Answer:
The two stadiums are approximately 3115.1 meters away from each other
Step-by-step explanation:
Since we can construct two right angle triangles between the blimp and the two stadiums as shown in the attached image, then the distance "x" between the two can be find as the difference between the right triangle legs that extend on the ground.
In order to find the size of such legs, one can use the tangent function of the given depression angles as shown below:
[tex]tan(75.2^o)=\frac{1100}{a} \\a=\frac{1100}{tan(75.2^o)}\\a\approx 290.6\,\,meters[/tex]
and for the other one:
[tex]tan(17.9^o)=\frac{1100}{b} \\b=\frac{1100}{tan(17.9^o)}\\b\approx 3405.7\,\,meters[/tex]
The the distance between the stadiums is the difference:
b - a = 3405.7 - 290.6 meters = 3115.1 meters
An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each other. One airplane is 150 miles from the point and has a speed of 300 miles per hour. The other is 200 miles from the point and has a speed of 400 miles per hour.(a) At what rate is the distances between the planes decreasing?(b) How much time does the air traffic controller have to get one of the planes on a different flight path?
Answer:
The answer to this question can be defined as follows:
In option A, the answer is "- 357.14 miles per hour".
In option B, the answer is "-0.98".
Step-by-step explanation:
Given:
[tex]\frac{dx}{dt} =- 300 \text{ miles per hour}[/tex]
[tex]\frac{dy}{dt} =- 400 \text{ miles per hour}[/tex]
find:
[tex]\frac{ds}{dt} =?[/tex] when
[tex]x= 150 \\y= 200\\s=x+y\\\\[/tex]
[tex]= 150+200 \\\\=350[/tex]
[tex]\to s^2=x^2+y^2\\[/tex]
differentiate the above value:
[tex]\to 2s\frac{ds}{dt}= 2x \frac{dx}{dt}+2y \frac{dy}{dt}[/tex]
[tex]\to 2s\frac{ds}{dt}= 2(x \frac{dx}{dt}+y \frac{dy}{dt})\\\\\to \frac{ds}{dt}= \frac{(x \frac{dx}{dt}+y \frac{dy}{dt})}{s}\\\\[/tex]
[tex]= \frac{(150 \times -300 +200 \times -400 )}{350}\\\\= \frac{-45000+ (-80000) }{350}\\\\= \frac{- 125000 }{350}\\\\= - 357.14 \ \text{miles per hour}[/tex]
In option B:
[tex]\to d=rt\\\\ \to t= \frac{d}{r}[/tex]
[tex]\to \ \ d= 350 \ \ \ \ \ \ r= -357.14\\[/tex]
[tex]\to t= - \frac{350}{357.14}\\\\\to t= - 0.98[/tex]
Triangle A' B' C' is a dilation of a triangle ABC. The scale factor is [tex]\frac{3}{4}[/tex]. Point B is 11 inches away from the center of dilation is point B'?
Answer:
None of the options are correct
Step-by-step explanation:
Let us assume point B is at (x, y) and the center of dilation is at (a, b). Therefore the distance between the two points is:
[tex]Distance =\sqrt{(b-y)^2+(a-x)^2}=11 \\\\\sqrt{(b-y)^2+(a-x)^2}=11[/tex]
If Triangle ABC is then dilated by 3/4, the new coordinate is B'(3/4 (x-a) + a, 3/4 (y - b) + b). The distance between B' and the center of dilation would be:
[tex]Distance =\sqrt{(b-[\frac{3}{4}( y-b)+b])^2+(a-[\frac{3}{4} (x-a)+a])^2}[/tex]
Therefore the distance cannot be gotten until the center of dilation is given
A line passes (-8,-2) and has a slope of 5/4. Write an equation in Ax + By=C
Answer:
5x-4y = -32
Step-by-step explanation:
First write the equation in point slope form
y-y1 = m(x-x1)
y - -2 = 5/4 ( x- -8)
y+2 = 5/4 (x+8)
Multiply each side by 4 to clear the fraction
4( y+2 )= 4*5/4 (x+8)
4y +8 = 5(x+8)
4y+8 = 5x+40
Subtract 4y from each side
8 = 5x-4y +40
Subtract 40 from each side
-32 = 5x-4y
5x-4y = -32
Answer:
The answer is
5x - 4y = -32Step-by-step explanation:
To write an equation of a line given a point and slope use the formula
y - y1 = m( x - x1)
where
m is the slope
( x1 , y1) is the point
From the question
slope = 5/4
point (-8 , -2)
So the equation of the line is
[tex]y + 2 = \frac{5}{4} (x + 8)[/tex]Multiply through by 4
4y + 8 = 5( x + 8)
4y + 8 = 5x + 40
5x - 4y = 8 - 40
We have the final answer as
5x - 4y = -32Hope this helps you
What is the rule for the transformation below?
