Answer:
Yes. If you are asking if the duration between those two times is a total of 12 hours, the answer is yes.
Step-by-step explanation:
9:45am is 12 hours away from 9:45pm. This applies to all times and their am/pm counterparts such as 12am/12pm.
a point is chosen at random on ak. what is the probability that the point will be on bg. dont forget to reduce
there is a 20% chance that the point chosen at random will lie on bg.
To find the probability that a point chosen at random will be on the line segment bg, we need to consider the length of bg in relation to the length of the entire line segment ak.
Let us assume that ak is a straight line segment, and bg is a smaller segment that lies entirely within it. To find the probability, we need to divide the length of bg by the length of ak.
Let the length of bg be x and the length of ak be y. Then the probability that a point chosen at random will be on bg is:
Probability = Length of bg / Length of ak
Probability = x / y
However, we need to be careful here. If we choose a point anywhere on ak, it may not necessarily lie on bg. There are an infinite number of points on ak, but only one segment bg. Therefore, the probability we are looking for is actually the ratio of the lengths of bg to ak.
So, if we know the lengths of bg and ak, we can find the probability by dividing them. For example, if bg is 2 units long and ak is 10 units long, the probability of choosing a point on bg is:
Probability = 2 / 10
Probability = 0.2 or 20%
In this case, there is a 20% chance that the point chosen at random will lie on bg.
In conclusion, the probability of a point chosen at random on ak being on bg is directly proportional to the length of bg in relation to the length of ak. Therefore, we need to find the ratio of the lengths of the two line segments to determine the probability.
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what is the probability a point is chosen at random on ak and then the point will be on bg. dont forget to reduce the products?
Could you please solve this one.
The proof that the lines CD and XY are parallel is shown below in paragraghs
How to prove the lines CD and XY are parallelGiven that
∠CAY ≅ ∠XBD
This means that the angles CAY and XBD are congruent angles
The above means that
The angles ∠AYX & ∠ACD correspond to the angle ∠CAYThe angle ∠BXY & ∠BDC corresponds to the angle ∠XBDBy the corresponding angles, we have
∠BXY = ∠AYX
∠ACD = ∠BDC
By the congruent angles above, the following lines are parallel
Line AC and BX
Line AY and BD
Line CD and XY
Hence, the lines CD and XY are parallel
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The box plots show a random sample of wait times for two rides at a water park
The median wait time for Speed Slide is 2 minutes longer than the median wait time for Wave Machine and the IQR for both rides is 6 minutes.
Define the term box plot?A box plot, also known as a box and whisker plot, is a graphical representation of a data set that shows the distribution of the data along a number line.
In the box plots show a random sample of wait times for two rides at a water park is shown in figure.
If we compare the wait times in the box plots,
then for, Speed Slide: Median = 11
IQR= Q1 - Q3 (Calculation formula of IQR)
= 12 - 6
IQR = 6 minutes
for wave slide: median: 9
IQR= Q1 - Q3 (Calculation formula of IQR)
= 11 - 9
IQR = 2 minutes
The median wait time for Speed Slide is 2 minutes longer than the median wait time for Wave Machine and the IQR for both rides is 6 minutes.
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help I’ll give brainliest ^•^ just question (7) thanks!!
Answer:
To shift the graph of f(x) = |x| to have a domain of [-3, 6], we need to move the left endpoint from -6 to -3 and the right endpoint from 3 to 6.
A translation to the right by 3 units will move the left endpoint of the graph of f(x) to -3, but it will also shift the right endpoint to 6 + 3 = 9, which is outside the desired domain.
A translation to the left by 3 units will move the right endpoint of the graph of f(x) to 3 - 3 = 0, which is outside the desired domain.
A translation upward or downward will not change the domain of the graph, so options B and D can be eliminated.
Therefore, the correct answer is C g(x) = x - 3. This translation will move the left endpoint to -3 and the right endpoint to 6, which is exactly the desired domain.
Find the value of X using the picture below.
Answer:
x = 7
Step-by-step explanation:
The two angles are equal so the opposite sides are equal.
5x-2 =33
Add two to each side.
5x-2+2 = 33+2
5x=35
Divide by 5
5x/5 =35/5
x = 7
Let the Universal Set, S, have 158 elements. A and B are subsets of S. Set A contains 67 elements and Set B contains 65 elements. If Sets A and B have 9 elements in common, how many elements are in neither A nor B?
There are 92 elements in A but not in B.
