At an airport, two business partners both walk at 1.5 m/sm/s from the gate to the main terminal, one on a moving sidewalk and the other on the floor next to it. The partner on the moving sidewalk gets to the end in 60 ss, and the partner on the floor reaches the end of the sidewalk in 90s.

Required:
What is the speed of the sidewalk in the Earth reference frame?

Answers

Answer 1

Answer:

[tex]v=0.8m/s[/tex]

Explanation:

From the question we are told that

Distance [tex]d=1.5m/sm/s[/tex]

Time  [tex]t_1=60s[/tex]  

Time  [tex]t_2=90s[/tex]  

Generally the  the equation for the distance traveled is mathematically given as

[tex]d=vt[/tex]

[tex]d=1.5*90[/tex]

[tex]d=138m[/tex]

Generally equation for speed of side walk is mathematically given as

[tex]d=(v+u)t[/tex]

[tex]v=\frac{d}{t}-u[/tex]

[tex]v=\frac{138}{60}-1.5[/tex]

[tex]v=0.8m/s[/tex]


Related Questions

A long, straight wire carries a current of 5.20 A. An electron is traveling in the vicinity of the wire. At the instant when the electron is 4.40 cm from the wire and traveling at a speed of 6.20 * 104 m>s directly toward the wire, what are the magnitude and direction (relative to the direction of the current) of the force that the magnetic field of the current exerts on the electron

Answers

Answer:

Explanation:

Magnetic field due to current at a distance of 4.4 cm

B = 10⁻⁷ x 2 x 5.2 / 4.4 x 10⁻²           [ B = 10⁻⁷ x 2i / r = ]

= 2.36 x 10⁻⁵ T.

Force on moving electron = Bqv , B is magnetic field , q is charge and v is velocity of charge .

Force = 2.36 x 10⁻⁵  x 1.6 x 10⁻¹⁹ x 6.2 x 10⁴

= 23.41 x 10⁻²⁰ N .

This force will be perpendicular to the direction of current .

Which of the following is a vector quantity?
speed
distance
acceleration

Answers

c) Acceleration
For example, if person A is the observer, then he/she can predict the distance or speed or time by simply looking at it. But at the same time, the observer can't predict the acceleration of a moving object as he/she can't determine the direction of the object. So, without a direction, the acceleration can't be predicted. For example, displacement, force, velocity, momentum, etc. are vector quantities.
◙ But, Distance, speed and time are only specified with their magnitude. For example, work, volume, density, mass, etc. don't need a direction for their representation.
So, (c)Acceleration is the answer.

A sprinter starts from rest and accelerated at a rate of 0.16 m/s over a distance of 50.0 meters. How fast is the athletes traveling at the end of the 50.0 meters?

Answers

Answer:

40m/s

Explanation:

v²=u²+2as

v²=0²+2(16)(50)

v²=160v=40m/s

A solid sphere of radius R = 5 cm is made of non-conducting material and carries a total negative charge Q = -12 C. The charge is uniformly distributed throughout the interior of the sphere.

What is the magnitude of the electric potential V at a distance r = 30 cm from the center of the sphere, given that the potential is zero at r = [infinity] ?

Answers

Answer:

V= -3.6*10⁻¹¹ V

Explanation:

Since the charge is uniformly distributed, outside the sphere, the electric field is radial (due to symmetry), so applying Gauss' Law to a spherical surface at r= 30 cm, we can write the following expression:

      [tex]E* A = \frac{Q}{\epsilon_{0} } (1)[/tex]

At r= 0.3 m the spherical surface can be written as follows:

       [tex]A = 4*\pi *r^{2} = 4*\pi *(0.3m)^{2} (2)[/tex]

Replacing (2) in (1) and solving for E, we have:

      [tex]E = \frac{Q}{4*\pi *\epsilon_{0}*r^{2} } = \frac{(9e9N*m2/C2)*(-12C)}{(0.3m)^{2} y} (3)[/tex]

Since V is the work done on the charge by the field, per unit charge, in this case, V is simply:V = E. r (4)Replacing (3) in (4), we get:

       [tex]V =E*r = E*(0.3m) = \frac{(9e9N*m2/C2)*(-12C)}{(0.3m)} = -3.6e11 V (5)[/tex]

V = -3.6*10¹¹ Volts.

