first second and last term of Ap are a,b,2a respectively, find its sum​

Answer:

Divide the diameter by 2.

Step-by-step explanation:

The radius of any circle is always the end to the center.

The diameter is a point of the circle to the opposite side.

This means that the diameter is twice the size of the radius, so to find the radius from the diameter, divide the diameter by 2.

Hope this helped!

Answer:

Divide the diameter by 2. d/2=r

Step-by-step explanation:

If a diameter has been given instead of a radius, you can find the radius by dividing the diameter by 2, for example.

If the diameter was 10, the radius would 10/2=5.

Answer:

52 units^2

Step-by-step explanation:

It's unclear what the leg lengths and the width are.  I must assume that the lengths are 12 units and 14 units and that the width of the trapezoid is 4 units.  You were given an illustration for this problem and should have shared it or described the trapezoid in words.  Please do this if the answer given below does not agree with any of your answer choices.

If the lengths are 12 units and 14 units and that the width of the trapezoid is 4 units, then the area is

      12 units + 14 units

A = ---------------------------- * 4 units = 52 units^2

                    2

Answer:  ¹/₂( x² - 10y² + 10xy - xy )

Step-by-step explanation:

From the diagram area of the triangle = ¹/₂ ˣ base ˣ height

where the base = x + 10y and the height = x - y

Therefore putting these into the formula above

Area  =   ¹/₂ [( x + 10y )( x -y )]

         =   ¹/₂( x² - xy + 10xy - 10y²)units²

         = ¹/₂( x² - 10y² + 10xy - xy )

Answer:

[tex]a = \frac{3}{4}[/tex]

Step-by-step explanation:

Let's convert everything to sixths to make it easier to work with.

[tex]\frac{4}{6}a - \frac{1}{6} = \frac{2}{6}[/tex]

Add 1/6 to both sides:

[tex]\frac{4}{6}a = \frac{3}{6}[/tex].

Dividing both sides by 4/6:

[tex]a = \frac{3}{6} \div \frac{4}{6}\\\\a = \frac{3}{6} \cdot \frac{6}{4}\\\\a = \frac{18}{24}\\\\a = \frac{3}{4}[/tex]

Hope this helped!

Answer:

a; H0: u= 140 Ha: u ≠ 140 two tailed test.

b. Therefore reject H0 as t= 3 ≠ t≤ t ( ∝/2) (n-1) =2.353 or

3 > t ( ∝/2) (n-1) =2.353    

c. If we check from the table the p- value is 0.6 which lies between 0.1 and 0.05  therefore reject H0.

d. Again reject H0 as 140 < 150.163

e. A type II error has not been committed as H0 is rejected.

Step-by-step explanation:

We formulate the null and alternative hypotheses as

a; H0: u= 140 Ha: u ≠ 140 two tailed test.

For a two tailed test the significance level ∝= 0.1 the critical region is given by

t ≤ t ( ∝/2) (n-1) and t > t ( ∝/2) (n-1)

So the critical region will be

t≤ t ( ∝/2) (n-1) =2.353

where

t= x` - u / s/ √n

Sr. No X X²

1 150 22500

2 150 22500

3 180 32400

4 170 28900

∑ 650 106,300

X`= ∑x/n = 650/4= 162.5

s²= 1/n-1 (x-x`)²= 1/n-1 [ ∑x² -(∑x)²/n ]

= 1/3[106,300 -650²/4] = 225

s= 15

Putting the values in the above equation

t= 162.5- 140/ 15/ √4

t= 3

So calculated value of t= 3

b. Therefore reject H0 as t= 3 ≠ t≤ t ( ∝/2) (n-1) =2.353 or

3 > t ( ∝/2) (n-1) =2.353    

c. If we check from the table the p- value is 0.6 which lies between 0.1 and 0.05  therefore reject H0.

d. a 90% confidence interval based on the calculated values will be

x`± 1.645 (s)/ √n

Putting the values

162.5 ±1.645 ( 15/2)

162.5 ±12.3375

174.84 , 150.163

d. Again reject H0 as 140 < 150.163

e. A type II error has not been committed as H0 is rejected.

Answer:

-52

Step-by-step explanation:

Think of it this way.  Opposite means to take the negation.  So we are taking the negation of the negation of negative 52.  This means mathematically:

- ( - ( -52 ) ) == -52

Cheers.

