Answer:
High
Explanation:
Concentration in chemistry refers to the amount of substance present in a system.
If potassium cyanide is dissolved in water, we have the following equilibrium being set up in solution;
KCN(aq) ⇄K^+(aq) + CN^-(aq)
This means that the concentration of both potassium ions and cyanide ions increases.
Hence, If potassium cyanide is dissolved in water you can say that the equilibrium concentrations of potassium and cyanide ions are high in the solution.
9.0+ 2.000 (35.35) =
Answer:
79.7
Explanation:
Answer:79.7
Explanation:just got it right on the quiz!
Which compound has atoms sharing 2 electrons
N2
CO2
BR2
CCI4
Answer:
CO2
Explanation:
They share 2 electrons with carbon.
Make tag question.
neither of them plays cricket,......?
Answer:
neither of them plays cricket,does anyone?
Explanation:
I know you will think I its weird but it is the rule of grammar and 100% correct!
Answer:
neither of them plays cricket, do you?
Explanation:
FULL FORM OF NASA??
lol
Answer:
NASA stands for National Aeronautics and Space Administration
Answer:
National Aeronautics and Space Administration
hope this will help you more
You have selected your two primers and added all of the PCR components to a test tube. Use the answer choices [A-C] to explain what will happen as the polymerase chain reaction proceeds. Answers may be used more than once or not at all.
Hi. You did not provide any response options. However, a PCR reaction proceeds as follows.
After the primers are added to the test tube containing the PCR components. This tube is placed in a device called a thermocycler. At that moment, the stage called denaturation will begin, where the thermocycler increases the temperature to the point of breaking the hydrogen bonds that hold the two strands of DNA together. The thermal cycler increases the temperature up to 96°C.
After that, the second step of the reaction begins. At that moment, the thermal cycler lowers the temperature to 55º - 65ºC, which is the ideal temperature for the primers to be able to attach themselves to the DNA strands, preparing them for the presence of the polymerase.
After that, the thermocycler raises the temperature to 72ºC, which is the ideal temperature for the DNA polymerase to work. At this stage, the DNA polymerase will use the DNA strand and the primer to build a new DNA strand, which will be annealed to the DNA strand used as a template.
These three steps will be repeated about 35 times, generating many copies of DNA.
write the formula two atom of iron and three atoms of oxygen
Answer:
Fe2O3 is the formula this is your correct answer
4. How many electrons are in the electron shell closest to the nucleus?
Answer:
2
Explanation:
there are 2 electrons close to the nucleus
Answer:
2
Explanation:
2*n^2, where n is the electron shell.
If we plug 1 in, we will get 2*1, which is 2.
what is interpolation?
Explanation:<3 sorry.
What is the pressure, in atm, exerted by 41.6 g oxygen in a 22.0L container at 30.0C ?
Answer:
1.47 atm
Explanation:
Step 1: Calculate the moles corresponding to 41.6 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
41.6 g × 1 mol/32.00 g = 1.30 mol
Step 2: Convert 30.0 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 30.0 + 273.15 = 303.2 K
Step 3: Calculate the pressure exerted by the oxygen
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 1.30 mol × (0.0821 atm.L/mol.L) × 303.2 K / 22.0 L = 1.47 atm
What is the total number of atoms in one formula unit of MgSO4.7H2O?
Answer:
11.
O4 means 4 atoms of oxygen. H2O
has one atom of oxygen, so seven "units" of
H2O has 7.
For a gas of N identical molecules of molecular volume Vm in total volume V at temperature T, the number of ways of locating the N molecules in the volume is
Answer:
[tex]\left(\frac{V_m}{V}\right)^N[/tex]
Explanation:
Given :
Number of identical volumes = N
The molecular volume = [tex]V_m[/tex]
The total volume = V
Temperature = T
Therefore, the number of the ways for locating one molecule within the volume V is : [tex]\frac{V_m}{V}[/tex]
There are N molecules.
So, the total umber of ways of locating N molecules is [tex]\left(\frac{V_m}{V}\right)^N[/tex]
The solubility of compound A in water is 3 g /100ml at 25oC, 11 g/100 ml at 60 oC . If you were to dissolve 20 g of A in 200 ml of water at 60 oC and then slowly cool down the solution to induce crystallization, how many grams of compound A would come out of solution at 25oC?