The electrical potential module will be [tex]-3.6*10^-^1^1 V[/tex]

We can arrive at this answer as follows:

To answer this, we owe Gauss's law. This is because the charge is evenly distributed across the sphere. This will be done as follows:

[tex]E*A=\frac{Q}{^E0} \\\\\\A=4*\pi*r^2[/tex]

Solving these equations will have:

[tex]E=\frac{Q}{4*\pi*^E0*r^2} \\E= \frac{(9e9N*m2/c2)*(-12C)}{(0.3m)^2y}[/tex]

As we can see, the electric potential is carried out on the field charge. In this case, using the previous equations, we can calculate the value of V as follows:

[tex]V=E*r\\V=E*0.3m= \frac{(9e9N*m^2/C2)*(-12C)}{0.3m} \\V= -3.6*10^-^1^1 V.[/tex]

More information about Gauss' law at the link:

https://brainly.com/question/14705081

A person pushes down on a lever with a force of 100 N. At the other end of the lever, a force of 200 N lifts a heavy object. What is the mechanical advantage of the lever?

A. 1/2, because the object will be lifted half the distance
B. -1, because the direction changes
C. 2, because the output force is twice the input force
D. 1, because the same amount of work is done​

Answers

Answer:

Explanation:

C 200÷100=2

Output ÷ Input= MA

As waves crash into rock along the shoreline, particles of sand, shell, and other materials in the ocean water loosen tiny bits of sediment from the rock. As the waves recede, they carry the sediment away. In this scenario, which process represents weathering, and which process represents erosion?

Answers

Answer:

WEATHERING is represented by the scenario (As waves crash into rock along the shoreline, particles of sand, shell, and other materials in the ocean water loosen tiny bits of sediment from the rock).

Erosion is represented by the scenario (As the waves recede, they carry the sediment away).

Explanation:

A wave is a disturbance which travels through a medium and transfers energy from one point to another. When wind blows over a water body like the ocean, ocean waves are formed. As the generated energy from the wind is transported through the water by the waves, the can hit against rocks on the shores leading to its break down with time. WEATHERING occurs when tiny bit of sediments from rocks are loosened due to the impact of ocean waves.

Erosion can be described as the wearing away of the earth's surface due to the impact of wind, rainfall ( water) or waves. There are different types of erosion which is classified according it's cause of formation.

Wave erosion occurs when sediments such as sand, shell and other materials are carried to the shoreline by ocean waves. This erodes the shore over time as the sediments act like sandpapers.

what is momentum of a train that is 60,000 kg that is moving at velocity of 17m/s?
explain your answer​

Answers

momentum=mass x velocity
=60000 x 17
=1020kgm/s

A car is traveling on a straight road at a constant 35 m/sm/s, which is faster than the speed limit. Just as the car passes a police motorcycle that is stopped at the side of the road, the motorcycle accelerates forward in pursuit. The motorcycle passes the car 13.5 ss after starting from rest. What is the acceleration of the motorcycle (assumed to be constant)

Answers

Answer:

2.59m/s

Explanation:

Using the equation of motion

v = u+at

v is the final velocity = 35ms

u is the initially velocity = 9m/s

t is the time = 13.5s

a is the acceleration

Substitute into the formula

35 = 0+13.5a

a = 35/13.5

a = 2.59m/s²

Hence the acceleration of the motorcycle is 2.59m/s

Which of the physical variables listed below will change when you change the area of the capacitor plates (while keeping the battery connected).

a. Capacitance
b. Charge on the plates
c. Voltage across the plates
d. Net electric field between the plates
e. Energy stored in the capacitor

Answers

Answer:

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Explanation:

Let A be the area of the capacitor plate

The capacitance of a capacitor is given as;

[tex]C = \frac{Q}{V} = \frac{\epsilon _0 A}{d} \\\\[/tex]

where;

