A rectangular park of length 60 m breadth 50 m encloses w volleyball court of length 18 m and breadth 10 m. Find the area of the park excluding the court at the rate of Rs 110 per square meter.​

Answers

Answer 1

Given

A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.

To find:

The area of the park excluding the court at the rate of Rs 110 per square meter.​

Solution:

Area of a rectangle is:

[tex]Area=length \times breadth[/tex]

Area of whole park is:

[tex]A_1=60 \times 50[/tex]

[tex]A_1=3000[/tex]

Area of volleyball court is:

[tex]A_2=18 \times 10[/tex]

[tex]A_2=180[/tex]

Now, the area of the park excluding the court is:

[tex]A=A_1-A_2[/tex]

[tex]A=3000-180[/tex]

[tex]A=2820[/tex]

Therefore, the area of the park excluding the court is 2820 square meter.


Related Questions

NEED some HElp please
Explain why the amount of money in the account at the end of the first year is given by the formula with n as the exponent:

P = P∨0 (1 + r/n)^n

Answers

Answer:

Is this answer correct.Does the anwer help you

Find the value of x-8 when x=16.

Answers

Answer:

8

Step-by-step explanation:

x=16

x(16)-8=8

The answer is 8, plug in 16 for x (16)-8=8

1. write it on a piece of paper

Answers

[tex]\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{6+11}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{17}{4}[/tex]

2:-

[tex]\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}[/tex]

[tex]\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}[/tex]

[tex]\\ \sf\longmapsto \dfrac{155+225}{35}[/tex]

[tex]\\ \sf\longmapsto \dfrac{380}{35}[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

3:-

[tex]\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{132+160}{30}[/tex]

[tex]\\ \sf\longmapsto \dfrac{292}{30}[/tex]

4:-

[tex]\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}[/tex]

[tex]\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}[/tex]

[tex]\\ \sf\longmapsto 4+\dfrac{10}{3}[/tex]

[tex]\\ \sf\longmapsto \dfrac{12+10}{3}[/tex]

[tex]\\ \sf\longmapsto \dfrac{22}{3}[/tex]

1.

[tex] \bf \large \longrightarrow \: \: 1 \frac{1}{2} \: + \: 2 \frac{3}{4} \: = \: \\ [/tex]

[tex] \bf \large \longrightarrow \: \: \frac{3}{2} \: + \: \frac{11}{4} \\ [/tex]

[tex] \bf \large \longrightarrow \: \: \frac{6 \: + \:11 }{4} \\ [/tex]

[tex] \bf \large \longrightarrow \: \: \frac{17}{4} \\ [/tex]

2.

[tex]\bf \large \longrightarrow \: \: 4 \frac{3}{7} \: + \: 6 \frac{1}{5} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{31}{7} \: + \: \frac{31}{5} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{155 \: + \: 217}{35} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{372}{35} \\ [/tex]

3.

[tex]\bf \large \longrightarrow \: \: 4 \frac{2}{5} \: + \: 5 \frac{2}{6} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{22}{5} \: + \: \frac{32}{6} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{132 \: + \: 160}{30} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{292}{30} \\ [/tex]

4.

[tex]\bf \large \longrightarrow \: \: 3 \frac{7}{7} \: + \: 3 \frac{1}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{28}{7} \: + \: \frac{10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \cancel\frac{28 ^{4} }{7 \: ^{1} } \: + \: \frac{10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{4}{1} \: + \: \frac{10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{12 \: + \: 10}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \frac{22}{3} \\ [/tex]

The lengths of the diameters of two concentric circles are 6 and 8. What is the distance between the circles?

Answers

Answer:  1 unit

Explanation:

The diameters are 6 and 8, which cut in half to 3 and 4 respectively.

The difference in these radii values is 4-3 = 1.

This is the distance from one circle's edge to the other circle's edge, such that we're on the same line that goes through the center of the circles. This is the gap width or ring width so to speak.

please answer algebra question I put it into a calculator and it didn’t work 4x-5=4(x-2)+3

Answers

Answer:

solving for X it would be (-infinity ♾️, +infinity ♾️) or all real numbers

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
The median of the lower half of the data set is the _____________.
A. Third quartile
B. First quartile
C. Fourth quartile
D. Second quartile

Answers

Answer:

B. First quartile

Step-by-step explanation:

The first quartile is the first 25% of a line graph, and the median of the lower half of a data set would be the median of the median, which means it would split the graph at 25%

provisions for 630 men to last for 25 days. How many men must be transferred to another camp so that the food lasts for 30 days?​

Answers

Answer:

105

Step-by-step explanation:

25 days = Food for 630 men

30 days = x           (Inverse variation)

30 * x = 630 * 25

x = 630 * 25/30

  = 21 * 25

  = 525 men.

