Ed decided to build a storage box. At first, he was planning to build a cubical box with edges of length n
inches. To increase the amount of storage, he decided to make the box 1 inch taller and 2 inches longer,
while keeping its depth at n inches. The volume of the box Ed built has a volume how many cubic inches
greater than the box he originally planned to build?
O 3n2 + 2n
312 + 3n+3
O 6n2 + 3n
O 6n2 + 3n+3

Answer:

I am pretty sure that your answer would be 3.

Step-by-step explanation:

The reason why is because if B if half of line segment AD and AD is equal to 12, then B must be equal to 6 since half of 12 is 6. Next, since C is the mid-point for line segment BD then C must be 3 since half of 6 is 3. And finally, that means line segment BC is three since it is 1/2 of BD.

Hope this helps! :)

Answer:

BC = 3

Step-by-step explanation:

If B is the midpoint of AD, that means AB = BD

AD = 12 so BD = 1/2 of AD  and BD = 6

If C is the midpoint of BD, that means BC = CD

BD = 6 so BC = 1/2 of BD  and BC = 3

Answer:

40.4502 billion dollars

51.3432 billion dollars

Step-by-step explanation:

Given :

Total amount spent in billions in pets x years after year, 2000 ;

P(x)=2.1786x + 25.2

Amount spent in 2007 ;

x = 2007 - 2000 = 7 years

Put x = 7 in the equation :

P(7)=2.1786(7) + 25.2 = 40.4502

Amount spent in 2012 :

x = 2012 - 2000 = 12 years

Put x = 12 in the equation :

P(12) = 2.1786(12) + 25.2 = 51.3432

The amount spent in billik dollars on pets in :

2007 = $404502 billion

2012 = $51.3432 billion

Answer:

this will give you the answer: for cylinder

V = 3×2^2×7 = 84cm

this will give you the answer for cone:

V = 3× 2^2 × 6/3 = 24cm

then we just add

84 + 24 = 108cm^3

Step-by-step explanation:

hope it helps!

Answer:

10.35 miles per hr

Step-by-step explanation:

first convert ft into mi

then calculate the distance traveled in one min

multiply the answer by 60

then you get the answer

Answer:

2 Inches

Step-by-step explanation:

Area of a triangle = (1/2)* Base * Hight

lets consider the base of the triangle is X inches,

then, Hight of the triangle is 2X

Then the Area of the Angle is = (1/2)*X*2X

                                               4 = x^{2}

                                               X = 2

Answer:

proper fraction

Step-by-step explanation:

a proper fraction has smaller numerator than its denominatot.

Answer: Proper Fraction

Step-by-step explanation:

The denominator is equal or bigger than the numerator.

Must click thanks and mark brainliest

Answer:

a) The rocket travels 200 meters horizontally.

b) The height of the rocket mid-flight is of 1000 meters.

Step-by-step explanation:

Height of the rocket:

The height of the rocket, in meters, after an horizontal distance of x, is given by:

[tex]y = 0.1x(200 - x)[/tex]

a) How far does the rocket travel horizontally?

This is x when [tex]y = 0[/tex]. So

[tex]0.1x(200 - x) = 0[/tex]

Then

[tex]0.1x = 0[/tex]

[tex]x = 0[/tex]

And

[tex]200 - x = 0[/tex]

[tex]x = 200[/tex]

So

The rocket travels 200 meters horizontally.

b How high does the rocket reach mid-flight?

This it the height y when x = 0, so:

[tex]y = 20*100 - 0.1*100^2 = 1000[/tex]

The height of the rocket mid-flight is of 1000 meters.

Answer:

6x+36=180

6x=144

x=24

Step-by-step explanation:

this is the correct answer

Answer:

3m = -3

Step-by-step explanation:

2m−6=8m

Subtract 2m from each side

2m−6-2m=8m-2m

-6 = 6m

Divide by 6

-6/6 = 6m/6

-1 = m

3m = 3(-1) = -3

2m - 6 = 8m

2m - 8m = 6

-6m = 6

m = -6/6

m = -1

Answer:

B: 30 and 60

Step-by-step explanation:

First, let's set up an equation. Since the two angles are complementary, we can write the equation like this:

2p + p = 90

Now, let's solve it!

2p + p = 90

Combine like terms:

3p = 90

Divide each side by 3 to isolate p:

3p/3 = 90/3

p = 30

Now that we know how many degrees one of our angles is, we can subtract that from 90 to get both of the complementary angles.

90 - 30 = 60

Therefore, the two angles that are complementary in this case are 30 and 60 degrees.

Answer:

Domain { -6,3,4,6,10}

The range is the output values, listed from smallest to largest with no repeats

Range { -13,-9,2,14,19}

Step-by-step explanation:

The domain is the input values, listed from smallest to largest with no repeats

Domain { -6,3,4,6,10}

The range is the output values, listed from smallest to largest with no repeats

Range { -13,-9,2,14,19}

Answer:

Range: 14, 19, -9, 2, -13

Domain: -6, 10, 4, 3, 6

Step-by-step explanation:

I don't know but this is it I think .

the answer will be 0.092 as a decimal

Answer:

Part A)

0.1 liters per minute.

