Fixed costs are $3,000, variable costs are $5 per unit. The company will manufacture 100 units and chart a 50% markup. Using the cost-plus pricing method, what will the selling price be? (2 pts)
Your company has fixed costs of $150,000 per year. The variable costs per unit in 2018 were $3 per unit, and 30,000 units were produced that year. Your company uses cost-based pricing and has a profit margin of $3 per unit. In 2019, production increased and your team had more experience—variable costs went down to $2 per unit because of your team’s higher skill and 65,000 units were produced that year. What is the change in selling price from 2018 to 2019? (2 pts)
Fixed Costs are $500,000. Per unit costs are $75, and the proposed price is $200. How many units must be sold to break even? How many units must be sold to realize a $200,000 target return? (2 pts)
Congratulations! You you just decided to become the proud owner of a new food truck offering traditional Mediterranean cuisine. Kitchen and related equipment costs are $100,000. Other fixed costs include salaries, gas for the truck, and license fees and are estimated to be about $50,000 per year. Variable costs include food and beverages estimated at $6 per platter (meat, rice, vegetable, and pita bread). Meals will be priced at $10.

x=3

Step-by-step explanation:

x+2=5

x=5-2

x=3

Answer:

384 kmph

Step-by-step explanation:

Answer:

x+ 4

Step-by-step explanation:

      ____x__+4___

x+2 | [tex]x^2 + 6x + 8[/tex]

        [tex]x^2 + 2x[/tex]

        ------------

                [tex]4x + 8\\[/tex]

                 [tex]4x + 8\\[/tex]

                  --------

                     0

Answer:

x+4

Step-by-step explanation:

It looks like you're asked to compute

[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz[/tex]

where C is parameterized by ⟨t, t, t⟩ with 0 ≤ t ≤ 1.

In other words, x = y = z = t, so dx = dy = dz = dt, and the integral reduces to

[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz = \int_0^1 t\,\mathrm dt + t\,\mathrm dt + t\,\mathrm dt \\\\ = 3 \int_0^1 t\,\mathrm dt \\\\ =\frac32t^2\bigg|_{t=0}^{t=1} \\\\ =\boxed{\frac32}[/tex]

Answer:

d) you can reach a large audience with one communication

Step-by-step explanation:

common sense

Answer:

Kofi earned today = 30 cedis

Step-by-step explanation:

Given:

Kofi earned yesterday = 50 cedis

Kofi earned today = 60% of Kofi earned yesterday

Find:

Kofi earned today

Computation:

Kofi earned today = 60% of Kofi earned yesterday

Kofi earned today = 60% x 50

Kofi earned today = 0.60 x 50

Kofi earned today = 30

Kofi earned today = 30 cedis

Answer:

3x=63

Step-by-step explanation:

3 coins means a coin is x and total expenditure is equal to 63

Equate whats inside (arguments) [tex]\sin[/tex] with base period of sine function [tex]2\pi[/tex] and solve for x to get period,

[tex]\pi x=2\pi\implies x=2[/tex]

So the period of the graph of the given function is precisely 2.

Hope this helps :)

Answer:

Step-by-step explanation:

bvjvhvghj

2x + 2y must equal 24. 24 - 2x = 2y and 24 - 2y = 2x. Therefore, 12 - y = x. x could be able to add with y to get 12.

example: x = 4, y = 8. (4 + 4 + 8 + 8 = 16 + 8 = 24)

x = 9, y = 3. (9 + 9 + 3 + 3 = 24)

x = 5, y = 7. (5 + 5 + 7 + 7 = 24)

The estimated slope is approximately 2.344

The given table is presented as follows;

[tex]\begin{array}{ccc}Number \ of Bids &&Price \ in \ Dollars\\1&&23\\2&&34\\4&&44\\9&&46\\10&&50\end{array}[/tex]

The regression line formula to be considered = [tex]\bar u = b_0 + b\cdot \bar x[/tex]

The required parameter is;

The estimated slope

The method to find the estimate slope;

The least squares regression formula (method) is presented as follows;

[tex]\bar u = b_0 + b\cdot \bar x[/tex]

