a. Do the waves made by the two faucets travel faster than the waves made by just one faucet?
b. How do you know this? Describe how the two-faucet wave pattern compares with the one-faucet pattern.
c. Describe what happens to the two-faucet wave pattern as the separation of the faucets is increased.

We know

[tex]\boxed{\sf Work\:Done=Force\times Displacement} [/tex]

[tex]\\ \rm\longmapsto Work\:done=0.420\times 4.60[/tex]

[tex]\\ \rm\longmapsto Work\:done=1.932J[/tex]

56.1∘

Question: A glass is half-full of water, with a layer of vegetable oil (n = 1.47) floating on top. A ray of light traveling downward through the oil is incident on the water at an angle of 56.1∘ .

A glass is half-full of water, with a layer of vegetable oil (n ...https://study.com › academy › answer › a-glass-is-half-ful...

Answer:

Explanation:

( a ) At top position , vertical component of velocity will be zero .

So answer is position no (3)

b )

At position (3) which is the topmost position , acceleration is acting due to gravity , so it will be downwards.

c )

Horizontal component of acceleration at all points will be zero because gravity acts vertically downwards.

d )

Vertical displacement will be zero at position ( 1 ) and ( 5 )

e )

Displacement is maximum at extreme  position , ie at position ( 5 )

f )

Speed is highest at position (1) and it is lowest at position ( 3 )

From highest to lowest

( 1 ) , ( 2 ) , ( 3 )

Answer:

v(7) = 52.915 m/s

Explanation:

First, find the value for acceleration.

F = ma

100 = .5 * a

a = 200 m/s²

Next find the velocity at x = 7 using kinematic equations.

v² = v₀² + 2a(Δx)

v² = (0)² + 2(200)(7)

v = [tex]\sqrt{2800}[/tex]

v = 52.915 m/s

5 kg of liquid oxygen at -220°C will have the most thermal energy due to its higher mass and temperature.

Thermal energy is the total heat required to raise the entire mass of a given substance.

Q = mcΔθ

where;

Thus, 5 kg of liquid oxygen at -220°C will have the most thermal energy due to its higher mass and temperature.

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Answer:

Explanation:

You final velocity is correct but not to the correct number of significant digits. The actual answer should be 18.1 m/s. We will use that to find the total time the stone was in the air in the equation:

v = v₀ + at

18.1 = 6.63 + (-9.81)t and

11.5 = -9.81t so

t = 1.17 seconds.

We know this was how long the stone was in the air (as compared to the time that the stone took to reach its max height or some other height) because we used the velocity with which the stone hit the ground to find the total time the rock was in the air before it hit the ground going at that velocity.

Answer:

Creation of energy by joining the nuclei of two hydrogen atoms to form helium

When a liquid is cooled,the kinetic energy of the particles decreases. The force of attraction between the particles increases, the space between the particles decreases.

Answer:

Explanation:

Bhjb

Explanation:

its because a concrete surface is a hard surface which doesn't absorb the energy of gravitation when we fall down so we get hurt more badly..

hope this helps

Answer:

a) [tex]F=940.8N[/tex]

b)  [tex]S=234.14m[/tex]

c)  [tex]W=2.2*10^5J[/tex]

d)  [tex]W=0[/tex]

Explanation:

Mass [tex]m=160kg[/tex]

Velocity [tex]v=53m/s[/tex]

Time [tex]t=9seconds[/tex]

a)

Generally the Newton's equation for motion is mathematically given by

[tex]a=\frac{v}{t}[/tex]

[tex]a=\frac{53}{9}[/tex]

[tex]a=5.9m/s^2[/tex]

Therefore

F=ma

[tex]F=160*5.88[/tex]

[tex]F=940.8N[/tex]

b)

Generally the Newton's equation for motion is mathematically given by

[tex]S=0.5at^2[/tex]

[tex]S=0.5*5.9*9^2[/tex]

[tex]S=234.14m[/tex]

c)

Generally the Newton's equation for  work done is mathematically given by

[tex]W=Fd[/tex]

[tex]W=940.8*238.14[/tex]

[tex]W=2.2*10^5J[/tex]

d)

Generally the Newton's equation for  work done  by the force of the road on the wheels is mathematically given by

[tex]W=Fdcos\theta[/tex]

[tex]W=0[/tex]

The sign is held in equilibrium. Using Newton's second law, we set up the equations of the net forces acting on the sign in the horizontal and vertical directions:

∑ F (horizontal) = T₁ cos(29.5°) - T₂ cos(44.5°) = 0

(right is positive, left is negative)

∑ F (vertical) = T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N = 0

(up is positive, down is negative)

Solve the system of equations. I use elimination here:

