Answer: x' = 30t
y' = 20t
Step-by-step explanation:
To find the derivative, multiply the exponent to the leading coefficient and decrease the exponent by 1.
x = 15t²
x' = 2 · 15t²⁻¹
= 30t¹
= 30t
y = 10t²
y' = 2 · 10t²⁻¹
= 20t¹
= 20t
x-6/2=2x/7 solve the equation
Answer:
x-6/2=2x/7
7x-42=4x
7x-4x=42
3x= 42
X = 42/3
How do u simplify each expression by combining like terms?
Answer:
1. 8y - 9y = -1y
( 8 - 9 = -1)
3. 8a - 6 +a - 1
( i have showed the like terms here)
8a - 1a= 7a
-6 - 1 = -7
7a - 7
5. -x - 2 + 15x
( i have showed the like terms here)
-x + 15x = 14x
(x = 1)
14x + 2
7. 8d - 4 - d - 2
( i have showed the like terms here)
8d - d = 7d
-4 -2 = -6
7d - 6
8. 9a + 8 - 2a - 3 - 5a
( i have showed the like terms here)
9a - 2a - 5a = 2a
8 - 3= 5
2a + 5
Mr. Lee is 32 years older than his son. Five years later, Mr. Lee’s age will be 5 times that of his son. How old is Mr. Lee now?
Answer: mr lee is 37 year .
Step-by-step explanation:32+5=37
Answer:
Mr. lee is 35 yrs old right now. his son 3
Step-by-step explanation:
after 5 yrs, his son will be 8 and lee 40, 8×5=40
The graph below shows Roy's distance from his office (y), in miles, after a certain amount of time (x), in minutes: Graph titled Roys Distance Vs Time shows 0 to 10 on x and y axes at increments of 1.The label on x axis is time in minutes and that on y axis is Distance from Office in miles. Lines are joined at the ordered pairs 0, 0 and 1, 1 and 2, 2 and 3, 3 and 4, 4 and 5, 4 and 6, 4 and 7, 4.5 and 7.5, 5 and 8, 6. Four students described Roy's motion, as shown in the table below: Student Description Peter He drives a car at a constant speed for 4 minutes, then stops at a crossing for 6 minutes, and finally drives at a variable speed for the next 2 minutes. Shane He drives a car at a constant speed for 4 minutes, then stops at a crossing for 2 minutes, and finally drives at a variable speed for the next 8 minutes. Jamie He drives a car at a constant speed for 4 minutes, then stops at a crossing for 6 minutes, and finally drives at a variable speed for the next 8 minutes. Felix He drives a car at a constant speed for 4 minutes, then stops at a crossing for 2 minutes, and finally drives at a variable speed for the next 2 minutes. Which student most accurately described Roy's motion? Peter Shane Jamie Felix
Answer:
Felix
Step-by-step explanation:
The graph contains 3 segments,
first one is for the first 4minutes,
second one is for the next 2 minutes (standing still)
third one is for the last 2 minutes.
Only Felix has it right, the other students use absolute time in their statements, in stead of the difference between start and end. (e.g., from 4 to 6 is 2 minutes).
The student that most accurately described Roy's motion is Felix.
How to find the function which was used to make graph?There are many tools we can use to find the information of the relation which was used to form the graph.
A graph contains data of which input maps to which output.
Analysis of this leads to the relations which were used to make it.
We need to find the student that most accurately described Roy's motion.
Here we can see that the graph contains 3 segments, first one is for the first 4 minutes, Second one is for the next 2 minutes (standing still) and the third one is for the last 2 minutes.
Now, Only Felix has it right, the other students use absolute time in their statements, in stead of the difference between start and end.
Therefore, the student that most accurately described Roy's motion is Felix.
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PLEASE HELP
Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations). The figures below are based on semicircles or quarter circles and problems b), c), and d) are involving portions of a square.
Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
Step-by-step explanation:
First we need to deal with the half circle. The radius of this circle is 4, because the diameter is 8. The formula for the circumference of a circle is 2piR.
2pi4 so the perimeter for the half circle would be 8pi/2.
The area of that half circle would be piR^2 so 16pi/2.
Now moving on the triangle part, we need to find the hypotenuse side of AC. We will use the pythagoram theorem. 4^2+10^2=C^2
16+100=C^2
116=C^2
C=sqrt(116)
making the perimeter of this triangle 2×sqrt(116)
The area of this triangle is 8×10=80, than divided by 2 which is equal to 40.