630 - 525 = 105 men.

Therefore, 105 men must be transferred to another camp so that the food lasts for 30 days.

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!

Answers

Answer: will be A

Step-by-step explanation:

The most reasonable answer would be A

A regular square pyramid has a slant height of 5 in and a base area of 49 in2. Find the surface area of the pyramid. ------------------------------------------------------------------------------------------- 171.5 square inches 70 square inches 119 square inches 245 square inches

Answers

Answer:

C: 119 square inches

Step-by-step explanation:

We are given;

Slant height; L = 5 in

Base area; B = 49 in²

Since it's a square pyramid, the base portion has a square shape.

Thus, area of base = x²

Where x is a side of the square.

Thus;

x² = 49

x = √49

x = 7

Perimeter of base = 7 × 4 = 28 in

Area of pyramid = ½PL + B

Plugging in the relevant values;

Area of pyramid = (½ × 28 × 5) + 49

Area of pyramid = 119 in²

What is the correct answer to this multiple choice question? Please help!

Answers

Answer:

[tex]\sqrt[3]{4}[/tex]

Step-by-step explanation:

To solve this we need to take the square root of both sides with a certain degree.

[tex]4^6 = a^{18}[/tex]

We can take the root of both sides with a degree of 18.

[tex]\sqrt[18]{4^6} = \sqrt[18]{a^{18}} \\(4^6)^{\frac{1}{18} } = a\\a = 4^{\frac{6}{18} } = 4^{\frac{1}{3} } = \sqrt[3]{4}[/tex]

It's helpful to understand that when a number has its square root taken with some degree n. The square root can be represented as just the value raised to the (1/n) power.

It's also helpful to understand that when you raise something to the power of another power, you can simply multiply the powers together. For instance (2^3)^5 = 2^15

Find the surface area of the composite figure

Answers

Answer: SA = 644 cm²

Step-by-step explanation:

STEP ONE: Find the surface area of the smaller rectangle (green)

There are in total 5 sides because one of the sides is not shown on the surface level.

Upper base = 3 × 3 = 9 cm²

4 sides = 3 × 8 × 4 = 96 cm²

Total = 9 + 96 = 105 cm²

STEP TWO: Find the surface area of the larger rectangle (orange)

There are in total 5 whole sides with one side covered by the base of the smaller rectangle (green) which should later be subtracted.

Front and back = 7 × 10 × 2 = 140 cm²

Left and right = 7 × 12 × 2 = 168 cm²

Lower base = 10 × 12 = 120 cm²

Upper base = 10 × 12 - 3 × 3 = 111 cm²

Total = 140 + 168 + 120 + 111 = 539 cm²

STEP THREE: Find the total surface area

SA = Green + Orange = 105 + 539 = 644 cm²

Hope this helps!! :)

Please let me know if you have any questions

HELP QUICK ILL GIVE BRAINLIEST

Answers

Answer:

here's the answer to your question

Answer: √18

√(4-1)^2 + (5-2)^2

√9 + 9

√18

Answered by Gauthmath must click thanks and mark brainliest

When leaving a town, a car accelerates from 30 kmh-1 to 60 kmh-1 in 5 s. Assuming the
acceleration is constant, find the distance travelled in this time.
A. 6 m
B. 62.5 m
C. 41.7 m
D. 20.8 m

Answers

Answer:

B .62.5 m

Step-by-step explanation:

convert Kmh-1 in to ms-1

30 Kmh-1 = (30×1000) ÷3600 = 8.3ms-1

60 Kmh-1 = (60×1000) ÷3600 = 16.6 ms-1

acceleration = (16.6 - 8.3) ÷ 5 = 1.66 ms-2

V^2 = U^2 +2aS

(16.6)^2 = (8.3)^2 + 2×1.66 ×S

S = 62.5 m


write x²-y² in factorize form.
write (p+p) ²in expanded form. ​

Answers

Answer:

(x-y)^2

p^2+p^2

Step-by-step explanation:

^2 means square

Answer:

see explanation

Step-by-step explanation:

x² - y² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

x² - y²

= (x - y)(x + y)

------------------------------

(p + p)²

= (2p)²

= 2p × 2p

= 4p²

Does the point (2, 6) lie on the circle shown? Explain.
O Yes, the distance from (3, 0) to (0, ) is 3 units.
O Yes, the distance from (0, 0) to (2, V6) is 3 units.
O No, the distance from (3, 0) to (2, 6) is not 3 units.
O No, the distance from (0, 0) to (2, 6) is not 3 units.