This is equivalent to x^2+8x+13

======================================================

Explanation:

The vertex of f is at (0,0). The vertex of g is at (-4, -3). The vertex has moved 4 units to the left and 3 units down.

To shift to the left, we replace x with x+4. So we have f(x) = x^2 turn into f(x+4) = (x+4)^2 so far.

Then we subtract off 3 to move everything 3 units down. We have

g(x) = (x+4)^2-3

---------------------

Optionally we can expand things out like so

g(x) = (x+4)^2-3

g(x) = (x+4)(x+4)-3

g(x) = x(x+4)+4(x+4)-3

g(x) = x^2+4x+4x+16-3

g(x) = x^2+8x+13

Showing that (x+4)^2-3 is equivalent to x^2+8x+13

[tex]_6C_3=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20[/tex]

Answer:

Step-by-step explanation:

Let REPEAT [tex]_{TM[/tex]= { | M is a TM, and for all s ∈ L(M), s = uv where u = v }

To prove that REPEAT [tex]_{TM[/tex]  is undecidable.

Let  REPEAT [tex]_{TM[/tex] {| M is a TM that does not accept M}

Then, we form a TM  u for L by applying TM v as a subroutine.

Assume Repeat   is decidable

Let M be the algorithm that  TM which decides the REPEATU = on input "s" simulate the M

Accept; if M ever enters the accept state

Reject; if M ever enters the reject state

U does not decide the REPEAT as it may loop over s

so REPEAT is undecidable

Answer: approx 1196 students.

Step-by-step explanation:

As known for normal distribution 95.4% of all results are situating at +-2*s distance from the mean. (s is the standard deviation)

2s=16*2=32 . The mean +2s= 104+32=136 = approx 140.

95.4% from 52000 = 49608 students. The residual amont ( which is out of the border mean+-2s)= 52000-49608=2392

Because of the normal distribution simmetry the number of the students which has IQ 140 and more is twice less than 2392.

N=2392:2=1196

Answer:

32 one-dollar bills.

Step-by-step explanation:

Let x represent one-dollar bills and y represent two-dollar bills.

He has a total of 49 bills. Therefore:

[tex]x+y=49[/tex]

The total amount of money James has is 66. x is worth one dollar, while y is worth two dollars. Therefore:

[tex]1x+2y=66\\x+2y=66[/tex]

We have a system of equations. Solve by substitution:

[tex]x+2y=66\\x+y=49\\x=49-y\\(49-y)+2y=66\\y=17\\x=49-17=32[/tex]

Therefore, James has 32 one-dollar bills and 17 two-dollar bills.

Checking:

[tex]32(1)+17(2)\stackrel{?}{=}66\\32(1)+17(2)\stackrel{\checkmark}{=}66\\\\32+17\stackrel{?}{=}49\\49\stackrel{\checkmark}{=}49[/tex]

Answer: 3 pounds.

Step-by-step explanation:

We have two metals:

One that contains 20% nickel, let's call it metal A.

One that contains 80% nickel, let's call it metal B.

We have 6 pounds of metal B, in those 6 punds we have:

0.80*6lb = 4.8lb of nickel.

Now, if we add X pounds of metal A, then we will have:

X + 6lb in total weight.

4.8lb + 0.2*X of nickel.

And we want to have exactly 60% of nickel, so we must have that the quotient between the amount of nickel and the total weight is equal to 0.6

(4.8lb + 0.2*X)/(6lb + X) = 0.6

now we solve it for X:

(4.8lb + 0.2*X) = 0.6*(6lb + X) = 3.6lb + 0.6*X

4.8lb - 3.6lb = 0.6*X - 0.2*X

1.2lb = 0.4*X

1.2lb/0.4 = 3lb = X

We should use 3 pounds of the metal with 20% of nickel.

Answer:

Hello the options to your question is missing below are the options

 A) if sample means were obtained for a long series of samples, approximately 95 percent of all sample means would be between 10 and 16 miles

B.the unknown population mean is definitely between 10 and 16 miles

C.if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians

D.the unknown population mean is between 10 and 16 miles with probability .95

Answer : if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians  ( c )

Step-by-step explanation:

95%  confidence

interval = 10 to 16 miles

To have 95% confidence signifies that if these intervals were constructed for a long series of samples, approximately 95 percent would include the unknown mean commute distance for all Californians

confidence interval covers a range of samples/values in the interval and the higher the % of the confidence interval the more precise the interval is,

Complete Question

Find the probability of winning a lottery with the following rule. Select the  six  winning numbers from​ 1, 2, . . .​ ,34 . ​(In any order. No​ repeats.)

