Find the greatest common factor of 15 x²y³ and -18 x³yz .

9514 1404 393

Answer:

  y -9

Step-by-step explanation:

From 4 years ago until 5 years from now, John will age 9 years. That is, his age 4 years ago is 9 years less than it will be in 5 years.

John's age 4 years ago is y-9 years.

Answer:

900 at 12%

2100 at 10%

Step-by-step explanation:

Let x= amount invested at 12%

let y= amount invested at 10%

with that being said we can write the two equation

Equation 1: x+y=3000

Equation 2: 3000*.106=.12x+.1y

isolte x from equation 1

x= 3000-y

plug this into equation 2

318=.12(3000-y)+.1y

318=360-.12y+.1y

-42= -.02y

y= 2100

Plug this into equation 1

x+2100=3000

x=900

she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.

Let's denote the amount of money Hattie invests at 12% as \(x\) dollars, and the amount she invests at 10% as \(\$3000 - x\) dollars.

The formula for calculating interest is: \(\text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time}\).

For the 12% account:

Interest_12% = \(x \times 0.12 \times 1\) (1 year)

For the 10% account:

Interest_10% = \((3000 - x) \times 0.10 \times 1\) (1 year)

Hattie wants to earn 10.6% interest on the total investment, so we can set up the equation:

\(\text{Total Interest} = \text{Interest}_12% + \text{Interest}_10%\)

\(3000 \times 0.106 = x \times 0.12 + (3000 - x) \times 0.10\)

Now, solve for \(x\):

\(318 = 0.12x + 300 - 0.10x\)

\(318 = 0.02x + 300\)

\(18 = 0.02x\)

\(x = 900\)

Hattie should invest $900 at 12% and \(3000 - 900 = 2100\) at 10%.

Therefore, she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.

Learn more about interest at https://brainly.com/question/29451175

#SPJ3

Answer:

y = 0.9143x - 0.8

Step-by-step explanation:

Given the data :

Region Temperature Yield (in bushes per acre)

4 ______ 3

8 ______ 7

10 _____ 8

12 _____ 10

9 ______ 8

6 ______ 4

Using technology, the least square regression equation obtained by fitting the data is :

y = 0.9143x - 0.8

Where ;

y = predicted Bush yield, predicted variable

x = Average temperature, dependent variable

The slope Coefficient = 0.9143

The intercept = - 0.8

Answer:

1/4.

Step-by-step explanation:

2^-2 = 1/2^2

= 1/4.

Answer:

The function represents the sequence is - 3 n + 23.

Step-by-step explanation:

20. 17, 14, 11, 8,......

Here, the first term is

a = 20

Common difference, d = -3

Let the nth term is Tn.

Tn = a + (n -1) d

Tn = 20 + (n -1) x (-3)

Tn = 20 - 3 n + 3

Tn = 23 - 3 n = - 3 n + 23

So, the function represents the sequence is - 3 n + 23.

Answer:

Y'all know what it is already, but I want points, so: f(n) = -3n + 23

Answer:

Step-by-step explanation:

Answer:

a. difference of means

Step-by-step explanation:

Given that :

Mean , x = 9.4

Standard deviation, [tex]s.d_1[/tex] = 2.5

Number, [tex]n_1[/tex] = 12

Mean, y = 6.5

standard deviation, [tex]s.d_2[/tex] = 2.4

Number, [tex]n_2[/tex] = 12

The null hypothesis is : [tex]$H_0: \mu_1=\mu_2$[/tex]

The alternate hypothesis is : [tex]$H_1: \mu_1>\mu_2$[/tex]

Level of significance, [tex]\alpha[/tex] = 0.1

From the [tex]\text{standard normal table, right tailed,}[/tex] [tex]$t_{1/2}$[/tex] = 1.363

Since out test is right tailed.