Answers

Answer:

A.

Step-by-step explanation:

the square root of 6 is roughly 1.57

so that means the ordered pair would read (2,1.57).

if you were to plot that point it would be on the circle.

Also the distance from the origin (0,0) to (3,0) is 3 units

We will see that the correct option is:

"No, the distance from (0, 0) to (2, 6) is not 3 units."

Does (2, 6) lie on the circle shown?

We know that the circle has a radius of 3 units, then we need to see if the distance between (0, 0) and (2, 6) is 3 units.

Here we have:

[tex]D = \sqrt{(6 - 0)^2 + (2 - 0)^2} = \sqrt{36 + 4} = \sqrt{40} \neq 3[/tex]

So the distance between (0, 0) and (2, 6) is different than 3 units, meaning that the point is not in the circle.

If you want to learn more about circles:

https://brainly.com/question/1559324

#SPJ5

Find the value of x for which (4/5)-4 X(4/5)-7 = (4/5)2x-1

Answers

Answer:

0.8 -4*0.8-7=0.8*2x-1

0.8-3.2-7=1.6x-1

0.8-10.2+1=1.6x

1.8-10.2=x1.6

-8.4=x 1.6

x= -8.4 / 1.6

x= - 5.25

i need help anybody ?

Answers

Answer and Step-by-step explanation:

Simply use the Pythagorean Theorem to solve.

The Pythagorean Theorem is used to solve for a side in right triangles.

[tex]A^{2} +B^{2}= C^{2}[/tex]

Plug the sides values into the equation.

[tex]A^{2} + 13^2 = 20^2\\\\A^2 + 169 = 400\\\\A^2 = 231\\\\A = 15.1987[/tex]<- This is the answer.

#teamtrees #PAW (Plant And Water)

if you have 500 dollars and spend 20 every week then what would be the slope explain

Answers

Answer:

y=-20m+500

Step-by-step explanation:

Elias made a polyhedron with 9 edges and 5 faces. Which solid could he have made?

Answers

The polyhedron that Elias could have made is a TRIANGULAR BASED PRISM.

Triangular based prism are as described below:

A triangular-based prism is known to consists of 9 edges and 5 faces as shown in the diagram below.

It is a three-sided prism and also a polyhedron made of a triangular base, a translated copy, and 3 faces joining corresponding sidesThe edges are made up of lines and these lines are the ones that intersect to form faces

Learn more here: https://brainly.com/question/16682058

Answer: c

Step-by-step explanation:

HELP DUE IN 10 MINUTES

Answers

Answer:

Step-by-step explanation:

For Part A, use the pythagorean theorem to find the height, which ca be found by finding one length of the leg. Using the imaginary bisector, you can determine one of the legs is 5 cm, and the hypotenuse is 13 cm

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse. Plug in the values to solve for one leg, you get 25+b^2=169

Solve algebraically, b^2= 144, so b=12, which is the height.

Part B

Determine the surface area of each cardboard piece, and add together.

20 × 13 × 2 = 520

1/2 × 10 × 12 × 2 = 120

20 × 10 = 200

So approximately 840 cm of cardboard was used

Can u help solve this

Answers

Answer:

Sure:)! the answer is-487.5

Step-by-step explanation:

1.3x3xr^31.3x3=3.93.9r^3r=55x5x5=1253.9x125=487.5

As said in the problem pie=3 as determined in the problem. Hence, the answer is 487.5

Hope this helps :)!

Step-by-step explanation:

[tex]volume = \frac{4}{3} \pi \: {r}^{3} \\ = here\pi = 3 \\ then \: v = \frac{4}{3} \times 3 \times {5}^{3} \\ = 4 \times 125 \\ = 500 {in}^{3} \\ thank \: you[/tex]

integers
[tex]18 \div ( - 9) = [/tex]
[tex] - 10 \div 2 = [/tex]
[tex] - 2 + ( - 6) = [/tex]
[tex] - 8 - 4 = [/tex]
[tex]( - 2 \times - 12) \div (18 \div - 9 = [/tex]
[tex](120 - 30) \div ( - 42 - 3) = [/tex]
[tex]1000 \div (125 \times - 2) = [/tex]
[tex](5 - 30) \div ( 8 - 3) = [/tex]
[tex]12 \div (4 - 8) = [/tex]


Answers

(1) 18÷(-9)= -2(2) -10÷2= -5(3) -2+(-6)= -2-6= -8(4) -8-4= -12(5) (-2×-12)÷(18÷9)= 24÷2= 12(6) (120-30)÷(-42-3)= 90÷(-45)= -2(7) 1000÷(125×-2)=1000÷(-250)= -4(8) (5-30)÷(8-3)= -25÷5= -5(9) 12÷(4-8)=12÷(-4)= -3

please mark this answer as brainlist

What is the expected value?

