5. How is a cell wall different from a cell membrane?

Answers

Answer 1
Cell membrane is present is all cells while cell wall is only present in plants, bacteria, fungi and algae. ... Cell wall is made up of cellulose whereas cell membrane is made up of lipids and proteins.

Related Questions

what is the type of bonding for ammonium lauryl sulfate?

Answers

Answer:

Hydrogen bonding.

Explanation:

Ammonium lauryl sulfate is also known as ammonium dodecyl sulfate there are two parts in Ammonium lauryl sulfate one is nonpolar hydrocarbon and other part polar sulfate group.

Due to polarity of sulfate group its form hydrogen bond very easily.

It is mainly used as foaming agent the main reason of its use is very much soluble in water and making hydrogen bond with water.

A reaction starts with 20.0 grams of lithium hydroxide (LiOH) and produces 31.0 grams of lithium chloride (LiCl), what is the percent yield of lithium chloride (LiCl)? *
LiOH + KCl - LiCl + KOH

A) 64.5%
B) 88.6%
C) 81.5%
D) 92.8%

Answers

Answer:

B) 88.6%

Explanation:

Percent yield equals actual yield divided by theoretical yield

actual yield is 31.0g

theoretical yield is 35g

percent yield was 88.57 which rounds up to 88.6%

Which is the control center for the endrocrine system?

Answers

Answer:

hypothalamus

Explanation:

Which statement describes a gas condensing into a liquid?
A.
The atoms in the molecules get heavier so they move less.
B.
The molecules break into smaller pieces that take up less space.
C.
The molecules stick together to make bigger molecules.
D.
The molecules get closer together and move more slowly.

Answers

Answer: molecules get closer

Explanation:

Condensation is the process in which molecules of a gas slow down, come together, and form a liquid. When gas molecules transfer their energy to something cooler, they slow down and their attractions cause them to bond to become a liquid

hope this helps

pls mark me brainliest

Answer:

D. The molecules get closer together and move more slowly.

How many moles are in 100g of carbon dioxide?
A.2.27 mol
B.3.51 mol
C. 2.36 mol
D. 1.49 mol

Answers

Answer:

A

Explanation:

First, let's find the molar mass of CO₂. This is 12 + 2(16) = 44 g/mole.

Now we can write 100g * (1 mole / 44g) = 2.27 mol, or A. Hope this helps!

what is the molarity of 2.3 mol of Kl dissolved in 0.5 L of water

Answers

Answer:

[tex]4.6\,\,moL\,\,L^{-1}[/tex]

Explanation:

Molarity refers to a measure of concentration.

Molarity = moles of solute/Litres of solution

Molarity refers to number of moles of solute present in this solution.

In order to find a solution's molarity, use value for the number of moles of solute  and the total volume of the solution expressed in liters

As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,

Molarity = [tex]\frac{2.3}{0.5} =4.6\,\,moL\,\,L^{-1}[/tex]

Gas Laws
Assignment Active
Applying Gas Laws to Aerosol Can D
(国座
Explain why it is not a good idea to throw an
aerosol can into a fire. Which gas law applies?
DONE​

Answers

Answer:

Ideal Gas Law

PV = nRT

Explanation:

Pressure is proportional to temperature;

The heat of the fire would cause increased pressure inside the closed aerosol vessel, eventually resulting in explosion of the vessel, once the temperature rises enough.

50 POINTS!!!

Calculate the Pressure in atmospheres of 0.5 mol of helium (He) at 20 degrees celcius and occupying 2.50 L. Show all work.

Answers

Answer:

Pressure = 4.81atm

Explanation:

Pressure = ?