Answer:
14g of A would come out
Explanation:
The solubility of A at 60°C is 11g/100mL. In 200mL, solubility is:
22g/200mL. That means, the 20g of A will be dissolved completely at 60°C.
Then, at 25°C, the solubility of A is 6g/200g. That means the amount of A that precipitates during the temperature decreasing is:
20g-6g =
14g of A would come out
A certain liquid has a normal freezing point of and a freezing point depression constant . Calculate the freezing point of a solution made of of alanine () dissolved in of .
The question is incomplete, the complete question is;
A certain liquid X has a normal freezing point of 5.40 °C and a freezing point depression constant K=3.05 ?kg mol solution made of 46.1g of alanine (C3H,NO2) dissolved in 750. g of i. Round your answer to 3 significant digits.
Answer:
3.3 °C
Explanation:
If ∆T= K m I
Where;
∆T = freezing point depression
K = freezing point constant
m= morality of solution
i= Van't Hoff factor
Number of moles of solute = 46.1 g/89.09 g/mol = 0.52 moles
Molality of solution = 0.52 moles /750 ×10-3Kg
= 0.69 m
∆T= 3.05 × 0.69 × 1
∆T= 2.10 °C
Freezing point of solution the solution = freezing point of pure solvent - freezing point depression
= 5.40°C - 2.10 °C
= 3.3 °C
A 1M solution is made of each item in a pair. When would this combination create a buffer? Chose the pairs below that you could use to make a buffered solution.
a. HCI/NaOH
b. HCOOH/ NaHCOO
c. HNO2/H2SO3
d. NaNO3/ HNO3
Answer:
b. HCOOH/ NaHCOO.
Explanation:
A buffer system may be formed in one of two forms:
A weak acid with its conjugate base.A weak base with its conjugate acid.Chose the pairs below that you could use to make a buffered solution.
a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.
b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.
c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.
d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.
What is the pH of an acetic acid solution where the concentration of acetic acid is 2 mM and the concentration of sodium acetate is 20 mM. The pKa of acetic acid is 4.76.
Answer:
pH = 5.76
Explanation:
We can solve this problem by using Henderson-Hasselbach's equation:
pH = pKa + log[tex]\frac{[SodiumAcetate]}{[AceticAcid]}[/tex]
We are already know all the required information, thus we input the data given by the problem:
pH = 4.76 + log(20/2)
And finally calculate the pH:
pH = 5.76
The pH of that acetic acid solution is 5.76.
Note: Please show all work and calculation setups to get full credit. T. he following may be used on this assignment: specific heat of (water=4.184 J/g oC; ice=2.03 J/g oC; steam=1.99 184 J/g oC); heat of fusion of water=80. cal/g; heat of vaporization=540 cal/g; 1cal=4.184J.
Calculate the energy required (in J) to convert 25 g of ice at -15 oC to water at 75 oC.
Answer:
1.7 × 10⁴ J
Explanation:
Step 1: Calculate the heat required to raise the temperature of ice from -15 °C to 0°C
We will use the following expression.
Q₁ = c(ice) × m × ΔT
Q₁ = 2.03 J/g.°C × 25 g × [0°C - (-15°C)] = 7.6 × 10² J
Step 2: Calculate the heat required to melt 25 g of ice
We will use the following expression.
Q₂ = C(fusion) × m
Q₂ = 80. cal/g × 25 g × 4.184 J/1 cal = 8.4 × 10³ J
Step 3: Calculate the heat required to raise the temperature of water from 0°C to 75 °C
We will use the following expression.
Q₃ = c(water) × m × ΔT
Q₃ = 4.184 J/g.°C × 25 g × (75°C - 0°C) = 7.8 × 10³ J
Step 4: Calculate the total heat required
Q = Q₁ + Q₂ + Q₃
Q = 7.6 × 10² J + 8.4 × 10³ J + 7.8 × 10³ J = 1.7 × 10⁴ J
What is always true of a salt
(a) shows both acidic and basic properties
(b) creates a neutral pH in solution
(c) is an ionic compound formed from an acid-base reaction
(d) can react with acid but not with a base
How many moles of AICI3 are produced?
