The Fahrenheit temperature of the cup of water after 5 minutes is approximately 194°F.
According to Newton's Law of Cooling, the temperature of an object decreases proportionally to the difference between its temperature and the surrounding temperature. The formula is given as:
T = T_a + (T_0 - T_a) * e^(-kt)
In this case, T_a represents the temperature of the room (67°F), T_0 represents the initial temperature of the water (201°F), t represents time in minutes, T represents the temperature of the water at a given time, and k is the decay constant we need to find.
We know that after 3 minutes, the temperature of the water reaches 190°F. Plugging in these values into the equation:
190 = 67 + (201 - 67) * e^(-3k)
Simplifying the equation:
123 = 134 * e^(-3k)
Dividing both sides by 134:
e^(-3k) = 123/134
Taking the natural logarithm of both sides:
-3k = ln(123/134)
Dividing both sides by -3:
k ≈ ln(123/134) / -3 ≈ -0.0104
Now that we have the value of k, we can use the equation to determine the temperature of the water after 5 minutes:
T = 67 + (201 - 67) * e^(-0.0104 * 5)
Calculating the expression:
T ≈ 67 + 134 * e^(-0.052)
T ≈ 67 + 134 * 0.9492
T ≈ 67 + 127.2268
T ≈ 194.23°F
Therefore, the Fahrenheit temperature of the cup of water after 5 minutes is approximately 194°F.
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