Temperature = 20°C = (20 + 273.15)K = 293.15K

Volume = 2.50L

R = 0.082J/mol.K

n = 0.5mol

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles of the gas

R = ideal gas constant and may varies due to unit of pressure and volume

T = temperature of the ideal gas

PV = nRT

Solve for P,

P = nRT/ V

P = (0.5 * 0.082 * 293.15) / 2.50

P = 12.01915 / 2.50

P = 4.807atm

P = 4.81atm

The pressure of the ideal gas is 4.81atm

calculate the density of a solid that has a volume of 2cm3 and a mass of 3g

Answers

Answer:

The density is 6

Explanation:

p = m × v

p = 3 × 2

p = 6

Hope this helped! :)

The density of the substance depends on the mass and the volume of the substance or object. It is given by the ratio of mass and volume. The density of 3 gm solid is 1.5 g/cm³.

What is density?

In chemistry and physics, density is a quantitative measurement that tells about the tightness of the substance packed in an area. It relates to two parameters that include mass and volume.

The density can be said to have a proportion of mass to the volume of the substance. The mass can be in grams or kilograms, while volume can be in a liter, cubic meter, and cubic centimeter.

Given,

Mass of solid (M) = 3 gm

The volume of solid (V) = 2 cm³

Density (ρ) is calculated as:

ρ = M ÷ V

= 3 ÷ 2

= 1.5 gm/cm³

Therefore, 1.5 gm/cm³ is the density of 3 gm solid.

Learn more about density here:

https://brainly.com/question/19642139

#SPJ2

How many copper atoms are in a 70g copper

Answers

Answer:

[tex]x = 6.634\times 10^{23}\,atoms[/tex]

Explanation:

The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:

[tex]x = \left(\frac{70\,g}{63.546\,\frac{g}{mol}} \right)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)[/tex]

[tex]x = 6.634\times 10^{23}\,atoms[/tex]

Answer:

6.64x10^23 atoms.

Explanation:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.

1 mole of Cu = 63.5g

If 63.5g of Cu contains 6.02x10^23 atoms,

Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.

Therefore, there are 6.64x10^23 atoms in 70g oh Cu

What conclusion can you draw from the heating curve?

Answers

Answer:A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.

Particles of the substance have the most kinetic energy when the substance is(a)_______. The part of the graph that represents where the substance has the least amount of potential energy is labeled(b)_______.


multiple choice answers available.
(a)
1. A gas
2. A solid
3. Melting
4. vaporizing

(b)
1. Solid
2. Vaporizing
3. melting
4.liquid
5.gas

Answers

Answer: 1- gas 2- solid

Explanation:

PLEASE HELP
Consider the chemical equations shown here.

3 equations. 1: upper N upper O gas plus upper O subscript 3 gas right arrow upper N upper O subscript 2 gas plus upper O subscript 2 gas. Delta H subscript 1 equals 198.9 kilojoules. 2: StartFraction 3 over 2 EndFraction upper O gas right arrow upper O subscript 3 gas. Delta H subscript 2 equals 142.3 kilojoules. 3: upper O gas right arrow one half upper O subscript 2 gas. Delta H subscript 3 equals negative 247.5 kilojoules.



What is DeltaHrxn for the reaction shown below?


NO(g)+O(g)->NO2(g)

Answers

Answer:

-304.1

I had this question and that’s what I got

Answer:

-867.7

Explanation:

yeah

All chemicals pollute the environment.
True
False​

Answers

Answer:

False,not all chemicals pollute the enviorment

Explanation:

Hope this helps!

Brainliest?

Answer:

False

Explanation:

Oxygen?

Which statements describe gridlines on a map? Select three options. They are measured in degrees. They set up a reference system. They make straight lines on a globe. They run north to west and south to east. They divide Earth into four equal parts.

Answers

Answer:

The options that apply to the description of grid-lines of the map are;

They are measured in degrees

They set up a reference system

They divide Earth into four equal parts

FIRST OPTION , SECOND OPTION and FIFTH OPTION are correct.

Explanation:

FIRST OPTION gave the describtion that the grid-lines of the map are measure in degrees,this option is applied to the gridlines on a map because the grid are lined as a result of angular measurement which makes it to makes the unit to be measured degrees and angles.

