A margin of error tells us how often the confidence interval estimates the parameter incorrectly. how often a confidence interval is correct. how accurate the statistic is when using it to estimate the parameter.

Answer:

y = 14

Step-by-step explanation:

[tex] \frac{15}{21} = \frac{5}{7} [/tex]

[tex] \frac{10}{x} = \frac{5}{7} [/tex]

[tex]x = 14[/tex]

Now,

10/15 = y/21

15y = 10*21

y = 210/15

y = 14

This is a Right answer...

I hope you understand..

Mark me as brainliest...

Answer:

A. 32

Step-by-step explanation:

If the center is (0, 0) and a point is (0, 4) then the distance from the center to that point is 4 units. That distance is the radius. If you are dilating by a factor of 4, multiply the radius by 4 and you get 16. The new radius is 16 and the diameter= radius*2.

16*2=32

Answer:

No mode

Step-by-step explanation:

Mode = number that appears the most

No number appears more than 1 time

Hence there is no mode

Answer:Should be no mode tell me if i'I'm wrong

Step-by-step explanation:

Answer:

about 7.3 years

Step-by-step explanation:

[tex]8600=5000(1+\frac{.075}{4})^{4*t}\\1.72=(1.01875)^{4t}\\log_{1.01875}1.72=4t\\29.19428479=4t\\t=7.298571198[/tex]

Answer:

The answer is t=7.3

I can't see the diagram sorry.

Step-by-step explanation:

Is there supposed to be a picture attached?

The question is incomplete. The complete question is :

The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?

Solution :

Given data :

Mean, μ = 1900

Standard deviation, σ = 65

Sample size, n = 150

Sample mean, [tex]$\overline x$[/tex] = 1902

Level of significance = 0.01

The hypothesis are :

[tex]$H_0 : \mu = 1900$[/tex]

[tex]$H_1 : \mu > 1900$[/tex]

Test statics :

We use the z test as the sample size is large and we know the population standard deviation.

[tex]$z=\frac{\overline x - \mu}{\sigma / \sqrt{n}}$[/tex]

[tex]$z=\frac{1902-1900}{65 / \sqrt{150}}$[/tex]

[tex]$z=\frac{2}{5.30723}$[/tex]

[tex]$z=0.38$[/tex]

Finding the p-value:

P-value = P(Z > z)

             = P(Z > 0.38)

             = 1 - P(Z < 0.38)

From the z table. we get

P(Z < 0.38) = 0.6480

Therefore,

P-value = 1 - P(Z < 0.38)

            = 1 - 0.6480

             = 0.3520

Decision :

If the p value is less than 0.01, then we reject the [tex]H_0[/tex], otherwise we fail to reject  [tex]H_0[/tex].

Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject  [tex]H_0[/tex].

Conclusion :

At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.

Answer:

Growth: y = 1700(1.25)^t, y = 4000(1.0825)^t, y = 1.5(10)^t

Decay: y =240(1/2)^t, y = 12,000(0.72)^t,  y = 8000(0.97)^t

Step-by-step explanation:

In an exponential equation, growth and decay are determined by the factor you are multiplying by exponentially. If it's under 1 you're basically exponentially dividing the initial value. Over 1 and you are increasing the value.

Answer:

[tex]{ \tt{y = \frac{2 {x}^{2} + 5x + 2}{ {x}^{2} - 4x + 3 } }} \\ x - intercept : y = 0 \\ { \tt{ \frac{2 {x}^{2} + 5x + 2 }{ {x}^{2} - 4x + 3 } = 0 }} \\ \\ { \tt{2 {x}^{2} + 5x + 2 = 0}} \\ x = \frac{1}{2} \: \: and \: \: x = - 2[/tex]

Answer:

Step-by-step explanation:

This appears to be an SSA application of solving the triangle

We have 2 sides, so we will use the law of cosines

The law of cosines defines for a triangle ABC with side a/b/c with corresponding angles A/B/C

a^2 = b^2+c^2 - 2*b*c * (cos A)

this applies to the other 2 sides

first using the pythagorean theorem we find that BC = sqrt(55)

then we substitute all 3 sides into our equation to find angle A

55 = 64 + 9 - 2*8*3* (cos A)

18 = 2*8*3(cos A)

3/8 = (cos A)

and angle A is approximately 68 degrees

Please check if I'm correct

Answer:

67.98°

Step-by-step explanation:

Given 2 sides, you can find the missing angle of a right triangle using basic trig functions.

