76 + 38

∠B = 114

Answer:

a) 122°

b) 37°

Step-by-step explanation:

a) supplement angle of 58° = 180° - 58° =122°

b) complement angle of 53° = 90° - 53° = 37°

Answer:

9x - 9

Step-by-step explanation:

4(2x + x - 3) - 3x + 3

Simplify the expression, combine like terms in the parenthesis,

4(3x - 3) - 3x + 3

Distribute, multiply every term inside the parenthesis by the number outside of it;

(4)(3x) + (4)(-3) - 3x + 3

Simplify,

12x - 12 - 3x + 3

Combine like terms,

12x - 12 - 3x + 3

9x - 12 + 3

9x - 9

Answer:

7 students

Step-by-step explanation:

1+2+4=7students

Answer:

115°

Step-by-step explanation:

in a parallelogram vertically opposite angles are equal.

m∠MNK=m∠KLM=115°

Answer:

Step-by-step explanation:

This is a sideways cubic translated down 2 units. The graph shown is the sideways cubic translated up 2. So locate the graph that looks like this but has its "squiggly part" at -2 instead of 2.

Answer:

The sphere

[tex]v=\frac{4}{3} \pi r^{3}=\frac{4}{3}*3.14 *2^{3}=\frac{4*3.14*8}{3}=\frac{100.48}{3}=33.493[/tex]

The cylinder

[tex]v=\pi r^{2} h=3.14*(\frac{4}{2} )^{2}*3=3.14*2^{2}*3=9.42*4=37.68[/tex]

Add those two volumes together:

[tex]33.493 + 37.68 = 71.173 in^{3}[/tex]

Answer:

see explanation

Step-by-step explanation:

Using the Pythagorean identity

sin²θ + cos²θ = 1 ( divide terms by sin²θ )

[tex]\frac{sin^20}{sin^20}[/tex] + [tex]\frac{cos^20}{sin^20}[/tex] = [tex]\frac{1}{sin^20}[/tex] , that is

1 + cot²θ = cosec²θ ← as required

Answer:

Step-by-step explanation:

Answer:

Sequence = 120

Step-by-step explanation:

Given

6 rolls of a die;

Required

Determine the possible sequence of rolls

From the question, we understand that there were three possible outcomes when the die was rolled;

The outcomes are either of the following faces: 1, 2 and 3

Total Number of rolls = 6

Possible number of outcomes = 3

The possible sequence of rolls is then calculated by dividing the factorial of the above parameters as follows;

Sequence = \frac{6!}{3!}

Sequence = \frac{6 * 5 * 4* 3!}{3!}

Sequence = 6 * 5 * 4

Sequence = 120

Hence, there are 120 possible sequence.

Step-by-step explanation:

Hope this helps

Answer:

11.2

Step-by-step explanation:

[tex]p =\frac{160.16}{14.3}=\frac{160.16*10}{14.3*10}\\\\p = \frac{1601.6}{143}\\\\[/tex]

p = 11.2

Answer:

The person above me is correct I just did the work and I got the same answer as them :)

Step-by-step explanation:

Answer:

1/10, 0.9, 3/10

Step-by-step explanation:

#carryonlearning

Answer:

is it possable you can show the graph

Step-by-step explanation:

Answer:

2nd option ,that is, Both tables do not represent a function.

Step-by-step explanation:

For a table to represent a function it's input value must correspond to exactly one output value.

As in Table A the input value of 3 corresponds to 2 different outputs, where

as in table B the input value of 5 corresponds to 2 different outputs.

Therefore, Both tables dobnot represent a function.

Answer:

[tex]y=a(x-h)^{2} +k[/tex]

[tex](x,y)=(-3,14)[/tex]

[tex](h,k)=(-4,6)[/tex]

[tex]14=a(-3-(-4))^{2})+6[/tex]

[tex]14=a(-3+4)^{2} +6[/tex]

[tex]14=a(1)^{2} +6,-6[/tex]

[tex]8=a[/tex]

[tex]ANSWER:8[/tex]

--------------------------

HOPE IT HELPS

HAVE A GREAT DAY!!

Answer:

The vertical line test can be used to determine whether a graph represents a function.

If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.

Answer:

{2,3,4}

Step-by-step explanation:

The range are simply the f(x) values

The range are the x values

To get the x values, we simply get x from each f(x)

So we have;

1-2x = -3

1+ 3 = 2x

2x = 4

x = 4/2

x = 2

Secondly;

1-2x = -5

1 + 5 = 2x

2x = 6

x = 6/2

x = 3

lastly;

1-2x = -7

1 + 7 = 2x

2x = 8

x = 8/2

x = 4

So the domain values are;

{2,3,4}

Answer: 3172

Step-by-step explanation:

Answer:

slope= ⅗

Step-by-step explanation:

Rewrite the equation into the slope-intercept form, y=mx +c, where m is the gradient and c is the y-intercept.

3x- 5y= 0

+5y on both sides of the equation:

5y= 3x

Divide both sides by 5:

y= ⅗x

From the coefficient of x, the slope of the line is ⅗.

