Answer:
Slope: 0.28
y-intercept: (0,65)
Answer:
slope: .28 y-int: 65
because y=mx+b m is slope and b is the y intercept
Can someone help me with this please !!
Step-by-step explanation:
I need help to...
I keep putting it in and no one has ever answered it and I'm struggling and getting stressed.
A tax on which of these products or services would not be considered a sin
tax"?
O A. Alcohol
O B. Gambling
O C. Electronics
O D. Tobacco
Answer: electronics
Hope that helps
The option that is not considered a sin tax is option B, gambling.
What is a sin tax?
A sin tax is a tax that is applied to "harmful things" to society or individuals. An example of this is Tobacco.
From the given options, the harmful ones are alcohol, gambling, and tobacco. These 3 are considered harmful, so would be included under the sin taxes.
Then the option that is not considered a sin tax is option B, gambling.
If you want to learn more about taxes:
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PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Find the interquartile range of the data set that consists of 3, 11, 4, 3, 10, 6, 4, 5.
A. 3.5
B. 5.75
C. 4.5
D. 8
Answer:
I am thinking it's c
I am not sure
Answer:
25th Percentile: 3.5
50th Percentile: 4.5
75th Percentile: 8
= Interquartile Range: 4.5
I think it shows it's '4.5'.
C
please someone help me! asap!!
Answer:
Last option= 30 minutes
please help, i don't understand the subject so i need an answer to help me out:) i will give brainliest to a good answer.
To be honest, I don't think it has anything to do with the exponent part at all. Instead, I think it has to do with the fact that integers are inherently easier to grasp compared to fractions (which is exactly what rational numbers are).
For instance, it's much easier to say 2+3 = 5 than it is to say 1/2 + 1/4 = 3/4
So going back to the exponent example, it's easier to say
x^2*x^3 = x^(2+3) = x^5
than it is to say
x^(1/2)*x^(1/4) = x^(1/2+1/4) = x^(3/4)
So that's my opinion as to why rational exponents are more tricky to grasp compared to integer exponents. Of course, everyone learns math differently so maybe some find fractions easier than others.
Find the area of the figure.
we observe that this figure could be divided into a triangle and a rectangle.
for the area of the triangle, bxh/2, we have 15 x 12/2 = 90
and for the rectangle, we have 5 x 12 = 60
so, 90 + 60 = 150
hope it helps :)
WILL MARK BRAINLIEST!!
Angelica uses the point 4,3 to represent the location of her house and uses the point 10,8 to represent the location of a gas station. Each unit on the graph represents 1 mi. How far is the gas station from Angelica’s house? Show your work.
Answer:
Angelica's house is 11 miles away from the gas station.
Step-by-step explanation:
The most simple path from Angelica's house is 11 blocks away from the gas station and each unit/block is 1 mile. So 11 miles.
Samira and Sonia each have a bag containing 20 sweets. In each bag, there are 5 red, 6 green and 9 yellow sweets.
(a)
(b)
Samira chooses one sweet at random from her bag.
Write down the probability that she chooses a yellow sweet.
[1] Sonia chooses two sweets at random, without replacement, from her bag.
(i) Show that the probability that she chooses two green sweets is 3 . 38
(ii) Calculate the probability that the sweets she chooses are not both the same colour.
Step-by-step explanation:
there must be some typos here. but I try to address the right issues.
there is nothing under (a). so, really nothing to answer.
(b)
there are 20 sweets in her bag. 9 if the 20 are yellow.
so, the probability is the ratio of desired possibilities vs. total possibilities.
that is, tada! 9/20
that is the probabilty for Samira to pick a yellow sweet.
[1] (i)
again, 20 sweets to start with.
6 are green.
when she picks the first one, her probability to pick a green one is 6/20 = 3/10 = 0.3
and now, under the assumption that this came true, she picks another sweet.
this time she had only 19 left, and 5 of them are green.
so, this probabilty is 5/19
now both events need to happen for the case we are discussing. there is no overlapping, no ors, ifs and buts. it is just the product of both probabilities.
3/10 × 5/19 = 15/190 = 3/38
I think that is what the description asks for.