=================================================
Explanation:
The translation notation T(-5, 3) looks like an ordered pair point, but it is not. Instead, it is a rule to tell you how to shift any point left/right and up/down. The first number is the left/right shifting as its done along the x axis. The negative value means we shift left, so we shift 5 units to the left. The positive 3 in the y coordinate place means we shift 3 units up.
We see this shifting happen when we go from
A = (-1, -1) to A ' = (-6, 2) B = (2, 3) to B ' = (-3, 6)C = (5, -3) to C ' = (0, 0)The translation notation T(-5, 3) is the same as writing [tex](x,y) \to (x-5, y+3)[/tex] which may be a more descriptive notation to use, and it would avoid confusion with ordered pair point notation.
40. Which families of plane figures given below are NOT always similar?
A. Squares
C. Equilateral triangles
B. Circles
D. rectangle
Answer:
Rectangle
Explanation:
Rectangles can be oblong, and square is also a rectangle.
If PR = 4X - 2 AND RS = 3X - 5 which expression represents PS?
Answer:
7x - 7
Step-by-step explanation:
If PR, RS, and PS are line segments then the equation below will work.
PR + RS = PS
(4x-2) + (3x-5) = 7x - 7
really urgent...i need the working also ...pls help me
Answer:
See below.
Step-by-step explanation:
In each case, you are looking for time. We know speed is distance divided by time. Lets start with the speed formula.
speed = distance/time
Now we solve it for time. Multiply both sides by time and divide both sides by speed.
speed * time = distance
time = distance/speed
Time is distance divided by speed. In each problem, you have a speed and a distance. Divide the distance by the speed to to find the time.
1) speed = 44.1 km/h; distance = 150 km
time = distance/speed = 150 km/(44.1 km/h) =
= 3.401 hours = 3 hours + 0.401 hour * 60 min/hour = 3 hours 24 minutes
2) speed = 120 km/h; distance = 90 km
time = distance/speed = 90 km/(120 km/h) =
= 0.75 hours = 0.75 hour * 60 min/hour = 45 minutes
3) speed = 125 m/s; distance = 500 m
time = distance/speed = 500 m/(125 m/s) =
= 4 seconds
First Question The following table shows the length and width of a rectangle: Length Width Rectangle A 4x + 5 3x − 2 Which expression is the result of the perimeter of rectangle A and demonstrates the closure property? A.14x + 6; the answer is a polynomial B.14x + 6; the answer may or may not be a polynomial C.2x + 6; the answer is a polynomial D.2x + 6; the answer may or may not be a polynomial
Answer: A.14x + 6; the answer is a polynomial
Step-by-step explanation:
Since all of the variables have integer exponents that are positive this is a polynomial.
According to data from the U.S. Department of Education, the average cost y of tuition and fees at public four-year institutions in year x is approximated by the equation where x = 0 corresponds to 1990. If this model continues to be accurate, during what year will tuition and fees reach $4000?
Answer:
Graphing Calculator
Step-by-step explanation:
WILL GIVE BRAINLIEST!!!!!! Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting two slanting rods, one of which, labeled PR, is shown: Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer, stating the theorem you used. Show all your work. Part B: The length of rod PR is adjusted to 17 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work.
A) Here, We'll use "Pythagoras Theorem" which tells:
a² + b² = c²
So, PR² = PQ² + QR²
PR² = 14² + 9²
PR² = 196 + 81
PR = √277
In short, Your Answer would be 16.64 Feet
B) Again, Use the Pythagoras Theorem,
c² - a² = b²
18² - 14² = b²
b² = 324 - 196
b = √128
b = 11.31
In short, Your Answer would be 11.31 Feet
Part A: Using the Pythagorean Theorem. a^2 + b^2 = c^2
PQ^2 + QR^2 = PR^2 (The rods make a right triangle, where PR would be the hypotenuse, and QR and PQ would be legs a and b.)