Since Cos∅=adjacent/ hypotenuse, we can use the adjacent side to the angle, 3 and they hypotenuse, 8 in the ratio by doing 3/8. This is 0.375. Then we use the inverse cosine function to find the angle. This gives 67.98°

Or

Cos∅=0.375

Cos^-1= 67.98

Answer:

The price of 1 exercise book is $122.45.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the price of one exercise book.

y is the price of one textbook.

Total cost of 10 exercise books and 2 textbooks is $1400.00.

This means that:

[tex]10x + 2y = 1400[/tex]

Since we want x:

[tex]2y = 1400 - 10x[/tex]

[tex]y = 700 - 5x[/tex]

One also finds the total cost of 3 textbooks and 30 exercise books is $3000.

This means that:

[tex]3x + 30y = 3000[/tex]

Since [tex]y = 700 - 5x[/tex]

[tex]3x + 30(700 - 5x) = 3000[/tex]

[tex]3x + 21000 - 150x = 3000[/tex]

[tex]147x = 18000[/tex]

[tex]x = \frac{18000}{147}[/tex]

[tex]x = 122.45[/tex]

The price of 1 exercise book is $122.45.

Answer:

[tex]\log_{10}(147) = 2.1673[/tex]

Step-by-step explanation:

Given

[tex]\log_{10} 3 = 0.4771[/tex]

[tex]\log_{10} 5 = 0.6990[/tex]

[tex]\log_{10} 7= 0.8451[/tex]

[tex]\log_{10} 11 = 1.0414[/tex]

Required

Evaluate [tex]\log_{10}(147)[/tex]

Expand

[tex]\log_{10}(147) = \log_{10}(49 * 3)[/tex]

Further expand

[tex]\log_{10}(147) = \log_{10}(7 * 7 * 3)[/tex]

Apply product rule of logarithm

[tex]\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)[/tex]

Substitute values for log(7) and log(3)

[tex]\log_{10}(147) = 0.8451 + 0.8451 + 0.4771[/tex]

[tex]\log_{10}(147) = 2.1673[/tex]

Answer:

E and C

Step-by-step explanation:

Given:

The limit problem is:

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]

To find:

The value of the given limit problem.

Solution:

We have,

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]

In the function [tex]-2x^5-3x+1[/tex], the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex]

Therefore, [tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex].

Answer:

[tex]y = \frac{5ct}{3b}[/tex]

Step-by-step explanation:

[tex]\frac{5t}{4y} =\frac{3b}{4c}[/tex]

1. start by multiplying y to both sides:

y × [tex]\frac{5t}{4y} =\frac{3b}{4c}[/tex] × y

[tex]\frac{5t}{4} =\frac{3b}{4c}y[/tex]

2. divide both sides by [tex]\frac{3b}{4c}[/tex]

[tex]\frac{5t}{4}/\frac{3b}{4c} =\frac{3b}{4c}y/\frac{3b}{4c}[/tex]

[tex]y = \frac{5ct}{3b}[/tex]

Answer:

x^2+y^2=r^2 is quation of circle whose centre is (0,0)

Given:

The equation is:

[tex]\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8[/tex]

To find:

The solution for the given equation.

Solution:

We have,

[tex]\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8[/tex]

It can be written as:

[tex]\ln x+\ln x^2=2\ln 8[/tex]              [tex][\because \ln e^x=x][/tex]

[tex]\ln (x\cdot x^2)=2\ln 8[/tex]              [tex][\because \ln a+\ln b=\ln (ab)][/tex]

[tex]\ln (x^3)=\ln 8^2[/tex]         [tex][\because \ln x^n=n\ln x ][/tex]

On comparing both sides, we get

[tex]x^3=8^2[/tex]

[tex]x^3=64[/tex]

Taking cube root, we get

[tex]x=\sqrt[3]{64}[/tex]

[tex]x=4[/tex]

Therefore, the required solution is [tex]x=4[/tex].

Answer:

x=4

Step-by-step explanation:

What is the true solution to the equation below?

ln e Superscript ln x Baseline + ln e Superscript ln x squared Baseline = 2 ln 8

x = 2

x = 4

x = 8

Answer:

162 t-shirts, 324 posters

Step-by-step explanation:

Assuming they only sold t-shirts and posters, you can find the amount of t-shirts sold by dividing 486 by 3, or multiplying it by 1/3. This equals 162. This is because one third were t-shirts. To find the rest you just subtract 162 from the total of 486, or multiply 162 by 2. (since you already know the amount of 1/3, 2/3 is double that.)

Answer:

z = (2xy-x)

Step-by-step explanation:

Let the first number be x and the other number is z.