What are sets?In mathematics, a set is a well-defined collection of objects or elements. Sets are denoted by uppercase symbols, and the number of elements in a finite set is denoted as the cardinality of the set enclosed in curly braces {…}.
Empty or zero quantity:
Items not included. example:
A = {} is a null set.
Finite sets:
The number is limited. example:
A = {1,2,3,4}
Infinite set:
There are myriad elements. example:
A = {x:
x is the set of all integers}
Same sentence:
Two sets with the same members. example:
A = {1,2,5} and B = {2,5,1}:
Set A = Set B
Subset:
A set 'A' is said to be a subset of B if every element of A is also an element of B. example:
If A={1,2} and B={1,2,3,4} then A ⊆ B
Universal set:
A set that consists of all the elements of other sets that exist in the Venn diagram. example:
A={1,2}, B={2,3}, where the universal set is U = {1,2,3}
n(A ∪ B) = n(A – B) + n(A ∩ B) + n(B – A)
Hence, There are 92 elements in A but not in B.
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A box contains ten cards labeled j, k, l, m, n, o, p, q, r, and s. One card will be randomly chosen. What is the probiability of choosing a letter from n to q
The probability of choosing a letter from n to q would be = 2/5
What is probability ?Probability is defined as the expression that is used to represent the possibility of an outcome of an event which can be solved with the formula = chosen events/ total outcomes.
The number of cards in the box = 10
The various cards are labelled as follows= j, k, l, m, n, o, p, q, r, and s.
The number of cards from n to q = 4
Therefore the probability that a number from n to q will be chosen = 4/10 = 2/5.
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Answer this imagine please
The expression that is not equivalent to the model shown is given as follows:
-4(3 + 2). -> Option C.
What are equivalent expressions?Equivalent expressions are mathematical expressions that have the same value, even though they may look different. In other words, two expressions are equivalent if they produce the same output for any input value.
The expression for this problem is given by three times the subtraction of four, plus three times the addition of 2, hence:
3(-4) + 3(2) = -12 + 6 = 3(-4 + 2) = 3(-2) = -6.
Hence the expression that is not equivalent is the expression given in option C, for which the result is given as follows:
-4(3 + 2) = -4 x 5 = -20.
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When expressions of the form (x −r)(x − s) are multiplied out, a quadratic polynomial is obtained. For instance, (x −2)(x −(−7))= (x −2)(x + 7) = x2 + 5x − 14.
a. What can be said about the coefficients of the polynomial obtained by multiplying out (x −r)(x − s) when both r and s are odd integers? when both r and s are even integers? when one of r and s is even and the other is odd?
b. It follows from part (a) that x2 − 1253x + 255 cannot be written as a product of two polynomials with integer coefficients. Explain why this is so.
a.(1) When both r and s are odd integers, the quadratic polynomial obtained by multiplying out (x - r)(x - s) will have a coefficient of 1 for x^2 term, and both the coefficient of x term and constant term will be odd integers.
(2) When both r and s are even integers, the polynomial obtained by multiplying out (x - r)(x - s) will also have a coefficient of 1 for x^2 term, but the coefficient of x term and constant term will be even integers.
(3) When one of r and s is even and the other is odd, the polynomial obtained by multiplying out (x - r)(x - s) will have a coefficient of 1 for x^2 term, the coefficient of x term will be an odd integer, while the constant term will be an even integer.
b. x^2 - 1253x + 255 cannot be written as a product of two polynomials with integer coefficients.
a. When both r and s are odd integers, the product (x − r)(x − s) will have a coefficient of 1 for x^2 term, and both the coefficient of x term and constant term will be odd integers. This is because the sum of two odd integers and the product of two odd integers is also an odd integer.
When both r and s are even integers, the product (x − r)(x − s) will also have a coefficient of 1 for x^2 term, but the coefficient of x term and constant term will be even integers. This is because the sum of two even integers and the product of two even integers is also an even integer.
When one of r and s is even and the other is odd, the product (x − r)(x − s) will have a coefficient of 1 for x^2 term, and the coefficient of x term will be an odd integer, while the constant term will be an even integer. This is because the sum of an odd and even integer is an odd integer, and the product of an odd and even integer is an even integer.
b. If x^2 - 1253x + 255 can be written as a product of two polynomials with integer coefficients, then we can write it as (x - r)(x - s) where r and s are integers. From part (a), we know that both r and s cannot be odd integers since the coefficient of x term would be odd, but 1253 is an odd integer. Similarly, both r and s cannot be even integers since the constant term would be even, but 255 is an odd integer. Therefore, one of r and s must be odd and the other must be even. However, the difference between an odd integer and an even integer is always odd, so the coefficient of x term in the product (x - r)(x - s) would be odd, which is not equal to the coefficient of x term in x^2 - 1253x + 255. Hence, x^2 - 1253x + 255 cannot be written as a product of two polynomials with integer coefficients.