We than just need to add up the perimeters and areas for both the half circle and triangle.
The area would be equal to 8pi+40
The perimeter would be equal to 4pi+4(sqrt(29))
The probability that a company will launch the product A and B are 0.45 and 0.60 respectively, in main while, probability that both products launched, is 0.35. What is the probability that Neither will of these products launch? (04) At least one product will be launched ?
Answer:
1) 0.3 ; 0.7
Step-by-step explanation:
Given the following :
Probability that product A launch : P(A) = 0.45
Probability that product B launch : P(B) = 0.60
Probability that both product launch : P(AnB) = 0.35
P(A alone) = p(A) - p(AnB)
P(A alone) = 0.45 - 0.35 = 0.1
P(B alone) = p(B) - p(AnB)
P(B alone) = 0.60 - 0.35 = 0.25
Probability that neither product will launch :
1 - [p(A alone) + p(B alone) + p(AnB)]
1 - [0.1 + 0.25 + 0.35]
1 - 0.7 = 0.3
Probability that at least one product will launch :
P(A alone) + p(B alone) + p(AnB)
0.1 + 0.25 + 0.35 = 0.7
how many unique 10 digit numbers can be formed if the number 2 is in the first place and repetition is allowed?
Answer:
362880 ways
Step-by-step explanation:
Given
10 digits
Required
Number of 10 digits that can be formed if no repetition and 2 must always start;
Since digit 2 must always start and no repetition is allowed, then there are 9 digits left
Digit 2 can only take 1 position
9 digits can be arranged without repetition in 9! ways;
Calculating 9!
[tex]9! = 9 * 8 *7 * 6 * 5 * 4 * 3 * 2 * 1[/tex]
[tex]9! = 362880[/tex]
Number of arrangement = 1 * 362880
Number of arrangement = 362880 ways
Complete the square to transform the expression x2 - 2x - 2 into the form a(x - h)2 + k
Answer:
A
Step-by-step explanation:
Find the vertex form of the quadratic function below.
y = x^2 - 4x + 3
This quadratic equation is in the form y = a{x^2} + bx + cy=ax
2
+bx+c. However, I need to rewrite it using some algebraic steps in order to make it look like this…
y = a(x - h)^2 + k
This is the vertex form of the quadratic function where \left( {h,k} \right)(h,k) is the vertex or the “center” of the quadratic function or the parabola.
Before I start, I realize that a = 1a=1. Therefore, I can immediately apply the “completing the square” steps.
STEP 1: Identify the coefficient of the linear term of the quadratic function. That is the number attached to the xx-term.
STEP 2: I will take that number, divide it by 22 and square it (or raise to the power 22).
STEP 3: The output in step #2 will be added and subtracted on the same side of the equation to keep it balanced.
Think About It: If I add 44 on the right side of the equation, then I am technically changing the original meaning of the equation. So to keep it unchanged, I must subtract the same value that I added on the same side of the equation.
STEP 4: Now, express the trinomial inside the parenthesis as a square of a binomial, and simplify the outside constants.
After simplifying, it is now in the vertex form y = a{\left( {x - h} \right)^2} + ky=a(x−h)
2
+k where the vertex \left( {h,k} \right)(h,k) is \left( {2, - 1} \right)(2,−1).
Visually, the graph of this quadratic function is a parabola with a minimum at the point \left( {2, - 1} \right)(2,−1). Since the value of “aa” is positive, a = 1a=1, then the parabola opens in upward direction.
Example 2: Find the vertex form of the quadratic function below.
The approach to this problem is slightly different because the value of “aa” does not equal to 11, a \ne 1a
=1. The first step is to factor out the coefficient 22 between the terms with xx-variables only.
STEP 1: Factor out 22 only to the terms with variable xx.
STEP 2: Identify the coefficient of the xx-term or linear term.
STEP 3: Take that number, divide it by 22, and square.
STEP 4: Now, I will take the output {9 \over 4}
4
9
and add it inside the parenthesis.
By adding {9 \over 4}
4
9
inside the parenthesis, I am actually adding 2\left( {{9 \over 4}} \right) = {9 \over 2}2(
4
9
)=
2
9
to the entire equation.
