Answer:
Ideal Gas Law
PV = nRT
Explanation:
Pressure is proportional to temperature;
The heat of the fire would cause increased pressure inside the closed aerosol vessel, eventually resulting in explosion of the vessel, once the temperature rises enough.
According to one acid-base theory a molecule acts as an acid when the molecule
A sample of diborane gas has a pressure of 345 torr at a temperature of -15c and volume of 3.48L if conditions are changed so that the temperature is 36c and the pressure is 468 torr what will be the volume of the sample
Answer: 3.05L= V2
Explanation:
using
P1V1/T1=P2V2/T2
where p1= 345torr
T1, tempertaure= -15c+ 273=258K
T2, temperature= 36+ 273=309K
p2, Pressure= 468 torr
V2=???
P1V1/T1=P2V2/T2
v2=P1V1T2/T1P2= 345X3.46L X 309/ 258X 468=
V2= 3.05L
Given:
CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ/mol
How much energy is released when 59.7 grams of methane (CH4) reacts with oxygen?
The combustion of 59.7 grams of methane releases ____ kilojoules of energy
Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄ [tex]= \frac{59.7}{16} = 3.73125 \ moles[/tex]
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Answer:
The combustion will release -3,321 KJ/mol of energy
Explanation:
What is the % of each element in Ni3{PO4) 2 ?
Answer:
nickel 48.1063%
Phosphorus 16.9245%
Oxygen 34.9692%
The percent composition of each element like nitrogen, oxygen and phosphorous in Ni₃(PO₄)₂ are 48.03%, 34.97% and 16.93% respectively.
How do we calculate % composition?Percent composition of any element present in any compound will be calculated as:
% comosition = (Mass of element / Mass of compound)×100%
Mass of Ni₃(PO₄)₂ compound = 366.02 g/mol
Molar mass of 3 Nitrogen atoms = 3×58.6 = 175.8 g/mol
Moar mass of 2 Phosphorous atoms = 2×31 = 62 g/mol
Moar mass of 8 Oxygen atoms = 8×16 = 128 g/mol
% comosition of Nitrogen = (175.8/366.02)×100% = 48.03%
% comosition of Oxygen = (128/366.02)×100% = 34.97%
% comosition of Phosphorous = (62/366.02)×100% = 16.93%
Hence % composition of nitrogen, oxygen and phosphorous is 48.03%, 34.97% and 16.93% respectively.
To know more about percent composition, visit the below link:
https://brainly.com/question/21044245
Wax is a nonpolar substance . In which type of substance is it the most soluble ?
Answer:
nonpolar
Explanation:
Use the phrase "like dissolves like"
- Hope that helps! Please let me know if you need further explanation.
How many grams of CO2 are produced from the burning of 1.0 mol of amyl alcohol, C5H11OH?
Answer:
220g of CO2
Explanation:
Step 1:
The balanced equation for the reaction.
2C5H11OH + 15O2 —> 10CO2 + 12H2O
Step 2:
Determination of the number of mole of CO2 produced by burning 1 mole of C5H11OH.
From the balanced equation above,
2 moles of C5H11OH produced 10 moles CO2.
Therefore, 1 mole of C5H11OH will produce = (1 x 10)/2 = 5 moles of CO2.
Therefore, 5 moles of CO2 is produced from the reaction.
Step 3:
Conversion of 5 moles of CO2 to grams.
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Number of mole of CO2 = 5 moles
Mass of CO2 =...?
Mass = mole x molar mass
Mass of CO2 = 5 x 44
Mass of CO2 = 220g.
Therefore, 220g of CO2 were obtained from the reaction.
(Multiple Choice, 30 pts)
A student thinks that halogens are highly reactive because their electrons are weakly attracted to their nuclei. Which is evidence that disputes this student's idea?