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7.4y-2.9y
pls lmk....
4.5y
subtract 2.9y from 7.4y, and you get 4.5y
Given that a randomly chosen card from a standard deck of 52 cards is less
than 7, what is the probability it is the 5 of diamonds? Assume that aces are
low cards.
The probability that a randomly chosen card that is less than 7 is the 5 of diamonds is 5%.
How to Solve Probability?There are four suits in a standard deck of 52 cards: diamonds, clubs, hearts, and spades. Each suit has 13 cards, with ranks ranging from 2 (low) to 10, jack, queen, king, and ace (high).
If a randomly chosen card from the deck is less than 7, there are only two possibilities: it is either a 2, 3, 4, 5, or 6 of any suit, or it is the 5 of diamonds.
There are 20 cards that are less than 7 in the deck (4 cards of each of the 5 ranks). Out of these 20 cards, only one is the 5 of diamonds.
Therefore, the probability that a randomly chosen card that is less than 7 is the 5 of diamonds is:
1/20 = 0.05 = 5%
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The Venn diagram here shows the cardinality of each set. Use this to find the cardinality of the given set.
n(A)=
The cardinality of set A, n(A) = 29
What is cardinality of a set?The cardinality of a set is the total number of elements in the set
Given the Venn diagram here shows the cardinality of each set. To find the cardinality of set A, n(A), we proceed as follows.
Since the cardinality of a set is the total number of elements in the set, then cardinality of set A , n(A) = 9 + 8 + 3 + 9
= 29
So, n(A) = 29
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16.5% of an amount is 891. What is the original amount?
Answer:
Jika 16,5% dari suatu jumlah adalah 891, kita dapat menggunakan persamaan:
0,165x = 891
di mana x adalah jumlah aslinya. Kita ingin menyelesaikan persamaan ini untuk x.
Kita dapat memulai dengan membagi kedua sisi dengan 0,165:
x = 891 / 0,165
x = 5400
Jadi, jumlah aslinya adalah 5400.
Konsultasi Tugas Lainnya: WA 0813-7200-6413
SOMEONE HELP PLEASE!!!
Find P(C|Y) from the information in the table.
To the nearest tenth, what is the value of P(C|Y)?
A. 0.4
B. 0.5
C. 0.7
D. 0.8
Answer:
The answer to your problem is, B, 0.5
Step-by-step explanation:
We are given the following table below;
X Y Z Total
A 32 10 28 70
B 6 5 25 36
C 18 15 7 40
Total 56 30 60 146
As we know that the conditional probability formula of P(A/B) is given by:
P(A/B) = [tex]\frac{P(AnB)}{P(b)}[/tex]
P(C/Y) = [tex]\frac{P(CnY)}{P(Y)}[/tex]
P ( Y ) = [tex]\frac{30}{146}[/tex] and P(CnY) = [tex]\frac{15}{146}[/tex] [ because of the third column shown ]
Thus, the answer is, B. 0.5
Feel free to ask any questions down below \/ !
During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the machine recommends that the temperature of the machine part remain below 131°F. The temperature T in degrees Fahrenheit x minutes after the machine is put into operation is modeled by T=-0.005x^2+0.45x+125. Will the temperature of the part ever reach or exceed 131°F? Use the discriminant of a quadratic equation to decide.
answer options
1. No
2. Yes
From the discriminant of the give quadratic equation, the temperature of the machine will part after 50 minutes of operation.
Will the temperature of the part ever reach or exceed 135°F?The given equation that models the temperature of the machine is;
T = -0.005x² + 0.45x + 125
Let check if there's a value that exists for T = 135
Putting T = 135 in the given equation,
135 = -0.005x² + 0.45x + 125
We can simplify this to;
0.005x² - 0.45x + 10 = 0
From the general form of quadratic equation which is ax² + bx + c = 0, where a = 0.005, b = -0.45, and c = 10.
