Answer:
LCM of 4 and 10 is 20
Step-by-step explanation:
yes that is the answer
Answer:
Step-by-step explanation:
Factor 4 and 10 into primes
4: 2 * 2
10:2 * 5
Number of 2s = 2 twos
Number of 5s = 1 five
LCM of 4 and 10 = 4 * 5 = 20
solve for the measure of c pt 2 (18pts)
Answer:
d: 20
Step-by-step explanation:
alternative angle
f(x) =-x^2+x+13
find f(9)
Answer:
f(9) = - 59
Step-by-step explanation:
Substitute x = 9 into f(x) , that is
f(9) = - (9)² + 9 + 13
= - 81 + 22
= - 59
Answer:
-59
Step-by-step explanation:
f(x) =-x^2+x+13
Let x = 9
f(9) = - (9)^2 +9+13
= -81 +9+13
= -59
1. 42.78 + 19.56
2. 0.0997 + 1.4
3. $62.74 + $1.75 + $12
4. 40.75 – 17. 46
5. 0.95 – 0.68
6. $60 - $31.74
7. 5.4 x 0.07
8. 5.9 x 1.2
9. 0.24 ÷ 0.8
10. 6.56 ÷ 4
1. - 62.34
2. - 1.4997
3. - $76.49
4. - 23.29
5. - 0.27
6. - $28.26
7. - 0.378
8. - 7.08
9. - 0.3
10. - 1.64
Answer:
1. 62.34
2. 1.4997
3. $76.49
4. 23.29
5. 0.27
6. $28.26
7. 0.378
8. 7.08
9. 0.3
10. 1.64
hello i need help someone please!!
find the inverse of this relation
h(t) = -6t + 7
Answer:
73
Step-by-step explanation:
Answer:
[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]
Step-by-step explanation:
let y = h(t) and rearrange making t the subject
y = - 6t + 7 ( add 6t to both sides )
6t + y = 7 ( subtract y from both sides )
6t = 7 - y ( divide both sides by 6 )
t = [tex]\frac{7-y}{6}[/tex]
Change y back into terms of x with t = [tex]h^{-1}[/tex] (t)
[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]
What is one possible perimeter of the garden, in meters?
Answer:
24.1 is a possibility for the perimeter
Step-by-step explanation:
The third side between 12+0.5 and 12-0.5, or 12.5 and 11.5.
The third side is between 11.5 and 12.5.
Simce it isn't isosceles third side can't be 12.
So it's asking you to choose a number between 11.5 and 12.5 with the exclusiion of 12 for the third side measurement in meters.
So let's choose 11.6.
So the perimeter is just the sum of all side measurements.
11.6+12+0.5
11.6+0.5+12
12.1+12
24.1
24.1 is a possibility for the perimeter
Which lists all of the shapes that are in a two-dimensional net of a square pyramid? 6 squares 4 triangles 1 square and 3 triangles 1 square and 4 triangles
Answer:
4 triangles and 1 square
Step-by-step explanation:
Required
The shapes in two-dimensional net of a square pyramid
To do this, I will attach an attachment of a 2D net of a square pyramid (see attachment)
From the attachment, we can see that:
The 2d shape of the pyramid is made of 4 triangles and 1 square
Answer:
D
Step-by-step explanation:
If T is the midpoint of SU what are ST, TU, and SU?
a. ST = 7, TU = 63, and SU = 126
b. ST = 63, TU = 63, and SU = 126
c. ST = 80, TU = 80, and SU = 160
d. ST = 18, TU = 18, and SU = 36
Answer:
B
Step-by-step explanation:
As T is the midpoint of SU, ST=TU. 9x=5x+28, 4x=28, x=7. ST=TU=63 and SU=126
i don’t know what it is can someone help
Answer:
b
Step-by-step explanation:
The hypotenuse of a right triangle measures nem and one of its legs measures o em.
Mnd the measure of the other leg. If necessary, round to the nearest tenth.