A. Halogens react with alkali metals.
B. Halogens cannot react with noble gases.
C. Halogens tend to attract electrons when bonding.
D. Halogens have a full octet of electrons.
Answer:
c
Explanation:
¨Halogens being non metals have greater electronegativities hence, attract electrons and making the statement disputed. Nobel gases are highly stable; this explains why they are nonreactive. They do not form chemical bonds because they only have a little tendency to either gain or lose an electron; on the other hand, halogens are reactive because they only need one additional electron to complete their octet. ¨
i found that from another users answer for the same question
Answer:
answer c
Explanation:
A group of tissues working together is?
Answer:
An organ
Explanation:
An organ is one or more tissues that work together to form a specific function.
- Hope that helps! Please let me know if you need further explanation.
5. On what organ does alcohol have the most noticeable effect?
Answer:
the liver
Explanation:
it processes alcohol, work very hard
Which of the following Noble Gases has a mass of 10.0 g?
Answer:
Option B is correct.
0.119 mole of Kr has a mass of 10.0 g
Explanation:
The complete Question was ontained online, albeit, it was incomplete, even from the online source. But the solution is possible based on the part of the question obtained.
Complete Question
Which of the following Noble Gases has a mass of 10.0 g?
A. 2.02 mol Ne B. 0.119 mol Kr C.
Solution
Number of moles = (Mass)/(Molar Mass)
Mass = (Number of moles) × (Molar mass)
Checking the options, one at a time,
A. 2.02 moles of Neon
Number of moles = 2.02 moles
Molar Mass of Neon = 20.1797 g/mol
Mass = 2.02 × 20.1797 = 40.762994 g ≠ 10.0 g
Not the answer.
B. 0.119 moles of Krypton
Number of moles = 0.119 moles
Molar Mass of Krypton = 83.798 g/mol
Mass = 0.119 × 83.798 = 9.971962 g ≈ 10.0 g
This is definitely the answer.
Hope this Helps!!!
Answer: 0.119 mol Kr
Explanation:
Balance equation: _NO + _H2O = _NH3 + _O2
Answer:
4NO + 6H2O = 4NH3 + 5O2
Explanation:
Think about it this way: there are 4N's 4O's and 12H's and 10O's on both sides that's what makes it balanced
Hope this helps :)
When humans plant more trees, carbon can begin entering the ____
a- hydrosphere
b- geosphere
c- biosphere
Answer:
biosphere
Explanation:
The carbon cycle is the biogeochemical cycle by which carbon is exchanged between the biosphere, geosphere, hydrosphere and atmosphere of the Earth.
The biosphere refers to the regions of the surface and atmosphere of the earth or another planet occupied by living organisms.
Plants are responsible for taking in carbon in nature. When more trees are planted, carbon is absorbed by plants which is a component of the biosphere. Hence planting more trees means increasing the intake of carbon into the biosphere.
What is the percentage composition of cobalt in cobalt(II) fluoride, CoF2?
Answer:
60.8%
Explanation:
We'll begin obtaining the molar mass of cobalt(II) fluoride, CoF2. This can be done as shown below:
Molar mass of CoF2 = 59 + (19x2) = 97g/mol.
The percentage composition of cobalt in cobalt(II) fluoride, CoF2 is given by:
Mass of Co/Molar Mass of CoF2 x 100
=> 59/97 x 100 = 60.8%
Therefore, the percentage composition of cobalt in cobalt(II) fluoride, CoF2 is 60.8%
Which phrase describes a volcano that is not expected to erupt again?
quiet volcano
extinct volcano
dormant volcano
explosive volcano
Which options identify what the arrows in the diagram
represent? Check all that apply.
D atoms
elements
energy
gas
particles
Answer:
D
Explanation:
What is the mass of 3.00 moles of carbon
Answer:
36 grams as 1 mole is 12 grams
Answer:
tbh idk cause I will love to answer your question but ehh
Why might you have difficulty determining the pH of bleach using ph strips?