The discriminant of this quadratic equation is given by:
D = b² - 4ac
= (-0.45)² - 4(0.005)(10)
= 0.2025 - 0.2
= 0.0025
The discriminant of the equation is positive which indicates we have two roots. Therefore, the temperature of the machine part will cross 135°F at some point during the operation.
We can also find the roots of the quadratic equation using the formula:
[tex]x = (-b \± \sqrt(D)) / 2a[/tex]
Substituting the values of a, b, and D, we get:
[tex]x = (0.45 \± \sqrt(0.0025)) / 2(0.005)\\= (0.45 \± 0.05) / 0.01[/tex]
Taking the positive value, we get:
x = 50
Therefore, the temperature of the machine part will cross 135°F after 50 minutes of operation.
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exercise 2.4.3 in each case, solve the systems of equations by finding the inverse of the coefficient matrix.
The inverse of the coefficient matrix is A^-1 = [-2 2]. The solution to the system of equations is x = -1 and y = 1/5.
To solve the system of equations:
2x + 2y = 1
2x - 3y = 0
We can write this system in matrix form as:
[2 2] [x] [1]
[2 -3] [y] = [0]
The coefficient matrix is:
[2 2]
[2 -3]
To find the inverse of the coefficient matrix, we can use the following formula:
A^-1 = (1/|A|) adj(A)
where |A| is the determinant of A and adj(A) is the adjugate of A.
The determinant of the coefficient matrix is:
|A| = (2)(-3) - (2)(2) = -10
The adjugate of the coefficient matrix is:
adj(A) = [-3 2]
[-2 2]
Therefore, the inverse of the coefficient matrix is:
A^-1 = (1/-10) [-3 2]
[-2 2]
Multiplying both sides of the matrix equation by A^-1, we get:
[x] 1 [-3 2] [1]
[y] = -10 [-2 2] [0]
Simplifying the right-hand side, we get:
[x] [-1]
[y] = [1/5]
Therefore, the solution to the system of equations is:
x = -1
y = 1/5
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_____The given question is incomplete, the complete question is given below:
solve the systems of equations by finding the inverse of the coefficient matrix. a. 2x+2y=1 2x-3y-0
in one of his experiments conducted with animals, thorndike found that cats learned to escape from a puzzle box:
In one of his experiments conducted with animals, Thorndike found that cats learned to escape from a puzzle box is increased gradually
To quantify the learning process, Thorndike used a mathematical formula known as the Law of Effect equation. The equation is:
B = f(log S1/S2)
where B represents the strength of the behavior, S1 represents the satisfaction of the positive consequence, and S2 represents the degree of frustration or negative consequence.
In the context of Thorndike's puzzle box experiment, the Law of Effect equation can be used to describe how the cat's behavior changed over time as it learned to escape the puzzle box more quickly and efficiently. Initially, the cat's behavior was weak because it did not know which actions would lead to a positive outcome.
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Which graph represents the function f(x)=∣x+1∣−3?
By looking at the vertex of the graph, we can see that the fourth graph is the correct option.
Which graph represents the function f(x)=∣x+1∣−3?Here we want to see which one of the given graphs represents the given absolute value function.
Remember that for the absolute value function:
f(x) = |x - a| + b
Has a vertex at the point (a, b) and opens up.
Then in this particular case, with the function f(x)=∣x+1∣−3, the vertex will be at the point (-1, -3), so we just need to identify which one of the given graphs has that vertex, we can see that the correct option is the fourth option.
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Please help! 20 points
Order the simplification steps of the expression below using the properties of rational exponents.
Given: We have the expression [tex]\sqrt[3]{875x^5y^9}[/tex]
Step-1: [tex]\sqrt[3]{875x^5y^9}[/tex]
Step-2: [tex](875\times x^5 \times y)^{1/3}[/tex] [break the cube root as power [tex]1/3[/tex]]
Step-3: [tex](125.7)^{1/3}\times x^{5/3} \times y^{9/3}[/tex] [break [tex]875=125\times7[/tex]]
[tex]125=5^3[/tex]
Step-4: [tex](5^3)^{1/3}\times7^{1/3}\times x^{(1+2/3)}\times y^{9/3}[/tex] [ [tex]\frac{5}{3} =1+\frac{2}{3}[/tex] ]
Step-5: [tex]5^1\times7^{1/3}\times x^1\times x^{2/3}\times y^{3}[/tex] [break the power of [tex]x[/tex]]
Step-6: [tex]5\times x\times y^{3} \ (7^{1/3}\times x^{2/3})[/tex]
Step-7: [tex]5xy^3 \ (7x^2)^{1/3}[/tex]
Step-8: [tex]5xy^3\sqrt[3]{7x^2}[/tex]
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what is 8 x 1 ????????????
