A marker is randomly selected from a drawer that contains 20 green, 44 orange, and 30 blue markers. Which statement is true? P(blue)≈0. 41 P(green)≈0. 21 P(orange)≈0. 53.

Answers

Answer 1

none of the provided approximations for the probabilities are accurate.To determine which statement is true, we need to calculate the probabilities of selecting each color marker.

Total number of markers = 20 green + 44 orange + 30 blue = 94 markers.

P(blue) = Number of blue markers / Total number of markers = 30 / 94 ≈ 0.319.

P(green) = Number of green markers / Total number of markers = 20 / 94 ≈ 0.213.

P(orange) = Number of orange markers / Total number of markers = 44 / 94 ≈ 0.468.

Based on the calculations, none of the given statements are true. The actual probabilities are approximately:

P(blue) ≈ 0.319,
P(green) ≈ 0.213,
P(orange) ≈ 0.468.

Therefore, none of the provided approximations for the probabilities are accurate.

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