Answer:
pH test strips will lose colour and their pH sensitivity as strips are made from universal indicator. Universal indicator is composed of phenolphthalein, methyl red, methyl orange and thymol blue.
Explanation:
pH test strips are made from the universal indicator. The universal indicator is composed of phenolphthalein, methyl red, methyl orange, and thymol blue. All of these will react with chlorine in bleach. As a result, they will lose color and pH sensitivity. Due to this, it is difficult to determine the pH of bleach using ph strips.
5) Usted empuja muy fuerte un escritorio pesado e intenta moverlo. Usted efectúa trabajo sobre el escritorio: a.- Ya sea que lo mueva o no, siempre y cuando usted ejerza una fuerza. B.- Sólo si el escritorio se mueve. C.- Sólo si el escritorio no se mueve. D.- Nunca; el escritorio hace trabajo sobre usted. E.- Ninguna de las anteriores. ME AYUDAN PORFA?
Answer:
5) You push hard on a heavy desk and try to move it. You do work on the desk: A.- Whether you move it or not, as long as you exert a force. B.- Only if the desktop moves. C.- Only if the desktop does not move. D.- Never; the desk does work on you. E.- None of the above. CAN YOU HELP ME?
B.- Only if the desktop moves.
Explanation:
No work is done if a force is exerted but no displacement occurs. A force perpendicular to the displacement does no generate work.
What is the overall reduction potential for the reaction Agt (aq) + Cu(s)——>Ag(s) + Cu2+ (aq)?
-0.46 V
+0.46 V
+0.57 v
+1.14V
Answer:
it should be +0.46 :)
Explanation:
I just took the test and got it right.
Answer:
I think it's +1.14 V, but don't take my word for it..
Which statement describes a gas condensing into a liquid?
A.
The atoms in the molecules get heavier so they move less.
B.
The molecules break into smaller pieces that take up less space.
C.
The molecules stick together to make bigger molecules.
D.
The molecules get closer together and move more slowly.
Answer: molecules get closer
Explanation:
Condensation is the process in which molecules of a gas slow down, come together, and form a liquid. When gas molecules transfer their energy to something cooler, they slow down and their attractions cause them to bond to become a liquid
hope this helps
pls mark me brainliest
Answer:
D. The molecules get closer together and move more slowly.
Calculate the hyrdrogen ion concentration [h+] for the aquesous solution in which [oh-] is 1 x 10-2 mol/l.Is the solution acidic,basic,or neutral? Show your work
Answer:
- [tex][H^+]=1x10^{-12}[/tex]
- Basic.
Explanation:
Hello,
In this case, given the concentration of hydroxyl ions, one could compute the pOH as shown below:
[tex]pOH=-log([OH^-])=pOH=-log(1x10^{-2})=2[/tex]
Then, since the pOH and the pH are related by:
[tex]pH+pOH=14[/tex]
One computes the pH:
[tex]pH=14-pOH=14-2=12[/tex]
Now, we compute the concentration of hydronium by:
[tex][H^+]=10^{-pH}=10^{-12}[/tex]
[tex][H^+]=1x10^{-12}[/tex]
Finally, since the pH is greater than 7 (neutral point) we conclude that the solution is basic.
Best regards.
Answer:
A. Hydrogen ion concentration, [H+] is 1x10^–12 mol/L
B. Since the pH is 12, the solution is basic.
Explanation:
Data obtained from the question. This includes the following:
Concentration of Hydroxide ion, [OH-] = 1x10^–2 mol/L
Concentration of Hydrogen ion, [H+] =.?
pH =..?
A. Determination of the hydrogen ion concentration, [H+] .
The hydrogen ion concentration, [H+] can be obtained as follow:
[H+] x [OH-] = 1x10^–14
[OH-] = 1x10^–2
[H+] x 1x10^–2 = 1x10^–14
Divide both side by 1x10^–2
[H+] = 1x10^–14 / 1x10^–2
[H+] = 1x10^–12 mol/L
B. Determination of the pH of the solution.
The pH of the solution can be obtained as follow:
pH = –Log [H+]
[H+] = 1x10^–12 mol/L
pH = –Log 1x10^–12
pH = 12.