Where;

b₀ = The y-intercept

[tex]\mathbf{ b = \dfrac{\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right) }{\sum \left(x_i - \bar x\right )^2 } = The \ estimated \ slope}[/tex]

From MS Excel, we have;

[tex]\bar x[/tex] = 5.2, [tex]\bar u[/tex] = 39.4

[tex]\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right)[/tex] = 156.6

[tex]{\sum \left(x_i - \bar x\right )^2 }[/tex] = 66.8

Therefore;

The estimated slope, b = 156.6/66.8 ≈ 2.344 (by rounding the answer to three decimal places)

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[tex]\\ \sf\longmapsto \sqrt{10}\times \sqrt{15}[/tex]

[tex]\\ \sf\longmapsto \sqrt{10\times 15}[/tex]

[tex]\\ \sf\longmapsto \sqrt{2\times 5\times 3\times 5}[/tex]

[tex]\\ \sf\longmapsto \sqrt{5\times 5\times 6}[/tex]

[tex]\\ \sf\longmapsto 5\sqrt{6}[/tex]

None of the above should be 4th option

Answer:

Step-by-step explanation:

3*(2k + 3) - 8k + 5 + 5           Remove the brackets on the left

6k + 9 - 8k + 5 + 5                Combine like terms

6k-8k+9 + 5 + 5

-2k + 19

Answer:

A. QT ≅ AZ

Step-by-step explanation:

When writing a congruence statement of two triangles, the order of arrangement of the letters used in naming the triangles are carefully considered. Corresponding sides and angles of both triangles are arranged accordingly in the order they appear.

Given that ∆QPT ≅ ∆ARZ, we have the following sides that correspond and are congruent to each other:

QP ≅ AR

PT ≅ RZ

QT ≅ AZ

The only correct one given in the options given above is QT ≅ AZ

Answer:

1130

Step-by-step explanation:

1109+7 = 1116

1116+7 = 1123

Adding 7 each time

1123+7 = 1130

[tex]\\ \sf\longmapsto 0.0000000015[/tex]

[tex]\\ \sf\longmapsto 0.0015\times 10^{-6}s[/tex]

[tex]\\ \sf\longmapsto 0.015\times 10^{-7}s[/tex]

[tex]\\ \sf\longmapsto 0.15\times 10^{-8}s[/tex]

[tex]\\ \sf\longmapsto 1.5\times 10^{-9}s[/tex]

Answer: 0.0000000015 = 1.5 × 10⁻⁹

Concept:

When converting an integer to scientific notation:

- If the number is ≥1, then count the moves of the decimal point to the right until the number is 0<number<10. The number of moves will be the exponent that is positive.

- For example: If converting 300, since there are two moves until it is left with 0<3<10. Thus, the scientific notation will be 3 × 10²

- If the number is <1, then count the moves of the decimal point to the left until the number is 0<number<10. The number of moves will be the exponent that is negative.

- For example: If converting 0.004, since there are three moves until it is left with 0<4<10. Thus, the scientific notation will be 4 × 10⁻³

Solve:

0.0000000015

The decimal point needs to move 9 times to the left to get a number that is between 0 and 10. The number is 1.5.

Thus, the scientific notion of 0.0000000015 will be 1.5 × 10⁻⁹

Hope this helps!! :)

Please let me know if you have any questions

9514 1404 393

Answer:

  perimeter ≈ 12.4 units

Step-by-step explanation:

The side adjacent to the angle is given. The relationships useful for the other two sides are ...

  Tan = Opposite/Adjacent

  Cos = Adjacent/Hypotenuse

From these, we have ...

  opposite = 5·tan(22°) ≈ 2.02

  hypotenuse = 5/cos(22°) ≈ 5.39

Then the perimeter is ...

  P = a + b + c = 2.02 + 5 + 5.39 = 12.41

The perimeter of ∆ABC is about 12.4 units.

We have to find LCM

3 | 45,75,63

3 | 15,25,21

5 | 5,25,7

5 | 1,5,7

7 | 1,1,7

LCM=3×3×5×5×7=1575

The least common denominator for the group of denominators using the method of prime numbers is 1575.

