Answer:
$196.28
Step-by-step explanation:
Original cost: 39 × $8 = $312
Revenue: 32 × $16.19 = $518.08
Return charge: 7 × $1.4 = $9.8
$312 + $9.8 = total cost, which is $321.8
$518.08 - $321.8 = profit
Profit = $196.28
Find the length of CE
Answer:
C. 37.8 units
Step-by-step explanation:
ED = 17/ cos(38°) = 17 / 0.7880 = 21.6 units
DF = 17× tan (38°) = 17× 0.7813 = 13.3 units
CD = 10/13.3 × 21.6 = 16.2 units
so, the length of CE = 21.6+16.2 = 37.8 units
it is known that the population proton of utha residnet that are members of the church of jesus christ 0l6 suppose a random sample of 46 selceted and prioon of the sample that belongs to the churh is calcutated what is the problaity of obtaining a sample priton less than 0;50 g
Answer:
0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Proportion of 0.6
This means that [tex]p = 0.6[/tex]
Sample of 46
This means that [tex]n = 46[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.6[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.6*0.4}{46}} = 0.0722[/tex]
Probability of obtaining a sample proportion less than 0.5.
p-value of Z when X = 0.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.5 - 0.6}{0.0722}[/tex]
[tex]Z = -1.38[/tex]
[tex]Z = -1.38[/tex] has a p-value of 0.0838
0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.
Joe works as a salesman at the baby retail store. He receives a 5% commission on the first $ 10 000,9% on the next $ 7000, and 13% on any additional sales. Calculate how much Joe must sell to make $ 2082.9 in commission
Answer:
Joe must sell $ 24,330 to make $ 2,082.9 in commission.
Step-by-step explanation:
Since Joe works as a salesman at the baby retail store, and he receives a 5% commission on the first $10,000, 9% on the next $7,000, and 13% on any additional sales, to calculate how much Joe must sell to make $2082.9 in commission the following calculation must be performed:
10,000 x 0.05 = 500
7,000 x 0.09 = 630
2,082.90 - 500 - 630 = X
952.90 = X
0.13X = 952.90
X = 952.90 / 0.13
X = 7.330
10,000 + 7,000 + 7,330 = X
24,330 = X
Therefore, Joe must sell $ 24,330 to make $ 2,082.9 in commission.
Hannah ran 12 laps for 8 days. How many laps did she run in total if she take a break of 1 complete day and 1 half day.
Answer:
The correct answer would be - 9.75 laps (if runs 12 laps in 8 days) or 78 laps (if 12 laps each day for 8 days)
Step-by-step explanation:
Given:
a) Laps covered in 8 days = 12
interval = 1 and half day
total laps = ?
Solution:
To know the total laps with intervals we need to calculate the laps run each day :
= 12/8 laps per day
= 3/2 laps per day
Now multiply the daily run with days
= (3/2)*6.5 (due to 8 - 1.5 = 6,5 days)
= 9.75 laps
B) Given:
Laps covered in 8 days = 12*8 =96
interval = 1 and half day
total laps = ?
Solution:
To know the total laps with intervals we need to calculate the laps run each day :
= 96/8 laps per day
= 12laps per day
Now multiply the daily run with days
= 12*6.5 (due to 8 - 1.5 = 6,5 days)
= 78 laps
Need help please....
Answer:
-14 x²
Step-by-step explanation:
10 x² - 24 x² = -14 x²
The answer is 14
if you multiply both P(x) and Q(x), the third part becomes 14x², so the coefficient of x² becomes 14.
Answered by GAUTHMATH
A car took 6 minutes to travel between two stations that are 3 miles apart find the average speed of the car in mph
Answer: 30 mph is the answer.
Step-by-step explanation:
s = 3 miles
t = 6 minutes
so,
60 minute = 1 hour
1 minute = 1/60 hour
6 minutes = 1/60 * 6 = 0.1 hour
so
average speed = s/t
= 3/0.1 = 30 mph
Quality control. As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.
(a) What population is under consideration in the data set?
(b) What parameter is being estimated?
(c) What is the point estimate for the parameter?
(d) What is the name of the statistic can we use to measure the uncertainty of the point estimate?
(e) Compute the value from part (d) for this context.
(f) The historical rate of defects is 10%. Should the engineer be surprised by the observed rate of defects
during the current week?