According to question,

The average of two number is xy i.e.

[tex]\dfrac{x+z}{2}=xy\\\\x+z=2xy\\\\z=2xy-x[/tex]

So, the value of z is (2xy-x) i.e. the other number is (2xy-x).

Answer:

18 feet

Step-by-step explanation:

The question is  illustrated using the attached image.

From the image, we have:

[tex]\theta = 31.43^o[/tex] --- angle of depression

[tex]h = 11ft[/tex] --- Emir's height

Required

The distance from the base of the tree (x)

From the attached triangle, we have:

[tex]\tan(90 - \theta) = \frac{Opposite}{Adjacent}[/tex]

This gives:

[tex]\tan(90 - 31.43) = \frac{x}{11}[/tex]

[tex]\tan(58.57) = \frac{x}{11}[/tex]

Make x the subject

[tex]x = 11 * \tan(58.57)[/tex]

[tex]x = 18.00[/tex]

Answer:

18

Step-by-step explanation:

took the test

Answer:

Step-by-step explanation:

Let take a look at the given function y = 4x - 1 whose point is located between (1,3) and (4,15) on the graph.

Here, the function of y is non-negative. Now, expressing y in terms of x in y = 4x- 1

4x = y + 1

[tex]x = \dfrac{y+1}{4}[/tex]

[tex]x = \dfrac{1}{4}y + \dfrac{1}{4}[/tex]

By integration, the required surface area in the revolve is:

[tex]S = \int^{15}_{ 3} 2 \pi g (y) \sqrt{1+g'(y^2) \ dy }[/tex]

where;

g(y) = [tex]x = \dfrac{1}{4}y + \dfrac{1}{4}[/tex]

∴

[tex]S = \int^{15}_{ 3} 2 \pi \Big( \dfrac{1}{4}y + \dfrac{1}{4}\Big) \sqrt{1+\Bigg(\Big( \dfrac{1}{4}y + \dfrac{1}{4}\Big)'\Bigg)^2 \ dy }[/tex]

[tex]S = \dfrac{1}{2} \pi \int^{15}_{ 3} (y+1) \sqrt{1+\Bigg(\Big( \dfrac{1}{4}\Big ) \Bigg)^2 \ dy } \\ \\ \\ S = \dfrac{1}{2} \pi \int^{15}_{ 3} (y+1) \dfrac{\sqrt{17}}{4} \ dy[/tex]

[tex]S = \dfrac{\sqrt{17}}{8} \pi \int^{15}_{ 3} (y+1) \ dy[/tex]

[tex]S = \dfrac{\sqrt{17} \pi}{8} (\dfrac{1}{2}(y+1)^2)\Big|^{15}_{3} \\ \\ S = \dfrac{\sqrt{17} \pi}{8} (\dfrac{1}{2}(15+1)^2-\dfrac{1}{2}(3+1)^2 ) \\ \\ S = \dfrac{\sqrt{17} \pi}{8} *120 \\ \\\mathbf{ S = 15 \sqrt{17}x}[/tex]

Answer:

y=-2

Step-by-step explanation:

y=-2*-7*+8y

y= 14+8y

-7y=14

y=-2

That's a question about percentage.

Let's imagine that we want to know how much is 90% of 200. To do this calculation, we should multiply 200 by 90 and then divide the result by 100. We do that because 90% is the same thing that [tex]\frac{90}{100} =0,9[/tex]. So, 90% of 200 is equal to:

[tex]\frac{200\cdot90}{100} =\\\\\frac{18000}{100} =\\\\180[/tex]

Now, imagine that you would like to know how much is 100% of 999. First, we multiply 999 by 100 and divide the result by 999. So, 100% of a number is equal to itself. That's a very important information, because it's possible to understand this:

Now, we can solve our problem! \o/

The options that the percentage is less than 100% are: 35% of 300, 62% of 182 and 89% of 525. Therefore, their answers will be less than the original number.

And, the option that the percentage is greater than 100% are: 250% of 18, 300% of 250 and 120% of 72. So, their answers will be greater than the original number.

On the image, you can see the answer in a table.

