Algebra is hard for me

Because all the angles are congruent (the same), this is an equilateral triangle. All equilateral triangles have congruent angles and congruent sides, so all sides has to be 14.

Answer:

y = 4x - 8

Step-by-step explanation:

y = 4x + b

4 = 4(3) + b

4 = 12 + b

-8 = b

Answer:

surface area of a square = 2 ( lb + bh + hl )

given that,

length = 8cm

breadth = 10cm

height = 15 cm

surface area = 2 ( 8* 10 + 10*15 + 15*8 )

                     = 2 ( 80 + 150 + 120 )

                     = 2 * 350

                     = 700 [tex]cm^{2}[/tex]

hope this answer helps you!!

Answer:

Tan X = 14/48 = 7/24

Answered by GAUTHMATH

Answer:

7/24

Step-by-step explanation:

tan(x) is the ratio of the opposite leg to the adjacent leg. The opposite leg of x's measure is 14, and the adjacent leg to x has a measure of 48. (It's not 50 since 50 is opposite the right angle, meaning that it's the hypotenuse.)

14 / 48 = 7 / 24. Simplest form is 7/24.

Answer:

14 yards shorter

Step-by-step explanation:

Use Pythagoras' Theorem

a²+b²=c²

16²+63²=4225

√4225= 65yd

The diagonal line (c) is 65 yards long

16 + 63 = 79 yd

It would be 14 yards shorter (79-65)

Answer:

it should be 90 I could be wrong

Answer:  [tex](x-3)^2 + (y-2)^2 = 16[/tex]

Explanation:

The center of this circle is point A(3,2). These coordinates are the (h,k) values.

The radius is r = 4

Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.

Answer:

13/45

Step-by-step explanation:

x = .2888888888

100(x + .2888888)

100x + 28.8888

 10x + 2.88888

90x = 26

x = 26/90 = 13/45

Answer: 4. A base area of 16y^2 square units and height of y^2 + y + 3 units

Step-by-step explanation:

Using the distributive property; you can see that 16y^2(y^2+y+3)=

16y^4+16y^3+48y^2

Answer:

D. a base area of 16y2 square units and height of y^2 + y + 3 units

Step-by-step explanation:

Ed22

Answer:

RS, RT, ST

Step-by-step explanation:

We require the third angle in the triangle

∠ T = 180° - (92 + 71)° = 180° - 163° = 17°

The shortest side is opposite the smallest angle

∠ T = 17° → opposite side RS

The longest side is opposite the largest angle

∠ R = 92° → opposite side ST

Then sides from shortest to longest is

RS, RT, ST

Answer:

100% - 76% = 24%

24% = 0.24

0.24*50 = 12

You got 12 questions wrong.

Step-by-step explanation:

Please mark brainliest!

Number of questions that got wrong are 12 .

Given,

76% on a 50 question test.

Here,

Let total percentage value be 100%.

Then,

100% - 76% = 24%

24% questions got wrong.

Number of questions that got wrong out of 50 will be ,

24% of 50

= 0.24*50

= 12

Therefore 12 questions got wrong.

Know more about percentages,

https://brainly.com/question/23418123

#SPJ4

Answer: 111.1 m

Step-by-step explanation:

(30*2)/60 = 1 km ( the tunnel length is 1 Km.)

1 Km = 1000 m.

1000/9 = 111.1 m.

Answer: 2, acute equilateral

Step-by-step explanation:

the image shows a triangle with all 3 sides congruent and 3 acute angles

Answer: 96

Step-by-step explanation:

This equation helps

X / 100 = is / of

32/100 = X / 300 (cross multiplication)

32 times 300, divided by 100

= 96

Answer:

96

Step-by-step explanation:

every percent is out of hundred so (32 * 300)/100 = 96

Answer:

210

Step-by-step explanation:

In a normal distribtuion mean=mode=median

so 210=median

Answer:

10

Step-by-step explanation:

2000/ 2x = 10

Multiply each side by 2x

2000/ 2x = 10 *2x

2000 = 20x

Divide by 20

2000/20 = 20x/20

100 = x

Take the square root of each side

sqrt(100) = sqrt(x)

10 = sqrt(x)

The combined radical is: [tex]- 26\sqrt{3}[/tex]

The radical is given as:

[tex]- 12\sqrt{12} - 2\sqrt{3}[/tex]

We start by expressing 12 as 4 * 3

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12\sqrt{4* 3} - 2\sqrt{3}[/tex]

Split the radical

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12\sqrt{4}* \sqrt{3} - 2\sqrt{3}[/tex]