SECOND OPTION described it as been set up by a reference system which let us know that the area that are plotted were all grid as a result of the size

FIFTH OPTION also applied to the

description of the gridlines on a map because the Earth is divided into 4 equal parts through the Prime Meridian i.e the latitudinal line and longitudinal line .

.

Answer:

They are measured in degrees.

They set up a reference system.

They divide Earth into four equal parts.

Explanation:

i took the test

Have scientists found any reliable predictors for earthquakes, like radon gas release or weird animal behavior?

Answers

Answer:

The "Parkfield earthquake prediction experiment" was the most heralded scientific earthquake prediction ever. It was based on an observation that the Parkfield segment of the San Andreas Fault breaks regularly with a moderate earthquake of about M 6 every several decades: 1857, 1881, 1901, 1922, 1934, and 1966.

Explanation:

this is the best I could come up with. luv u.

What mass of sulfuric acid (H2SO4) is contained in 50.00 mL of a 5.85 M solution? grams

Answers

Answer:

28.69 grams

Explanation:

To find the mass, we first need to find the moles. Once we have the moles, it is easy to use the molar mass of H2SO4 to find its mass.

To find the moles, remember that molarity (M) is equal to the moles divided by the volume (L). The volume HAS TO be converted to liters!

M = moles / V

5.85 M = moles / 0.05 L

moles = 0.2925

Now we know that we have 0.2925 moles of sulfuric acid. The molar mass of sulfuric acid is 98.08 g/mol.

0.2925 moles * (98.08 g / mol) = 28.69 grams

Make sense? If you have any questions, don't hesitate to ask!

En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L alcancen el equilibrio a 150°C. ¿Cuáles son las presiones parciales de equilibrio de IBr, I2 y Br2?

Answers

Answer:

P IBr: 15.454atm

I₂: 0.923 atm

P Br₂: 0.923atm

Explanation:

Basados en la reacción:

I₂(g) + Br₂(g) ⇄ 2 IBr(g)

La constante de equilibrio, Keq, es definida como:

[tex]Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}[/tex]

Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio

Usando PV = nRT, la presión inicial de IBr es:

P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = 17.3 atm

Siendo las presiones en equilibrio:

P IBr: 17.3 - 2X

P I₂: X

P Br₂: X

Donde X representa el avance de reacción.

Remplazando en Keq:

280 = (17.3 - 2X)² / X²

280X² = 4X² - 69.2X + 299.29

0 = -276X² - 69.2X + 299.29

Resolviendo para X:

X = -1.174 → Solución falsa. No existen presiones negativas

X = 0.923 → Solución real

Así, las presiones parciales en equilibrio de cada compuesto son:

P IBr: 17.3 - 2X = 15.454atm

P I₂: X = 0.923atm

P Br₂: X = 0.923atm

Answer:

[tex]p_{I_2}=0.926atm\\p_{Br_2}=0.926atm\\p_{IBr}=15.5atm[/tex]

Explanation:

Hello,

In this case, given the initial load of 0.500 mol of IBr in the 1.00-L, we compute its initial concentration:

[tex][IBr]_0=\frac{0.500mol}{1.00L}=0.500M[/tex]

Hence, by knowing the original reaction, we should invert it as IBr will produce iodine and bromine considering the initial load:

[tex]2IBr(g)\rightleftharpoons I_2(g) + Br_2(g)[/tex]

Therefore, the equilibrium constant should be inverted:

[tex]K'=\frac{1}{Keq}=\frac{1}{280}=3.57x10^{-3}[/tex]

So we write the law of mass action:

[tex]K'=\frac{[I_2][Br_2]}{[IBr]^2}[/tex]

That in terms of the change [tex]x[/tex] due to the reaction extent turns out:[tex]3.57x10^{-3}=\frac{(x)(x)}{(0.500-2x)^2}[/tex]

In such a way, solving by using solver or quadratic equation we obtain:

[tex]x_1=-0.0339M\\x_2=0.0267M[/tex]