V is the potential difference between the plates

The charge on the plates is given as;

[tex]Q = \frac{V\epsilon _0 A}{d}[/tex]

The energy stored in the capacitor is given as;

[tex]E = \frac{1}{2} CV^2\\\\E = \frac{1}{2} (\frac{\epsilon _0 A}{d} )V^2[/tex]

Thus, the physical variables listed that will change include;

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

What Coulombs discovered almost 300
years ago

Answers

Answer:

ummm hehe this is my time to shine

Explanation:

  MERICIA!!!!!!!!!!!!!!!!!!!!!!!

Christopher Columbus discovered
America

When the bowling ball has fallen halfway down the building (height = 20 m), it has a speed of 19.8 m/s.
How much potential energy does the bowling ball have?
How much kinetic energy does the bowling ball have?
How much total energy (potential + kinetic) does the bowling ball have?
Of the bowling ball’s total energy, is more in the form of potential or kinetic energy?

Answers

Answer:

I think the answer is 19.8 potential energy

Explanation:

NONE.

A 40 kg boy standing on a skateboard throws a 2 kg ball 20 m/s to the left.
a. What is the ball's momentum?
O 10 kg m/s
O 20 kg mis
O 40 kg m/s
O 1 kg m/s

Answers

Answer:

40 kg m/s

Explanation:

Given the following data;

Mass of boy = 40kg

Mass of ball = 2kg

Velocity = 20m/s

To find the momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum =mass * velocity

Substituting into the equation, we have

Momentum = 2 * 20

Momentum = 40 kg m/s

A 500 kg wrecking ball is knocking down a wall. When it is pulled back to its highest point, it is at a height of 6.2 m. When it hits the wall, it is moving at 3.1 m/s. How high is the wrecking ball when it hits the wall? (Show your work and follow all of the steps of the GUESS method. Check your answer after you submit the form - it's in the feedback for this question.) |​

Answers

The first is that you have the time to write a letter ✉️ and a lot more of the same, and the like are the same time as a result of the most popular connection and a half ago I was in a way ↕️ and a few other people are paying for new cars at the time of his death own or manage Hotel in a way ↕️ and the second half of the season ❄️ and a half ago I had a lot of people the first time I have to admit I have to say I am a little more time with my own personal information on how the hell out of the box house and a few other people and the second one of the most popular and a half ago I had to do it again in the first.

Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts a force of 75.0N, the second child exerts a force of 90.0 N, friction is 12.0 N, and the most of the third child plus wagon is 23.0 kga)what is the system of interest if the acceleration of the child in the wagon is to be calculated

Answers

Answer:

Explanation:

75 N and 90 N are acting in opposite direction so net force = 90 - 75 = 15 N .

Friction force will act in the direction opposite to the direction of net force .

So friction force will act in the direction in which 75 N is acting .

Total force acting in the direction of 75 =  75 + 12 = 87 N

Net force acing on the third child = 90 - 87 = 3 N  

Its direction will be that in the direction of 90 N .

If there is "waste" energy, does the Law of Conservation of Energy still apply? please don't type something random if so i'll just report it.​

Answers

Explanation:

Yes, the law of conservation of energy still applies even if there is waste energy.

The waste energy are the transformation products of energy from one form to another.

According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".

But of then times, energy is lost as heat or sound within a system.

If we take into account these waste energy, we can see that energy is indeed conserved. The sum total of the energy generated and those produced will be the same if we factor in other forms in which the energy has been transformed into.

A cylindrical tank of radius R, filled to the top with a liquid, has a small hole in the side, of radius r, at distance d below the surface. Find an expression for the volume flow rate through the hole. A 4.0-mm-diameter hole is 1.0 m below the surface of a 2.0-m-diameter tank of water. What is the rate, in mm/min, at which the water level will initially drop if the water is not replenished?