LCM stands for Least Common Multiple. It is a method to find the smallest common multiple between any two or more numbers.  A factor is one of the numbers that multiplies by a whole number to get that number.

For the given situation,

The numbers are 45, 75, 63​

Prime factors of 45 = [tex]3,3,5[/tex]

Prime factors of 75 = [tex]3,5,5[/tex]

Prime factors of 63 = [tex]3,3,7[/tex]

Then the LCM can be found by, first take the common factors then multiple the remaining factors as,

⇒ [tex](3)(3)(5)(5)(7)[/tex]

⇒ [tex]1575[/tex]

Hence we can conclude that the least common denominator for the group of denominators using the method of prime numbers is 1575.

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Answer:

[tex](5^{0} -4^{-1} )(\frac{3}{4} )\\\\=(1-\frac{1}{4^{1}} )(\frac{3}{4} )\\\\=(\frac{4}{4} -\frac{1}{4} )(\frac{3}{4} )\\\\=(\frac{3}{4} )(\frac{3}{4} )\\\\=\frac{9}{16}[/tex]

Answer:

Find the value of x:-

To find Y, use Pythagorean theorem:- [tex]c^{2} =a^{2} +b^{2}[/tex]

[tex](2.1)^{2} =y^{2} +(1.4)^{2}[/tex]

[tex]2.1^{2}=4.41[/tex]

[tex]1.4^{2} =1.96[/tex]

[tex]4.41=y^{2} +1.96[/tex]

subtract 1.96 from both sides

[tex]2.45=y^{2}[/tex]

[tex]y=1.5652[/tex]

Now, to find x:-

[tex]x=y+y[/tex]

[tex]= 1.5632+1.5652[/tex]

[tex]x=3.1 \: ft[/tex]

~OAmalOHopeO

Answer:

Rational number

Step-by-step explanation:

Given

[tex]5\frac{3}{8}[/tex]

Required

The subset it belongs to

Express as improper fraction

[tex]5\frac{3}{8} = \frac{43}{8}[/tex]

The above number is rational because it is represented by the division of 2 integers, i.e. 43 and 8 are integers

Express as decimals

[tex]5\frac{3}{8} = 5.375[/tex]

The above number cannot be classified as integers or whole because it has decimal parts

Step-by-step explanation:

X= -4,-2,2,4 (respectively)

Y=4,-4 (respectively)

hope it helps

Answer:

Part A)

About 0.51% per year.

Part B)

About 0.30% per year.

Part C)

About 28.26%.

Step-by-step explanation:

We are given that the population of Americans age 55 and older as a percentange of the total population is approximated by the function:

[tex]f(t) = 10.72(0.9t+10)^{0.3}\text{ where } 0 \leq t \leq 20[/tex]

Where t is measured in years with t = 0 being the year 2000.

Part A)

Recall that the rate of change of a function at a point is given by its derivative. Thus, find the derivative of our function:

[tex]\displaystyle f'(t) = \frac{d}{dt} \left[ 10.72\left(0.9t+10\right)^{0.3}\right][/tex]

Rewrite:

[tex]\displaystyle f'(t) = 10.72\frac{d}{dt} \left[(0.9t+10)^{0.3}\right][/tex]

We can use the chain rule. Recall that:

[tex]\displaystyle \frac{d}{dx} [u(v(x))] = u'(v(x)) \cdot v'(x)[/tex]

Let:

[tex]\displaystyle u(t) = t^{0.3}\text{ and } v(t) = 0.9t+10 \text{ (so } u(v(t)) = (0.9t+10)^{0.3}\text{)}[/tex]

Then from the Power Rule:

[tex]\displaystyle u'(t) = 0.3t^{-0.7}\text{ and } v'(t) = 0.9[/tex]

Thus:

[tex]\displaystyle \frac{d}{dt}\left[(0.9t+10)^{0.3}\right]= 0.3(0.9t+10)^{-0.7}\cdot 0.9[/tex]

Substitute:

[tex]\displaystyle f'(t) = 10.72\left( 0.3(0.9t+10)^{-0.7}\cdot 0.9 \right)[/tex]

And simplify:

[tex]\displaystyle f'(t) = 2.8944(0.9t+10)^{-0.7}[/tex]

For 2002, t = 2. Then the rate at which the percentage is changing will be:

[tex]\displaystyle f'(2) = 2.8944(0.9(2)+10)^{-0.7} = 0.5143...\approx 0.51[/tex]

Contextually, this means the percentage is increasing by about 0.51% per year.

