Assume that the breaking system of a train consists of two components connected in series with both of them following Weibull distributions. For the first component the shape parameter is 2.1 and the characteristic life is 100,000 breaking events. For the second component the shape parameter is 1.8 and characteristic life of 80,000. Find the reliability of the system after 2,000 breaking events:

NUE is 30° LUN is 60° EUS is 30° LUE is 90° LUS is 120°

Step-by-step explanation:

NUE is given

LUN was from the 90° angle LUE but just minus 30°

EUS is honestly a guess :/

LUE is obviously 90° as we used it earlier

LUS was the 90° plus the EUS

Answer:

the adjustment made to the cost of goods sold is -$2,014

Step-by-step explanation:

The computation of the adjustment made to the cost of goods sold is given below:

Total actual overhead expenses $110,822

Less: Total overheads allocated -$112,836

Adjustment made to the cost of goods sold -$2,014

Hence, the adjustment made to the cost of goods sold is -$2,014

The same should be considered

Answer:

(0.38, 4.79)

Step-by-step explanation:

Answer:

that is the answer

Step-by-step explanation:

use triangle RSQ

from pythogrus theorem

a² + b² = c²

4² + 5² = RQ²

16 + 25 = RQ²

41 = R

Answer:

-18

Step-by-step explanation:

B=-6 C=2 P.E.M.D.A.S.

b - 6(c)

-6 - 6(2)

-6 - 12 . The negatives cancel out, adding each other

-6 + -12

= -18 :)

Answer:

b - 6c

= -6 - 6x2

= -6 x( 1+2)

= -6x3

= -18

Answer:

86°

Step-by-step explanation:

180° is the sum of all angles in a triangle

The two angles given are 68° and 26°

The equation is : 180° - 68° - 26° = x°

180° - 68° - 26° = 86°

x° = 86°

If my answer is incorrect, pls correct me!

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-Chetan K

Answer:

305°

Step-by-step explanation:

The bearing in the reverse direction is 180° plus the bearing in the forward direction, that is

bearing of B from A = 180° + 125° = 305°

Answer:

4

Step-by-step explanation:

The mean is the average of a data set. It can be found by adding up all of the values in a data set and then dividing it by the number of values in the data set.

The values in this data set;

[tex]7,5,5,3,2,2[/tex]

The number of values in this data set,

[tex]6[/tex]

Find the mean;

[tex]\frac{sum\ of\ vlaues}{number\ of\ values}[/tex]

[tex]=\frac{7+5+5+3+2+2}{6}\\\\=\frac{24}{6}\\\\=4[/tex]

Answer:

Step-by-step explanation:

We have similar triangles here.

The ratio of corresponding sides of similar triangles is same:

Take the similar triangles,

→ ∆ADE ≈ ∆ABC

Now we can find,

The height of the tree in meters,

→ BC/DE = AC/AE

In this equation BC is the height of tree,

→ BC/2 = 30/3

→ BC/2 = 10

→ BC = 10 × 2

→ BC = 20

Hence, the height of the tree is 20 m.

Answer:

[tex]P(\frac{A}{B'})[/tex]=0.111

Step-by-step explanation:

Given:

The probability of winning the first game is 10.1

The first game is won

The probability of winning the second game is 15

If the first is lost, the probability of winning the second game is 25

Solution:

[tex]P(B)=P(A)P(\frac{B}{A})+P(A')P(\frac{B}{A'})\\ =0.1(0.15)+(0.3)*0.25)\\P(B)=0.24 ------(1)\\P(\frac{A}{B})=\frac{P(\frac{B}{A})P(A) }{P(B)}\\ =\frac{0.15(0.1)}{0.24}\\ =0.0625 ------(2)\\P(B')=1-P(B)=0.76 ------(3)\\P(A)=P(B)P(\frac{A}{B})+P(B')P(\frac{A}{B'})\\0.1=0.24(0.0625)+0.76(p(\frac{A}{B'} ))\\P(\frac{A}{B'})=0.111[/tex]

Answer:

[tex]P(W_1/W_2')=0.1110[/tex]

Step-by-step explanation:

Probability of winning the first game be considering the given factors be, [tex]W_1=0.1[/tex]

Probability of winning the second game be considering the given factors be, [tex]W_2[/tex]= probability of winning the second game when the first game is won + probability of winning the second game when the first game is lost:

[tex]P(W_2)=P(W_1).P(W_2/W_1)+P(W_1').P(W_2/W_1')[/tex]

[tex]P(W_2)=0.1\times 0.15+0.9\times 0.25[/tex]

[tex]P(W_2)=0.24[/tex]

Hence the probability of losing the second game:

[tex]P(W_2')=1-P(W_2)[/tex]

[tex]P(W_2')=0.76[/tex]

Probability of winning the first game when the second game is won:

[tex]P(W_1/W_2)=\frac{P(W_2/W_1).P(W_1)}{P(W_2)}[/tex]