Answers

Answer:

2.1

Step-by-step explanation:

The expected value of a probability is given by the formula:

E(x) = Σxp(x)

Therefore from the table showing the winnings of a game, the expected value of the probability distribution is:

E(x) = Σxp(x) = (0 * 0.5) + (2 * 0.2) + (4 * 0.15) + (6 * 0.1) + (10 * 0.05)

E(x) = 0 + 0.4 + 0.6 + 0.6 + 0.5 = 2.1

Hence we can conclude that the expected value of the winnings of the game is 2.1.

Please help: 6m - m = 5/6(6m - 10)

Will mark brainliest!!

Answers

Answer:

No solution.

Step-by-step explanation:

[tex]6m-m=\frac{5}{6}(6m-10)\\5m=5m-\frac{25}{3}\\0\neq -\frac{25}{3}[/tex]

Therefore, there is no solution.

Simplify: squrt 18x⁷

Answers

Answer:

3x^3 ⋅ √2x

Step-by-step explanation:

I will be marking brainliest please help me with these questions.

Answers

Answer/Step-by-step explanation:

1. To find the area of the shaded region, you'd find the area of the white rectangular shape, next, find the area of the whole triangular shape, then find the difference of their areas to get the area of the shaded region. Thus, the formula to use would be:

Area of shaded region = area of triangle - area of rectangle

Area of shaded region = ½*base*height - length*width

1. a. Volume of triangular prism = area of triangular base * height of prism

Volume of triangular prism = ½bh * H

Where,

b = 6 m

h = 4 m

H = 8 m

Substitute

Volume of prism = ½*6*4*8

Volume of prism = 96 m³

b. Volume of sphere = ⁴/3πr³

Where,

r = 9 cm

Substitute

Volume = ⁴/3*π*9³

Volume = ⁴/3*π*729

Volume ≈ 3,053.6 cm³ (nearest tenth)

2. Use Pythagorean theorem to find the height of the cone

radius of the cone (r) = ½(16) = 8 cm

Slant height (l) = 11 cm

height (h) = ?

Using Pythagorean theorem, we have:

h = √(l² - r²)

Substitute

h = √(11² - 8²)

h = √(57)

h ≈ 7.5 cm (nearest tenth)

b. Volume of the cone = ⅓πr²h

where,

r = 8 cm

h = 7.5 cm

Volume = ⅓*π*8²*7.5

Volume = 502.7 cm³ (nearest tenth)

If 12 out of 30 fruits are oranges, how many oranges fruits will there be per 100 fruits total?​

Answers

Answer:

40 oranges are there in 100 fruites.

The numbers 8,x,9 and 36 are in proportion.Find x​

Answers

If you can give the proportion then it would be better.

I am asuming

8:x::9:36

Then 8:x::1:4

So x = 32

Answered by Gauthmath must click thanks and mark brainliest

Answer:

x = 32

Step-by-step explanation:

[tex]\frac{8}{x}[/tex] = [tex]\frac{9}{36}[/tex] = [tex]\frac{1}{4}[/tex] ( cross- multiply )

x = 8 × 4 = 32

m. Proportions
1) Write a proportion for the situation, then solve the
proportion to answer the question.
nation:
a. A 6 foot high fence casts a 7 foot shadow.
Standing beside the fence is a tree that casts a
31.5 foot shadow. How tall is the tree?

Answers

Answer:

height of tree is 27 ft

Step-by-step explanation:

The corresponding parts of the problem are in proportion

let h be the height of the tree , then

[tex]\frac{6}{h}[/tex] = [tex]\frac{7}{31.5}[/tex] ( cross- multiply )

7h = 189 ( divide both sides by 7 )

h = 27

Height of tree is 27 feet

The football team loses 5 yards on first down.
a. Write an integer to represent this situation.

Answers

Answer:

-5

Step-by-step explanation:

since it is a lose, it is represented by a negative sign.

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