Answer:

The  probability is  [tex]P(winning ) = 7.435 *10^{-7}[/tex]

Step-by-step explanation:

From the question we are told that

     The  total winning numbers   n =  34

      The total number to select is   r =  6

The total outcome of  lottery is mathematically represented as

      [tex]t_{outcome}) = \left n } \atop {}} \right. C_r[/tex]

      [tex]t_{outcome}) = \frac{n! }{(n-r )! r!}[/tex]

substituting values

      [tex]t_{outcome}) = \frac{ 34 ! }{(34 - 6 )! 6!}[/tex]

      [tex]t_{outcome}) = \frac{ 34 ! }{28 ! 6!}[/tex]

     [tex]t_{outcome}) =1344904[/tex]

The  number of desired outcome is  

           [tex]t_{desired} = 1[/tex]

 this is because the desired outcome is choosing the six winning number

   The probability of winning a lottery is mathematically represented as

      [tex]P(winning ) = \frac{t_{desired}}{t_{outcome}}[/tex]

substituting values  

     [tex]P(winning ) = \frac{1}{1344904 }[/tex]

      [tex]P(winning ) = 7.435 *10^{-7}[/tex]

Answer:

x ≥-10

Step-by-step explanation:

–2.5x ≤ 25

Divide each side by -2.5, remembering to flip the inequality

–2.5x/-2.5 ≥ 25 /-2.5

x ≥-10

Answer:

[tex]x\leq -10[/tex]

Step-by-step explanation:

[tex]-2.5x\leq 25[/tex]-----> Multiply by -1:

[tex]2.5x\geq -25[/tex]-----> Divide by 2.5:

[tex]x\geq -10[/tex]

Hope this helps!

Answer:

b

Step-by-step explanation:

because its right dummy

Answer:

.25 hour / dollar

Step-by-step explanation:

We want hours per dollar

9 hours/ 36 dollars

1/4 hour / dollar

Answer:

204

Step-by-step explanation:

To simplify the shape, you can do multiple things. I've opted to shave down both prongs to take it from a 'T' shape to a rectangular prism.

For height of the prongs, take 4 from 6.

6 - 4 = 2

Divide by 2 as there are 2 prongs.

2 / 2 = 1

Remember L * W * H

6 * 3 * 1 = 18

Remember that there are two prongs!

3 + 4 = 7

6 * 7 * 4 = 168

168 + 2(18) = 204

Answer:

Mean = 108

Median = 45

The better measure of Lauren's "typical class size" is the Mean

Step-by-step explanation:

1. Calculating mean and median.

The mean is an important measure of central tendency, and it is the average of the measurement of a given set of data. It is calculated as follows:

[tex]Mean\ (\overline {X}) &= \frac{\sum X}{N}[/tex]

where X = individual data sets

N = total number of data

[tex]Mean= \frac{375\; +\ 35\ +\ 45\ +\ 25\ +\ 60}{5} \\=\frac{540}{5} \\= 108[/tex]

The Median divides the measurements into two equal parts, and in order to calculate the median, the distribution has to first be arranged in ascending or descending order. Arranging this series in descending order:

375, 60, 45, 35, 25

The formula for calculating median is given by:

[tex]M_{d} = \frac{N\ +\ 1}{2} th\ data\\\\=\frac{5\ +\ 1}{2}th\ data\\\\=\frac{6}{2} th\ data\\= 3rd\ data\\M_{d} = 45[/tex]

from the list or arranged data in descending order (375, 60, 45, 35, 25), the third data is 45.

Therefore, Median = 45

2. The better measure of typical class size is Mean because the mean depends on all the values of the data sets, whereas the median does not. When there are extreme values (outliers) the effect on the median is very small, whereas it is effectively captured by the mean.

The base 1 is matched with height 2, base 2 is matched with height 3 and base 3 is matched with height 1. The base to the corresponding height is matched in the attached figure.

Triangle is the closed shaped polygon which has 3 sides and 3 interior angles. The height of the triangle is the dimension of the elevation from the opposite peak to the length of the base.

Thus, the base 1 is matched with height 2, base 2 is matched with height 3 and base 3 is matched with height 1. The base to the corresponding height is matched in the attached figure.