Clearly, the solution is 0.0267M, thus, the equilibrium concentrations are:

[tex][I_2]=x=0.0267M[/tex]

[tex][Br_2]=x=0.0267M[/tex]

[tex][IBr]=0.5M-2x=0.5M-2*0.0267M=0.447M[/tex]

Thus, with the given temperature (150+273.15=423.15K), we compute the partial pressures by using the ideal gas equation:

[tex]p_{I_2}=[I_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{I_2}=0.926atm\\\\p_{Br_2}=[Br_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{Br_2}=0.926atm\\\\p_{IBr}=[IBr]RT=0.447\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{IBr}=15.5atm[/tex]

Best regards.

Which is the best example of the use of imagery in a sentence?

Answers

Sound-The concert was so loud that her ears rang for days afterward. Sight The sunset was the most gorgeous they'd ever seen the clouds were edged with pink and gold. Smell.After eating the curry, his breath reeked of garlic. Touch: The tree bark was rough against her skin.

Answer:

Explanation: As the good witch Azura said when she was in the bog of immediate regret I challenge you to a witches duel.

im sorry if that was bad i got nothing lol

also took it from The Owl House

how many number of electrons are in nitrogen and aluminium in their ionic States?​

Answers

If you look at the periodic table you’ll noticed a trend. Group one, sometimes called 1A, has hydrogen in it, it’s group (column) has a positive charge. The group (column) next to it Group 2 sometimes called 2A has twice the charge as group 1. Then you skip the transition metals, and then land on group (column) 13. These guys have a charge of +3 typically. Then you have group 14, sometimes called 4A, and it’s weird and it kind of breaks with this trend. Then you have group (column) 15 next to it, sometime called 5A, which now starts to count down in charge, it has a charge of -3.

And each group (column) after that countdown to zero charge, once you have zero charge you know that you’re in the noble gases.

So, nitrogen in group (column) 15, also know as column 5A. This column has for the most part a charge of -3.

Aluminum is in group (column) 13, they have a charge of +3 typically.


I hope that helps.

What is frequency and what unit is it measured in?

Answers

Answer: The rate at which a vibration occurs that constitutes a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light), usually measured per second. Also it is measured in Hertz.

Explanation:

Answer frequency is the number of occurrences of a repeating event per unit of time. Frequency is measured in Hertz. Unit frequency is measured as the number of wave cycles that occur in one second.

The unit of frequency measurement is hertz

Explanation:

A group of tissues working together is?

Answers

Answer:

An organ

Explanation:

An organ is one or more tissues that work together to form a specific function.

- Hope that helps! Please let me know if you need further explanation.

C2H6O(g) + 3O2(g) 2CO2(g) + 3H2O(g) Inside the piston of an automobile engine, 0.461 g of ethanol (C2H6O) gas reacts with 0.640 grams of oxygen gas to produce carbon dioxide and water, according to the balanced equation shown above. What is the limiting reagent?

Answers

Answer:

Oxygen is the limiting reactant.

Explanation:

Hello,

In this case, given the reaction:

[tex]C_2H_6O(g) + 3O_2(g)\rightarrow 2CO_2(g) + 3H_2O(g)[/tex]

Hence, given the masses of both ethanol and oxygen, we are able to compute the available moles ethanol by:

[tex]n_{C_2H_6O}^{available}=0.461g*\frac{1mol}{46g}=0.01mol C_2H_6O[/tex]

Next, we compute the moles of ethanol that react with the 0.640 grams of oxygen considering their 1:3 molar ratio in the chemical reaction:

[tex]n_{C_2H_6O}^{consumed\ by\ O_2}=0.64gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6O}{3molO_2} =0.0067molC_2H_6O[/tex]

In such a way, since there are 0.01 available moles of ethanol but just 0.0067 moles are reacting, we evidence ethanol is in excess, therefore the oxygen is the limiting reactant.

Best regards.

Answer:

Oxygen O₂ will be the limiting reagent.