14^2 + 9^2 = PR^2
196 + 81 = PR^2
Square root of 277 = PR
16.64 = PR
So, the hypotenuse would be equal to 16.64 ft.
Part B: Using the Pythagorean Theorem. a^2 + b^2 = c^2
PR^2 - PQ^2 = QR^2 (Trying to find the height of QR this time, not the hypotenuse, since we know what it is already. Subtracting the value of leg a from the hypotenuse will give us the value of leg b, QR.)
18^2 - 14^2 = QR^2
324 - 196 = QR^2
Square root of 128 = QR
So, the new height of QR would be 11.31 ft.
All points of the step function f(x) are graphed
What is the domain of f(x)?
O {x4
O {x] -3 < x 54}
O {x|1 < x 54}
O {x|2
Why the answer question now correct
Answer:
461.58 in²
Step-by-step explanation:
The surface area (A) is calculated as
A = area of base + area of curved surface
= πr² + πrl ( r is the radius of base and l is slant height )
= 3.14 × 7² + 3.14 × 7 × 14
= 3.14 × 49 + 3.14 × 98
= 3.14(49 + 98)
= 3.14 ×147
= 461.58 in²
Consider line A which is defined by the equation:
y=5/6x-5/2
and the point P(-3,6) and then answer the following questions:
a. How would you find the line (B) that passes through point P and is perpendicular to line A? What is the equation of that line?
b. How would you find the length of the segment of line B from point P to line A?
c. How would you find the midpoint between point P and the intersection of line A and line B ?
Answer:
y = -6/5x +12/5distance from P to A: (66√61)/61 ≈ 8.4504midpoint: (-18/61, 168/61) ≈ (-0.2951, 2.7541)Step-by-step explanation:
a. The slope of the perpendicular line is the negative reciprocal of the slope of the given line, so is ...
m = -1/(5/6) = -6/5
Then the point-slope form of the desired line through (-3, 6) can be written as ...
y = m(x -h) +k . . . . . line with slope m through (h, k)
y = (-6/5)(x +3) +6
y = -6/5x +12/5 . . . equation of line B
__
b. The distance from point P to the intersection point (X) can be found from the formula for the distance from a point to a line.
When the line's equation is written in general form, ax+by+c=0, the distance from point (x, y) to the line is ...
d = |ax +by +c|/√(a² +b²)
The equation of line A can be written in general form as ...
y = 5/6x -5/2
6y = 5x -15
5x -6y -15 = 0
Then the distance from P to the line is ...
d = |5(-3) -6(6) -15|/√(5² +(-6)²) = 66/√61
The length of segment PX is (66√61)/61.
__
c. To find the midpoint, we need to know the point of intersection, X. We find that by solving the simultaneous equations ...
y = 5/6x -5/2
y = -6/5x +12/5
Equating y-values gives ...
5/6x -5/2 = -6/5x +12/5
Adding 6/5x +5/2 gives ...
x(5/6+6/5) = 12/5 +5/2
x(61/30) = 49/10
x = (49/10)(30/61) = 147/61
y = 5/6(147/61) -5/2 = -30/61
Then the point of intersection of the lines is X = (147/61, -30/61).
So, the midpoint of PX is ...
M = (P +X)/2
M = ((-3, 6) +(147/61, -30/61))/2
M = (-18/61, 168/61)
PLZ HELP!!!! ASAP !!!!
Answer:
(A)
Sin á = a/c
Cos ∅ = a/c
Tan á = a/b
(B)
Sin á = a/c
Cos á = b/c
Tan á = a/b
Therefore á=
(inverse sin) a/c
Or
(Inverse cos) b/c
Or
(Inverse tan) a/b
(C)
If b = 12 and c = 13
then a =√(c²-b²)
= 5
Hence 5/13 = a/c
Therefore sin á = cos ∅ = a/c = 5/13
Michael is using a number line to evaluate the expression –8 – 3. A number line going from negative 12 to positive 12. A point is at negative 8. After locating –8 on the number line, which step could Michael complete to evaluate the expression?
Answer:
move to the left 3 more spaces
Step-by-step explanation:
you are at -8 already. Therefore, you (-3) more spaces, so you go to the left three more spaces. Use the saying keep change change to help with this.
Keep the first number sign, change the next sign, and the next sign.
Answer:
d
Step-by-step explanation:
The following expression is a polynomial: 4x + 5y True False
Answer: False. This expression is a monomial!