Take square root of 4

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12*2* \sqrt{3} - 2\sqrt{3}[/tex]

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 24* \sqrt{3} - 2\sqrt{3}[/tex]

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 24\sqrt{3} - 2\sqrt{3}[/tex]

Combine like terms

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 26\sqrt{3}[/tex]

Hence, the combined radical is: [tex]- 26\sqrt{3}[/tex]

Read more about surd radicals at:

https://brainly.com/question/14923091

Answer:

The answer is 98

Step-by-step explanation:

Can I get branly plz and hope this help

Answer:

D

Step-by-step explanation:

graph it

Answer:

right by 3 I think

Step-by-step explanation:

Answer: Right by 3 Units

Step-by-step explanation:

Right on edge 2021

Their LCM is

70

hope it helps you.

Answer:

Their L.C.M IS

70....

IT IS YOUR ANSWER

A general cosine function (we could also use a sine function) is written as:

y = A*cos(k*x + p) + M

We will find that the function of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

Let's return to the general function:

y = A*cos(k*x + p) + M

A is the amplitude, it defines the distance between the value of a maximum and the value of the minimum, such that A is exactly half of that difference.

Here we can see that the maximum is 0, and the minimum is -4

The differene is: 0 - (-4) = 4

Then:

A = 4/2 = 2

f(x) = 2*cos(k*x + p) + M.

M is the midline, this is, the horizontal line that cuts the graph in two halves. Here we can see that the midline is x = -2, then:

M = -2

f(x) = 2*cos(k*x + p) - 2

p is the phase shift.

In the graph, we can see that f(0) = -3, so we have:

f(0) = 2*cos(0 + p) - 2 = -3

      cos(p) = -1/2

             p = Acos(-1/2) = 2.09

Then we have:

f(x) = 2*cos(k*x + 2.09) - 2

Finally, k is related to the frequency of the function.

We can see that the function does a complete cycle at x = pi

This means that:

f(x) = f(x + pi)

Knowing that the period of a cosine function is 2*pi, then:

k*(x + pi) = k*x + 2*pi

k = 2

Then the equation of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

If you want to learn more, you can read:

https://brainly.com/question/24372261

Answer(s):

[tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2 \\ y = 2cos\:(2x - 1\frac{1}{4}\pi) - 2[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{5}{8}\pi} \hookrightarrow \frac{-1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{5}{8}\pi} \hookrightarrow \frac{1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then by all means, go for it, but be careful and follow what is explained here. Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2sin\:(2x - 1\frac{1}{4}\pi) - 2,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex] which means the C-term will be negative. Now, BEFORE we go any further, we must remember that this particular cosine graph [thank goodness it is a cosine graph we are working with] ALREADY has a horisontal shift and does not have a single crest oscıllαtıng about any endpoint on the y-axis. So, in this case we need to figure out how far the FIRST oscıllαtıng crest is from the origin, and that obviously would be [tex]\displaystyle \frac{5}{8}\pi\:units.[/tex] Though, sinse we want the sine equation of this graph, it must be “negative”; so, by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{5}{8}\pi} = \frac{-1\frac{1}{4}\pi}{2},[/tex] in which the value of C is [tex]\displaystyle -1\frac{1}{4}\pi.[/tex] So, the sine equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [\frac{7}{8}\pi, -2],[/tex] from there to [tex]\displaystyle [-\frac{\pi}{8}, -2],[/tex] they are obviously [tex]\displaystyle \pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**As you can see, this is one of those moments where you will really need to be careful because if you notised, both equations have OPPOCITE horisontal shifts and C-values. Now, the ONLY TIME this occurs is when all crests in a SINUSOIDAL graph cycle half-way in between endpoints. Your best bet is to jot this down for when you see graphs like these in the future.

I am delighted to assist you at any time.

Answer:

First, we apply the Distributive property and then we combine like terms,

To combine like terms, we add or subtract.

[tex]-(2x +y) - 2 ( -x - y)[/tex]

[tex]=-2x-y+2x+2y[/tex]

[tex]=(-2x+2x)+(-y+2y)[/tex]

[tex]=0+y[/tex]

[tex]=y[/tex]

OAmalOHopeO

Answer:

y is the simplest result here.