(g) Suppose the true population value was found to be 10%. If we use this proportion to recompute the value in part (e) using p = 0.1 instead of pˆ, does the resulting value change much?
Answer:
See Explanation
Step-by-step explanation:
According to the Question,
Given That, As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.(a) The sample is from all computer chips manufactured at the factory during the week of production. We might be tempted to generalize the population to represent all weeks, but we should exercise caution here since the rate of defects may change over time.
(b) The fraction of computer chips manufactured at the factory during the week of production that had defects.
(c) Estimate the parameter using the data: phat = 27/212 = 0.127.
(d) Standard error (or SE).
(e) Compute the SE using phat = 0.127 in place of p:
SE ≈ √(phat(1−phat)/n) = 0.023.
(f) The standard error is the standard deviation of phat. A value of 0.10 would be about one standard error away from the observed value, which would not represent a very uncommon deviation. (Usually beyond about 2 standard errors is a good rule of thumb.) The engineer should not be surprised.
(g) Recomputed standard error using p = 0.1: SE = 0.021. This value isn't very different, which is typical when the standard error is computed using relatively similar proportions (and even sometimes when those proportions are quite different!).
I need some help please!
Answer:
See below
Step-by-step explanation:
Given :-
y || zTo Prove :-
m∠5 + m∠2 + m∠6 = 180°Proof :-
Here we are required to prove that ,
[tex]\rm\implies m\angle 5 + m\angle 6 + m\angle 2 = 180^o [/tex]
And here it's given that , y || z . Therefore ,
∠3 = ∠6 ( alternate interior angles )∠1 = ∠5 ( alternate interior angles )Now we know that the measure of a straight line is 180°. Therefore ,
[tex]\rm\implies m\angle 1 + m\angle 2 + m\angle 3 = 180^o \\\\\implies\boxed{\rm m\angle 5 + m\angle 6 + m\angle 2 = 180^o} [/tex]
From 1 and 2 .Hence Proved !
Jose bought 217 shares of Darien Electric for $21.96 apiece. His broker charged him a commission of $106.12 for the
purchase. If the yearly dividend on Darien Electric is 77 cents per share, what is the annual yield on Jose's stock? Show
work.
Answer:
what is photosynthic ..
p.l.e.a.s.e join eti-fgdd-xjs
why do plant need it
Mathematics I need help
There are two points of the form (x,-4) that have a distance of 10 units from the point (3,2). Give the x value for one of those points.
Answer:
x = - 5
Step-by-step explanation:
[tex]Let \ (x _ 1 , y _ 1 ) \ and \ (x _ 2 , y _ 2 ) \ be \ the \ points. \\\\The \ distance \ between \ the \ points \ be ,\ d = \sqrt{(x_2 - x_1)^2 + ( y _ 2 - y_1)^2}[/tex]
Given : d = 10 units
And the points are ( x , - 4) and ( 3 , 2 ).
Find x
[tex]d = \sqrt{( 3 - x)^2 + ( -4 - 2)^2} \\\\10 = \sqrt{( 3 - x)^2 + ( -6)^2} \\\\10^2 = [ \ \sqrt{( 3 - x)^2 + 36} \ ]^2 \ \ \ \ \ \ \ \ \ [ \ squaring \ both \ sides \ ] \\\\100 = ( 3 - x )^2 + 36\\\\100 - 36 = ( 3 - x )^ 2\\\\( 3 - x ) = \sqrt{64}\\\\3 - x = \pm 8\\\\3 - x = 8 \ and \ 3 - x = - 8\\\\-x = 8 - 3 \ and \ -x = - 8 - 3\\\\-x = 5 \ and \ -x = - 11\\\\x = - 5 \ and \ x = 11\\\\[/tex]
Check which value of x satisfies the distance between the points.
x = 11
[tex]d = \sqrt{(3-11)^2 + (-2--4)^2} = \sqrt{(-8)^2 + (-2+4)^2}= \sqrt{64+4} = \sqrt {68} \ units[/tex]
does not satisfy.
x = - 5:
[tex]d = \sqrt{ (3 -- 5)^2 + ( - 4 - 2)^2} = \sqrt{8^2 + 6^2} = \sqrt{100} =10 \ units[/tex]
Therefore , x = - 5
Use the P (A + B) = P (A) x P (B) rule to find the probability of system failure. Let A and B be the events that the first alarm and second alarm, respectively, fail. Do you get the same answer you did in the earlier question?