Answer:
false
Step-by-step explanation:
it is molonomial
What the answer question
Answer:
Surface area = 373.66Step-by-step explanation:[tex]T.S.A = \pi r(r+l)\\l = 10mm\\r = 7mm\\\\T.S.A = 3.14 \times 7(7 + 10)\\= 21.98(17)\\T.S.A = 373.66\\\\T.S.A = 373.66[/tex]
If a and b are acute angles such that tan (a+b)= 1.73 and tan(a-b) =1/1.73, find a and b
[tex] \LARGE{ \underline{ \boxed{ \orange{ \rm{Solution:)}}}}}[/tex]
Given,tan (a + b) = 1.73 [tex]\approx[/tex] √3tan (a - b) = 1 / 1.83 [tex]\approx[/tex] 1 / √3To find:Value of a and b in degrees....?Solution:☃️ Refer to the trigonometric table....
Then, proceeding
⇛ tan 60 ° = √3
⇛ tan 60° = tan (a + b)
⇛ 60° = a + b
Flipping it,
⇛ a + b = 60° --------(1)
And,
⇛ tan 30° = 1 / √3
⇛ tan 30° = tan (a - b)
⇛ 30° = a - b
Flipping it,
⇛ a - b = 30° ---------(2)
Now adding eq.(1) and eq.(2),
⇛ a + b + a - b = 60° + 30°
⇛ 2a = 90°
⇛ a = 90° / 2
⇛ a = 45°
Putting value of a in eq.(1),
⇛ 45° + b = 60°
⇛ b = 15°
☄ So, Our Required answers:
a = 45°b = 15°━━━━━━━━━━━━━━━━━━━━
A stone is thrown downward straightly its speed at speed of 20 second what and it reaches the ground at 40 metre second what will be the height of building
Answer:
[tex]\Huge \boxed{\mathrm{61.22 \ m}}[/tex]
Step-by-step explanation:
A stone is thrown downward straightly with the velocity of 20 m/s and it reaches the ground at the velocity of 40 m/s. What will be the height of building? (Question)
The initial velocity ⇒ 20 m/s
The final velocity ⇒ 40 m/s
We can apply a formula to solve for the height of the building.
[tex](V_f)2 - (V_i)^2 =2gh[/tex]
[tex]V_f = \sf final \ velocity \ (m/s)[/tex]
[tex]V_i = \sf initial \ velocity \ (m /s)[/tex]
[tex]g = \sf acceleration \ due \ to \ gravity \ (m/s^2 )[/tex]
[tex]h = \sf height \ (m)[/tex]
Plugging in the values.
Acceleration due to gravity is 9.8 m/s².
[tex](40)^2 - (20)^2 =2(9.8)h[/tex]
Solve for [tex]h[/tex].
[tex]1600 - 400 =19.6h[/tex]
[tex]1200 =19.6h[/tex]
[tex]\displaystyle h=\frac{1200}{19.6}[/tex]
[tex]h= 61.22449[/tex]
The height of the building is 61.22 meters.
Mildred’s salary has increased from £24,600 to £25,338. By what percentage has her salary increase?
Answer:
The answer is 3%Step-by-step explanation:
To find the percentage increase we use the formula
[tex]Percentage \: change = \frac{ change}{original \: quantity} \times 100[/tex]
To find the change subtract the smaller quantity from the bigger one
From the question
original price = $24,600
Current price = $ 25,338
Change = $25,338 - $ 24,600
Change = $ 738
So the percentage increase is
[tex] \frac{738}{24600} \times 100[/tex]
[tex] = \frac{3}{100} \times 100[/tex]
We have the final answer as
Percentage increase = 3%Hope this helps you
Vanessa uses the expressions (3x2 + 5x + 10) and (x2 – 3x – 1) to represent the length and width of her patio. Which expression represents the area (lw) of Vanessa’s patio?
To get the area simply multiply the length by the width.
(3x^2+5x+10)(x^2-3x-1) = 3x^4 - 4x^3 - 8x^2 - 35x - 10
Answer:
the answer is A
Step-by-step explanation:
got it right on edge
the sum of 35 and one fifth part of itself is added to the sum of one seventh of 11 and 8
Answer:
313/7
Step-by-step explanation:
Here, we are interested in turning the wordings of the statement to numeric values.
We take it one at a time.