Part B)

Evaluate f'(t) when t = 17. This yields:

[tex]\displaystyle f'(17) = 2.8944(0.9(17)+10)^{-0.7} =0.3015...\approx 0.30[/tex]

Contextually, this means the percetange is increasing by about 0.30% per year.

Part C)

For this question, we will simply use the original function since it outputs the percentage of the American population 55 and older. Thus, evaluate f(t) when t = 17:

[tex]\displaystyle f(17) = 10.72(0.9(17)+10)^{0.3}=28.2573...\approx 28.26[/tex]

So, about 28.26% of the American population in 2017 are age 55 and older.

9514 1404 393

Explanation:

1. End behavior is the behavior of the function when the value of the independent variable gets large (or otherwise approaches the end of the domain). There are generally four kinds of end behavior:

Of these, behavior 2 will ultimately look like one of the others.

For polynomials, the function will always approach ±∞ as the independent variable approaches ±∞. Whether the signs of the infinities agree or not depends on the even/odd degree of the polynomial, and the sign of its leading coefficient.

For exponential functions, the end behavior is a horizontal asymptote in one direction and a tending toward ±∞ in the other direction.

For trig functions sine and cosine, the end behavior is the same as the "middle" behavior: the function oscillates between two extreme values.

For rational functions (ratios of polynomials), the end behavior will depend on the difference in degree between numerator and denominator. If the degree of the denominator is greater than or equal to that of the numerator, the function will have a horizontal asymptote. If the degree of the numerator is greater, then the end behavior will asymptotically approach the quotient of the two functions—often a "slant asymptote".

__

2. A polynomial inequality written in the form f(x) ≥ 0, or f(x) > 0, will be solved by first identifying the real zeros of the function f(x), including the multiplicity of each. For positive values of x greater than the largest zero, the sign of the function will match the sign of the leading coefficient. The sign will change at each zero that has odd multiplicity, so one can work right to left to identify the sign of the function in each interval between odd-multiplicity zeros.

The value of the function will be zero at each even-multiplicity zero, but will not change sign there. Obviously, the zero at that point will not be included in the solution interval if the inequality is f(x) > 0, but will be if it is f(x) ≥ 0. Once the sign of the function is identified in each interval, the solution to the inequality becomes evident.

As a check on your work, you will notice that the sign of the function for x > max(zeros) will be the same as the sign of the function for x < min(zeros) if the function is of even degree; otherwise, the signs will be different.

The solution to a polynomial inequality is a set of intervals on the real number line. The solution to a polynomial equation is a set of points, which may be in the complex plane.

__

3. A composite function is a function of a function, or a function of a composite function. For example f(g(x)) is a composite function. The composition can be written using either of the equivalent forms ...

  [tex](f\circ g)(x)\ \Leftrightarrow\ f(g(x))[/tex]

It can be easy to confuse an improperly written composition operator with a multiplication symbol, so the form f(g(x)) is preferred when the appropriate typography is not available.

When simplifying the form of a composition, the Order of Operations applies. That is, inner parenthetical expressions are evaluated (or simplified) first. As with any function, the argument of the function is substituted wherever the independent variable appears.

For example, in computing the value f(g(2)), first the value of g(2) is determined, then that value is used as the argument of the function f. The same is true of other arguments, whether a single variable, or some complicated expression, or even another composition.