Answers

Answer:

a)[tex]V=\pi *r^2 * \sqrt{2gd}[/tex]

b)[tex]dh / dt = 0.2658 mm / min[/tex]

Explanation:

From the question we are told that

Diameter of hole [tex]d_h=4mm=>0.004m[/tex]

Depth of hole [tex]D=0mm=>0.001m[/tex]

Diameter of tank [tex]d_t=2mm=>0.002m[/tex]

Generally the equation for pressure is mathematically given as

[tex]Pressure P= \rho*g*d[/tex]

[tex]P= 1/2*\rho *v^2[/tex]

Where

[tex]v = \sqrt {2gd}[/tex]

[tex]V = Area*v[/tex]

[tex]V=\pi *r^2 * \sqrt{2gd}[/tex]

Generally the level at which the water level will initially drop if the water is not replenished is mathematically given by

[tex]dh / dt = (r/R)^2 *sqrt{2gd}\\dh / dt = (2/2000)^2 *sqrt(2*9.81*1) \\dh / dt = 4.429*10^-3 mm/s \\[/tex]

Therefore the level at which the water level will initially drop if the water is not replenished

[tex]dh / dt = 0.2658 mm / min[/tex]

The rate, in mm/min, at which the water level will initially drop will be 1.0625 mm/min.

Given data:

The diameter of hole is, d = 4.0 mm = 0.004 m.

The depth of hole is, h = 1.0 m.

The diameter of tank is, d' = 2.0 m.

The given problem is based on the flow rate, which is defined as the flow of liquid through a given section per unit time.

Let us first obtain the equation of pressure as,

[tex]P=\dfrac{1}{2} \times \rho \times v^{2}[/tex]

Here, v is the velocity of efflux and its value is,

[tex]v=\sqrt{2gh} \\\\v^{2}=2gh[/tex]

And the level at which the water level will initially drop if the water is not replenished is mathematically given by,

[tex]\dfrac{dH}{dt}=(r/R)^{2} \times v[/tex]

Here,

r is the radius of hole.

R is the radius of tank.

Solving as,

[tex]\dfrac{dH}{dt}=((d/2) /(d'/2))^{2} \times \sqrt{2gh} \\\\\dfrac{dH}{dt}=((0.004/2) /(2/2))^{2} \times \sqrt{2 \times 9.8 \times 1}\\\\\dfrac{dH}{dt}=1.77 \times 10^{-5} \;\rm m/s\\\\\dfrac{dH}{dt}=1.77 \times 10^{-5} \times 6 \times 10^{4} \;\rm mm/min\\\\\dfrac{dH}{dt}=1.0625 \;\rm mm/min[/tex]

Thus, we can conclude that the rate, in mm/min, at which the water level will initially drop will be 1.0625 mm/min.

Learn more about the flow rate here:

https://brainly.com/question/11816739

The mass of 60 paper clips is 18.0 grams. What is the mass of one paper clip?

Answers

Answer:

3.333333333333333333333333333333333333333

Explanation:

3.3333333333333333333333333333333333

Two metal bricks are held off the edge of a balcony from the same height above the ground. The bricks are the same size but one is made of Titanium (density of 4.5 g/cm%) and one is made of Lead (density of 11.3 g/cm3) so the Lead is about twice as heavy as the Titanium. The time it takes the bricks to reach the ground will be:________.
a. less but not necessarily half as long for the heavier brick
b. about half as long for the lighter brick
c. less but not necessarily half as long for the lighter brick
d. about half as long for the heavier brick
e. about the same time for both bricks

Answers

Answer:

e.

Explanation:

Assuming that the air resistance is neglectable, both bricks are only accelerated by gravity, which produces a constant acceleration on both bricks, which is the same, according  Newton's 2nd Law, as we can see below:[tex]F_{g} = m*g = m*a (1)[/tex]⇒a = g = 9.8m/s² (pointing downward)Since acceleration is constant, if both fall from the same height, we can apply the following kinematic equation:

       [tex]\Delta y = v_{o} * t - \frac{1}{2} *g*t^{2} (2)[/tex]

Since both bricks are held off the edge, the initial speed is zero, so (2) reduces to the following equation:

        [tex]h =\frac{1}{2} *g*t^{2} (3)[/tex]

Since h (the height of the balcony) is the same, we conclude that both bricks hit ground at exactly the same time.If the air resistance is not negligible, due both bricks have zero initial speed, and have the same shape, they will be affected by the drag force in similar way, so they will reach the ground at approximately the same time.