(ii)
that probability is
first selection is red and second is not red +
first selection is green and second is not green +
first selection is yellow and second is not yellow
so,
red and not red
5/20 = 1/4 red
15/19 not red (there are still 15 sweets of other colors in the bag, but again now only 19 total).
red and not red = 1/4 × 15/19 = 15/76 = 0.1974
green and not green
6/20 = 3/10 = green
14/19 = not green
green and not green = 3/10 × 14/19 = 52/190 = 26/95 =
= 0.2737
yellow and not yellow
9/20 = yellow
11/19 = not yellow
yellow and not yellow = 9/20 × 11/19 = 99/380 = 0.2606
so, now assuming up all 3 possibilities ("or" = sum) gives us the general possibility of selecting two different colors
= 0.7316
Write an equation in point-slope form for the line through the given point with the given slope. (Need ASAP help)
Is it a, b, c or d?
Convert 7 6/7 into an improper fraction.
Answer:
55/7Explanation:
Step 1
Multiply the denominator by the whole number
7 × 7 = 49
Step 2
Add the answer from Step 1 to the numerator
49 + 6 = 55
Step 3
Write answer from Step 2 over the denominator
Answer = 55/7
I hope you are enjoying your day and that this helps you out! Brainliest would be appreciated :)Answer:
55/7
Step-by-step explanation:
To convert 7 6/7 to an improper fraction
Start by multiplying the whole number with the denominator 7 x 7 = 49Then add the numerator to the number you get 49 + 6 = 55 The 55 will be your numerator for your improper fraction. 55/7 The denominator will remain the sameFind an explicit formula for the geometric sequence \dfrac12\,,-4\,,\,32\,,-256,.. 2 1 ,−4,32,−256,..start fraction, 1, divided by, 2, end fraction, comma, minus, 4, comma, 32, comma, minus, 256, comma, point, point. Note: the first term should be \textit{a(1)}a(1)start text, a, left parenthesis, 1, right parenthesis, end text. a(n)=a(n)=a, left parenthesis, n, right parenthesis, equals
Answer:
a(n)= 1/2 * (-8) n-1
Step-by-step explanation:
In a geometric sequence, the ratio between successive terms is constant. This means that we can move from any term to the next one by multiplying by a constant value. Let's calculate this ratio over the first few terms:
\dfrac{-256}{32}=\dfrac{32}{-4}=\dfrac{-4}{\frac12}=\blue{-8}
32
−256
=
−4
32
=
2
1
−4
=−8start fraction, minus, 256, divided by, 32, end fraction, equals, start fraction, 32, divided by, minus, 4, end fraction, equals, start fraction, minus, 4, divided by, start fraction, 1, divided by, 2, end fraction, end fraction, equals, start color #6495ed, minus, 8, end color #6495ed
We see that the constant ratio between successive terms is \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. In other words, we can find any term by starting with the first term and multiplying by \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed repeatedly until we get to the desired term.
Let's look at the first few terms expressed as products:
nn 111 222 333 444
h(n)\!\!\!\!\!h(n)h, left parenthesis, n, right parenthesis \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large0}\!\!\!\!\!\!
2
1
⋅(−8)
0
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 0, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large1}\!\!\!\!\!\!
2
1
⋅(−8)
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, 1, end superscript \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large2}\!\!\!\!\!\!
2
1
⋅(−8)
2
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, squared \red{\dfrac12}\cdot\!\!\!\left(\blue{-8}\right)^{\,\large3}
2
1
⋅(−8)
3
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, cubed
We can see that every term is the product of the first term, \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, and a power of the constant ratio, \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed. Note that this power is always one less than the term number nnn. This is because the first term is the product of itself and plainly 111, which is like taking the constant ratio to the zeroth power.
Thus, we arrive at the following explicit formula (Note that \red{\dfrac12}
2
1
start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030 is the first term and \blue{-8}−8start color #6495ed, minus, 8, end color #6495ed is the constant ratio):
a(n)=\red{\dfrac12}\cdot\left(\blue{-8}\right)^{\large{\,n-1}}a(n)=
2
1
⋅(−8)
n−1
a, left parenthesis, n, right parenthesis, equals, start color #df0030, start fraction, 1, divided by, 2, end fraction, end color #df0030, dot, left parenthesis, start color #6495ed, minus, 8, end color #6495ed, right parenthesis, start superscript, n, minus, 1, end superscript
Note that this solution strategy results in this formula; however, an equally correct solution can be written in other equivalent forms as well.
