A 2.87 g sample of carbon reacts with hydrogen to form 3.59 g of car fuel. What is the empirical formula of the car fuel?

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Answer 1
This is the Answer:
A 2.87 G Sample Of Carbon Reacts With Hydrogen To Form 3.59 G Of Car Fuel. What Is The Empirical Formula

Related Questions

The solubility of lithium fluoride, LiF, is 1.6 g/L, or 6.2 x 10â2 M.
a. Write the balanced solubility equilibrium equation for LiF.
b. Determine the molar concentration of the lithium ion and the fluoride ion.
c. Write the Ksp expression for the reaction.
d. Calculate Ksp for lithium fluoride.

Answers

Answer:

a. LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

b. [Li⁺] = [F⁻] = 6.2 x 10⁻² M

c. Ksp = [Li⁺] [F⁻]

d. Ksp = 3.8 × 10⁻³

Explanation:

The solubility (S) of lithium fluoride, LiF, is 1.6 g/L, or 6.2 x 10⁻² M.

a. The balanced solubility equilibrium equation for LiF is:

LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

b. We will make an ICE chart.

        LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

I                       0           0

C                     +S         +S

E                       S           S

Then, [Li⁺] = [F⁻] = S = 6.2 x 10⁻² M

c. The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution.

Ksp = [Li⁺] [F⁻]

d.

Ksp = [Li⁺] [F⁻] = (6.2 x 10⁻²)² = 3.8 × 10⁻³

The chemical formula for strontium sulfide is SrS . A chemist measured the amount of strontium sulfide produced during an experiment. She finds that 199.g of strontium sulfide is produced. Calculate the number of moles of strontium sulfide produced. Be sure your answer has the correct number of significant digits.

Answers

Answer:

The number of moles of strontium sulfide produced is:

= 1.663.

Explanation:

Chemical formula for strontium sulfide = SrS

Production of strontium sulfide = 199g

1 mole = 1 moles Strontium Sulfide, which is equal to 119.685 grams

The number of moles of strontium sulfide produced = 1.663 (199/119.685)

The number of moles of strontium sulfide produced is the dividend of the amount of strontium sulfide produced during the experiment divided by the mass of 1 mole.

3 molecules NaOH determine the amount of grams

Answers

Answer:

In three mocelus 0.0001 gram.

Which of the following substances can be used to neutralize HF?

A: HF
B: SO2
C: HCI
D: NaOH

Answers

Answer:

option (D) NaOH is right answer

A neutralization reaction is "a reaction in which an acid and a base react to form water and a salt and involves H+ ions and OH- ions to produce water.

What is an acid?

An acid is "any hydrogen-containing substance that is capable of donating a proton or hydrogen ion to another substance".

What is base?

Base is "a substance that gets dissociated in an aqueous solution to form hydroxide ions OH-".

Hence, NaOH can be used to neutralize HF.

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8) Determine whether mixing each pair of the following results in a buffera. 100.0 mL of 0.10 M NH3 with 100.0 mL of 0.15 MNH4Cl b. 50.0 mL of 0.10 M HCL with 35.0 mL of 0.150 M NaOHc. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOHd. 175.0 mL of 0.10 M NH3 with 150.0 mL of 0.12 M NaOH

Answers

Answer:

a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.

c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.

Explanation:

A buffer system is formed in 1 of 2 ways:

A weak acid and its conjugate base.A weak base and its conjugate acid.

Determine whether mixing each pair of the following results in a buffer.

a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.

YES. NH₃ is a weak base and NH₄⁺ (from NH₄Cl ) is its conjugate base.

b. 50.0 mL of 0.10 M HCl with 35.0 mL of 0.150 M NaOH.

NO. HCl is a strong acid and NaOH is a strong base.

c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.

YES. HF is a weak acid and it reacts with NaOH to form NaF, which contains F⁻ (its conjugate base).

d. 175.0 mL of 0.10 M NH₃ with 150.0 mL of 0.12 M NaOH.

NO. Both are bases.

How is a light bulb related to radiation?
A. Light bulbs do not have anything to do with radiation.
B. A light bulb emits radiation when its filament is burned out and can longer emit light. This makes it important to remove dead lightbulbs as soon as they wear out.
C. As light is emitted from the filament, the energy in the metal is replaced as lightbulbs absorb background radiation. This prevents the filament from burning out quickly but the radiation cannot be used as power so electricity is still required for the lightbulb to work.
D. The light emitted by a light bulb is a form of radiation that occurs when the filament heats up and its thermal emission gains enough energy to move into the visible spectrum.

Answers

Answer:

As light is emitted from the filament, the energy in the metal is replaced as lightbulbs absorb background radiation. This prevents the filament from burning out quickly but the radiation cannot be used as power so electricity is still required for the lightbulb to work.

Hydrogengasand oxygengas react to form water vapor. Suppose you have of and of in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest .

Answers

The question is incomplete. The complete question is :

Hydrogen [tex](H_2)[/tex] gas and oxygen [tex](O_2)[/tex] gas react to form water vapor [tex](H_2O)[/tex]. Suppose you have 11.0 mol of [tex]H_2[/tex] and 13.0 mol of [tex]O_2[/tex] in a reactor. Calculate the largest amount of [tex]H_2O[/tex] that could be produced. Round your answer to the nearest 0.1 mol .