Sum of 35 and 1/5(35) = 35 + 7 = 42
This is added to 1/7(11 + 8)
= 1/7(19) = 19/7
So we have;
42 + 19/7 = (294 + 19)/7 = 313/7
Write each expression using a positive exponent. ("/" means division)("^" means to the power of) 9^-4
Answer:
[tex]\frac{1}{9^4}[/tex].
Step-by-step explanation:
[tex]9^{-4}[/tex]
= [tex]\frac{1}{9^4}[/tex]
= [tex]\frac{1}{9 * 9 * 9 * 9}[/tex]
= [tex]\frac{1}{81 * 81}[/tex]
= [tex]\frac{1}{6561}[/tex]
= 0.0001524157903.
Hope this helps!
One hundred people, ages 11-15, were randomly surveyed to find their opinion of their favorite leisure time activity. Sixty-four percent of them said they liked to spend time watching TV. If there are 1500 students in your school, about how many of them would you predict would enjoy watching t.v. A.2343 B.960 C.640 D.500
Answer:
If there are 1500 students in your school then 960 students would enjoy watching TV
Step-by-step explanation:
Step 1: We know that 64% of kids aged from 11 to 15 enjoy watching TV and there is 1500 students in your school
Step 2: We now want to find 64% of 1500, we can rewrite 64% as 0.64. We multiple 1500 by 0.64 to find out how many students enjoy watching TV
0.64 x 1500 = # of students who like watching TV
960 = # of students who like watching TV
Therefore out of 1500 students, 960 would enjoy watching TV
ux=x+y/k, solve for x
Answer:
x = y/( ku-1)
Step-by-step explanation:
Here in this question, we are asked to solve for x.
we have;
Ux = x+ u/ k
cross multiply;
k * Ux = x + y
kUx = x + y
kUx- x = y
x(KU-1) = y
x = y/( ku-1)
Find the value of x. A. 53–√ m B. 241−−√ m C. 6 m D. 6+35–√ m
Answer:
x = 2√41 mStep-by-step explanation:
Since the triangle is a right angled triangle we can use Pythagoras theorem to find the missing side x
Using Pythagoras theorem we have
a² = b² + c²
where a is the hypotenuse
From the question x is the hypotenuse
So we have
[tex] {x}^{2} = {8}^{2} + {10}^{2} [/tex][tex] {x}^{2} = 64 + 100[/tex][tex] {x}^{2} = 164[/tex]Find the square root of both sides
We have the final answer as
x = 2√41 mHope this helps you
Answer:
2 sqrt(41) =c
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
8^2 + 10^2 = c^2
64+ 100 = c^2
164 = c^2
take the square root of each side
sqrt(164) = sqrt(c^2)
sqrt(4*41) = c
2 sqrt(41) =c
Multiply and simplify. (1 − 5i)(1 − 2i) A) 1 + 7i B) 9 − 7i C) 1 − 7i D) − 9 − 7i
Answer:
The product renders: [tex]-9-7\,i[/tex]
Step-by-step explanation:
Recall that the product of the imaginary unit i by itself renders -1
Now proceed with the product of the two complex numbers using distributive property:
[tex](1-5\,i)\,(1-2\,i)=1-2\,i-5\,i+10\,i^2=1-7\,i-10=-9-7\,i[/tex]
Given an angle of a triangle and the opposite side length; which trigonometric function would you use to find the hypotenuse? a TAN b COS c SIN d Not enough information
Answer:
Sin
Step-by-step explanation:
Sin < = opposite/hypotenuse
Please explain and help
Answer:
y=-x+2
Step-by-step explanation:
it is linear equation y=mx+b two points (0,2),(1,1)
find m ( slope)=y2-y1/x2-x1 ⇒1-2/1-0⇒-1
y=mx+b choosea point from graph :(0,2)\when x =0 the y=b=2
y=-x+2
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
The two inequalities that show the solution to these equations are n ≥ 55 and y ≥ 6
Step-by-step explanation:
We are given two inequalities that we have to solve. We can solve these inequalities as if we are solving for the variable.
n/5 ≥ 11
Multiply by 5 on both sides.
n ≥ 55
Now, let's do the second one.
-3y ≤ -18
Divide by -3 on both sides. When we divide by a negative in inequalities, then the sign is going to flip to its other side. So, this sign (≤) becomes this sign (≥)
y ≥ 6