A brick is in the shape of a rectangular prism with a length of 6 inches, a width of 3 inches, and a height of 5.5 inches. The brick has a density of 2.7 grams per cubic centimeter. Find the mass of the brick to the nearest gram.
pls pls pls help
y............. xnxnxnxnxnccncncncnnncncjcjnf
Given that cos 75 = X, show that cos 105 = −X
Step-by-step explanation:
cos(90) = 0
around this point the cos function "mirrors" with opposite signs. cos(<90) is positive and cos(>90) is negative.
but |cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
75 = 90 - 15
105 = 90 + 15
so, a = 15
and because of
|cos(90-a)| = |cos(90+a)| for 0 <= a <= 90
cos (90-15) = cos(75) = -cos(90+15) = -cos(105)
Question 10 The hypotenuse of a right triangle is I m longer than the longer leg. The other leg is 7 m shorter than the longer leg. Determine the lengths of the three sides of the triangle. (3 marks)
Answer:
5, 12, 13
Step-by-step explanation:
let x be the longer leg then x + 1 is the hypotenuse and x - 7 the shorter leg
Using Pythagoras' identity in the right triangle
x² + (x - 7)² = (x + 1)² ← expand using FOIL
x² + x² - 14x + 49 = x² + 2x + 1
2x² - 14x + 49 = x² + 2x + 1 ( subtract x² + 2x + 1 from both sides )
x² - 16x + 48 = 0 ← in standard form
(x - 4)(x - 12) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 12 = 0 ⇒ x = 12
x = 4 , then x - 7 = 4 - 7 = - 3 ← not possible
x = 12, then x - 7 = 12 - 7 = 5 and x + 1 = 12 + 1 = 13
The lengths of the 3 sides are
longer leg = 12 m , shorter leg = 5 m and hypotenuse = 13 m
Find: (6m5 + 3 – m3 – 4m) – (–m5 + 2m3 – 4m + 6)
Answer: 7m⁵ -3m³ - 3
Working:
= (6m⁵ + 3 - m³ - 4m) -(-m⁵ + 2m³- 4m +6)
= 6m⁵ + 3 - m³ - 4m +m⁵-2m³+4m - 6
= 6m⁵ + m⁵-m³ -2m³ -4m + 4m - 6 +3
= 7m⁵ -3m³ - 3
Answered by Gauthmath must click thanks and mark brainliest
Please Help Asap Its Pre-Calculus
The point (−2, 2) is a solution to which of the following systems?
y > −2x + 2 and y > x + 5
y < x + 2 and y > x − 1
y < 2x + 8 and y ≥ −x − 3
y < 2x + 3 and y ≥ −2x − 5
The point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Given point: [tex](-2,2)[/tex]
Given systems:
[tex]y>-2x+2[/tex] and [tex]y>x+5[/tex] [tex]y<x+2[/tex] and [tex]y>x-1[/tex] [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex] [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]To find: The system to which the given point is a solution
If a point is a solution of a system, then the coordinates of the point satisfies all the equation(s) or inequation(s) of the system. So, we can substitute the x & y coordinates of the given point into the inequalities of each of the given systems and check if the inequalities are satisfied by the coordinates of the point.
(1) [tex]y>-2x+2[/tex] and [tex]y>x+5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y>-2x+2[/tex] to get,
[tex]2>-2(-2)+2[/tex]
[tex]2>4+2[/tex]
[tex]2>6[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(2) [tex]y<x+2[/tex] and [tex]y>x-1[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<x+2[/tex] to get,
[tex]2<-2+2[/tex]
[tex]2<0[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
(3) [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+8[/tex] to get,
[tex]2<2(-2)+8[/tex]
[tex]2<-4+8[/tex]
[tex]2<4[/tex]
This is a true inequality. Then, the given point satisfies the first inequality of the system.