Part B)

There was initially 3.8 liters of water.

[tex]\displaystyle V(t) = 0.1(t - 10) + 4.8[/tex]

Part C)

562 minutes.

Step-by-step explanation:

A tank is filled at a constant rate. After 10 minutes, the tank contains 4.8 L of water and after 35 minutes, the tank contains 7.3 L of water.

Part A)

We can represent the current data with two points: (10, 4.8) and (35, 7.3). The x-coordinate is measured in minutes since the tank began to be filled and the y-coordinate is measured in how full the tank is in liters.

To find the rate at which the tank is being filled, find the slope between the two points:

[tex]\displaystyle m = \frac{\Delta y}{\Delta x} = \frac{(7.3)-(4.8)}{(35)-(10)} = \frac{2.5}{25} = 0.1[/tex]

In other words, the rate at which the tank is being filled is 0.1 liters per minute.

Part B)

To find the function of the volume of the tank, we can use the point-slope form to first find its equation:

[tex]\displaystyle y - y_1 = m( x - x_1)[/tex]

Where m is the slope/rate of change and (x₁, y₁) is a point.

We will substitute 0.1 for m and let (10, 4.8) be the point. Hence:

[tex]\displaystyle y - (4.8) = 0.1(x - 10)[/tex]

Simplify:

[tex]\displaystyle y = 0.1(x-10) + 4.8[/tex]

Since y represent how full the tank is and x represent the time in minutes since the tank began to be filled, we can substitute y for V(t) and x for t. Thus, our function is:

[tex]\displaystyle V(t) = 0.1(t - 10) + 4.8[/tex]

The initial volume is when t = 0. Evaluate:

[tex]\displaystyle V(0) = 0.1 ((0) - 10) + 4.8 = 3.8[/tex]

There was initially 3.8 liters of water.

Part C)

To find how long it will take for the tank to be completely filled given its maximum capacity of 60 liters, we can let V(t) = 60 and solve for t. Hence:

[tex]60 = 0.1(t - 10) + 4.8[/tex]

Subtract:

[tex]55.2 = 0.1(t - 10)[/tex]

Divide:

[tex]552 = t - 10[/tex]

Add. Therefore:

[tex]t = 562\text{ minutes}[/tex]

It will take 562 minutes for the tank to be completely filled.

9514 1404 393

Answer:

  -0.84

Step-by-step explanation:

In decimal, the expression is ...

  -1.34 +1.50 -1.00 = -0.84

__

As fractions, the expression is ...

  -67/50 +75/50 -50/50 = (-67+75-50)/50 = -42/50 = -21/25

Area of rhombus = 1/2 × d1 × d2

Let the other diagonal be x

ATQ

1/2 × 18 × x = 24

9 × x = 24

x = 24/9

x = 8/3

Now half each diagonal = 9 and 4/3

Now side = b² + p² = h²

9²+(4/3)² = h²

81 + 16/9 = h²

729/9 + 16/9 = h²

745/9 = h²

√(745/9) = h

Therefore the side of the rhombus is √(745/9)cm

Answered by Gauthmath must click thanks and mark brainliest

Answer:

[tex]x=5[/tex]

[tex]h=\sqrt{(5)^{2}+x^{2} } =\sqrt{(5)^{2}+(5)^{2} }[/tex]

[tex]h=\sqrt{25+25} =\sqrt{50}[/tex]

[tex]h=5\sqrt{2}[/tex]

OAmalOHopeO

Answer:

[tex]i)14 + 4 \sqrt{6} [/tex]

[tex]ii) \sqrt{10} + 28[/tex]

[tex]iii) 243[/tex]

Step-by-step explanation:

[tex]i)(2 \sqrt{3} + \sqrt{2} {)}^{2} [/tex]

➡️ [tex]12 + 4 \sqrt{6} + 2[/tex]

➡️ [tex]14 + 4 \sqrt{6} [/tex] ✅

●●●●●●●●●●●●●●●●●●●●●●●●●●●●●●

[tex]ii)(3 \sqrt{5} - \sqrt{2} ) \times ( \sqrt{2} + 2 \sqrt{5} )[/tex]

➡️ [tex]3 \sqrt{10} + 30 - 2 - 2 \sqrt{10} [/tex]

➡️ [tex] \sqrt{10} + 28[/tex] ✅

●●●●●●●●●●●●●●●●●●●●●●●●●●●●●●

[tex]iii)3 \sqrt{81} \times 3 \sqrt{9} [/tex]

➡️ [tex]3 \times 9 \times 3 \times 3[/tex]

➡️ [tex]243[/tex] ✅

Answer:

ur box cannot be opend  repain the window

Step-by-step explanation:

please mark this answer as brainlist

Answer:

∠ ABC = 125°

Step-by-step explanation:

∠ ABC = ∠ ABD + ∠DBC that is

∠ ABC = 65° + 60° = 125°

The area is just the base times the height. In this case, the base is (x+4) and the height is (x+6), and then you just distribute to get x^2 +4x+6x+24 which is x^2+10x+24.

