Engineering High School

All of the following are common manual transmission problems EXCEPT: (A) bent shift mechanism. B) worn thrust washers. (C) clogged modulator valve. (D) damaged extension housing.​

Answers

Answer 1

Option (C) clogged modulator valve is not a common manual transmission problem. This component is typically associated with automatic transmissions, not manual transmissions.

Explanation

Manual transmission problems can include a range of issues that can affect the performance of the transmission. Here short explanation about other option except C as common manual transmission problems:

Bent shift mechanism.
The shift mechanism in a manual transmission is responsible for moving the gears into the correct position for each gear change. If the shift mechanism is bent or damaged, it can cause difficulty in shifting gears or even prevent the transmission from shifting at all. This can happen due to wear and tear, damage from impact or other causes.Worn thrust washers.
Thrust washers are small components in the transmission that help to control the movement of the gears. If the thrust washers become worn, they can cause excessive play in the gears, leading to difficulty in shifting and even gear slippage. This can happen due to normal wear and tear or improper lubrication.Damaged extension housing.
The extension housing is the outermost component of the transmission on the backside that houses the output shaft. If it becomes damaged due to wear and tear, impact or other causes, it can cause leaks in the transmission or even prevent it from operating altogether. A damaged extension housing can cause the transmission to fail or operate poorly.

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Related Questions

how many grams of water can be heated from 10 degrees to 45 degrees using 20,500 joules of energy

Answers

Therefore, 20,500 Joules of energy can heat 1,104.3 grams of water from 10 degrees Celsius to 45 degrees Celsius.

Specific heat capacity

Calculate the energy (in Joules) required to heat 1 gram of water from 10 degrees Celsius to 45 degrees Celsius:

Q = m * c * ΔT

Q = 1 gram * 4.184 Joules/gram-degree Celsius * (45 - 10) degrees Celsius

Q = 18.47 Joules

Calculate the amount of water (in grams) that can be heated with 20,500 Joules of energy:

20,500 Joules / 18.47 Joules = 1,104.3 grams

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