Answer:
please correct it, the question is incomplete
Nitrogen gas and chlorine gas will react to form nitrogen monochloride gas. 5 moles of nitrogen and 10 moles of chlorine are mixed in a previously evacuated 2 L flask at 500 K. After equilibrium has been established, there are 3 moles of NCl (g) present. What is the equilibrium constant (Kc) for this reaction at 500 K
Answer:
0.30
Explanation:
Step 1: Calculate the known initial and equilibrium molar concentrations
[N₂]i = 5 mol/2 L = 2.5 M
[Cl₂]i = 10 mol/2 L = 5 M
[NCl]e = 3 mol/2 L = 1.5 M
Step 2: Make an ICE chart
N₂(g) + Cl₂(g) ⇄ 2 NCl(g)
I 2.5 5 0
C -x -x +2x
E 2.5-x 5-x 2x
Step 3: Find the value of x
We know that [NCl]e = 2x = 1.5 ⇒ x = 0.75 M
Step 4: Calculate the concentrations at equilibrium
[N₂]e = 2.5-x = 2.5-0.75 = 1.75 M
[Cl₂]e = 5-x = 5-0.75 = 4.25 M
[NCl]e = 1.5 M
Step 5: Calculate the equilibrium constant (Kc)
Kc = [NCl]² / [N₂] × [Cl₂]
Kc = 1.5² / 1.75 × 4.25 = 0.30
Calculate the amount of energy produced by the conversion of 50.0 kg of mass into energy. Use 3.00 x 108 m/s for the speed of light. Round to 3 significant digits.
Which setup will solve this problem?
Answer:
tanong mo sa teacher mo ok
Answer:
E = (50.0 kg)(3.00 x 108 m/s)2
Explanation:
ASAP!!!!! The data table below shows a person’s heart rate measured in beats per minute (bpm) at five different times in the beginning of a day. What causes the change in heart rate over time?
1. tired
2. increased activity
3. passing of time
4. forgetting to eat
This week's imide synthesis involves two reactions. In the first reaction (24A), a(n) ________ bond is formed between the two reactants. Hint: What type of functional group is formed
Answer:
C - N Bond formation.
Explanation:
Imide synthesis is a chemical reaction in organic chemistry which consists of two acyl groups which bond to nitrogen atom. The compound structure is related to acid anhydrides. Imides are monoacyl which are used as valuable intermediates in organic synthesis.
What other reactions is taking place?
how many grams of NaOH will make 1M of its aqueous solution in 1000cm3
Answer: The mass of NaOH is 40 g
Explanation:
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex] .....(1)
Given values:
Molarity of NaOH = 1 M
Molar mass of NaOH = 40 g/mol
Volume of the solution = [tex]1000cm^3=1000 mL[/tex] (Conversion factor: [tex]1cm^3=1mL[/tex])
Putting values in equation 1, we get:
[tex]1=\frac{\text{Mass of NaOH}\times 1000}{40\times 1000}\\\\\text{Mass of NaOH}=\frac{1\times 40\times 1000}{1000}=40g[/tex]
Hence, the mass of NaOH is 40 g
Please Help !! This is an Earth science lab question.
Explain why erosion occurs on the outside of a meander and deposition on the inside of a meander.
Answer:
The sideways movement occurs because the maximum velocity of the stream shifts toward the outside of the bend, causing erosion of the outer bank. At the same time the reduced current at the inside of the meander results in the deposition of coarse sediment, especially sand
Which statement best describes the intermolecular forces between H2
molecules and NH3 molecules in the liquid phase?
A. Dipole-dipole forces are the strongest force between H2
molecules, and Van der Waals forces are the strongest force
between NH3 molecules.
B. Van der Waals forces are the strongest force between H2
molecules, and hydrogen bonding is the strongest force between
the NH3 molecules.
C. Hydrogen bonding is the strongest force between H, molecules
and between NH3 molecules.
D. Van der Waals forces are the strongest force between H2
molecules and between NH3 molecules.
Answer:
D. Van der Waals forces are the strongest force between H2
molecules and between NH3 molecules.