In the given figure, three triangles is shown with base and height. Here,

Thus, the base 1 is matched with height 2, base 2 is matched with height 3 and base 3 is matched with height 1. The base to the corresponding height is matched in the attached figure.

Learn more about the base and height of the triangle here;

https://brainly.com/question/26043588

#SPJ2

Answer:

it should be 308,608. the comma is after every three in this scenario.

Step-by-step explanation:

Answer:

6344

Step-by-step explanation:

Find 26% of 24400

24400 * 26%

24400 * .26

6344

Answer:

6 sandwiches to choose from because

3×2 = 6

Answer:

math is really a difficult subject for me. sometimes i feel confident when i get my answers correct, but sometimes i feel bored when i dnt get my answer. Sometimes i feel anxious , sometimes i feel excited to solve the problems.

Learn more:

brainly.com/question/13061296

Answer:

The brothers would not sell any ton.

Step-by-step explanation:

Facts we are given;

-Fresno coounty is the largest agriculture procuring county.

-It has harvested more than 99000 acres

-Fresno sold at $4300 a ton of almonds

For the Sagardia Brothers;

-Grew 600 acres of almond

- Sold at $4500 a ton of almonds

Now, from the given data, we can see that the price being sold by the brothers is higher than that of fresno county despite the fact that fresno is the biggest county producer in the country and as well has way more products in the market than the brothers.

Thus, the Brothers will likely not sell any product because the industry is price controlled and in addition to that, their prices are higher than the existing benchmark from county.

Also, the brothers don't even have the kind of name or quantity available from Fresno County.

The brothers sold 600 tons at a price of $2,700,000

Let x represent the number of tons of almonds produced by Sagardia Brothers and y represent the amount of money made.

Since 600 acres of almonds were farmed and each acre produces about a ton of almonds. Hence:

Total ton produced = 600 acres * 1 ton per acre = 600 tons

Each ton is priced at $4500 a ton, hence:

y = 600 tons * $4500 per ton

y = $2,700,000

The brothers sold 600 tons at a price of $2,700,000

Find out more at: https://brainly.com/question/21105092

Answer:

2√2

Step-by-step explanation:

hope you understand.

Answer:

hundredths place, 7,500.

Step-by-step explanation:

They would be the same when they are all rounded all of the numbers to the the hundredths place. And that number would be 7,500.

When rounding its 5 or higher round up, if its 4 or lower round down.

Answer:

1) [tex]\boxed{p(x) = x^3-x^2+x-1}[/tex]

2) [tex]\boxed{p(x) = x^2+x-2}[/tex]

3) [tex]\boxed{p(x) =- 2x^2+2x+4}[/tex]

4) [tex]\boxed{p(x) = 2x^2+x-4}[/tex]

Step-by-step explanation:

Part (1)

[tex]p(x) = x^3-x^2+x-1[/tex]

As we have to determine it by ourselves, this is the polynomial having a degree of 3. p(x) with a degree of 3 means that the highest degree/exponent of x should be 3.

Part (2)

[tex]p(x) = x^2+x-2[/tex]

This can be the polynomial having the factor x-1 because if we put:

x - 1 = 0 =>  x = 1 in the above polynomial, it gives us a result of zero which shows us that (x-1) "is" a factor of the polynomial.

Part (3)

[tex]p(x) = -2x^2+2x+4[/tex]

This can be the polynomial for which p(0) = 4 and p(-1) = 0

Let's check:

[tex]p(0) =- 2(0)^2+2(0)+4\\p(0) = 0 + 0+4\\p(0) = 4[/tex]

[tex]p(-1)= -2(-1)^2+2(-1)+4\\p(-1) = -2(1)-2+4\\p(-1) = -2-2+4\\p(-1) = 0[/tex]

So, this is the required polynomial determined by "myself".

Part (4):

[tex]p(x) = 2x^2+x-4[/tex]

This is the polynomial having a remainder 6 when divided by (x-2)

Let's check:

Let x - 2 = 0 => x = 2

Putting in the above polynomial

[tex]p(x) = 2(2)^2+(2)-4\\Given \ that \ Remainder = 6\\6 = 2(4) +2-4\\6 = 8+2-4\\6 = 10-4\\6 = 6[/tex]

So, Proved that it has a remainder of 6 when divided by (x-2)