Note that the expression f(g(x)) is written as the composition shown above. The expression g(f(x)) would be written using the composition operator with g on the left of it, and f on the right of it:

  [tex](g\circ f)(x)\ \Leftrightarrow\ g(f(x))[/tex]

That is, with respect to the argument of the composition, the functions in a composition expression are right-associative. For example, ...

  for h(x)=2x+3, g(x)=x^2, f(x)=x-2 we can evaluate f(g(h(x)) as follows:

  f(g(h(x)) = f(g(2x+3) = f((2x+3)^2) = (2x+3)^2 -2

It should be obvious that g(h(f(x)) will have a different result.

  g(h(f(x)) = g(h(x-2)) = g(2(x-2)+3) = (2(x-2)+3)^2

Answer:

b. Kinsey must save $72 per month to achieve her goal.

Step-by-step explanation:

Goal over 16 months: $60 x 16 = $960

Collected after 11 months: $600

$360 ÷ 5 = $72

Kinsey must save $72 per month to achieve her goal. The answer we got by converting the sentence to Equation and solving.b is the required answer.

Kinsey has a plan to save $60 a month for 16 months so that she can purchase a new television. After 11 months Kinsey has saved $600. If the most that Kinsey can possibly save is $80 per month, which of the following statements given is true.

Two expressions with equal sign is called equation.

Goal over 16 months: $60 x 16 = $960

Collected after 11 months: $600

$360 still needed

5 months lefts

$360 ÷ 5 = $72

Therefore Kinsey must save $72 per month to achieve her goal.

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Answer:

To maximize the monthly rental profit, 90 units should be rented out.

The maximum monthly profit realizable is $38,200.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

[tex]f(x) = ax^{2} + bx + c[/tex]

It's vertex is the point [tex](x_{v}, y_{v})[/tex]

In which

[tex]x_{v} = -\frac{b}{2a}[/tex]

[tex]y_{v} = -\frac{\Delta}{4a}[/tex]

Where

[tex]\Delta = b^2-4ac[/tex]

If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]y_{v}[/tex].

In this question:

Quadratic equation with [tex]a = -12, b = 2160, c = -59000[/tex]

To maximize the monthly rental profit, how many units should be rented out?

This is the x-value of the vertex, so:

[tex]x_{v} = -\frac{b}{2a} = -\frac{2160}{2(-12)} = \frac{2160}{24} = 90[/tex]

To maximize the monthly rental profit, 90 units should be rented out.

What is the maximum monthly profit realizable?

This is p(90). So

[tex]p(90) = -12(90)^2 + 2160(90) - 59000 = 38200[/tex]

The maximum monthly profit realizable is $38,200.

Answer:

11:7

Step-by-step explanation:

Solution

Here

7a-11b=0

a:b=?

we know that

a=7

b=11

ans =11:7

Hence proved

Answer:

[tex]thank \: you[/tex]

Answer:

question is not proper

Step-by-step explanation:

question is

Answer:

slope is undefined

Step-by-step explanation:

(9, 1 ) and (9, - 4 )

Since the x- coordinates of the 2 points are 9, then the line is vertical and parallel to the y- axis with slope being undefined.

Slope is the change in y over the change in x.

Slope = (-4 - 1) / (9 -9) = -5/0 you cannot divide by 0,so the slope is undefined. This means it is a vertical line

Answer:

A

Step-by-step explanation:

The first term of the sequence is 4, the common difference is 3. So the equation of this sequence is 4+(n-1)*3 or 1+3*n. Plug in n=100

Answer:

The p-value of the test is 0.0301 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

The company's promotional literature claimed that under 64% fail in the first 1000 hours of their use.

At the null hypothesis, we test if the proportion is of at least 64%, that is:

[tex]H_0: p \geq 0.64[/tex]

At the alternative hypothesis, we test if the proportion is of less than 64%, that is:

[tex]H_1: p < 0.64[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

64% is tested at the null hypothesis:

This means that [tex]\mu = 0.64, \sigma = \sqrt{0.64*0.36}[/tex]

A sample of 900 computer chips revealed that 61% of the chips fail in the first 1000 hours of their use.

This means that [tex]n = 900, X = 0.61[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.61 - 0.64}{\frac{\sqrt{0.64*0.36}}{\sqrt{900}}}[/tex]

[tex]z = -1.88[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.61, which is the p-value of z = -1.88.

Looking at the z-table, z = -1.88 has a p-value of 0.0301.

The p-value of the test is 0.0301 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the company's claim.