• Multiply the first equation by sin(29.5°) and the second by cos(29.5°):

sin(29.5°) (T₁ cos(29.5°) - T₂ cos(44.5°)) = 0

cos(29.5°) (T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N) = 0

T₁ cos(29.5°) sin(29.5°) - T₂ cos(44.5°) sin(29.5°) = 0

T₁ cos(29.5°) sin(29.5°) + T₂ cos(29.5°) sin(44.5°) = (215 N) cos(29.5°)

• Subtract the first equation from the second to eliminate T₁ :

T₂ cos(29.5°) sin(44.5°) - (- T₂ cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)

• Solve for T₂ :

T₂ (cos(29.5°) sin(44.5°) + cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)

T₂ sin(74.0°) = (215 N) cos(29.5°)

… … … (using the fact that sin(x + y) = sin(x) cos(y) + cos(y) sin(x))

T₂ = (215 N) cos(29.5°) / sin(74.0°)

T₂ ≈ 195 N

• Solve for T₁ :

T₁ cos(29.5°) - T₂ cos(44.5°) = 0

T₁ cos(29.5°) = T₂ cos(44.5°)

T₁ = T₂ cos(44.5°) / cos(29.5°)

T₁ ≈ 160. N

90 degrees - 30 = 60 degrees

Velocity = (5m/s - 4.35m/s x cos(30)) / cos(60)

Velocity = 2.47 m/s

The answer is D) 2.47 m/s at 61.9 degrees

The velocity and angle of the second ball after the collision are (A.) 1.25 m/s at  31.2° below the horizontal. Option A

Use the conservation of momentum and conservation of kinetic energy to solve this problem.

Let's denote the velocity and angle of the second ball after the collision as v₂ and θ₂, respectively.

Thus:

Conservation of momentum: [tex]m_1v_1 = m_1v_1'cos(30^o) + m_2v_2cos(\theta_2)[/tex]

Conservation of kinetic energy: [tex](1/2)m_1v_1^2 = (1/2)m_1v_1'^2 + (1/2)m_2v_2^2[/tex]

where m₁ and m₂ are the masses of the first and second balls, respectively.

Since the masses and initial velocity are the same, we can simplify the equations to:

m₁v₁ = m₁v₁'cos(30°) + m₂v₂cos(θ₂)

[tex]v_1^2 = v_1'^2 + v_2^2[/tex]

Substitute in the given values

[tex](1)(5) = (1)(4.35)cos(30^o) + (1)(v_2)cos(\theta_2)\\5^2 = 4.35^2 + v2^2\\v_2 = 1.25 m/s\\\theta2 = 31.2^o[/tex]

Therefore, the velocity and angle of the second ball after the collision are approximately 1.25 m/s at an angle of 31.2° below the horizontal.

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Answer:

256 ohms

Explanation:

Applying,

R = R'[1+α(T-T')]............. Equation 1

Where R = Final resistance of the wire, R' = Initial resistance of the wire, T = Final temperature, T' = Initial temperature, α = Temperature coefficient of resistance

From the question,

Given: R' = 200 ohms, T = 90 degrees, T' = 20 degrees, α = 0.004/degree

Substitute these values into equation 1

R = 200[1+0.004(90-20)]

R = 200[1+0.28]

R = 200(1.28)

R = 256 ohms

The resistance of the wire at 90 °C correct to the nearest ohm assuming the coefficient of resistance is 0.004 °C¯¹ is 256 ohm

α = R₂ – R₁ / R₁(T₂ – T₁)

0.004 = R₂ – 200 / 200(90 – 20)

0.004 = R₂ – 200 / 200(70)

0.004 = R₂ – 200 / 14000

Cross multiply

R₂ – 200 = 0.004 × 14000

R₂ – 200 = 56

Collect like terms

R₂ = 56 + 200

R₂ = 256 ohm

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Answer:

the amplitude of the oscillation of the given mass is 0.1 m.

Explanation:

The amplitude of an oscillation is the maximum displacement of the object from the equilibrium position.

The equilibrium position of the given mass in question is at the zero (0) mark.

The maximum displacement of the object from the equilibrium position is 0.1 m upwards or 0.1 m downwards.

Therefore, the amplitude of the oscillation of the given mass is 0.1 m.

Answer:

Explanation:

Relative velocity is defined as the velocity of an object B in the rest frame of another object A.

Answer:

[tex]8.46*10^8[/tex]

Complete question:

The recoil of a shotgun can be significant. Suppose a 3.6-kg shotgun is held tightly by an arm and shoulder with a combined mass of 15.0 kg. When the gun fires a projectile with a mass of 0.040 kg and a speed of 380 m/s, what is the recoil velocity of the shotgun and arm–shoulder combination?