Why multiply by 22 to get the “true” value added to the entire equation? Remember, I factored out 22 in the beginning. So for us to find the real value added to the entire equation, we need to multiply the number added inside the parenthesis by the number that was factored out.
STEP 5: Since I added {9 \over 2}
2
9
to the equation, then I should subtract the entire equation by {9 \over 2}
2
9
also to compensate for it.
STEP 6: Finally, express the trinomial inside the parenthesis as the square of binomial and then simplify the outside constants. Be careful combining the fractions.
It is now in the vertex form y = a{\left( {x - h} \right)^2} + ky=a(x−h)
2
+k where the vertex \left( {h,k} \right)(h,k) is \left( {{{ - \,3} \over 2},{{ - 11} \over 2}} \right)(
2
−3
,
2
−11
).
Example 3: Find the vertex form of the quadratic function below.
Solution:
Factor out - \,3−3 among the xx-terms.
The coefficient of the linear term inside the parenthesis is - \,1−1. Divide it by 22 and square it. Add that value inside the parenthesis. Now, figure out how to make the original equation the same. Since we added {1 \over 4}
4
1
inside the parenthesis and we factored out - \,3−3 in the beginning, that means - \,3\left( {{1 \over 4}} \right) = {{ - \,3} \over 4}−3(
4
1
)=
4
−3
is the value that we subtracted from the entire equation. To compensate, we must add {3 \over 4}
4
3
outside the parenthesis.
Therefore, the vertex \left( {h,k} \right)(h,k) is \left( {{1 \over 2},{{11} \over 4}} \right)(
2
1
,
4
11
).
Example 4: Find the vertex form of the quadratic function below.
y = 5x^2 + 15x - 5
Solution:
Factor out 55 among the xx-terms. Identify the coefficient of the linear term inside the parenthesis which is 33. Divide it by 22 and square to get {9 \over 4}
4
9
.
Add {9 \over 4}
4
9
inside the parenthesis. Since we factored out 55 in the first step, that means 5\left( {{9 \over 4}} \right) = {{45} \over 4}5(
4
9
)=
4
45
is the number that we need to subtract to keep the equation unchanged.
Express the trinomial as a square of binomial, and combine the constants to get the final answer.
Therefore, the vertex \left( {h,k} \right)(h,k) is {{ - \,3} \over 2},{{ - \,65} \over 4}
2
−3
,
4
−65
.
Answer:
(x - 1 )^2 - 3
Step-by-step explanation:
( x - 1 )^2 + ( -3)
x^2 - 2x + 1 - 3
x^2 - 2x - 2
The cost of a pizza at the local pizza shop has a base price of $12 for a cheese pizza, plus $2 for each additional topping? What is the value of the slope?
Answer:
$2.
Step-by-step explanation:
This is because the base price is $12, which means the constant is 12. The toppings are the only things you can add to the pizza, so the price of each additional topping is the slope of the pizza's cost. The slope is 2 dollars.
Hope this helps!
Answer:
2
Step-by-step explanation:
If we were to write a linear equation in slope-intercept form (y = mx + b where m = slope and b = y-intercept) of this situation, it would be y = 2x + 12 where y is the price and x is the number of toppings. This is because the price for every topping is 2x but the base price doesn't change, therefore it's a constant so it would be + 12. In this case, since m = slope, the slope is 2.
21. Evaluate f(x) = 3x + 8 for x = 1.
Answer:
f(1) = 11
Step-by-step explanation:
f(x) = 3x + 8
Let x=1
f(1) = 3(1) +8
= 3+8
= 11
a diagonal of rectangle forms a 30 degree angle with each of the longer sides of the rectangle. if the length of the shorter side is 3, what is the length of the diagonal
Answer:
Length of diagonal = 6
Step-by-step explanation:
Given that
Diagonal of a rectangle makes an angle of [tex]30^\circ[/tex] with the longer side.
Kindly refer to the attached diagram of the rectangle ABCD such that diagonal BD makes angles of [tex]30^\circ[/tex] with the longer side CD and BA.
[tex]\angle CDB =\angle DBA =30^\circ[/tex]
Side AD = BC = 3 units
To find:
Length of diagonal BD = ?