Reject [tex]H_0[/tex], if [tex]$T_0>1.363$[/tex]

We use the test statics,

[tex]$t_0=\frac{(x-y)}{\sqrt{\frac{s.d_1}{n_1}+\frac{s.d_2}{n_2}}}$[/tex]

[tex]$t_0=\frac{(9.4-6.5)}{\sqrt{\frac{6.25}{12}+\frac{5.76}{12}}}$[/tex]

[tex]$t_0=2.899$[/tex]

[tex]$|t_0|=2.899$[/tex]

[tex]\text{Critical value}[/tex]

The value of [tex]$|t_{1/2}|$[/tex] with minimum [tex]$\left(n_1-1,n_2-1)$[/tex] that is 11 df is 1.363

We go [tex]$|t_0|=2.899$[/tex] and [tex]$|t_{1/2}|$[/tex] = 1.363

Decision making:

Since the value of [tex]|t_0|>|t_{1/2}|$[/tex]  and we reject the [tex]H_0[/tex]

The p-value : right tail [tex]H_a:(p>2.8988)[/tex]

                                      = 0.00724

Therefore the value of [tex]$p_{0.1} > 0.00724$[/tex], and so we reject the [tex]H_0[/tex]

Thus we are testing 'the difference of means" in this problem.

Answer:

True

Step-by-step explanation:

Required

Does dilation preserve angle measure?

When a point, side, line, or angle is dilated; the length of the line will be altered by the ratio or scale of dilation.

However, the measure of angle will remain the same.

Hence, the given statement is true.

Answer:

THIS IS THE ANSWER

Step-by-step explanation:

1 1/2 = 3/2

2 1/3 = 7/3

3/2 * 7/3 = 21/6 = 3 3/5 = 3 1/2 cups

Answer:

D. allows a person to borrow more money at a lower interest rate

y = -7(-13)

=> y = -7 × (-13)

= y = 91

Graph B is the best graph that represents the linear equation

Answer:

m=2b=1y=2x+1

just enter it

Answer:

7

Step-by-step explanation:

First, add all the cards.

[tex]2 + 5 + 7 + 8 + 9 = 31[/tex]

If we remove one card, the remaining four cards average will be 6, this means that the 4 remaning cards will average total will be at 24 because 6×4=24. So we need to find a value that will equal 24 if we remove that card.

The answer is 7 because

[tex] \frac{2 + 5 + 8 + 9}{4} = 6[/tex]

9514 1404 393

Answer:

  remove 7 to make the total be 6×4 = 24.

Step-by-step explanation:

The description "mean average" is redundant to no apparent purpose. "Mean" and "average" are the same thing: the total divided by the number of contributors.

If the mean of 4 cards is 6, then we require ...

  6 = (total of 4 cards) ÷ 4

  24 = total of 4 cards . . . . . . . multiply both sides of the equation by 4

__

We note that the total of all the cards shown is ...

  2 + 5 + 7 + 8 + 9 = 31

In order to make the total be 24, we need to remove a card that has a value of ...

  31 -24 = 7

Removing 7 will bring the total to 2 + 5 + 8 + 9 = 24, and the average to 24/4 = 6.

_____

Additional comment

It is worthwhile to remember the relationship between the total and the average and the number of contributors. This shows up a lot in problems involving adjusting an average or finding a value to give a certain average.

Answer:

The empirical rule, the approximate percentage of trees planted between 38 and 68 is 99.7%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 62, standard deviation of 8.

What is the approximate percentage of trees planted between 38 and 86?

38 = 62 - 3*8

86 = 62 + 3*8

So within 3 standard deviations of the mean, which, by the empirical rule, the approximate percentage of trees planted between 38 and 68 is 99.7%.

Answer:

BC = 28

Step-by-step explanation:

The midsegment DF is half the measure of the third side BC , then

BC = 2 × DF = 2 × 14 = 28

Answer: Assuming there isnt a fourth answer, the answer is the second choice.

Step-by-step explanation: Point A is located in the first quadrant, Point B is located at 3, -1/2 and Point C is reflected off the y axis, in the second choice.

Answer:

p = 15/x

x= -3

Step-by-step explanation:

For the first problem, we can expand the equation to 4px+4=64

then simplify it to:

4px=60

then divide 4x from both sides of the equation

p=60/4x

then simplify:

p=15/x

For the second problem:

plug in -5 for p so the equation would look like

4(-5x +1)=64

simplify

-20x=60

x= -3

Answer:

linear function

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The graph is a straight line, so it's a linear function.