Explanation:

C₂H₆O(g) + 3 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(g)

First of all you must know by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction) how much mass of each compound reacts. First of all, being:

C: 12 g/moleH: 1 g/moleO: 16 g/mole

the molar mass of each reagent is:

C₂H₆O: 2*12 g/mole + 6* 1 g/mole + 16 g/mole= 46 g/moleO₂: 2*16 g/mole= 32 g/mole

Then, since 1 mol of C₂H₆O and 3 moles of O₂ react by stoichiometry, the amount of mass that reacts is:

C₂H₆O: 1 mole* 46 g/mole= 46 gO₂: 3* 32 g/mole= 96 g

Now you apply a rule of three as follows: if 46 g of C₂H₆O reacts with 96 g of O₂ by stoichiometry, 0.461 g of C₂H₆O with how much mass of O₂ will they react?

[tex]mass of O_{2} =\frac{0.461 grams of C_{2}H_{6} O*96 grams ofO_{2} }{46 grams of C_{2}H_{6} O}[/tex]

mass of O₂= 0.962 grams

But 0.962 grams of O₂ are not available, 0.640 grams are available. Since you have less mass than you need to react with 0.461 g of C₂H₆O, oxygen O₂ will be the limiting reagent.

A 0.80 L sample of gas has a temperature of 27°C and a pressure of 0.925 atm. How many moles of gas are present?

Answers

Answer:

n= 0.03 moles

Explanation:

Using the ideal gas law:

PV=nRT

nRT=PV

n= PV/RT

 n: moles

 P: pressure in atm

 V= volume in L

 R= Avogadro's constant = 0.0821

 T= Temperature in K => ºC+273.15

n= (0.925 atm)(0.80 L) / (0.0821)(300.15 K)

n= 0.03 moles

Give the molecular geometry and number of electron groups for sf4. give the molecular geometry and number of electron groups for . square planar, 6 electron groups square pyramidal, 6 electron groups t-shaped, 5 electron groups octahedral, 6 electron groups seesaw, 5 electron groups

Answers

Answer:

5 electron groups, see saw

Explanation:

During the formation of SF4, the sulfur atom usually bonds with each of four fluorine atoms where 8 of valence electrons are used. The four fluorine atoms have 3 lone pairs of electrons in its octet which will further utilize 24 valence electrons. In addition, two electrons are present as a lone pair on the sulfur atom. We can determine sulfur’s hybridization state by counting of the number of regions of electron density on sulphur (the central atom in the molecule). When bonding takes place there is a formation of 4 single bonds to sulfur and it has 1 lone pair. Looking at this, we can say that the number of regions of electron density is 5. The hybridization state is sp3d.

SF4 molecular geometry is seesaw with one pair of valence electrons. The molecule is polar. The equatorial fluorine atoms have 102° bond angles instead of the actual 120° angle. The axial fluorine atom angle is 173° instead of the actual 180° bond angle.

Zinc reacts with iodine in a synthesis reaction: Zn + I2 → Znl2. What is the theoretical yield of Znl2, if 1.912 mol of zinc is used?

Answers

Answer:

610.3g

Explanation:

Zn:

m = 1.912

Zn : ZnI₂

1 : 1

1.912 : 1.912

ZnI₂:

m = 1.912  Mr = 65.4 + 2(126.9) = 319.2

mass = m×Mr:

mass = 1.912×319.2

mass = 610.3104 → 610.3g

The theoretical yield of Znl2, if 1.912 mol of zinc is used is 610.3g

Calculation of  theoretical yield:

Since Zinc reacts with iodine in a synthesis reaction: Zn + I2 → Znl2

And, there is 1.912 mol of zinc

So,

Zn : ZnI₂

1 : 1

And,

1.912 : 1.912

For

ZnI₂:

m = 1.912  Mr = 65.4 + 2(126.9) = 319.2

Now

mass = m×Mr:

= 1.912×319.2

= 610.3104

= 610.3g

Learn more about zinc here: https://brainly.com/question/14570683

HELP PLZZZ !!!!!!!!!!!!