[tex]P(W_1/W_2)=\frac{0.15\times 0.1}{0.24}[/tex]

[tex]P(W_1/W_2)=0.0625[/tex]

Probability of winning the first game be considering the given factors, [tex]W_1[/tex]= probability of winning the first game when the second game is won + probability of winning the first game when the second game is lost:

[tex]P(W_1)=P(W_2).P(W_1/W_2)+P(W_2').P(W_1/W_2')[/tex]

[tex]0.1=0.24\times0.0625+0.76\times P(W_1/W_2')[/tex]

[tex]P(W_1/W_2')=0.1110[/tex]

Answer:

A. reflection.

Step-by-step explanation:

If you were to use the reflection rule, then your answer will be:

B' (Now D): (1 , 2)

A' (Now E): (4 , 2)

C' (Now F): (3 , 5)

In this case, the reflected triangle does not match the given points, therefore it cannot be reflection.

~

Answer:

Yes, as for each trial there are only two possible outcomes, the trials are independent, and the number of trials is fixed.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they respond favorably, or they do not. The probability of a student responding favorably is independent of any other student, and the number of trials is fixed. Thus, this probability experiment represents a binomial experiment.

Answer:

[tex]{ \bf{A=(P + \frac{r}{100} ) {}^{n} }} \\ { \tt{ = (4000 + \frac{5.5}{100} ) {}^{15} }} \\ \\ { \tt{ = \: 1.074 \times {10}^{54} \: dollars}}[/tex]

Answer:

Step-by-step explanation:

Given expressions are,

[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex] and [tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

Remove the radicals from the denominator from both the expressions.

[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}} \times \frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

  [tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]

  [tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{5}[/tex]

[tex]\sqrt{p}=\sqrt{\frac{(\sqrt{10}-\sqrt{5})^2}{5}}[/tex]

      [tex]=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{5}}[/tex]

[tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

  [tex]=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}\times \frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex]

  [tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]

  [tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{5}[/tex]

[tex]\sqrt{q}=\sqrt{\frac{(\sqrt{10}+\sqrt{5})^2}{5}}[/tex]

     [tex]=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}[/tex]

[tex]\sqrt{q}-\sqrt{p}-2\sqrt{pq}=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}-\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}}-2(\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}})(\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}})[/tex]

                           [tex]=\frac{1}{\sqrt{5}}(\sqrt{10}+\sqrt{5}-\sqrt{10}+\sqrt{5})-\frac{2}{5}[(\sqrt{10})^2-(\sqrt{5})^2)][/tex]

                           [tex]=\frac{1}{\sqrt{5}}(2\sqrt{5})-\frac{2}{5}(10-5)[/tex]

                           [tex]=2-2[/tex]

                           [tex]=0[/tex]

Answer:

Good sampling technique

Step-by-step explanation:

In other to determine the mean value for a population, it may be necessary to make inference from the a small subset of the population, called the sample, if it is impossible, difficult or inefficient to get all population data. Hence, in other to select a subset of the population, then the sample must be selected at random, such that all elements of the population have equal chances of being selected and hence, be representative of the population. Since, the sampling technique adopted above is done at random, hence, it is a good sampling technique.

Answer:

Step-by-step explanation:

By applying cosine rule in the given triangle,

c² = a² + b²-2abcosC

c² = (5.6)² + (10.7)² - 2(5.6)(10.7)cos(109.3°)

c² = 185.46

c = 13.6 km

By applying sine rule in the given triangle ABC,

[tex]\frac{\text{sin}A}{a}= \frac{\text{sin}B}{b}= \frac{\text{sin}C}{c}[/tex]

[tex]\frac{\text{sin}A}{5.6}=\frac{\text{sin}B}{10.7}=\frac{\text{sin}109.3}{13.6}[/tex]

[tex]\frac{\text{sin}B}{10.7}=\frac{\text{sin}109.3}{13.6}[/tex]

sin(B) = [tex]\frac{10.7\times \text{sin}(109.30)}{13.6}[/tex]

         = 0.7425

B = [tex]\text{sin}^{-1}(0.7425)[/tex]

B = 48.0°

[tex]\frac{\text{sin}A}{5.6}=\frac{\text{sin}109.3}{13.6}[/tex]

sin(A) = [tex]\frac{[\text{sin}(109.3)]\times (5.6)}{13.6}[/tex]

         = 0.3886

A = [tex]\text{sin}^{-1}(0.3886)[/tex]

A = 22.9°

Answer:

2n+2

_____

9 2n

An acre requires 1.33 bushels of seed.

Thirty acres thusly require 30 times 1.33 bushels of seed.

So we have, [tex]1.33\cdot30=\boxed{39.9}[/tex] bushels of seed.

Hope this helps.

Answer:

Its C.  -6

Step-by-step explanation:

The coordinates of point B after translation are (-2, -6).

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

A translation T(-3, -8) follows the rule:

A translation is a movement of the graph either horizontally parallel to the -axis or vertically parallel to the -axis.