Answer:8
Step-by-step explanation:8x1=8
Bria is a customer who would like to display her collection of soap carvings on top of her bookcase. The collection needs an area of 300 square inches. What should b equal for the top of the bookcase to have the correct area? Round your answer to the nearest tenth of an inch. I need help
D: Please !!!!
Answer:
We can use the formula for the area of a rectangle to solve this problem. Let's assume that the length of the top of the bookcase is L and the width is b. Then, we can write:
L × b = 300
Solving for b, we get:
b = 300 / L
Since we don't know the length L, we cannot find the exact value of b. However, we can use the given information to make an estimate. Let's say that the length of the bookcase is 60 inches. Then, we have:
b = 300 / 60 = 5
So, if the length of the bookcase is 60 inches, the width needs to be at least 5 inches to accommodate Bria's soap carving collection. However, if the length is different, the required width will also be different.
francesca bought 27 keychains of two different kinds to make goodie bags for her birthday party. leather keychains were three dollars and beaded keychains for two dollars. she spent $73. how many keychains of each kind did she buy
Answer: Supergirl = 19 and Wonder Woman = 8
Step-by-step explanation:
Let g represent the quantity of Supergirl keychains and w represent the quantity of Wonder Woman keychains.
Qty Cost
Supergirl g $3g
Wonder Woman w $2w
Total 27 $73
Qty: g + w = 27 → -2(g + w = 27) → -2g - 2w = -54
Cost: 3g + 2w = 73 → 1(3g + 2w = 73) → 3g + 2w = 73
g = 19
Input g = 19 into one of the original equations to solve for w:
g + w = 27
(19) + w = 27
w = 8
I need help with this
The angles can be named with one letter are 2.
What is angles?Angles are a type of geometric shape which are formed when two straight lines intersect at a point. They are measured in degrees, usually between 0 and 360. Angles can be classified as acute, right, obtuse, straight and reflex, and the sum of any three angles in a triangle will always equal 180 degrees. Angles can be used in various ways, from providing stability in construction work to helping to identify other shapes. They can also be used to measure the size and shape of objects and to calculate distances and areas on maps. Angles are an important part of mathematics, geometry and trigonometry, and are used in a variety of applications in science and engineering.
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Match the definition:HistogramBinDescriptive StaticsMeanMedianModeStandard deviationA. The scatter around a central pointB. is a measure of a data’s variabilityC. is a graph of the frequency distribution of a set of dataD. values calculated from a data set and used to describe some basic characteristics of the data setE. a group in a histogramF. the middle value of a sorted set of dataG. is the most commonly occurring value in a data set
The matches of Histogram, Bin, Descriptive Statistics, Mean, Median and Standard Deviation are C, E, D, A, F, G and B respectively.
The Match the definition are given.
Histogram - C). is a graph of the frequency distribution of a set of data
Bin - E). a group in a histogram
Descriptive Statistics - D). values calculated from a data set and used to describe some basic characteristics of the data set
Mean - A). The scatter around a central point
Median - F). the middle value of a sorted set of data
Mode - G). is the most commonly occurring value in a data set
Standard Deviation - B). is a measure of a data’s variability
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Locate the absolute extrema of the function on the closed interval
Answer:
The absolute extrema is minimum at (-1, 2/9)
Step-by-step explanation:
Absolute extrema is a logical point that shows whether a the curve function is maximum or minimum.
Forexample a curve in the image attached. A, B and C are points of absolute maxima or absolute maximum. and P and Q are points of absolute minima or minimum.
Remember A, B, C, P, Q are critical points or stationary points.
How do we find absolute extrema?
The find the sign of the second derivative of the function.
