A business tenant has a percentage lease stating rent payment is greater of 2% of the business's total gross sales volume or a minimum base rental of $1,000.00 per month. In the past year, sales totaled $435,000. How much rent did the business pay?

Answer:

Look below.

Step-by-step explanation:

The location of the coordinate plane will be shown in the graph.

Coordinate geometry is the study of geometry using the points in space.

Henry gathered data about the types of nuts in five handfuls of mixed nuts.

The data he gathered is shown in the table.

Handful     Number of peanuts       Number of other nuts

  A                           9                                        7

  B                           6                                        5

  C                           8                                        9

  D                           5                                        7

  E                            7                                        4

The graph is shown below.

More about the coordinate geometry link is given below.

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1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

All of 4x+8 is under a cube root sign.

=====================================================

Work Shown:

To find the inverse, we swap x and y, then solve for y.

[tex]y = \frac{1}{4}x^3 - 2\\\\x = \frac{1}{4}y^3 - 2\\\\x+2 = \frac{1}{4}y^3\\\\4(x+2) = y^3\\\\4x+8 = y^3\\\\y^3 = 4x+8\\\\y = \sqrt[3]{4x+8}\\\\[/tex]

------------

Side note:

If [tex]f(x) = \frac{1}{4}x^3 - 2[/tex] and [tex]g(x) = \sqrt[3]{4x+8}[/tex], then [tex]f(g(x)) = x[/tex] and [tex]g(f(x)) = x[/tex]for all x values in the domain. Effectively, you use function composition to confirm that we have the correct inverse equation.

Answer:

ΔABC ~ ΔQPR by the Angle-Angle (AA) similarity theorem of two triangles

Step-by-step explanation:

The coordinates of the vertices are given as follows;

A = (1, 2), B =(9, 8), C = (1, 8)

P= (5, -3), Q = (-7, 6), R = (-7, -3)

The given dimensions of AB and PQ are 10, and 15 respectively

The, l lengths of the sides of triangles are found as follows;

[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]

For segment BC, we have;

B =(9, 8), C = (1, 8)

(x₁, y₁) = (9, 8), (x₂, y₂) = (1, 8), substituting gives;

Length BC = 8

For length CA, C = (1, 8) A = (1, 2)

(x₁, y₁) = (1, 8)

(x₂, y₂) = (1, 2)

The length found by substituting the values for (x₁, y₁), (x₂, y₂) in the length equation gives; Length CA = 6

Given that length  CA² + BC² = 8² + 6² = 64 + 36 = 100 = BA², we have by Pythagoras theorem, we have ΔABC is a right triangle

Similarly, for ΔQPR, we have;

Length QR, Q = (-7, 6), R = (-7, -3) = 9

Length PR, P= (5, -3), R = (-7, -3) = 12

QR² + PR² = 9² + 12² = 225 = 15² = PQ²

∴ ΔQPR is a right triangle

By comparing the ratio of the sides, we have;

cos(θ) = PR/PQ = 12/15 = 4/5, θ = cos⁻¹(4/5) = 36.9°

∠RPQ = 36.9°

sin(θ) = QR/PQ = 9/15 = 3/5

Similarly in triangle ΔABC, we have;

cos(θ) = BC/AB = 8/10 = 4/5

∠CBA = 36.9°

Therefore, ∠CBA ≅ ∠RPQ = 36.9°

Also ∠PRQ ≅ ∠BCA = 90° (Angle opposite hypotenuse side of right triangle

Therefore, ΔABC and ΔQPR are similar triangles by the Angle-Angle (AA) similarity theorem of two triangles.

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

[tex]\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}[/tex], with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}[/tex]

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}[/tex]

[tex]\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5[/tex]

So B has two solutions of 5 and -1.5.

Now to C!

[tex]\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}[/tex]

[tex]\frac{44}{8} = 5.5[/tex]

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

Answer:

Hey there!

1 1/10=1.1

2/25=0.08

Each serving requires 0.08 kg, and he has 1.1 kg.

Thus, he can make 1.1/0.08, or 13.75 servings.

Let me know if this helps :)

Answer:

13 servings of tofu dish.

Step-by-step explanation:

First, convert the fractions to decimal numbers:

1 1/10 kg = 0.1 kg

2/25 kg = 0.08 kg

Now find how many servings of tofu dish will cover 0.1 kg of tofu:

2/25 kg = 1 serving

1 1/10 kg = ?

= 1 1/10 ÷ 2/25 kg

= 11/10 × 25/2

= 55/4

= 13.75 servings

Approximate it to a whole number:

13 servings.

Answer:

x = 50°, y = z = 40°

Step-by-step explanation:

x = 50° ( Alternate angle )

z = 180° - (110 + 30)° = 180° - 140° = 40° ( sum of angles in Δ )

y = z = 40° ( Alternate angles )

Answer:

95%

Step by step explanation:

z = 17-21 / 2 and z = 25-21/2

z=-2 (2.28%) z=2 (97.72%)

97.72 - 2.28 = 5.44

100% - 5.44% is about equal to 95%

Answer:

T'(-1, -3)

U'(-8, -3)

V'(-9, -10)

W(1, -10)

Step-by-step explanation:

For each point, draw a segment from it to the line y = -x and perpendicular to the line, and extend it the same distance to the other side of the line.