Then pH of a solution ranges between 0 and 14.
A pH reading between 0 and 6 is termed an acidic solution, a pH reading of 7 is termed a neutral solution and a pH reading between 8 and 14 indicates an alkaline or a basic solution.
The higher the pH value, the more alkaline or basic the solution becomes.
Since the pH is 12, the solution is basic.
Na2O+H2O= 2NaOH how many grams of Na2O are required to produce 1.06*10^2 grams of NaOH
Answer:
77.5 grams of Na2O
Explanation:
Convert grams to mols.
1.06 x 10^2 grams x 1 mol NaOH/39.99
= 2.50 mols NaOH
Find the mole ratio of NaOH and Na2O
1:2
Convert mols NaOH to Na2O mols
2.50 mols NaOH x 1 mol Na2O/2 mols NaOH
= 1.25 mols Na2O
Convert to grams
1.25 mols Na2O x 61.98 grams Na2O/1 mol
= 77.5 grams Na2O required to produce 1.06 x 10^2 grams of NaOH
How many copper atoms are in a 70g copper
Answer:
[tex]x = 6.634\times 10^{23}\,atoms[/tex]
Explanation:
The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:
[tex]x = \left(\frac{70\,g}{63.546\,\frac{g}{mol}} \right)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)[/tex]
[tex]x = 6.634\times 10^{23}\,atoms[/tex]
Answer:
6.64x10^23 atoms.
Explanation:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.
1 mole of Cu = 63.5g
If 63.5g of Cu contains 6.02x10^23 atoms,
Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.
Therefore, there are 6.64x10^23 atoms in 70g oh Cu
The Ka of acetic acid (CH3COOH) is 1.8 x10-5.
Calculate the pH of a 3.0 M solution of acetic acid.
Answer: 2.13
Explanation: i crawled so you could run :)
En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L alcancen el equilibrio a 150°C. ¿Cuáles son las presiones parciales de equilibrio de IBr, I2 y Br2?
Answer:
P IBr: 15.454atm
I₂: 0.923 atm
P Br₂: 0.923atm
Explanation:
Basados en la reacción:
I₂(g) + Br₂(g) ⇄ 2 IBr(g)
La constante de equilibrio, Keq, es definida como:
[tex]Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}[/tex]
Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio
Usando PV = nRT, la presión inicial de IBr es:
P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = 17.3 atm
Siendo las presiones en equilibrio:
P IBr: 17.3 - 2X
P I₂: X
P Br₂: X
Donde X representa el avance de reacción.