(x, y)--->(x-3, y-8)

From the diagram you can see that point B has coordinates (1,2).

(1, 2)--->(1-3, 2-8)

(1, 2)--->(-2, -6)

According to the previous rule this point will transform in point B' with coordinates (-2,-6),

Hence, the coordinates of point B after translation are (-2, -6).

To learn more on Graph click:

https://brainly.com/question/17267403

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Answer:

please mark me brainlist

Step-by-step explanation:

Answer:

axis of symmetry=-2

y intercept=(0,-1)

the total of marbles = 16 + 10 +12 =38

A) white : blue = 16/10 = 8/5

B) red : total = 12/38 = 6/19

Step-by-step explanation:

1. find the total of marbles

Answer:

The probability is P = 0.08

Step-by-step explanation:

We have:

2 pink balls

7 purple balls

6 white balls

So the total number of balls is just:

2 + 7 + 6 = 15

We want to find the probability of randomly picking 3 purple balls (without replacement).

For the first pick:

Here all the balls have the same probability of being drawn from the urn, so the probability of getting a purple one is equal to the quotient between the number of purple balls (7) and the total number of balls (15)

p₁ = 7/15

Second:

Same as before, notice that because the balls are not replaced, now there are 6 purple balls in the urn, and a total of 14 balls, so in this case the probability is:

p₂ = 6/14

third:

Same as before, this time there are 5 purple balls in the urn and 13 balls in total, so here the probability is:

p₃ = 5/13

The joint probability (the probability of these 3 events happening) is equal to the product between the individual probabilities, so we have:

P = p₁*p₂*p₃ = (7/15)*(6/14)*(5/13)  = 0.08

The largest rate of change occurs in the same direction as the gradient of f at the point.

∇f(x, y, z) = (∂f/∂x, ∂f/∂y, ∂f/∂z) = (y, x, -1/z)

==>   ∇f (1, 1, 1) = (1, 1, -1)

In other words, f changes at the highest rate in the direction of the vector (1, 1, -1).

Answer:

Problem 17)

[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]

Problem 18)

[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]

Step-by-step explanation:

Problem 17)

We have the curve represented by the equation:

[tex]\displaystyle 4x^2+2xy+y^2=7[/tex]

And we want to find the equation of the tangent line to the point (1, 1).

First, let's find the derivative dy/dx. Take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{d}{dx}\left[4x^2+2xy+y^2\right]=\frac{d}{dx}[7][/tex]

Simplify. Recall that the derivative of a constant is zero.

[tex]\displaystyle \frac{d}{dx}[4x^2]+\frac{d}{dx}[2xy]+\frac{d}{dx}[y^2]=0[/tex]

Differentiate. We can differentiate the first term normally. The second term will require the product rule. Hence:

[tex]\displaystyle 8x+\left(2y+2x\frac{dy}{dx}\right)+2y\frac{dy}{dx}=0[/tex]

Rewrite:

[tex]\displaystyle \frac{dy}{dx}\left(2x+2y\right)=-8x-2y[/tex]

Therefore:

[tex]\displaystyle \frac{dy}{dx}=\frac{-8x-2y}{2x+2y}=-\frac{4x+y}{x+y}[/tex]

So, the slope of the tangent line at the point (1, 1) is:

[tex]\displaystyle \frac{dy}{dx}\Big|_{(1, 1)}=-\frac{4(1)+(1)}{(1)+(1)}=-\frac{5}{2}[/tex]

And since we know that it passes through the point (1, 1), by the point-slope form:

[tex]\displaystyle y-1=-\frac{5}{2}(x-1)[/tex]

If desired, we can simplify this into slope-intercept form. Therefore, our equation is:

[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]

Problem 18)

We have the equation:

[tex]\displaystyle y=\tan^{-1}\left(x^3\right)[/tex]

And we want to find the equation of the tangent line to the graph at the point (1, π/4).

Take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\tan^{-1}(x^3)][/tex]

We can use the chain rule:

[tex]\displaystyle \frac{d}{dx}[u(v(x))]=u'(v(x))\cdot v(x)[/tex]

Let u(x) = tan⁻¹(x) and let v(x) = x³. Thus:

(Recall that d/dx [arctan(x)] = 1 / (1 + x²).)

[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2[/tex]

Substitute and simplify. Hence:

[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2=\frac{3x^2}{1+x^6}[/tex]

Then the slope of the tangent line at the point (1, π/4) is:

[tex]\displaystyle \frac{dy}{dx}\Big|_{x=1}=\frac{3(1)^2}{1+(1)^6}=\frac{3}{2}[/tex]

Then by the point-slope form:

[tex]\displaystyle y-\frac{\pi}{4}=\frac{3}{2}(x-1)[/tex]

Or in slope-intercept form:

[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]

Answer:

the terms in the expression are p squared, negative 3,3p, negative 8,p,p cubed

Step-by-step explanation:

hope that helps