Answer:

The recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s

Explanation:

Given;

combined mass of the shotgun and arm–shoulder, m₁ = 15 kg

mass of the projectile, m₂ = 0.04 kg

speed of the projectile, u₂ = 380 m/s

let the recoil velocity of the shotgun and arm–shoulder combination = u₁

Apply the principle of conservation of linear momentum;

m₁u₁  +  m₂u₂ = 0

m₁u₁ = - m₂u₂

[tex]u_1 = -\frac{m_2u_2}{m_1} \\\\u_1 = - \frac{0.04\times 380}{15} \\\\u_1 =-1.013 \ m/s\\\\u_1 = 1.013 \ m/s \ \ \ in \ opposite \ direction[/tex]

Therefore, the recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s

Answer:

the work required to turn the crank at the given revolutions is 8,483.4 J

Explanation:

Given;

torque required to turn the crank, T = 4.50 N.m

number of revolutions, = 300 turns

The work required to turn the crank is given as;

W = 2πT

W = 2 x 3.142 x 4.5

W = 28.278 J

1 revolution = 28.278 J

300 revlotions = ?

= 300 x 28.278 J

= 8,483.4 J

Therefore, the work required to turn the crank at the given revolutions is 8,483.4 J

Answer:

[tex]P=45.2W[/tex]

Explanation:

From the question we are told that:

Amplitude [tex]A=0.56m[/tex]

Period [tex]T=3.4s[/tex]

Wavelength [tex]\lambda=2.0[/tex]

Area [tex]a=0.14m^2[/tex]

Generally the equation for Power is mathematically given by

[tex]Power = 2 \pi ^2 \rho a(\frac{\lambda}{T})(\frac{1}{T})*A[/tex]

[tex]P= 2 3.142^2 1025 0.14(\frac{2.0}{3.4})(\frac{1}{3.4})^2*0.56^2[/tex]

[tex]P=45.2W[/tex]

Answer:

Solar radiation may be converted directly into electricity by solar cells (photovoltaic cells). In such cells, a small electric voltage is generated when light strikes the junction between a metal and a semiconductor (such as silicon) or the junction between two different semiconductors.

Explanation:

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Solar radiation may be converted directly into electricity by solar cells or photovoltaic cells. This is how solar energy is used to generate electricity.

Solar energy is the radiant light and heat from the Sun that is captured and used in a variety of technologies, including solar power to generate electricity, solar thermal energy, and solar architecture.

When the sun shines on a solar panel, the photovoltaic cells in the panel absorb the energy from the sun. When light strikes the junction of a metal and a semiconductor (such as silicon) or the junction of two different semiconductors, a small electric voltage is generated. This energy generates electrical charges that move in response to an internal electrical field in the cell, resulting in the flow of electricity.

Therefore, solar energy is used to generate electricity.

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Answer:

Will be doubled.

Explanation:

For a capacitor of parallel plates of area A, separated by a distance d, such that the charges in the plates are Q and -Q, the capacitance is written as:

[tex]C = \frac{Q}{V} = e_0\frac{A}{d}[/tex]

where e₀ is a constant, the electric permittivity.

Now we can isolate V, the potential difference between the plates as:

[tex]V = \frac{Q}{e_0} *\frac{d}{A}[/tex]

Now, notice that the separation between the plates is in the numerator.

Thus, if we double the distance we will get a new potential difference V', such that:

[tex]V' = \frac{Q}{e_0} *\frac{2d}{A} = 2*( \frac{Q}{e_0} *\frac{d}{A}) = 2*V\\V' = 2*V[/tex]

So, if we double the distance between the plates, the potential difference will also be doubled.

Air pressure has no effect at all in an ideal gas approximation. This is because pressure and density both contribute to sound velocity equally, and in an ideal gas the two effects cancel out, leaving only the effect of temperature. Sound usually travels more slowly with greater altitude, due to reduced temperature.

Answer:

The resulting pressure is 3 times the initial pressure.

Explanation:

The equation of state for ideal gases is described below:

[tex]P\cdot V = n \cdot R_{u}\cdot T[/tex] (1)

Where:

[tex]P[/tex] - Pressure.

[tex]V[/tex] - Volume.

[tex]n[/tex] - Molar quantity, in moles.

[tex]R_{u}[/tex] - Ideal gas constant.

[tex]T[/tex] - Temperature.

Given that ideal gas is compressed isothermally, this is, temperature remains constant, pressure is increased and volume is decreased, then we can simplify (1) into the following relationship:

[tex]P_{1}\cdot V_{1} = P_{2}\cdot V_{2}[/tex] (2)

If we know that [tex]\frac{V_{2}}{V_{1}} = \frac{1}{3}[/tex], then the resulting pressure of the system is:

[tex]P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)[/tex]

[tex]P_{2} = 3\cdot P_{1}[/tex]

The resulting pressure is 3 times the initial pressure.