A neutral metal bob is hanging on the bottom of a pendulum that is 15 cm long. A charged balloon is held near the metal bob and the pendulum is pulled up to a vertical angle of 20-deg. If the mass of the metal bob is 0.025kg, what is the charge on the balloon.

Answers

Answer:

Explanation:

See the figure attached

F is electrostatic force .

T cos20 = mg

T sin20 = F

Tan20 = F / mg

F = mg tan 20 = .025 x 9.8 tan20

= .09 N

Distance between bob and balloon

= 15 sin20 = 5.1 cm = .051 m

If q be the charge on balloon

F = 9 x 10⁹ x q² / .051²

= 3460 x 10⁹ q² = .09

q² =  26 x 10⁻⁶ x 10⁻⁹

q = 16.12 x 10⁻⁸ C .

How is energy transferred when
hitting a nail?​

Answers

Answer:

kinetic energy

kinetic energy

Which is larger: 65 mph (miles per hour) or 120 kph (kilometers per hour)? As a percentage, how much faster is one than the other?

Answers

To Find :

Which is larger: 65 mph (miles per hour) or 120 kph (kilometers per hour).

Solution :

We know, 1 mph = 1.61 kph

So, 65 mph = 1.61 × 65 kph

65 mph = 104.65 kph

Since, 65 mph is 104.65 kph which is smaller than 120 kph.

Therefore, 120 kph is faster than 65 mph by ( 120 - 104.65 ) = 15.35 kph.

If a person weighs 140 lb'on Earth, their mass in kilograms is

Answers

Answer:

70 kg

Explanation:

divide it by 2

Hope this helped!

Answer:

63.502932 Kilograms

Explanation:

please help asap!!

Explain the movement of a roller coaster in terms of potential and kinetic energy? When are these energies thegreatest? Smallest? Are they ever the same?​

Answers

Answer:

Potential energy: Greatest at the top of the hill

Kinetic energy: Greatest at the bottom of the hill

The two meet at some point on the way down!

Explanation:

Potential energy is energy that represents an object's potential for motion. Kinetic energy is that object's energy during motion. They're two sides of the same coin, and in fact, their sum gets a special name: mechanical energy. Potential energy builds up in reaction to working against certain forces - in the case of the roller coaster, that primary force is gravity. Gravity exerts a downward force on the roller coaster, and it takes work to pull it up the hill.

When it reaches the peak, the coasters potential energy is at its highest, and the moment it crests over the hill and begins its descent, that gravitational potential energy starts converting into kinetic energy: the coaster starts accelarating down the track, and the potential energy decreases at the same rate that the kinetic energy increases.

At the bottom of the hill, all of that potential energy has become kinetic energy, and the coaster zooms along the track, hopefully not giving too many riders nausea

One disadvantage to experimental research is that experimental conditions do not always reflect reality.


Please select the best answer from the choices provided

T
F

Answers

Answer:

It's true I took the test on Edge.

Explanation:

Answer:

True

Explanation:

Got it right on edg

When researchers replicate a study, they are seeking to __________.
A.
prove that the hypothesis upon which the study was founded is untestable
B.
develop a new hypothesis
C.
change the study to provide new results
D.
support or reject the hypothesis upon which the study was founded



Please select the best answer from the choices provided


A
B
C
D

Answers

The best answer I think is D) it’s the best one

Answer:

D

Explanation:

right edge 2022

A vertical piston-cylinder device contains a gas at a pressure of 100 kPa. The piston has a mass of 10 kg and a diameter for 14 cm. Pressure of the gas is to be increased by placing some weights on the piston. Determine the local atmospheric pressure and the mass of the weights that will doublethe pressure of the gas inside the cylinder.

