Physics High School

A 3kg Snickers candy bar is dropped off the top of the Washington Monument. If the Monument is 170m tall, how fast does the Snickers hit the ground? (this is the orignal question)


The Snickers bar actually lands with a speed of 52m/s. How much energy was lost so air resistance?

Answers

Answer 1

To determine the amount of energy lost due to air resistance, we can use the principle of conservation of mechanical energy. Initially, the Snickers bar has gravitational potential energy, and upon hitting the ground, it has kinetic energy.

The gravitational potential energy (PE) of an object is given by the equation:

PE = m * g * h

Where:

m is the mass of the object (3 kg)

g is the acceleration due to gravity (approximately 9.8 m/s^2)

h is the height of the Washington Monument (170 m)

Calculating the potential energy, we have:

PE = 3 kg * 9.8 m/s^2 * 170 m

PE = 4998 J (joules)

At the moment of impact, all the potential energy is converted into kinetic energy, given by:

KE = 1/2 * m * v^2

Where:

m is the mass of the object (3 kg)

v is the velocity at impact (52 m/s)

Calculating the kinetic energy, we have:

KE = 1/2 * 3 kg * (52 m/s)^2

KE = 4056 J (joules)

The energy lost due to air resistance is the difference between the initial potential energy and the final kinetic energy:

Energy Lost = PE - KE

Energy Lost = 4998 J - 4056 J

Energy Lost = 942 J (joules)

Therefore, the amount of energy lost due to air resistance is 942 joules.

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Related Questions

A particle with a charge of 5nC has a distance of 0. 5m away from a charge of 9. 5nC. What is its electric potential energy?

Answers

The electric potential energy of the particle with a charge of 5nC, located 0.5m away from a charge of 9.5nC, is 1.9 J.

To calculate the electric potential energy, we can use the formula:

Electric potential energy = (k * q1 * q2) / r

Where:

k is the electrostatic constant (9 x 10^9 N m^2/C^2),

q1 and q2 are the charges of the two particles (in this case, 5nC and 9.5nC, respectively),

r is the distance between the charges (0.5m).

Substituting the given values into the formula:

Electric potential energy = (9 x 10^9 N m^2/C^2) * (5 x 10^-9 C) * (9.5 x 10^-9 C) / 0.5m

Calculating the expression:

Electric potential energy ≈ 1.9 J

Therefore, the electric potential energy of the particle is approximately 1.9 Joules.

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A 5-kg object is moving to the right at 4 m/s and collides with another object moving to the left at 5 m/s. The objects collide and stick together. After the collision, the combined object:

Answers

After the collision, the two objects stick together and move as one. Their total mass is m1 + m2 = 5 kg + m2.

How to determine the effect of the collision

In this case, we can apply the principle of conservation of linear momentum

The initial momentum of the first object (P1_initial) is given by its mass (m1) times its velocity (v1), which is [tex]5 kg * 4 m/s = 20 kg*m/s.[/tex]

Therefore, the total initial momentum [tex](P_{total_initial}) is P1_{initial} + P2_{initial} = 20 kg*m/s - m2 * 5 m/s.[/tex]

After the collision, the two objects stick together and move as one.

Their total mass is m1 + m2 = 5 kg + m2.

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