Answer:

The energy stored in a body due to either it's position or change in shape is called gravitational potential energy.

Explanation:

[tex] \implies v_{av} = \dfrac{total \: displacement}{total \: time} [/tex]

[tex] \implies v_{av} = \dfrac{100}{10} [/tex]

[tex]\implies v_{av} =10 \: {ms}^{ - 1} [/tex]

Answer:

9.1875 Joules

Explanation:

The kinetic energy of an object can be given by the equation [tex]EK = \frac{1}{2} mv^{2}[/tex], in which m is the mass and v is the velocity. Plugging in the mass and velocity values into the equation, we get:

[tex]EK = \frac{1}{2} (6kg)(1.75m/s)^2\\EK = 9.1875 J[/tex]

Answer:

[tex]\boxed {\boxed {\sf 9.19 \ Joules}}[/tex]

Explanation:

Kinetic energy is the energy an object possesses due to motion. The following formula is used to calculated kinetic energy.

[tex]E_k= \frac{1}{2} mv^2[/tex]

In this formula, m is the mass and v is the velocity.

The car has a mass of 6.00 kilograms and a velocity of 1.75 meters per second.

Substitute the values into the formula.

[tex]E_k= \frac{1}{2} (6.00 \ kg )(1.75 \ m/s)^2[/tex]

Solve the exponent.

[tex]E_k= \frac{1}{2}(6.00 \ kg )(3.0625 \ m^2/s^2)[/tex]

Multiply the numbers together.

[tex]E_k=\frac {1}{2} (18.375 \ kg*m^2/s^2)[/tex]

[tex]E_k= 9.1875 \ kg*m^2/s^2[/tex]

The original measurements of mass and velocity both have 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredths place. The 7 in the thousandths place to the right (9.1875) tells us to round to 8 up to a 9.

[tex]E_k \approx 9.19 \ kg*m^2/s^2[/tex]

1 kilogram meter squared per second squared is equal to 1 Joule. Our answer of 9.19 kg*m²/² is equal to 9.19 Joules.

[tex]E_k \approx 9.19 \ J[/tex]

The kinetic energy of the toy care is approximately 9.19 Joules.

Answer:

65.87 s

Explanation:

For the first time,

Applying

v² = u²+2as.............. Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance

From the question,

Given:  u = 0 m/s (from rest), a = 1.99 m/s², s = 60 m

Substitute these values into equation 1

v² = 0²+2(1.99)(60)

v² = 238.8

v = √238.8

v = 15.45 m/s

Therefore, time taken for the first 60 m is

t = (v-u)/a............ Equation 2

t = (15.45-0)/1.99

t = 7.77 s

For the final 40 meter,

t = (v-u)/a

Given: v = 0 m/s(decelerates), u = 15.45 m/s, a = -0.266 m/s²

Substitute into the equation above

t = (0-15.45)/-0.266

t = 58.1 seconds

Hence total time taken to cover the distance

T = 7.77+58.1

T = 65.87 s

Answer:

R = 20.21 ohms

Explanation:

Given that,

The length of the wire, l = 200 ft

The diameter of the wire, d = 0.01 in

Radius, r = 0.005 in

200 ft = 60.96 m

0.005 in = 0.000127 m

The resistivity of copper is, [tex]\rho=1.68\times 10^{-8}\ \Omega-m[/tex]

So, the resistance of a wire is given by :

[tex]R=\rho \dfrac{l}{A}\\\\R=\rho \dfrac{l}{\pi r^2}\\\\R=1.68\times 10^{-8}\times \dfrac{60.96 }{\pi \times (0.000127 )^2}\\\\R=20.21\ \Omega[/tex]

So, the resistance of the copper wire is 20.21 ohms.

Complete Question

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.

Answer:

[tex]\phi=123.75[/tex]

Explanation:

From the question we are told that:

Height [tex]h=27m[/tex]

Period [tex]T=32sec[/tex]

Time [tex]t=75sec[/tex]

Generally the equation for angular velocity is mathematically given by

[tex]\omega=\frac{2 \pi}{T}[/tex]

[tex]\omega=\frac{2 \pi}{32}[/tex]

[tex]\omega=0.196rad/s[/tex]

Therefore

[tex]\theta=\omega t[/tex]

[tex]\theta=0.196rad/s*75sec[/tex]

[tex]\theta=843.75 \textdegree[/tex]

Therefore

[tex]\phi=\theta-2(360)[/tex]

[tex]\phi=123.75[/tex]