Answers

Answer:

the local atmospheric pressure is  93.63 kPa

the mass of the weights is 156.9 kg

Explanation:

Given that;

Initial pressure of gas = 100 kPa

mass of piston = 10 kg and diameter = 14 cm = 0.14 m

g = 9.81 m/s²

Now,

P_gas = P_atm + P_piston

100 = P_atm + P_piston --------- let this equation 1

P_piston = M_piston × g / A = (10 × 9.81) / π/4×d²

P_piston = 98.1 / (π/4×( 0.14 )²)

P_piston = 98.1 / 0.01539 = 6374,269 Pa = 6.37 kPa

now, from equation 1

100 = P_atm + P_piston

we substitute

100 = P_atm + 6.37

P_atm = 100 - 6.37

P_atm = 93.63 kPa

Therefore, the local atmospheric pressure is  93.63 kPa

Now for pressure of the gas in the cylinder ⇒ 2×initial pressure

Pgas_2 = 2 × 100 = 200 kPa

Pgas_2 = P_atm + P_piston + P_weight

Pgas_2 =  P_gas  + P_weight

we substitute

200 kPa =  100 kPa  + P_weight

P_weight =  200 kPa -  100 kPa

P_weight = 100 kPa =  100,000 Pa

Also;

P_weight = M×g / A

100,000 Pa = ( M × 9.81 ) / (π/4 × (0.14)²)

100,000 × 0.01539 = M × 9.81

1539 = M × 9.81

M = 1539 / 9.81

M = 156.9 kg

Therefore, the mass of the weights is 156.9 kg

This table shows the mass and volume of four different objects.

A two-column table with 4 rows. The first column titled objects has entries W, X, Y, Z. The second column titled Measurements has entries Mass: 16 grams Volume: 84 centimeters cubed in the first cell, Mass: 12 grams Volume: 5 centimeters cubed in the second cell, Mass: 4 grams Volume: 6 centimeters cubed in the third cell, Mass: 408 grams Volume: 216 centimeters cubed in the fourth cell.

Which ranks the objects from most to least dense?

Answers

Answer:

Here its right but its also better than Barney's response

Explanation:

W, Y, Z, X or C

Answer:

W, Y, Z, X

Explanation:

In which number are the zeros not significant?
100.0
O 0.0003
O 4.00005
O 1.0004

Answers

Answer:

0.0003

Explanation:

In the rules of Sig Figs, all zeros before with decimals are not sigificant. I.E. 0.00000000000000009. Despite how many 0's there are, only the 9 is significant. Zeros before a number is not significant. In 100, only the one is signficant in 100. with a dot at the end, the one and the two zeros are significant. hope this helps.

Answers:

the second option

Explanation:

If there is "waste" energy, does the Law of Conservation of Energy still apply? ​

Answers

Explanation:

Yes, the law of conservation of energy still applies even if there is waste energy.

The waste energy are the transformation products of energy from one form to another.

According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".

But of then times, energy is lost as heat or sound within a system.

If we take into account these waste energy, we can see that energy is indeed conserved. The sum total of the energy generated and those produced will be the same if we factor in other forms in which the energy has been transformed into.

A stone is dropped from the top of a high cliff with zero initial velocity. In which system is the net momentum zero as the stone falls freely

Answers

Answer:

A system that includes the stone and the earth.

Explanation:

If the system of being dropped from the height of the cliff consists of just the stone alone, then it means that its momentum will certainly undergo changes as it falls freely. However, If the system is now expanded to include not only the stone but also the Earth, then it implies that the momentum of the stone which is in the downward direction will be equal and opposite to the momentum of the Earth in the upwards direction towards the stone. Therefore, the momentum will cancel out and net momentum will be zero.

A system of stone and earth can result to a net zero momentum.

Conservation of linear momentum

The principle of conservation of linear momentum states that the sum of the initial momentum is equal to the sum of final momentum.

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2 v_2[/tex]

A system that consists a linear system of stone and earth can result to a net zero momentum.

Thus, a system of stone and earth can result to a net zero momentum.

Learn more about conservation of momentum here: https://brainly.com/question/7538238

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