Solution:
We can use the trigonometric ratio to find the diagonal in the [tex]\triangle BCD[/tex] because [tex]\angle C =90^\circ[/tex]
Using the sine :
[tex]sin\theta = \dfrac{Perpendicular }{Hypotenuse }[/tex]
[tex]sin\angle CDB = \dfrac{BC}{BD}\\\Rightarrow sin30^\circ = \dfrac{3}{BD}\\\Rightarrow \dfrac{1}2 = \dfrac{3}{BD}\\\Rightarrow BD =2 \times 3 \\\Rightarrow BD = \bold{6 }[/tex]
So, the answer is:
Length of diagonal = 6
Given the equations of a straight line f(x) (in slope-intercept form) and a parabola g(x) (in standard form), describe how to determine the number of intersection points, without finding the coordinates of such points. Do not give an example.
Answer:
Step-by-step explanation:
Hello, when you try to find the intersection point(s) you need to solve a system like this one
[tex]\begin{cases} y&= m * x + p }\\ y &= a*x^2 +b*x+c }\end{cases}[/tex]
So, you come up with a polynomial equation like.
[tex]ax^2+bx+c=mx+p\\\\ax^2+(b-m)x+c-p=0[/tex]
And then, we can estimate the discriminant.
[tex]\Delta=(b-m)^2-4*a*(c-p)[/tex]
If [tex]\Delta<0[/tex] there is no real solution, no intersection point.
If [tex]\Delta=0[/tex] there is one intersection point.
If [tex]\Delta>0[/tex] there are two real solutions, so two intersection points.
Hope this helps.
what is (-3) + (-8)
Answer:
[tex]\huge \boxed{-11}[/tex]
Step-by-step explanation:
[tex](-3)+(-8)[/tex]
[tex]\sf Factor \ negative \ sign.[/tex]
[tex]-(3+8)[/tex]
[tex]\sf Add.[/tex]
[tex]-(11)[/tex]
Step-by-step explanation:
[tex]( - 3) + ( - 8) \\ \\ remove \: unecessary \: parantheses \\ - 3 - 8 \\ = 11[/tex]
A dwarf planet is discovered with a radius that is 1/100 the radius of planet c. Write the diameter of the dwarf planet as power. The diameter of the dwarf planet is meter
Answer:
1^-100
Step-by-step explanation:
in the negative powers the negative sign stands for the fraction line symbol and the power stands for the bottom number.
Resolve 36x2 – 81y2 into factors
Answer:
(6x + 9y)(6x - 9y)
Step-by-step explanation:
We can use the difference of squares which states that a² - b² = (a + b)(a - b), in this case, a = 6x and b = 9y so the answer is (6x + 9y)(6x - 9y).
which choice is the solution set for the inequality below
x < 3
Answer:
B) x < 9
Step-by-step explanation:
√x < 3
(√x)² > 3²
x < 9
Shaquira is baking cookies to put in packages for a fundraiser. Shaquira has made 86 8686 chocolate chip cookies and 42 4242 sugar cookies. Shaquira wants to create identical packages of cookies to sell, and she must use all of the cookies. What is the greatest number of identical packages that Shaquira can make?
Answer: 2
Step-by-step explanation:
Given: Shaquira has made 86 chocolate chip cookies and 42 sugar cookies.
Shaquira wants to create identical packages of cookies to sell, and she must use all of the cookies.
Now, the greatest number of identical packages that Shaquira can make= GCD of 86 and 42
Prime factorization of 86 and 42:
86 = 2 ×43
42 = 2 × 3 × 7
GCD of 86 and 42 = 2 [GCD = greatest common factor]
Hence, the greatest number of identical packages that Shaquira can make =2
Which equation does the graph of the systems of equations solve? 2 linear graphs. They intersect at 1,4
Answer:
See below.
Step-by-step explanation:
There is an infinite n umber of systems of equations that has (1, 4) as its solution. Are you given choices? Try x = 1 and y = 4 in each equation of the choices. The set of two equations that are true when those values of x and y are used is the answer.
Solve for w. | – w|≥2 Write a compound inequality like 1 < x < 3 or like x < 1 or x > 3. Use integers, proper fractions, or improper fractions in simplest form.