Sun
attempt to
Using Pythagorean theorem
[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]
[tex]\\ \sf\longmapsto P^2=11^2-9^2[/tex]
[tex]\\ \sf\longmapsto P^2=121-81[/tex]
[tex]\\ \sf\longmapsto P^2=40[/tex]
[tex]\\ \sf\longmapsto P=\sqrt{40}[/tex]
[tex]\\ \sf\longmapsto P=6.2cm[/tex]
Step-by-step explanation:
Given,
Hypotenuse = 11 cm
Base (One of the given leg) = 9 cm
Therefore,
According to Pythagoras Theorem,
[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]
[tex] = > {(9)}^{2} + {height}^{2} = {(11)}^{2} [/tex]
[tex] = > {height}^{2} = {(11)}^{2} - {(9)}^{2} [/tex]
[tex] = > {height}^{2} = 121 - 81[/tex]
[tex] = > {height}^{2} = 4 0[/tex]
[tex] = > height = \sqrt{40} [/tex]
=> height = 6.3245553203
When rounded to nearest tenth,
=> height = 6.3
Hence,
Required length of other leg is 6.3 (Ans)
Create a triangle ABC of your choice. Using GeoGebra tools, construct the angle bisectors of ∠A and ∠B. Mark the intersection point of the angle bisectors, and label it point D.
Create a line through point D perpendicular to .
Find the intersection of line segment and the perpendicular line, and label it point E. With point D as the center, create a circle passing through point E.
Measure and label the radius of the inscribed circle of ΔABC on the diagram.
Take a screenshot of your result, and paste it below.
The steps to create attached screenshot of the inscribed circle of triangle ΔABC using GeoGebra tools includes;
1) Clicking on the Geometry link, under Powerful Math Apps group
2) On the opened Geometry page click on the Polygon icon and follow the instructions that come up, which is Select all vertices and then the first vertex (selected) again (a second time)
3) Once the triangle is created, select the Angle Bisector icon, under the Construct group; A message will appear, asking to Select three points or two lines, select three vertex, of the triangle created with a mouse click, with the vertex A in the center, such as BAC, or CAB a straight line representing the angle bisector of angle ∠A is created
4) Repeat the above to create the angle bisector of angle ∠B
5) Click on the Point button under the Basic Tools group, then click on the intersection of the two angle bisectors created above, the point will be automatically labelled point D
6) Click on the Perpendicular Line, icon under the Construct group, then click on point D, and then the line AB to draw the perpendicular from D to AB
7) Click on the point Point icon and then the intersection point of the perpendicular from D and AB to label the point E
8) Click on the Circle with Center basic tool and then points D and E above, to create the inscribed circle of triangle ΔABC
9) Select the Segment tool, then select the center of the circle and a point
on the circumference. Click on the label, from the pop up options, select
the label option AA then change the label of the segment created to Radius
and select Show Label and Show Value. The inscribed circle of ΔABC created with GeoGebra tools is attached
Learn more about GeoGebra hear;
https://brainly.com/question/10400398
Answer:
Step-by-step explanation: from edmentum
What will be the first term of a geometric series which has its sum 280, common ratio 3 and the last term 189 ?
Answer:
b1=7
Step-by-step explanation:
If we deal with geometric series, we should use the formulas for it. If there is the last term, it is not infinite geometric series. The sum of geometric series which isn't infinite is equal to b1(r^n-1)/(r-1) where b1 is the first term and r is the common ratio.
So 280= b1(3^n-1)/(3-1)
560= b1(3^n-1)
560= b1*3^n-b1
Then express bn=b1*r^(n-1)
189= b1*3^(n-1)
189= b1*3^n*1/3
567= b1*3^n when
560= b1*3^n-b1
560=567-b1
b1=7
What is the equation of the graph shown?
Answer:
2y+3x-2=0
Step-by-step explanation:
The slope of the line is 3/2 and the equation of line is y=-1.5x+1
Is 3584 a term of the series 7+14+28+56........?
(please answer if you know; this is the question from geometric series:- General progression)
(full steps and process required)
(No spam answers or else you'll be reported )
Answer:
yes it is the 10th term in the series
Step-by-step explanation:
The nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 7 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{14}{7}[/tex] = 2 , then
[tex]a_{n}[/tex] = 7 [tex](2)^{n-1}[/tex]
Equate [tex]a_{n}[/tex] to 3584 and solve for n
7 [tex](2)^{n-1}[/tex] = 3584 ( divide both sides by 7 )
[tex]2^{n-1}[/tex] = 512 , that is
[tex]2^{n-1}[/tex] = [tex]2^{9}[/tex]
Since the bases on both sides are equal, both 2 , then equate the exponents
n - 1 = 9 ( add 1 to both sides )
n = 10
3584 is the 10th term in the series
What is the slope of a line that passes through the points (-2, 4) and (-6, 12)?