From the question;
[tex]{ \sf{g(x) = \sqrt[3]{x} }} \\ \\ { \sf{g(x) = {x}^{ \frac{1}{3} } }} \\ [/tex]
Find the first derivative of g(x)
[tex]{ \sf{g {}^{l}(x) = \frac{1}{3} {x}^{ - \frac{2}{3} } }} \\ [/tex]
Find the second derivative;
[tex]{ \sf{g {}^{ll} (x) = ( \frac{1}{3} \times - \frac{2}{3}) {x}^{( - \frac{2}{3} - 1) } }} \\ \\ { \sf{g {ll}^{(x)} = - \frac{2}{9} {x}^{ - \frac{5}{3} } }}[/tex]
Then substitute for x as -1 from [-1, 1]
[tex]{ \sf{g {}^{ll}(x) = - \frac{2}{9} ( - 1) {}^{ - \frac{5}{3} } }} \\ \\ = \frac{ - 2}{9} \times - 1 \\ \\ = \frac{2}{9} [/tex]
Since the sign of the result is positive, the absolute extrema is minimum
The five-number summary of a data set is given below.
Minimum: 3 Q1: 12 Median: 15 Q3: 16 Maximum: 20
Which of the following equals 1.5(IQR)?
The required value is 1.5(IQR) equals 6.
What is Data set?A dataset is a collection of facts that relates to a particular subject. The test results of each pupil in a particular class are an illustration of a dataset. Datasets can be expressed as a table, a collection of integers in a random sequence, or by enclosing them in curly brackets.
According to question:The IQR (interquartile range) is the difference between the third quartile (Q3) and the first quartile (Q1). So, we first need to calculate IQR:
IQR = Q3 - Q1 = 16 - 12 = 4
Now we can calculate 1.5 times the IQR:
1.5(IQR) = 1.5(4) = 6
Therefore, 1.5(IQR) equals 6.
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Complete question:
The five-number summary of a data set is given below.
Minimum: 3 Q1: 12 Median: 15 Q3: 16 Maximum: 20
Which of the following equals 1.5(IQR)?
Can someone please help with these 4
Answer:
Step-by-step explanation:
1) b (acute is less than 90)
2) a (obtuse: more than 90, less than 180)
3) c
4) c
Answer:
1. NOM, JOK, KOL
2. MOL, NOK, MOJ
3. NOJ, JOL
4. NOL, MOK
Given that x + 1/2 = 5, what is 2*x^2 - 3x + 6 - 3/x +2/x^2
pls help me soon
Sure, let's solve this step-by-step:
First, we need to solve for x in the equation x + 1/2 = 5.
We can do this by subtracting 1/2 from both sides, giving us x = 4 1/2.
Now, we can substitute x = 4 1/2 into the equation 2*x^2 - 3x + 6 - 3/x +2/x^2.
We can simplify the equation by multiplying both sides by x^2, giving us:
2*x^2 - 3x + 6 - 3/x +2 = 10*x^2 - 3x + 6.
Now, we can combine all of the terms with x:
10*x^2 - 6x + 6 = 0.
Finally, we can solve the equation using the quadratic formula:
x = 3/5 or x = 2.
Therefore, the answer to the equation is 10*(3/5)^2 - 6(3/5) + 6 = 4.8, or 10*2^2 - 6(2) + 6 = 16.
Mia has a collection of vintage action figures that is worth $190. If the collection appreciates at a rate of 6% per year, which equation represents the value of the collection after 5 years?
The equation that represents the value of the collection after 5 years is:
Value of collection after 5 years = 190 x (1 + 0.06)^5
Explanation:
To calculate the value of the collection after 5 years, we need to use the compound interest formula. This formula is represented as A = P x (1 + r)^n, where P is the principal amount (initial value of the collection), r is the rate of interest (in this case, 6%), and n is the number of years (in this case, 5).
Therefore, the equation for the value of the collection after 5 years is:
Value of collection after 5 years = 190 x (1 + 0.06)^5
This can also be written as:
Value of collection after 5 years = 190 x 1.31 (1.31 is the result of (1 + 0.06)^5)
Therefore, the value of the collection after 5 years is $246.90.
Answer: 254.26
Step-by-step explanation:
Write an equation in slope-intercept form for the line that passes through (3,-10) and (6,5).
Answer:
The slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula:
m = (y2 - y1) / (x2 - x1)
Substituting the values, we get:
m = (5 - (-10)) / (6 - 3) = 15/3 = 5
Now that we have the slope, we can use the point-slope form of a linear equation to write the equation of the line:
y - y1 = m(x - x1)
Substituting the values of m, x1, and y1, we get:
y - (-10) = 5(x - 3)
Simplifying and rearranging the equation, we get:
y + 10 = 5x - 15
y = 5x - 25
Therefore, the equation of the line passing through (3,-10) and (6,5) in slope-intercept form is y = 5x - 25.
Step-by-step explanation:
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