We will now check if the point satisfies the second inequality of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y \geq -x-3[/tex] to get,
[tex]2 \geq -(-2)-3[/tex]
[tex]2 \geq 2-3[/tex]
[tex]2 \geq -1[/tex]
This is also a true inequality. Then, the given point also satisfies the second inequality of the system.
Thus, the given point is a solution of this system.
(4) [tex]y<2x+3[/tex] and [tex]y \geq -2x-5[/tex]
Substitute the coordinates of the point [tex](-2,2)[/tex] into the inequalities of the system.
Put [tex]x=-2,y=2[/tex] in [tex]y<2x+3[/tex] to get,
[tex]2<2(-2)+3[/tex]
[tex]2<-4+3[/tex]
[tex]2<-1[/tex]
The above inequality is clearly impossible and thus, the coordinates of the given point does not satisfy this inequality.
This implies that the given point is not a solution of this system.
Thus, we can see that the coordinates of the given point [tex](-2,2)[/tex] satisfies the inequalities of the third system only.
Then, the point [tex](-2,2)[/tex] is a solution of the system given by [tex]y<2x+8[/tex] and [tex]y \geq -x-3[/tex].
Learn more about geometric solutions of system of linear inequalities here:
https://brainly.com/question/17174433
Find the 6th term of each geometric sequence. 9, 45, 225, 1125
Answer:
28125
Step-by-step explanation:
Refer to the image below.
heeeellllp...
...
...
...
...
...
...
Answer:
didn't shade all of them
Show all work to solve the equation for x. If a solution is extraneous, be sure to identify it in your final answer.
square root of the quantity x plus 7 end quantity minus 1 equals x
Answer:
x=2 true solution
x=-3 extraneous
Step-by-step explanation:
sqrt(x+7) -1 = x
Add 1 to each side
sqrt(x+7) -1+1 = x+1
sqrt(x+7) = x+1
Square each side
(sqrt(x+7))^2 = (x+1)^2
x+7 = x^2 +2x+1
Subtract x from each side
7 = x^2 +x +1
Subtract 7 from each side
0 = x^2 +x - 6
Factor
0 = (x+3)(x-2)
Using the zero product property
x+3 = 0 x-2 =0
x=-3 x=2
Check solutions
x=-3
sqrt(-3+7) -1 = -3
sqrt(4) -1 = -3
3 =-3 extraneous
x=2
sqrt(2+7) -1 = 2
sqrt(9) -1 = 2
3 -1 =2
2 =2 true
A manufacturer of radio sets produced 600 units in the third year and 700 units in the
seventh year. Assuming the production uniformly increases by a fixed number every year,
the production in the first year is
b) 530
d) 570
a) 500
c) 550
Answer:
Step-by-step explanation:
The easiest way to explain this is to use slope and then writing equations for lines. The reason for that is because we are told that the production uniformly increases. That "uniform increase" is the rate of change, and since the rate of change is constant, we are talking about the slope of a line, where the rate of change is constant throughout the whole length of the line.
Create coordinates from the info given:
In the third year, 600 units were made. Time is always an x thing, so the coordinate is (3, 600). Likewise for the other bit of info. Time is always an x thing, so the coordinate is (7, 700). Applying the slope formula:
[tex]m=\frac{700-600}{7-3}=\frac{100}{4}=25[/tex] which means that 25 units per year are produced. Write the equation to find the number of units produced in any year. I used the point-slope form of a line to do this:
y - 600 = 25(x - 3) and
y - 600 = 25x - 75 so
y = 25x + 525
If we want to know the number of units in the first year, we will replace x with 1 and do the math:
y = 25(1) + 525 so
y = 550 units, choice C.
solve for x.
solve for x.
solve for x.
Answer:
x = 10
Step-by-step explanation:
7(x+1+7)=6(x+5+6)
or, 7(x+8)=6(x+11)
or, 7x+56=6x+66
or, 7x-6x=66-56
or, x=10
Answered by GAUTHMATH
Can someone help me on this please
The choices :
Three
B , E , D
Find the value of b. PLEASE HELP ASAPPPP!!!!