[tex]\longrightarrow{\blue{64}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] = (10 {}^{2} - 6 {}^{2} ) [/tex]

[tex] = [(10 \times 10) - (6 \times 6)][/tex]

[tex] = (10 0- 36)[/tex]

[tex] = 64[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]

Answer:

38

Step-by-step explanation:

6⅓÷⅙

change 6⅓ to improper fraction

19/3÷1/6

keep the first fraction, change the division sign to multiplication and reciprocate/flip the second fraction

19/3× 6/1

the denominator 3 and numerator 6 will simplify/cancel each other

the new fraction is now: 19/1 × 2/1

there is no need to multiply the denominators because it will still be equal to 1 so we just need to multiply the numerators by each other

19×2=38 OR 38/1 (both answers are the same)

Answer:

3

Step-by-step explanation:

A = [tex]\frac{base1 + base2}{2}[/tex] x h     Formula

[tex]\frac{base1 + 5}{2}[/tex] x 20 = 80      Substitution

[tex]\frac{base1 + 5}{2}[/tex] = 4                 Work  (divide by 20, multiply by 2, subtract 5)

base1 + 5 = 8

base1 = 3                  Solution

9514 1404 393

Explanation:

The problem statement tells you the meaning of t. It is minutes after Riko leaves. 0 ≤ t < 52.5 is the answer to the question regarding the interval Riko is behind Yuto. It means Riko is behind Yuto for 52.5 minutes after she leaves their house.

t will not be negative because time moves forward. Here, we're only counting time after Riko leaves the house. A negative value for t would refer to a time before Riko leaves the house, which is irrelevant in this problem.*

_____

* One might argue that Riko is behind Yuto for all values of time after Yuto leaves the house, which would be for -21 < t < 52.5. The concept of "behind Yuto" has no meaning except in that interval.

Answer:

again again again hello or merhaba(hello)

speed = path / time

so we can say this;

speed × time = path

note;

two speeds in different directions add up

and

two speeds in the same direction subtract

our speeds are in the same direction so we subtract

0.35 - 0.25 = 0.10 speed

and our path is 5.25 miles because there are 5.25 miles between Yuto and Rico

when will they be in the same place now?

speed × time = path

0.10 × time = 5.25 miles

in this equation we find the time 52.5 minutes

After 52.5 minutes they will be in the same place but before 52.5 minutes Riko will be behind Yuto

0≤ t ≤ 52,5 ( this is our equation of time)

because time cannot take a negative value, as soon as they start moving, time passes and this cannot take a negative value

GOOD LUCK :D

Step-by-step explanation:

greetings from Turkey (≧▽≦)

Answer:

A) 27

Step-by-step explanation:

[tex]9^{x}[/tex] = 81

x = 2

3([tex]3^{2}[/tex]) = 3(9) = 27

Answer:

a. 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Distributive Property

Algebra I

Calculus

Integrals

Integration Rule [Reverse Power Rule]:                                                                      [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                        [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                             [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                           [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^2_0 {x(4x^2 + 1)} \, dx[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Answer:

option C is correct

x^4 - x^2 - 2.5

If we add any constant c in the function then it gets shifted upward by the c unit. Then the function g(x) is above the function f(x) by 2.5 units.

The function is an expression, rule, or law that defines the relationship between one variable to another variable.

Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

The functions are g(x) and f(x) are given below.

f(x) = x⁴-x²

g(x) = x⁴-x²+2.5

We know that if we add any constant c in the function then it gets shifted upward by the c unit.

The graph is shown.

More about the function link is given below.

brainly.com/question/5245372

#SPJ7

Incomplete question: we assume figures to explain further

Answer and explanation:

Given that client pays $0.15/kwh

If old fridge is inefficient and consumes 120kwh/month

And new fridge is efficient and therefore consumes 50kwh/month

For the old fridge, client will be paying

120×0.15= $18 per month on electricity charges

For the new fridge, client will be paying

50×0.15= $7.5 per month on electricity charges

what's the whole question??

Answer:

2000

Step-by-step explanation:

Since the number must be odd, it can have either 1, 3, 5, 7 or 9 in its one's place.

With a 4-digit number starting with 6, any of these digits can be in the one's place and it will still be greater than 6,000.

For the one's place, since we can choose from 5 digits, we have ⁵P₁. In the thousands place, we have one digit which is 6. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively.

So, the total number of 4 digit odd numbers greater than 6000 starting with 6 are 1 × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 1 × 10 × 10 × 5 = 500 numbers.

For the thousands place, we are left with the digits 7, 8 and 9. So, to arrange these 3 digits in the thousands place, we have ³P₁. For the tens and hundreds, place, we can choose from ten digits. So, we have ¹⁰P₁ and ¹⁰P₁ respectively. For the one's place, since we can choose from 5 digits, we have ⁵P₁.

So, the total number of 4 digit odd numbers greater than 6000 starting with 7, 8 or 9 are  ³P₁ × ¹⁰P₁ × ¹⁰P₁ × ⁵P₁ = 3 × 10 × 10 × 5 = 1500 numbers.

So, the total number of 4-digit numbers greater than 6000 that can be constructed is 500 + 1500 = 2000 numbers.

Domain of the function