I hope I've helped. ^^

Enjoy your studies! \o/

Answer/Step-by-step explanation:

2. a. 5y - 3 = -18

Add 3 to both sides

5y - 3 + 3 = -18 + 3

5y = -15

Divide both sides by 5

5y/5 = -15/5

y = -3

b. -3x - 9 = 0

Add 9 to both sides

-3x - 9 + 9 = 0 + 9

-3x = 9

Divide both sides by -3

-3x/-3 = 9/-3

x = -3

c. 4 + 3(z - 8) = -23

Apply the distributive property to open the bracket

4 + 3z - 24 = -23

Add like terms

3z - 20 = -23

Add 20 to both sides

3z - 20 + 20 = - 23 + 20

3z = -3

Divide both sides by 3

3z/3 = -3/3

z = -1

d. 1 - 2(y - 4) = 5

1 - 2y + 8 = 5

-2y + 9 = 5

-2y + 9 - 9 = 5 - 9

-2y = -4

-2y/-2 = -4/-2

y = 2

3. First, find the sum of 3pq + 5p²q² + p³ and p³ - pq

(3pq + 5p²q² + p³) + (p³ - pq)

3pq + 5p²q² + p³ + p³ - pq

Add like terms

= 3pq - pq + 5p²q² + p³ + p³

= 2pq + 5p²q² + 2p³

Next, subtract 2pq + 5p²q² + 2p³ from 3p³ - 2p²q² + 4pq

(3p³ - 2p²q² + 4pq) - (2pq + 5p²q² + 2p³)

Apply distributive property to open the bracket

3p³ - 2p²q² + 4pq - 2pq - 5p²q² - 2p³

Add like terms

3p³ - 2p³ - 2p²q² - 5p²q² + 4pq - 2pq

= p³ - 7p²q² + 2pq

4. Perimeter of the rectangle = sum of all its sides

Perimeter = 2(L + B)

L = (5x - y)

B = 2(x + y)

Perimeter = 2[(5x - y) + 2(x + y)]

Perimeter = 2[5x - y + 2x + 2y]

Add like terms

Perimeter = 2(7x + y)

Substitute x = 1 and y = 2 into the equation

Perimeter = 2(7(1) + 2)

Perimeter = 2(7 + 2)

Perimeter = 2(9)

Perimeter = 18 units

5. First let's find the quotient to justify if the value we get is greater than or less than 2.25

7⅙ ÷ 3⅛

Convert to improper fraction

43/6 ÷ 25/8

Change the operation sign to multiplication and turn the fraction by the left upside down.

43/6 × 8/25

= (43 × 8)/(6 × 25)

= (43 × 4)/(3 × 25)

= 172/75

≈ 2.29

Therefore, the quotient of 7⅙ ÷ 3⅛ is greater than 2.25

Answer:

l don't know

Step-by-step explanation:

Answer:

(0, -9)

Step-by-step explanation:

The y intercept is the y value when x =0

(0, -9)

Answer:

A) [ 7/3,  (-7/9)(x/2),  7/27(x-2)^2,  (-7/81)(x-2)^3 ]

B) attached below

Step-by-step explanation:

A)  Using the definition of a Taylor series

The first four nonzero terms of the series for f(x) = 7/ (1 +x), a = 2

= [ 7/3,  (-7/9)(x/2),  7/27(x-2)^2,  (-7/81)(x-2)^3 ]

attached below is the detailed solution

B) Finding Maclaurin series for f(x)

f(x) = e^-5x

attached below

Associated radius of convergence = ∞  ( infinity )

Answer:

Iam going to do question 21

Step-by-step explanation:

1/7*x=2

1/7x=2

x=2:1/7

x=2*7/1

x=14

Answer:

$370,881

Step-by-step explanation:

firstly we we multiply 1,5% by 2yrs. the answer we get is 3,0%. we then multiply 3 % by $123,627 and get $370,881

If Lisa bought a house The value of the house increased by 1.5% each year for 2 years.  The value of the house was £123,627. The initial amount of the house is  95120.7.

Percentage, a relative value indicating hundredth parts of any quantity.

Given,

Lisa bought a house The value of the house increased by 1.5% each year for 2 years

By the end of 2 years, the value of the house was £123,627.

A=P(1+rt)

A is the final amount,

r is rate of interest

t is the time

P is principle amount.

123,627=P(1+1.5/100 (2))

123657=P(1+0.15(2))

123657=P(1+0.3)

123657=1.3P

Divide both sides by 1.3

P=95120.7

The initial amount of the house when Lisa bought is 95120.7

To learn more on Percentage click:

https://brainly.com/question/28269290

#SPJ2

Answer:

-3

Step-by-step explanation:

12x + 1 - 2(y + 2)

=> 12x + 1 - 2y - 4

=> 12x - 3 - 2y

Answer:

-3

Step-by-step explanation:

12x+1-2y-4

12x+1-2y-4

12x-2y-3