Answer: B

Answer:

A) P(Type I error) = 0.045

B) P(Type II) error = 0.1

Step-by-step explanation:

We are told that the reliability of the test is 90% reliable.

Also, we are told that the probability that the test erroneously detects a lie even when the individual is actually telling the truth is 0.045.

Thus;

A) To calculate the probability of type I error:

From statistics, in this question we can say that the probability of a type I error is the probability that the test will erroneously detect a lie even though the individual is actually telling the truth. Thus;

Probability of (type I error) = P(rejecting true null) = 0.045

B) For probability of type II error, it is defined as the error where we accept a null hypothesis that is false. We can say that it produces a false negative and the formula is;

P(Type II) error = 1 - reliability

Reliability in the question is 0.90

Thus;

P(Type II) error = 1 - 0.9

P(Type II) error = 0.1

[tex]\\\\\\[/tex]

[tex]\sf{ }[/tex] [tex]\sf{ }[/tex] [tex]\sf{ }[/tex]

Answer:

(y-4) (y-8)

Step-by-step explanation:

y^2-12y+32

What two numbers multiply to 32 and add to -12

-8*-4 = 32

-8+-4 = -12

(y-4) (y-8)

Answer:

C. ⅐

Step-by-step explanation:

Recall: the slope of a line that is perpendicular to another is the negative reciprocal of the slope of the other line that it is perpendicular to.

Thus:

Slope of red line = -7

The green line that is perpendicular to the red line will have a slope that is the negative reciprocal of -7.

Negative reciprocal of -7 = ⅐

The slope of the green line is therefore ⅐

Answer:

0.2305 = 23.05% probability that exactly 2 workers say yes.

Step-by-step explanation:

For each worker, there are only two possible outcomes. Either they say yes, or they say no. The probability of a worker saying yes is independent of any other worker, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

5% of workers in the US use public transportation to get to work.

This means that [tex]p = 0.05[/tex]

You randomly select 25 workers

This means that [tex]n = 25[/tex]

Find the probability that exactly 2 workers say yes.

This is P(X = 2). So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{25,2}.(0.05)^{2}.(0.95)^{23} = 0.2305[/tex]

0.2305 = 23.05% probability that exactly 2 workers say yes.

Answer:

[tex]241^{257}\ mod\ 12 =1[/tex]

[tex]7 * 20 = 140[/tex]

[tex]\frac{1}{700}[/tex]

Step-by-step explanation:

Solving (a): 241^257 mod 12

To do this, we simply calculate [tex]241\ mod\ 12[/tex]

Because [tex]a\ mod\ b = a^n\ mod\ b[/tex]

The highest number less than or equal to 241 that is divisible by 12 is 240; So:

[tex]241\ mod\ 12 = 241- 240[/tex]

[tex]241\ mod\ 12 =1[/tex]

Hence:

[tex]241^{257}\ mod\ 12 =1[/tex]

Solving (b): 7 * 20

[tex]7 * 20 = 140[/tex]

Solving (c): Multiplicative inverse of 7 in 719

The position of 7 in 719 is 700

So, the required inverse is 1/700 ---- i.e. we simply divide 1 by the number

Answer:

18

Step-by-step explanation:

3:2 means 3/2 or 3÷2

but its better to leave it as

3/2

Answer:

all real numbers

Algebra Examples

The domain of the expression is all real numbers except where the expression is undefined

Hello!

The domain of an exponential function is the crowd of all real numbers, so: x ∈ ℝ.

Good luck! :)

Solution :

The significant figure of a number are defined as the positional notation of that number which are most reliable and are absolutely necessary to represent the quantity of something.

In the context, we have to express the given numbers into three significant figures in the form of scientific notation or in the exponential form :

(i). 5590    -----    [tex]$5.59 \times 10^3$[/tex]

(ii).  0.000498   -----    [tex]$4.98 \times 10^{-4}$[/tex]

(iii) 135000  -----   [tex]$1.35 \times 10^5$[/tex]

(iv) 0.000438   -----  [tex]$4.38 \times 10^{-4}$[/tex]

Answer:

55

Step-by-step explanation:

let the number=x

5x=7x-110

7x-5x=110

2x=110

x=110/2=55

[tex]x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]