T'(-1, -3)

U'(-8, -3)

V'(-9, -10)

W(1, -10)

Answer:

$29.25

Step-by-step explanation:

For every 1 hour, Carey earns $9.75.  Multiply $9.75 by 3 to find out how much she earns for 3 hours of work.

$9.75 × 3 = $29.25

Carey earns $29.25 for working 3 hours.

Answer:

29.25

Step-by-step explanation:

I got it right on edge!! trust me

Answer:

Hey there!

A simple way to think about slope is rise over run. Between any two points on this line, the rise is 3, and the run is -1.

3/-1=-3, so  the slope is -3.

Let me know if this helps :)

Answer:

quotient

Step-by-step explanation:

Answer:

quotient

Step-by-step explanation:

Cancelling identical factors in the numerator and the denominator will give the quotient. For example,x2+5x+6x+3=(x+2)(x+3)x+3 = x + 3

Answer:

>

Step-by-step explanation:

Even though its 0 its still greater than any negative number.

Answer:

Step-by-step explanation:

Answer:

D) 11 13 15 19 23 23 24 26.5 28 33​

Step-by-step explanation:

The box-and-whisker plot displayed above has the following key values that we can use to identify which of the given data set it matches. It has:

Minimum value = 11

Q1 = 15

Median = 23

Q3 = 26

Maximum value = 33

From the options given, using just the max and min value, we can conclude that the data set in option D matches the box plot.

The data set in option D has a minimum value of 11, and a maximum value of 33.

Answer:

y = 5x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 5, thus

y = 5x + c ← is the partial equation

To find c substitute (2, 13) into the partial equation

13 = 10 + c ⇒ c = 13 - 10 = 3

y = 5x + 3 ← equation of line

Answer:

a. €1200;$1667.70

Step-by-step explanation:

a. Number of euros

[tex]\text{euros} = \$1962 \times \dfrac{\text{1 euro}}{\text{\$1.635}} = \textbf{1200 euros}[/tex]

b. Dollars remaining

Dollars on hand                        = $1962.00

Less 15 % spent = 0.15 × 1962 =   -294.30

Balance remaining                   =  $1667.70

A rectangular lawn measuring 8m by 4m is surrounded by a flower bed of uniform width.

The combined area of the lawn and the flower bed is 165m^2. What is the width of the flower

:

Let x = the width of flower bed

:

Then the overall dimensions (flower bed & lawn) will be:

(2x + 8) by (2x + 4)

:

Overall area

(2x+8)*(2x+4) = 165

FOIL

4x^2 + 8x + 16x + 32 = 165

A quadratic equation

4x^2 + 24x + 32 - 165 = 0

4x^2 + 24x - 132 = 0

Simplify, divide by 4, results:

x^2 + 6x - 33 = 0

Use the quadratic formula to solve this

you have to solve each one to get your answer and I think that your answer will be inside the circle

Answer:

This is called the Unit Circle. It is used in trigonometry. It had a radius of 1.

It helps you when using the trig function of sin cos and tan.

Hope this helps!!!!

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\sqrt{x-3} +5=x\\\sqrt{x-3} =x-5\\squaring ~both~sides\\x-3=x^2-10x+25\\x^2-10x-x+25+3=0\\x^2-11x+28=0\\x^2-7x-4x+28=0\\x(x-7)-4(x-7)=0\\(x-7)(x-4)=0\\x=7,4[/tex]

put x=7 in the given equation

[tex]\sqrt{7-3} +5=7\\\sqrt{4} +5=7\\2+5=7\\7=7[/tex]

which is true .

∴ x=7 is a solution of the given eq.

now put x=4 in the given eq.

[tex]\sqrt{4-3} +5=7\\1+5=7\\6=7\\[/tex]

which is not true.

∴x=4 is an extraneous solution.

Answer:

358 and remainder of 3

Step-by-step explanation:

1. Divide it like any other problem

Hope this helps

Answer:

30

Step-by-step explanation:

fufyfuf7fjcjcufuy7fufucyyxyvkbuvufudydy shut up

Answer:

Step-by-step explanation:

Given this expression 2(b+3c), its equivalent expression is derived by simply opening up the bracket as shown below;

Open the parenthesis by multiplying the constant outside the bracket with all the variables in parenthesis.

= 2(b+3c)

=  2(b)+ 2(3c)

= 2b +2*3*c

= 2b +6c

It can also be written as sum of b+3c in 2 places i.e (b+3c)+(b+3c) because multiplying the function b+3c by 2 means we are to add the function by itself in two places.

Hence the equivalent expression are (b+3c)+(b+3c) and 2(b)+2(3c) or 2b+6c

Answer:

11

Step-by-step explanation:

The sum of the shortest two sides must be greater than the longest side.