Answer:
[tex]-2 \geq w \geq 2[/tex]
Step-by-step explanation:
Given
[tex]|-w| \geq 2[/tex]
Required
Solve for w
[tex]|-w| \geq 2[/tex]
In absolution functions;
[tex]|-w| = |w|[/tex]
So, the given expression can be rewritten as
[tex]|w| \geq 2[/tex]
Removing the absolute sign, will gibe
[tex]w \geq 2[/tex] or [tex]w \leq -2[/tex]
When the second inequality os rewritten, it gives
[tex]w \geq 2[/tex] or [tex]-2 \geq w[/tex]
Reorder both inequalities
[tex]-2 \geq w[/tex] or [tex]w \geq 2[/tex]
Lastly, both inequalities are combined
[tex]-2 \geq w \geq 2[/tex]
Evaluate the expression 52 + 2x when x = 5. Choose the phrase below that describes the resulting number.
Answer:
62
Step-by-step explanation:
hope that helps! if it is an answer
The Phrase is: "The resulting number is 62."
We have the expression as
52 + 2x
Now, To evaluate the expression 52 + 2x when x = 5,
we substitute the value of x into the expression and simplify:
=52 + 2(5)
= 52 + 10
= 62.
Thus, The resulting number is 62.
Learn more about Expression here:
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I need help on this :(
Answer:
26⁹
Step-by-step explanation:
26 * 26⁸
= 26¹ * 26⁸
= 26¹⁺⁸
= 26⁹
A recipe needs two and one sixth cups of walnuts and eight and one eighth cups of peanuts. How many cups of nuts are needed for the recipe in all? please answer!!!
Answer:
10 and seven twenty-fourths (10 7/24)
Step-by-step explanation:
2 1/6 + 8 1/8 =
2 4/24 + 8 3/24 =
10 7/24
PLEaSE HELP!!!!!! will give brainliest to first answer
Answer:
The coordinates of A'C'S'T' are;
A'(-7, 2)
C'(-9, -1)
S'(-7, -4)
T'(-5, -1)
The correct option is;
B
Step-by-step explanation:
The coordinates of the given quadrilateral are;
A(-3, 1)
C(-5, -2)
S(-3, -5)
T(-1, -2)
The required transformation is T₍₋₄, ₁₎ which is equivalent to a movement of 4 units in the leftward direction and 1 unit upward
Therefore, we have;
A(-3, 1) + T₍₋₄, ₁₎ = A'(-7, 2)
C(-5, -2) + T₍₋₄, ₁₎ = C'(-9, -1)
S(-3, -5) + T₍₋₄, ₁₎ = S'(-7, -4)
T(-1, -2) + T₍₋₄, ₁₎ = T'(-5, -1)
Therefore, the correct option is B
Becky's ship is 43 miles west all the harbor.
Clyde's yacht is a5 miles north from Beery. How
far is Clyde from the Harbor? Show your work.
С
x= Harbor
25
B.
43
Answer:
Clyde is 49.74 away from the harbor
Step-by-step explanation:
Here in this question, we are interested in knowing the distance of Clyde from the harbor.
The key to answering this question is having a correct diagrammatic representation. Please check attachment for this.
We can see we have the formation of a right angled triangle with the distance between Clyde’s ship and the harbor the hypotenuse.
To calculate the distance between the two, we shall employ the use of Pythagoras’ theorem which states that the square of the hypotenuse is equal the sum of the squares of the two other sides.
Let’s call the distance we want to calculate h.
Mathematically;
h^2 = 25^2 + 43^2
h^2 = 625 + 1849
h^2 = 2474
h = √2474
h = 49.74 miles
State whether the given measurements determine zero, one, or two triangles. A = 58°, a = 25, b = 28
Answer:
1
Step-by-step explanation:
I believe it is 1. Just picture or draw a diagram of the constraints. Don't quote me on this though...
Answer:
Step-by-step explanation:
apply sine formula
[tex]\frac{a}{sin ~A} =\frac{b}{sin~B} \\\frac{25}{sin~58} =\frac{28}{sin ~B} \\sin~B=\frac{28}{25} \times sin~58\\B=sin^{-1} (\frac{28}{25} \times sin ~58)=71.77 \approx 72 ^\circ[/tex]
so third angle=180-(58+72)=180-130=50°
∠C=50°
[tex]cos ~C=\frac{a^2+b^2-c^2}{2ab} \\or ~2abcos~C=a^2+b^2-c^2\\2*25*28*cos ~50=25^2+28^2-c^2\\c^2=625+784-1400 *cos~50\\c^2=1409-899.90\\c^2=509.1\\c=\sqrt{509.1} \approx 22.56 \approx 22.6[/tex]
so one triangle is formed.