Explanation:
Van der Waal’s forces are the forces which arises due to disturbance in the electron density of the molecule.
These are usually found in non polar molecules. Hence N2 is said to exhibit this force.
Out of these Van der Waals is the weakest force.
Consider the reaction of NO and CO to form N2 and CO2, according to the balanced equation: 2 NO (g) + 2 CO (g) → N2 (g) + 2 CO2 (g) Identify the excess reactant, the limiting reactant, and the product(s) using the molecular art. (Black spheres are carbon, blue spheres are nitrogen, and red spheres are oxygen.)
The image is not given in the question, it is attached below:
Answer: The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.
Explanation:
In the given image:
Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms
The combination of 1 black and 2 red spheres will represent carbon dioxide [tex](CO_2)[/tex] compound
The combination of 2 blue spheres will represent nitrogen molecule [tex](N_2)[/tex]
The combination of 1 blue and 1 red sphere will represent nitrogen monoxide [tex](NO)[/tex] compound
The combination of 1 black and 1 red sphere will represent nitrogen monoxide [tex](NO)[/tex] compound
Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.
Excess reagent is defined as the reagent which is left behind after the completion of the reaction.
We are given:
Given moles of NO = 6 moles
Given moles of CO = 4 moles
For the given chemical equation:
[tex]2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)[/tex]
By stoichiometry of the reaction:
If 2 moles of CO reacts with 2 moles of NO
So, 4 moles of CO will react with = [tex]\frac{2}{2}\times 4=4mol[/tex] of NO
As the given amount of NO is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.
Thus, CO is considered a limiting reagent because it limits the formation of the product.
Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.
Your Turn!
How many electrons are required to complete
the octet around nitrogen, when it forms N2
?
A. 2
B. 3
C. 1
D. 4
E. 6
Answer:
because.......
...........
.........
material or substance a wave transfers energy through what
Answer:
waves, energy is transferred through vibrations of electric and magnetic fields.
Explanation:
In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles
Determine the empirical formula of a compound having the following percent composition by mass: K: 24.74%; Mn: 34.76%; O: 40.50%
Answer: The empirical formula of the compound is [tex]KMnO_4[/tex]
Explanation:
The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Let the mass of the compound be 100 g
Given values:
% of K = 24.7%
% of Mn = 34.76%
% of O = 40.50%
Mass of K = 24.7 g
Mass of Mn = 34.76 g
Mass of O = 40.50 g
To calculate the empirical formula of a compound, few steps need to be followed:
Step 1: Calculating the number of moles of each elementWe know:
Molar mass of K = 39.10 g/mol
Molar mass of Mn = 54.94 g/mol
Molar mass of O = 16 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of K}=\frac{24.7g}{39.10g/mol}=0.632 mol[/tex]
[tex]\text{Moles of Mn}=\frac{34.76g}{54.94g/mol}=0.633 mol[/tex]
[tex]\text{Moles of O}=\frac{40.50g}{16g/mol}=2.53 mol[/tex]
Step 2: Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.632 moles[tex]\text{Mole fraction of K}=\frac{0.632}{0.632}=1[/tex]
[tex]\text{Mole fraction of Mn}=\frac{0.633}{0.632}=1[/tex]
[tex]\text{Mole fraction of O}=\frac{2.53}{0.632}=4[/tex]
Step 3: Writing the mole fraction as the subscripts of each of the elementThe empirical formula of the compound becomes [tex]K_1Mn_1O_4=KMnO_4[/tex]
Hence, the empirical formula of the compound is [tex]KMnO_4[/tex]
The empirical formula of the compound is KMnO₄
Data obtained from the question Potassium (K) = 24.74%Manganese (Mn) = 34.76%Oxygen (O) = 40.50%Empirical formula =? How to determine the empirical formulaDivide by their molar mass
K = 24.74 / 39 = 0.634
Mn = 34.76 / 55 = 0.632
O = 40.50 / 16 = 2.531
Divide by the smallest
K = 0.634 / 0.632 = 1
Mn = 0.632 / 0.632 = 1
O = 2.531 / 0.632 = 4
Therefore, the empirical formula of the compound is KMnO₄
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