If n is the longest side:

6 + 8 > n

14 > n

If 8 is the longest side:

6 + n > 8

n > 2

So n must be an integer greater than 2 and less than 14.

n can be 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, or 13.

There are 11 possible integers.

[tex] \LARGE{ \boxed{ \rm{ \purple{Answer}}}}[/tex]

We know,

Sum of two sides of a triangle > Third side

Then,

⇛ 6 + 8 > n

⇛ 14 > n

Nextly,

Difference of two sides of a triangle < Third side

Then,

⇛ 8 - 6 < n

⇛ 2 < n

Then, Range of third side:

☃️ 2 < n < 14

Possible measures of 3rd sides = 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 or 13.

There are 11 possible values of 3rd side. Out of them, any measure is the length of 3rd side.

━━━━━━━━━━━━━━━━━━━━

Answer:

[tex]1296x^3y^4[/tex]

Step-by-step explanation:

Given the terms:

[tex]144x^3y^2[/tex]

and [tex]81xy^4[/tex]

To find:

Greatest Common Divisor of the two terms or Least Common Multiple (LCM) of two numbers = ?

Solution:

First of all, let us find the HCF (Highest Common Factor) for both the terms.

i.e. the terms which are common to both.

Let us factorize them.

[tex]144x^3y^2 = \underline{3 \times 3} \times 16\times \underline x \times x^{2}\times \underline{y^{2} }[/tex]

[tex]81xy^4= \underline {3\times 3}\times 9 \times \underline{x} \times \underline{y^2}\times y^2[/tex]

Common terms are underlined.

So, HCF of the terms = [tex]9xy^2[/tex]

Now, we know the property that product of two numbers is equal to the product of the numbers themselves.

HCF [tex]\times[/tex] LCM = [tex]144x^3y^2[/tex] [tex]\times[/tex] [tex]81xy^4[/tex]

[tex]LCM = \dfrac{144x^3y^2 \times 81xy^4}{9xy^2}\\\Rightarrow LCM = 144x^3y^2 \times 9x^{1-1}y^{4-2}\\\Rightarrow LCM = 144x^3y^2 \times 9x^{0}y^{2}\\\Rightarrow LCM = \bold{1296x^3y^4 }[/tex]

Answer:

Step-by-step explanation:

let the cost based on number of book bought be x and the constant be c:

4800 = 20x + c

8000 = 40x + c

c is common in both equations:

c =4800-20x

c = 8000-40x

equate the two:

4800-20x = 8000 - 40x

20x = 3200

x = 160

and c = 4800-20*160

c = 1600

Cost of 1000 books:

160*1000 + 1600

= 161600

Answer:

-15

Step-by-step explanation:

-7p+10p-16=6p+36-7

3p-16=6p+29

3p-6p=29+16

-3p=45

p=45/-3

p=-15

Answer:

Step-by-step explanation:

Not always.

√3 * √27 = √81 = 9

Answer:

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question the equation is

y = 2x + 3

Comparing this equation with the general equation above

Slope / m = 2

Hope this helps you

Answer:

Step-by-step explanation:

Using the equation A(t) = 400e-.032t

a) replace t with 4 so A(4) = 400e((-.032)(4))

The hardest part about this is making sure to use order of operations. Be certain it works like this:

A(4) = 400e-.128

A(4) = 400(.8799)

A(4) = 351.9 grams

b) A(8) = 400e((-.032)(8)) = 309.7 grams

c) A(20) = 400e((-.032)(20)) = 210.9 grams

Note here that even after 20 years, not quite half of the original amount is gone. So, we can anticipate that in finding the half life, that our answer should be slightly greater than 20 years.

d) 200 = 400e(-.032t)

Divide both sides of the equation by 400.

.5 = e(-.032t)

Change this to logarithmic form.

Ln .5 = -.032t

-.6931≈ -.032t

t ≈ 21.7 years

Hope this helps!

The amount of radioactive lead,

(a).After 3 years is 454.23 grams

(b).After 8 years is 387.07 grams

(c).After 10 years is 363.07 grams.

(d). half life is 21.66 years.

The decay of radioactive lead is given by function,

                          [tex]A(t)=500e^{-0.032t}[/tex]

The amount of radioactive lead After 3 years is,

             [tex]A(3)=500e^{-0.032*3}=0.908*500=454.23g[/tex]

The amount of radioactive lead After 8 years is,

            [tex]A(8)=500e^{-0.032*8}=500*0.774=387.07g[/tex]

The amount of radioactive lead After 10 years is,

            [tex]A(10)=500e^{-0.032*10}=500*0.726=363.07g[/tex]

Half life is defined as the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

So,       [tex]250=500e^{-0.032t}[/tex]

            [tex]e^{-0.032t}=0.5\\\\-0.032t=ln(0.5)\\\\-0.032t=-0.693\\\\t=0.693/0.032=21.66 years[/tex]

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