A. 56
B. 140
C. 230
D. 65
Answer:
C
Step-by-step explanation:
b=360-2(65)=360-130=230
Answer:
230
Step-by-step explanation:
b= 360-2(65)
=360-130
=230
(PLEASE ANSWER ASAP I JUST NEED TO SEE IF I GOT THE RIGHT ANSWER PLEASE EXPLAIN ALSO)
Answer:
37.15 pounds left
Step-by-step explanation:
Add the two pound values
1.3+1.75= 3.05
Subtract it from the total number of pounds in the bag
40.2-3.05
=37.15
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU K NOW THE ANSWER!!
The entire group of objects or individuals under consideration in a survey is the ________________.
A. population
B. establishment
C. corporation
D. entity
Answer:
A: population
Step-by-step explanation:
Um its just the definition of the word i think.
Population: a collection of persons, things, or objects under study.
Will Mark Brainlest Help Please ,,,,
[tex]\\ \sf\longmapsto 2x+y=2[/tex]
[tex]\\ \sf\longmapsto 2x=2-y[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2-y}{2}\dots(1)[/tex]
And
[tex]\\ \sf\longmapsto x+1=y+2[/tex]
[tex]\\ \sf\longmapsto x=y+2-1[/tex]
[tex]\\ \sf\longmapsto x=y+1[/tex]
Put the value[tex]\\ \sf\longmapsto \dfrac{2-y}{2}=y+1[/tex]
[tex]\\ \sf\longmapsto 2-y=2(y+1)[/tex]
[tex]\\ \sf\longmapsto 2-y=2y+2[/tex]
[tex]\\ \sf\longmapsto 2-2=2y+y[/tex]
[tex]\\ \sf\longmapsto 3y=0[/tex]
[tex]\\ \sf\longmapsto y=\dfrac{0}{3}[/tex]
[tex]\\ \sf\longmapsto y=\infty[/tex]
Put in eq(1)[tex]\\ \sf\longmapsto x=\dfrac{2-y}{2}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2-\infty}{2}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{2}{2}[/tex]
[tex]\\ \sf\longmapsto x=1[/tex]
Answer:
x=1 , y=0
Step-by-step explanation:
2x+y=2.......1
x+1=y+2
x-y=2-1
x-y=1...... 2
from equation 2 we get ,
x-y=1
x=1+y
putting the value of x in equation 1 we get,
2*(1+y) +y=2
2+2y+y=2
2+3y=2
3y=2-2
3y=0
y=0/3
y=0
putting the value of y in equation 2 we get,
x-0=1
x=1+0
x=1
hence x=1 , y=0
An equilateral triangle has a perimeter of 18 feet. If a square whose sides have the same length as one side of the triangle is built, what will be the area of the square?
Answer:
36 ft²
Step-by-step explanation:
equilateral means all sides are equally long.
a triangle has 3 sides.
in our case they are all equally long.
and their sum (all 3 sides together) is the perimeter
P = 18 = 3 × side length
side length = 18/3 = 6 ft
a square with the same side length (6) had then an area of
side length × side length = 6×6 = 6² = 36 ft²
it is important to remember : a length is measured e.g. in feet (ft). an area is then meshed in square-feet (ft²). it is important to add this to the calculated numbers to express the right dimension of these numbers.
Please help will give brainliest, pls don’t just guess
Answer:
B = multiply both sides by 2y+1
Step-by-step explanation:
Answer:
B. multiply both sides by the equation 2y + 1
Answer pls……………………….
Answer:
D
Step-by-step explanation:
x^2=y^3
Then x^6=y^9 but x^3z=z^9 so 3z=6, z=2
Answer:
z = 2
Step-by-step explanation:
[tex]x^{3z} = y^{9}\\\\x^{3z} =y^{3*3} \\\\x^{3z}= (y^{3})^{3}\\\\x^{3z}=(x^{2})^{3}\\\\x^{3z} = x^{6}[/tex]
As bases are same, compare the powers
3z = 6
z = 6/3
z = 2
Find the coordinate of J' after a reflection of the triangle about the y-axis. Write your answer in the form (a,b)
Answer:
A (3,3)
J (5,2)
L (0,0)
Step-by-step explanation:
.........................