Answer:-3\2
Step-by-step explanation:
slope is difference y axis by x axis
4-12/-2+6=-6/4=-3\2
What is the answer for 76 = -4b
Answer:
-19 = b
Step-by-step explanation:
76 = -4b
Divide each side by -4
76/-4 = 4-b/-4
-19 = b
Answer:
b = -19
Step-by-step explanation:
76 = -4b
shift -4 to the left hand side and when you shift -4 divides 76
76/-4 = b
-19 = b
Find the value of a. A. 57 B. 104 C. 26 D. 52
Answer:
Option D, 52
Answered by GAUTHMATH
Round 4746.13662611 to the nearest whole number.
Answer:
4746
Step-by-step explanation:
The Vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).Find the length of each diagonal.Show me with the steps Please!
Answer:
13 and 17 units
Step-by-step explanation:
explaination is in pic.
The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.
What is the length between two points in a plane?The length between two given points (x₁, y₁) and (x₂, y₂) will be:
√[(x₂ - x₁)² + (y₂ - y₁)²] units
Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).
Therefore, the diagonals of the quadrilateral will be AC and BD.
The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).
Now, the length of the diagonal AC will be:
= √[(-8 - 4)² + (2 - (- 3))²] units
= √[(- 12)² + (5)²] units
= √[144 + 25] units
= √(169) units
= 13 units (length can't be negative)
Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).
Now, the length of the diagonal BD will be:
= √[(-1 - 7)² + (- 5 - 10)²] units
= √[(- 8)² + (- 15)²] units
= √[64 + 225] units
= √(289) units
= 17 units (length can't be negative)
Learn more about the length between two points on a plane here: https://brainly.com/question/14898312
#SPJ2
The mean of 14 numbers is 49. Removing one of the numbers causes the mean to decrease to 43. What number was removed?
Answer:
126 was removed.
Step-by-step explanation:
The total before division took place was
Total = mean * 14
mean = 49
Total = 49 * 14
Total = 685
Now you subtract x from the total
685 - x
And divide by 13 [one number is missing]
(685 - x)/13
and the result = 43
(685 - x ) / 13 = 43 Multiply both sides by 13
685 - x = 43 * 13
685 - x = 559 Subtract 685 from both sides
- x = - 126 Multiply by - 1
x = 126
PLEASE HELP DUE IN 15 MNUTES MARKING BRAINLIEST AND 15 POINTS YOU DONT HAVE TO EXPLAIN MUCH
Answer:
see below
Step-by-step explanation:
11a -2(x^2 -3)
Distribute
-2*x^2 -2(-3)
-2x^2 +6
11b 2x(x+4)
Distribute
2x*x +2x*4
2x^2 +8x
12 The perimeter is the sum of all sides
The top is equal to the bottom and the left side is equal to the right
x-10 + x+20+x-10+x+20
Combine like terms
4x +20
What is the solution set of { x | x <-5} n { x | x >5 }? Help needed!
Answer:
The Empty set............
Answer:
There is no solution for the intersection of these two sets, as they do not intersect! They don't have any numbers in common and thus form an empty set. The correct answer choice is option D. the empty set.
Step-by-step explanation:
The solution for { x | x <-5} is ---> x < -5
The solution for { x | x >5 } is ---> x > 5
If you placed the two sets on a number line close to each other, you would see that they do not intersect. Thus there is no solution for the intersection of set A and set B as defined in the given problem.
See the graph for better understanding. You see how there's an empty space or area between -5 and 5? Yeah, this is called the empty set which is option D from your answer choices.
Simplify
1)a³b⁴/ ab³
2)2 (x³ )²
3)3x*2x³ y²
Answer:
1) a³b⁴/ ab³ = a²b
2)2 (x³ )² = 2x^6
3)3x*2x³ y² = 6x⁴y²
One year ago, the ratio of Honey and Piyush ages was 2:3 respectively. After five years from now, this ratio becomes 4:5. How old is Piyush now?
Answer:
eşnatto eşmatoroorlfld
Answer:
Now , Piyush age =3+Honey age
Step-by-step explanation:
Honey age=x
Piyush age=y
1 year ago,Honey age=x-1
Piyush age=y-1
the ratio of Honey and Piyush age=2:3
x-1:y-1=2:3
x-1/y-1=2/3
3(x-1)=2(y-1)
3x-3=2y-2
3x-2y= -2+3
3x-2y=1 eq _1
after 5 years from now,
Honey age=x+5
Piyush age=y+5
the ratio of them=4:5
x+5/y+5=4/5
5(x+5) =4(y+5)
5x+25=4y+20
5x-4y=20-25
5x-4y=-5 _eq2
eq1and 2_
5x-4y= -5
3x-2y= 1
-
2x-2y=-6
x-y =-3
-y=-3-x
y=3+x
What is the value of x?