If L(t) = ⟨5 + t, 1 + 5t⟩, then the tangent vector to L(t) is

dL/dt = ⟨1, 5⟩

Any line parallel to L(t) will have the same tangent vector, up to some scalar factor (that is, if the tangent vector is a multiple of ⟨1, 5⟩).

Any line r(t) with tangent vector T(t) = dr/dt that is perpendicular to L(t) will satisfy

T(t) • ⟨1, 5⟩ = 0

• r(t) = ⟨-5, -2t, 1 - 10t⟩ is parallel to L(t) because its tangent vector is

T(t) = ⟨-2, -10⟩ = -2 ⟨1, 5⟩

• r(t) = ⟨1 + 1.5t, 3 + 7.5t⟩ is parallel to L(t) because

T(t) = ⟨1.5, 7.5⟩ = 1.5 ⟨1, 5⟩

• r(t) = ⟨-2 - t, 2 - 2t⟩ is neither parallel nor perpendicular to L(t) because

T(t) = ⟨-1, -2⟩ ≠ k ⟨1, 5⟩

for any real k (in other words, there is no k such that -1 = k and -2 = 5k), and

⟨-1, -2⟩ • ⟨1, 5⟩ = -1 - 10 = -11 ≠ 0

• r(t) = ⟨3 + 15t, -3t⟩ is perpendicular to L(t) because

T(t) = ⟨15, -3⟩

and

⟨15, -3⟩ • ⟨1, 5⟩ = 15 - 15 = 0

Answer:

Hence the correct option is option c has a Binomial distribution with n=21 and p=50%.

Step-by-step explanation:

1)  

A coin is tossed 19 times,  

P(Head)=0.5  

P(Tail)=0.5  

We have to find the probability of a total number of heads in all the coin tosses equals 9.  

This can be solved using the binomial distribution. For binomial distribution,  

P(X=x)=C(n,x)px(1-p)n-x  

where n is the number of trials, x is the number of successes, p is the probability of success, C(n,x) is a number of ways of choosing x from n.  

P(X=9)=C(19,9)(0.5)9(0.5)10  

P(X=9)=0.1762  

2)  

A fair die is rolled twice.  

Total number of outcomes=36  

Possibilities of getting sum as 9  

S9={(3,6),(4,5)(5,4),(6,3)}  

The total number of spots showing in all the die rolls equals 9 =4/36=0.1111  

3)  

The event of getting a good number of spots on a die roll is actually no different from the event of heads on a coin toss since the probability of a good number of spots is 3/6 = 1/2, which is additionally the probability of heads. the entire number of heads altogether the tosses of the coin plus the entire number of times the die lands with a good number of spots has an equivalent distribution because the total number of heads in 19+2= 21 tosses of the coin. The distribution is binomial with n=21 and p=50%.

C, just look at the "Total" for each single information.

the values in the inner grid combine multiple informations.

The table shows these data correctly entered in a two-way frequency is table C.

Two-way frequency tables show the potential connections between two sets of categorical data visually. The table's four (or more) inside cells contain the frequency (count) data, which is displayed above and to the left of the table's designated categories.

We have been the information 25 students play an instrument 20 are in a band 30 are not in a band.

So, the two way table is:

                                     Band            Not in Band       Total

Play instrument                20                   5                     25

Do not play instrument     0                     25                 25

Total                                  20                    30                50

So, Table C is Correct.

Learn more about two-way frequency here:

https://brainly.com/question/9033726

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9514 1404 393

Answer:

  4·10 +4·5 = 6·12 -6·2

Step-by-step explanation:

Each outside factor multiplies each inside term.

  4(10 +5) = 6(12 -2)

  4·10 +4·5 = 6·12 -6·2

Answer:

− 8 a ^7

Step-by-step explanation:

See picture for steps :)

Answer:

Option B, AAS

Option C, HA

Option E, ASA

these three options applies

Answer:

[tex]x^\frac{3}{5} = (x^3 )^\frac{1}{5}[/tex]

[tex]x^\frac{3}{5} = \sqrt[5]{x^3}[/tex]

[tex]x^\frac{3}{5} = (\sqrt[5]{x})^3[/tex]

Step-by-step explanation:

Given

[tex]x^\frac{3}{5}[/tex]

Required

The equivalent expressions

We have:

[tex]x^\frac{3}{5}[/tex]

Expand the exponent

[tex]x^\frac{3}{5} = x^{ 3 * \frac{1}{5}}[/tex]

So, we have:

[tex]x^\frac{3}{5} = (x^3 )^\frac{1}{5}[/tex] ----- this is equivalent

Express 1/5 as roots (law of indices)

[tex]x^\frac{3}{5} = \sqrt[5]{x^3}[/tex] ------ this is equivalent

The above can be rewritten as:

[tex]x^\frac{3}{5} = (\sqrt[5]{x})^3[/tex] ------ this is equivalent