Please answer question now
Answer:
3x3÷2= 4.5cm^2
The formula is 1/2×base×slanted height
Step-by-step explanation:
Answer:
150 in²Step-by-step explanation:
V = ¹/₃•(¹/₂•10•9)•10 = ¹/₃•45•10 = 15•10 = 150 in²
PLEASE ANSWER!!! Select the correct answer from each drop-down menu. Consider the function f(x) = 3x + 1 and the graph of the function g(x) shown below.
Function transformation involves changing the position of a function.
The graph of g(x) is the graph of f(x) translated 2 units right, and [tex]\mathbf{g(x) = 3(x -2) + 1}[/tex]
The function is given as:
[tex]\mathbf{f(x)=3x + 1}[/tex]
The graph of g(x) passes through (2,1) and (0,-5).
Start by calculating the slope (m)
[tex]\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}[/tex]
So, we have:
[tex]\mathbf{m = \frac{-5-1}{0-2}}[/tex]
[tex]\mathbf{m = \frac{-6}{-2}}[/tex]
[tex]\mathbf{m = 3}[/tex]
The equation is then calculated as:
[tex]\mathbf{g(x) = m(x -x_1) + y_1}[/tex]
So, we have:
[tex]\mathbf{g(x) = 3(x -2) + 1}[/tex]
By comparing [tex]\mathbf{f(x)=3x + 1}[/tex] and [tex]\mathbf{g(x) = 3(x -2) + 1}[/tex]
The graph of f(x) is shifted 2 units to the right
Read more about function transformation at:
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The equation of line WX is 2x + y = −5. What is the equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2)?
Answer: [tex]y=\dfrac12x-\dfrac{3}{4}[/tex]
Step-by-step explanation:
Given, The equation of line WX is 2x + y = −5.
It can be written as [tex]y=-2x-5[/tex] comparing it with slope-intercept form y=mx+c, where m is slope and c is y-intercept, we have
slope of WX = -2
Product of slopes of two perpendicular lines is -1.
So, (slope of WX) × (slope of perpendicular to WX)=-1
[tex]-2\times\text{slope of WX}=-1\\\\\Rightarrow\ \text{slope of WX}=\dfrac{1}{2}[/tex]
Equation of a line passes through (a,b) and has slope m:
[tex]y-b=m(x-a)[/tex]
Equation of a line perpendicular to WX contains point (−1, −2) and has slope [tex]=\dfrac12[/tex]
[tex]y-(-2)=\dfrac{1}{2}(x-(-1))\\\\\Rightarrow\ y+2=\dfrac12(x+1)\\\\\Rightarrow\ y+2=\dfrac12x+\dfrac12\\\\\Rightarrow\ y=\dfrac12x+\dfrac12-2\\\\\Rightarrow\ y=\dfrac12x-\dfrac{3}{4}[/tex]
Equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2) [tex]:y=\dfrac12x-\dfrac{3}{4}[/tex]
Find the vertex of f(x)= x^2+ 6x + 36
Pls help soon
Answer:
vertex(-3,27)
Step-by-step explanation:
f(x)= x^2+ 6x + 36 ( a=1,b=6,c=36)
V(h,k)
h=-b/2a=-6/2=-3
k=f(-3)=3²+6(-3)+36
f(-3)=9-18+36=27
vertex(-3,27)
prove tan(theta/2)=sin theta/1+cos theta for theta in quadrant 1 by filling in the calculations and reasons. PLEASE HELP!!!!
Answer:
See explanation
Step-by-step explanation:
We have to prove the identity
[tex]tan(\frac{\Theta }{2})=\frac{sin\Theta}{1+cos\Theta }[/tex]
We will take right hand side of the identity
[tex]\frac{sin\Theta}{1+cos\Theta}=\frac{2sin(\frac{\Theta }{2})cos(\frac{\Theta }{2})}{1+[2cos^{2}(\frac{\Theta }{2})-1]}[/tex]
[tex]=\frac{2sin(\frac{\Theta }{2})cos(\frac{\Theta }{2})}{2cos^{2}(\frac{\Theta }{2})}=\frac{sin(\frac{\Theta }{2})}{cos(\frac{\Theta }{2})}[/tex]
[tex]=tan(\frac{\Theta }{2})[/tex] [ Tan θ will be positive since θ lies in 1st quadrant ]