Answers

Answer:

1/ 421.2 g KNO3

2/ 66.6 g  S

3/ 275.0 g CO2

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Calculate the hyrdrogen ion concentration [h+] for the aquesous solution in which [oh-] is 1 x 10-2 mol/l.Is the solution acidic,basic,or neutral? Show your work

Answers

Answer:

- [tex][H^+]=1x10^{-12}[/tex]

- Basic.

Explanation:

Hello,

In this case, given the concentration of hydroxyl ions, one could compute the pOH as shown below:

[tex]pOH=-log([OH^-])=pOH=-log(1x10^{-2})=2[/tex]

Then, since the pOH and the pH are related by:

[tex]pH+pOH=14[/tex]

One computes the pH:

[tex]pH=14-pOH=14-2=12[/tex]

Now, we compute the concentration of hydronium by:

[tex][H^+]=10^{-pH}=10^{-12}[/tex]

[tex][H^+]=1x10^{-12}[/tex]

Finally, since the pH is greater than 7 (neutral point) we conclude that the solution is basic.

Best regards.

Answer:

A. Hydrogen ion concentration, [H+] is 1x10^–12 mol/L

B. Since the pH is 12, the solution is basic.

Explanation:

Data obtained from the question. This includes the following:

Concentration of Hydroxide ion, [OH-] = 1x10^–2 mol/L

Concentration of Hydrogen ion, [H+] =.?

pH =..?

A. Determination of the hydrogen ion concentration, [H+] .

The hydrogen ion concentration, [H+] can be obtained as follow:

[H+] x [OH-] = 1x10^–14

[OH-] = 1x10^–2

[H+] x 1x10^–2 = 1x10^–14

Divide both side by 1x10^–2

[H+] = 1x10^–14 / 1x10^–2

[H+] = 1x10^–12 mol/L

B. Determination of the pH of the solution.

The pH of the solution can be obtained as follow:

pH = –Log [H+]

[H+] = 1x10^–12 mol/L

pH = –Log 1x10^–12

pH = 12.

Then pH of a solution ranges between 0 and 14.

A pH reading between 0 and 6 is termed an acidic solution, a pH reading of 7 is termed a neutral solution and a pH reading between 8 and 14 indicates an alkaline or a basic solution.

The higher the pH value, the more alkaline or basic the solution becomes.

Since the pH is 12, the solution is basic.

Assuming a car (with a 70-L) gas tank can hold approximately 50,000 (5.00 * 10^4) g of octane(C8H18) or 50,000 (5.00 * 10^4) g of ethanol (C2H6O). How much carbon dioxide (CO2), in grams, is produced in one tank of gas from the combustion of each amount?

Answers

Answer:

- From octane: [tex]m_{CO_2}=1.54x10^5gCO_2[/tex]

- From ethanol: [tex]m_{CO_2}=9.57x10^4gCO_2[/tex]

Explanation:

Hello,

At first, for the combustion of octane, the following chemical reaction is carried out:

[tex]C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O[/tex]

Thus, the produced mass of carbon dioxide is:

[tex]m_{CO_2}=5.00x10^4gC_8H_{18}*\frac{1molC_8H_{18}}{114gC_8H_{18}}*\frac{8molCO_2}{1molC_8H_{18}}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=1.54x10^5gCO_2[/tex]

Now, for ethanol:

[tex]C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O[/tex]

[tex]m_{CO_2}=5.00x10^4gC_2H_6O*\frac{1molC_2H_6O}{46gC_2H_6O}*\frac{2molCO_2}{1molC_2H_6O}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=9.57x10^4gCO_2[/tex]

Best regards.

Molecules have Question 1 options: A) both potential and kinetic energy. B) neither kinetic nor potential energy. C) only kinetic energy. D) only potential energy.

Answers

Answer:A

Explanation:

Answer: A

Explanation:

Other Questions
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