Answer:
answer is in the pic Mark me brainliest plz
Step-by-step explanation:
Answer:
The probability of the first alarm failing is (1 - 0.8) = 0.2
The probability of the second alarm failing is (1−0.9)=0.1.
Using the multiplication rule (since A and B are independent), the probability of failure is 0.2 * 0.1 = 0.02
Step-by-step explanation:
Please help asap!!! :(
Answer:
Our maximum is 19 when x=3 and y=7 and our minimum is -21 when x=3 and y = -3
Step-by-step explanation:
First, we can graph these inequalities out. As you can see in the picture, the three vertices where the inequalities all connect form a triangle. We can check each of these vertices to find our minimum and maximum.
First, we have (3,7). 4y-3x = 4(7)-3(3)=28-9=19
Next, for (3, -3), we have 4y-3x = 4(-3)-3(3) = -12-9=-21
Finally, for (0.5, 2), we have 4y-3x=4(2)-3(0.5)=8-1.5 = 6.5
Our maximum is 19 when x=3 and y=7 and our minimum is -21 when x=3 and y = -3
Help me pls
I put the picture in the attach file below
(Sorry i'm in secondary school but i have a problem with my settings)
Answer:
1,2,4,8
Step-by-step explanation:
1
2
1,2
4
4,1
4,2
4,2,1
8
8,1
8,2
8,2,1
8,4
8,4,1
8,4,2
8,4,2,1
PLEASE HELP I DONT NEED EXPLANATION JUST THE EQUATION IM IN A TEST RN HELP ASAP THANK YOU SO MUCH :)))
Answer:
[tex]-x^{2}[/tex]
Step-by-step explanation:
It simple really its just a reflection over the x-axis making it a negative towards the parent function
Answer:
The answer is -x²
Step-by-step explanation:
Hope this helps :)
A manufacturer inspects a sample of 500 smart phones and finds that 496 of them have no defects. The manufacturer sent a shipment of 2000 smartphones to a distributor. Predict the number of smartphones in the shipment that are likely to have no dects.
Answer:
1984
Step-by-step explanation:
help help HELP!! will give brainliest
If f(x) = x², g(x) = 5x, and h(x) = x + 4, find each value.
Find h[f(4)].
Answer:
[tex]h(f(4))=20[/tex]
Step-by-step explanation:
We are given the functions:
[tex]f(x)=x^2,\, g(x)=5x\text{, and } h(x)=x+4[/tex]
And we want to find
[tex]h(f(4))[/tex]
Find f(4) first:
[tex]f(4)=(4)^2=16[/tex]
Thus:
[tex]h(f(4))=h(16)[/tex]
Now, evaluate h(16):
[tex]h(16)=(16)+4=20[/tex]
Hence:
[tex]h(f(4))=20[/tex]
3х + 2 +(-5)? I need help pls
Answer:
3x + 2 - 5
3x - 3
x = 3 ÷ 3
x = 1
I hope this helped!
f(X) = 10x^3 find inverse
Answer: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]
Step-by-step explanation:
[tex]f(x)=10x^{3}\\y=10x^{3}[/tex]
switch the x and y:
[tex]x=10y^{3}[/tex]
Now solve for y:
[tex]x=10y^{3} \\\frac{x}{10} =y^{3} \\\sqrt[3]{\frac{x}{10} } =y\\[/tex]
Therefore, the inverse of that function is: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]
1/4+3+11/2=
NEEED ANSWER ASAP BTW
Answer:
8.75 or 8 3/4
Step-by-step explanation:
To do this question, many do it differently. But for now, we will convert the fractions into decimals.
1/4 = 0.25
11/2= 5.5
0.25 + 3 + 5.5
3.25 + 5.5 =
8.75
The answer is 8.75 or 8 3/4
Answer:
[tex] \frac{35}{4} \: \: \: or \: \: \: 8 \frac{3}{4} [/tex]Decimal form :
8.75
Step-by-step explanation:
Hope it is helpful....
Compute the mean deviation of the following set of data; 9,6, 3, 9, 7, 2, 1, 5, 6, 8.