Step-by-step explanation:

Perform the indicated multiplication as a first step towards simplifying this expression:

-2x - y + 2x + 2y

-2x and 2x cancel each other out, leaving 2y - y, or just y

Parameterize C by

r(t) = 〈x(t), y(t)〉 = 〈cos(t), sin(t)〉

with 0 ≤ t ≤ π. Then the line integral is

[tex]\displaystyle \int_C (2+x^2y)\,\mathrm ds = \int_0^\pi (2+\cos^2(t)\sin(t))\left\|\mathbf r'(t)\right\|\,\mathrm dt \\\\ = \int_0^\pi (2+\cos^2(t)\sin(t)) \,\mathrm dt = \boxed{\frac23+2\pi}[/tex]

Answer:

12

Step-by-step explanation:

The first number they will both say = L.C.M of (6,4)

=> L.C.M of (6,4) is 12

The first number they will both say is 12

Answer:

The height is 12 cm

Step-by-step explanation:

Hi there!

We are given a triangle with the 3 sides marked as 15, 20, and 25 and we want to find the height of it (marked as x in the problem).

This problem can seem a bit difficult, but let's see if the triangle is a right triangle first off.  

One way to figure out if it is a right triangle is to apply the converse of the Pythagorean theorem.

Let's label the sides, where a is the shortest side, b is the second shortest side, and c is the longest side:

a=15

b=20

c=25  

Now square a and b, then add the result together. If it's the same as c squared, then the triangle is a right triangle

15²+20²=25²

225+400=625

625=625

So we can safely say that the triangle is a right triangle

This makes the problem way easier, as there are 2 ways to find the area of a right triangle:

The first way is to multiply the legs (the sides that make up the right angle) together, then divide the result by 2

The other way is to multiply the height and the hypotenuse (the side OPPOSITE to the right angle) together, and then divide the result by 2

First, we need to figure out which sides are the legs, and which side is the hypotenuse

By the triangle inequality theorem, the hypotenuse of a right triangle is the longest side, which means that the 25 cm side is the hypotenuse, and that leaves 15 cm and the 20 cm sides as the legs

So let's find the area of the triangle using the legs

A=[tex]\frac{15*20}{2}[/tex]=[tex]\frac{300}{2}[/tex]=150

So the area of the triangle is 150 cm²

However, as mentioned above, we can also find the area of the triangle by multiplying the hypotenuse by the base, then dividing the result by 2

Which means that the area is also:

A=[tex]\frac{25x}{2}[/tex] cm²

As these both equal the area of the triangle, we can set them equal to each other. This is possible via a property known as transitivity (if a=b and b=c, then a=c)

[tex]\frac{25x}{2}=150[/tex]

Multiply both sides by 2

25x=300

Divide both sides by 25

x=12 cm

So the height of the triangle is 12 cm

Hope this helps!

Answer:

Step-by-step explanation:

Remark

I have to assume that you know calculus. It is the only way the problem can be done that I know of. If you don't, I'm not sure how you will do this.

The curve is of y  = e^(-2x) + x^2 - 3

The curve crosses the y axis when x = 0. The y value is

y = e^0 + x^2 - 3

yint = 1 + 0 - 3

yint = -2

The slope at point (0,-2) is

y' = -2e^(-2x) +2x

y' = -2 at point A

Therefore the normal will have a slope

m1 * m2 = - 1

The slope of the curve C  at A = -2

The equation of the tangent line at A = -2x - 2

Call this m1

m2 = slope of the normal

-2 * m2 = -1

m2 = 1/2

Equation of the line (l) =

y = 1/2 x  - 2

The graph is shown below. Notice the two lines actually look like they are at a 90 degree angle.

Answer:

cosA = 0.6

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract sin²A from both sides )

cos²A = 1 - sin²A ( take the square root of both sides )

cosA = ± [tex]\sqrt{1-sin^2A[/tex]

Since only the positive value is required , then

cosA = [tex]\sqrt{1-(0.8)^2}[/tex]

         = [tex]\sqrt{1-0.64}[/tex]

         = [tex]\sqrt{0.36}[/tex]

         = 0.6

Answer:

Answer:

Answer:x = 25°

Answer:x = 25°Step-by-step explanation:

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2}

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 2

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2}

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 2

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )x = 25°

Answer:

x = 6

Step-by-step explanation:

The tangent- tangent angle WVU is half the difference of the measure of the intercepted arcs. , that is

5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - (23x - 5) )

5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - 23x + 5)

5x + 17 = [tex]\frac{1}{2}[/tex] (14x + 10) ← multiply both sides by 2 to clear the fraction )

10x + 34 = 14x + 10 ( subtract 14x from both sides )

- 4x + 34 = 10 ( subtract 34 from both sides )

- 4x = - 24 ( divide both sides by - 4 )

x = 6