Answer:
x = 46
Step-by-step explanation:
Assuming DE is an angle bisector , then it divides the opposite side into segments that are proportional to the other 2 sides, that is
[tex]\frac{HD}{DG}[/tex] = [tex]\frac{EH}{EG}[/tex] , substitute values
[tex]\frac{x+4}{58}[/tex] = [tex]\frac{55}{63.8}[/tex] ( cross- multiply )
63.8(x + 4) = 3190 ( divide both sides by 63.8 )
x + 4 = 50 ( subtract 4 from both sides )
x = 46
Which expression is equal to the expression below?
(2x6)^4
Answer:
2^4 x 6^4
Step-by-step explanation:
If the length of the shorter arc AB is 22cm and C is the center of the circle then the circumference of the circle
is:
Answer:
176 cmStep-by-step explanation:
The shorter arc is 22 cm.
Arc length formula:
s = πrθ/180Circumference formula:
C = 2πrUse the first formula to work out the value of C:
22 = πr*45/180πr/4 = 22πr = 88 2πr = 176C = 176 cmLength of arc=L=22cm
We know
[tex]\boxed{\sf L=\dfrac{\Theta}{360}\times πr}[/tex]
[tex]\\ \sf\longmapsto 22=\dfrac{45}{360}\times 2πr[/tex]
[tex]\\ \sf\longmapsto \dfrac{2πr}{8}=22[/tex]
[tex]\\ \sf\longmapsto {2πr=176}[/tex]
[tex]\\ \sf\longmapsto Circumference=176cm[/tex]
Here are two fractions 3/10 and 5/7 work out which one is closer to a 1/2
Answer:
Therefore 3/10 is closer to ½
Step-by-step explanation:
We've to get the difference:
» with 3/10 :
[tex] \frac{1}{2} - \frac{3}{10} = { \boxed{\frac{1}{5} }}[/tex]
» with 5/7
[tex] | \frac{1}{2} - \frac{5}{7} | = { \boxed{ \frac{3}{14} }}[/tex]
but:
[tex] \frac{3}{14} > \frac{1}{5} [/tex]
Among both the given fractions, the one that is closer to a ½ is 3/10.
What is a fraction?A number that is stated as a quotient in mathematics, when the numerator and denominator are split in half. Both are integers in a straightforward fraction. In the numerator or denominator of a complex fraction is a fraction.
An element of a whole or, more broadly, any number of equal pieces, is represented by a fraction. When used in conversational English, a fraction indicates the number of components of a particular size, as in one-half, eight-fifths, and three-quarters.
A fraction is a number that represents a portion of a whole. In order to evaluate it, a whole is divided into a number of components. A correct fraction has a numerator that is lower than its denominator.
Required calculations are done with both the fractions,
1/2 - 3/10 = 1/5
1/2 - 5/7 = 3/14
3/14 ≥ 1/5
Therefore, among both the given fractions, the one that is closer to a ½ is 3/10.
Learn more about fraction from here:
https://brainly.com/question/10354322
#SPJ2
Based only on the given information, it is guaranteed that LN I MO.
L
Given: ALON
LM: NM
LO = NO
MO #MO
M
0
N
Answer:
true
Step-by-step explanation:
We are given that sides LM and NM, LO and NO, MO and MO are congruent. Since this describes 3 sides of the triangle, you can say ΔMNO is congruent to ΔMLO. From this, you can say ∠OMN is congruent to ∠OML. The two angles (∠OMN and ∠OML) form a straight line, meaning they add up to 180 degrees. We can write:
∠OMN + ∠OML = 180
And since ∠OMN = ∠OML, we can substitute and solve:
∠OMN + ∠OMN = 180
2∠OMN = 180
∠OML =∠OMN = 90
Since both these angles are 90 degrees, LN is perpendicular to MO by definition.
could someone help me with these questions please i’m really confused
Answer:
C
Step-by-step explanation:
c
2. Write an equation that can be used to find M-Angle M. Then Solve it. Round to the nearest degree
Answer:
M = sin ^-1 (5/11)
M = 27 degrees
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp / hyp
sin M = 5/11
Taking the inverse sin of each side
sin ^-1 sin M = sin ^-1 (5/11)
M = sin ^-1 (5/11)
M=27.03569
To the nearest degree
M = 27