Answer:
5.6
Step-by-step explanation:
( 9 + 6 + 3 + 9 + 7 + 2 + 1 + 5 + 6 + 8 ) / 10
= 56 / 10
= 5.6
At one point in history, the NBA finals required that one of the two teams win at least three of five games in order to win the Championship. If one team wins the first two games, what is the probability that the same team wins the Championship, assuming that the two teams are well matched and each team is equally likely to win each game
Answer:
50% i believe
Step-by-step explanation:
because in every scenario theres 2 teams and if they are well matched it be half and half on every game assuming they're the same level of comp
(c) Construct a 99% confidence interval for u if the sample
size, n, is 35.
Answer:
The confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
In this question:
[tex]M = 1.99\frac{\sigma}{\sqrt{35}}[/tex]
The lower end of the interval is the sample mean subtracted by M, while upper end of the interval is the sample mean added to M. Thus, the confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.
Suppose the age that children learn to walk is normally distributed with mean 12 months and standard deviation 2.5 month. 34 randomly selected people were asked what age they learned to walk. Round all answers to 4 decimal places where possible.
Answer:
Step-by-step explanation:
a.) it's just mean, variance
so here it's just 12,6.25
b.) For the x bar thing just divide the variance by the number of people (mean stay the same)
the variance is then (2.5²/34)= .1838
which makes it (12,.1838)
c.) here we don't use x bar (and so it's normal (12,2.5²))
p(11.6) = (11.6-12)/(2.5)= -.16 = .4364
p(12.4)= (12.4-12)/2.5 = .16= .5636
.5636-.4364= .1272
d.) here we use x bar because it's asking for an average so it's normal (12, .1838)
same deal
p(11.6)=(11.6-12)/√.1838= -.93295= .1762
p(12.4)= (12.4-12)/√.1838= .93295= .8238
.8238-.1762= .6476
d.) no because they're probably IID
f.) It's average so here we use x bar
q1 is just the 25th percentile
the 25th percentile is -.6745
-.6745=(x-12)/(√.1838)= 11.711
q3 is the 75th percentile
.6745=(x-12)/√.1838
x=12.289
The interquartile range is just the difference between the two
12.289-11.711= .5784
Solve the expression using the correct order of operations.
0.75x3.2+ (9.1)2-((-2.3)-(-0.9))2
Answer:
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]
Step-by-step explanation:
Given
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]
Required
Solve
Start with the bracket
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]
Evaluate all exponents
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]
Evaluate all products
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]
2x+2y=38 y=x+3 solve by the solution
Answer:
x = 8 , y = 11
Step-by-step explanation:
[tex]2x + 2y = 38 => x + y = 19 - -- ( 1 ) \\\\y = x + 3 ---- ( 2 ) \\\\Substitute \ ( 2 ) \ in \ ( 1) :\\\\ x + y = 19\\\\x + ( x+ 3) = 19\\\\2x + 3 = 19\\\\2x = 19 - 3 \\\\2x = 16 \\\\x = \frac{16}{2} = 8\\\\Substitute \ x = 8 \ in \ ( 1 ) : \\\\x + y = 19\\\\8 + y = 19\\\\y = 19 - 8 = 11[/tex]
Tan^2t /sin t = tan t sec t
Answer:
Step-by-step explanation:
[tex]\frac{tan^2t}{sint}=\frac{tan t\times tant}{sin t} =\frac{tan t}{sint} \times \frac{sin t}{cos t} =\frac{tan t}{cos t} =tan t ~sec t[/tex]
Please help me on this real quick
Time Remaining 59 minutes 49 seconds00:59:49 PrintItem 1 Time Remaining 59 minutes 49 seconds00:59:49 At the end of Year 2, retained earnings for the Baker Company was $2,950. Revenue earned by the company in Year 2 was $3,200, expenses paid during the period were $1,700, and dividends paid during the period were $1,100. Based on this information alone, what was the amount of retained earnings at the beginning of Year 2?
Answer:
$2550
Step-by-step explanation:
Calculation to determine the amount of retained earnings at the beginning of Year 2
Using this formula
Beginning Retained Earnings + Revenue − Expenses − Dividends = Ending Retained Earnings
Let plug in the formula
Beginning Retained Earnings + $3,200 − $1,700 − $1,100 = $2950
Beginning Retained Earnings= $2,950-$400
Beginning Retained Earnings = $2,550
Therefore the amount of retained earnings at the beginning of Year 2 is $2550
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Answer:
Not a functionFunctionFunctionNot a functionNot a functionHope this helps!