Remplazando en Keq:
280 = (17.3 - 2X)² / X²
280X² = 4X² - 69.2X + 299.29
0 = -276X² - 69.2X + 299.29
Resolviendo para X:
X = -1.174 → Solución falsa. No existen presiones negativas
X = 0.923 → Solución real
Así, las presiones parciales en equilibrio de cada compuesto son:
P IBr: 17.3 - 2X = 15.454atm
P I₂: X = 0.923atm
P Br₂: X = 0.923atm
Answer:
[tex]p_{I_2}=0.926atm\\p_{Br_2}=0.926atm\\p_{IBr}=15.5atm[/tex]
Explanation:
Hello,
In this case, given the initial load of 0.500 mol of IBr in the 1.00-L, we compute its initial concentration:
[tex][IBr]_0=\frac{0.500mol}{1.00L}=0.500M[/tex]
Hence, by knowing the original reaction, we should invert it as IBr will produce iodine and bromine considering the initial load:
[tex]2IBr(g)\rightleftharpoons I_2(g) + Br_2(g)[/tex]
Therefore, the equilibrium constant should be inverted:
[tex]K'=\frac{1}{Keq}=\frac{1}{280}=3.57x10^{-3}[/tex]
So we write the law of mass action:
[tex]K'=\frac{[I_2][Br_2]}{[IBr]^2}[/tex]
That in terms of the change [tex]x[/tex] due to the reaction extent turns out:[tex]3.57x10^{-3}=\frac{(x)(x)}{(0.500-2x)^2}[/tex]
In such a way, solving by using solver or quadratic equation we obtain:
[tex]x_1=-0.0339M\\x_2=0.0267M[/tex]
Clearly, the solution is 0.0267M, thus, the equilibrium concentrations are:
[tex][I_2]=x=0.0267M[/tex]
[tex][Br_2]=x=0.0267M[/tex]
[tex][IBr]=0.5M-2x=0.5M-2*0.0267M=0.447M[/tex]
Thus, with the given temperature (150+273.15=423.15K), we compute the partial pressures by using the ideal gas equation:
[tex]p_{I_2}=[I_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{I_2}=0.926atm\\\\p_{Br_2}=[Br_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{Br_2}=0.926atm\\\\p_{IBr}=[IBr]RT=0.447\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{IBr}=15.5atm[/tex]
Best regards.
What mass of water will be collected if 20.0
grams of hydrogen are consumed
2H2+O2--->2H2O
358g
179g
44.7g
Or 89.4g
Answer: 179 of [tex]H_2O[/tex] will be produced.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} H_2=\frac{20.0g}{2.01g/mol}=9.95moles[/tex]
[tex]2H_2+O_2(g)\rightarrow 2H_2O[/tex]
According to stoichiometry :
2 moles of [tex]H_2[/tex] give = 2 moles of [tex]H_2O[/tex]
Thus 9.95 moles of [tex]H_2[/tex] will require=[tex]\frac{2}{2}\times 9.95=9.95moles[/tex] of [tex]H_2O[/tex]
Mass of [tex]H_2O=moles\times {\text {Molar mass}}=9.95moles\times 18g/mol=179g[/tex]
Thus 179 of [tex]H_2O[/tex] will be produced.
On May 3, Zirbal Corporation purchased 4,500 shares of its own stock for $36,000 cash. On November 4, Zirbal reissued 800 shares of this treasury stock for $7,200. Prepare the May 3 and November 4 journal entries to record Zirbal's purchase and reissuance of treasury stock.
Answer:
Explanation:
Each share costs $36000/4500
= $8
800 shares will cost 800*8
= $6400
Find attached the journal
How do astronomers know about the future collision of Andromeda and the Milky Way?
A) All galaxies will collide at some point
B) The two galaxies have collided previously
C) Astronomers have observed their movements over time
D) The Milky Way has changed course to head toward Andromeda
Answer:
Astronomers have observed their movements over time
Explanation:
Just took the test!!!
The future collision of Andromeda and milky way are known by astronomers because ; ( C ) Astronomers have observed their movements over time
Andromeda also known as messier 31 is a spiral galaxy that appears as a milky blur when viewed from the earth and it is believed to be slightly over 2.5 million years old.
Astronomers predict that based on its movement and the movement of the Milky way there is most likely going to be a collision in future between the Andromeda and milky way.
Hence we can conclude that The future collision of Andromeda and milky way are known by astronomers because Astronomers have observed their movements over time
Learn more : https://brainly.com/question/2849133
How might an antioxidant prevent another element from gaining or losing an electron?
Answer:
An antioxidant helps in the mopping up and elimination of free radicals and a common example is Glutathione. Oxidation reactions Involves the transfer of electrons or addition of oxygen to a substance.
Antioxidants help in decreasing or prevention of the oxidation of the molecules due to free radicals being formed which causes damage in the cells of animals.
What are the four main parts of the Sun? *
Answer: The inner layers are core, radiative zone, and convective zone. The putter layers a photosphere, the chromosphere, the transition region and the corona