Solution :

The balanced reaction for reaction is :

[tex]$2H_2(g) \ \ \ \ + \ \ \ \ \ O_2(g)\ \ \ \rightarrow \ \ \ \ 2H_2O(g)$[/tex]

11.0                      13.0

11/2                       13/1     (dividing by the co-efficient)

6.5 mol               13 mol    (minimum is limiting reagent as it is completely consumed during the reaction)

Therefore, [tex]H_2[/tex] is limiting reagent. It's stoichiometry decides the product formation amount from equation above it is clear that number of moles for [tex]H_2O[/tex] will be produced = number of moles of [tex]H_2[/tex]

                                     = 11.0 mol

the ability for carbon to form long chain or rings is

Answers

califactual. thsi is correct bcuz carbon takes 20 minutes to dissolve and ring making it a factual

Consider an equilibrium (K1) that is established after 10 mL of compound A and 10 mL of compound B are mixed. Now, imagine the equilibrium (K2) where 1 mL of compound A is added to 100 mL of compound B. How are K1 and K2 related algebraically (read this question VERY carefully, at least one more time)?

Answers

K1 and K2 are related algebraically because once the values are inserted into the equilibrium equation, both equations will yield a denominator of 100.

Calculate the enthalpy change for the reaction of hydrogen and chlorine using the bond energies below.
"BOND." " BOND ENERGY "
H-H. 436
CL-CL. 242
H-CL. 431 ​

Answers

Answer:

final-intial temperature= enthalpy change

A sample of gas contains 0.1200 mol of H2(g) and 0.1200 mol of O2(g) and occupies a volume of 11.5 L. The following reaction
takes place:
H2(g) + O2(g)>H2O2(g)
Calculate the volume of the sample after the reaction takes place, assuming that the temperature and the pressure remain constant.
L

Answers

Answer:

5.75L is the volume of the sample after the reaction

Explanation:

Based on the reaction, 1 mole of H2 reacts with 1 mole of O2 to produce 1 mole of H2O2.

As in the reaction, 0.1200 moles of H2 and 0.1200 moles of O2 are added, 0.1200 moles of H2O2 are produced.

Before the reaction, the moles of gas are 0.2400 moles and after the reaction the moles are 0.1200 moles of gas.

Based on Avogadro's law, the moles of a gas are directly proportional to the volume under temperatura and pressure constant. The equation is:

V1/n1 = V2/n2

Where V is volume and n are moles of 1, initial state and 2, final state.

Replacing:

V1 = 11.5L

n1 = 0.2400 moles

V2 = ?

n2 = 0.1200 moles

11.5L*0.1200 moles / 0.2400 moles = V2

V2 = 5.75L is the volume of the sample after the reaction

what is calcium anyone tell plz​

Answers

Answer:

Calcium is a chemical element with the symbol Ca and atomic number 20.

Calcium is a mineral that is necessary for life. In addition to building bones and keeping them healthy, calcium enables our blood to clot, our muscles to contract, and our heart to beat. About 99% of the calcium in our bodies is in our bones and teeth.

Which of the following are examples of single replacement reactions? Select all that apply.

Answers

Answer:

Na2S(aq)+Cd(No3)2(aq)=CdS(s)+2NaNo3(aq)

Answer: it’s checkbox 2&3

what is food nutrients​

Answers

Answer:

Nutrients arw compounds in foods essential to life and heath

Answer: In simple terms nutrients are the energy that you get from food certain foods give more nutrients and others give close to none. That is what nutrients in your food is

Explanation:

what is the difference between Absorption and adsorption​

Answers

Absorption is a process in which any substance (atoms, ions, or molecules) is taken by or absorbed by another substance, especially in the solid or liquid material. Adsorption is when the substances like gas, liquids or dissolved solids loosely adhere or stick to the surface of another substance which can be solid or liquid.

crassify the given quantities into scalar quantity and vetor quantity ​

Answers

Answer:

where is the quantities?

The enthalpy of formation for CO2 (s) and CO2 (g) is: -427.4 KJ/mole and -393.5 KJ/mole, respectively. The sublimation of dry ice is described by CO2 (s) → CO2 (g).

The enthalpy needed to sublime 986 grams of CO2 is:
(a) 181.5 Kcal
(b) 611.7 Kcal
(c) 248.3 Kcal
(d) 146.2 Kcal

Answers

Answer:

a. 181.5 kcal

Explanation:

Step 1: Calculate the enthalpy of the process (ΔH°).

Let's consider the following process.

CO₂(s) → CO₂(g)

We can calculate the enthalpy of the process using the following expression.

ΔH° = ∑ np × ΔH°f(p) - ∑ nr × ΔH°f(r)

ΔH° = 1 mol × ΔH°f(CO₂(g)) - 1 mol × ΔH°f(CO₂(s))

ΔH° = 1 mol × (-393.5 kJ/mol) - 1 mol × (-427.4 kJ/mol) = 33.9 kJ

According to the balanced equation, 33.9 kJ are required to sublime 1 mole of CO₂.

Step 2: Convert 986 g of CO₂ to moles

The molar mass of CO₂ is 44.01 g/mol.

986 g × 1 mol/44.01 g = 22.4 mol

Step 3: Calculate the enthalpy needed to sublime 22.4 moles of CO₂

22.4 mol × 33.9 kJ/1 mol = 759 kJ

We can convert it to Kcal using the conversion factor 1 kcal = 4.184 kJ.

759 kJ × 1 kcal/4.184 kJ = 181.5 kcal

Give the amino acid sequence in the following tetrapeptide using both 3-letter and 1-letter abbreviations for the amino acids. (Capitalize amino acid abbreviations appropriately.) ball

Answers

Answer:

ggggggggggggg

Explanation:

gggggggggggthyjum

A chlorine (CI) atom has 7 valence electrons. Which of the following would be the most likely way for a chlorine atom to become stable?

A. Lose 5 electrons
B. Gain 2 electrons
C. Gain 1 electron
D. Lose 7 electrons ​

Answers

Answer:

Option C. Gain 1 electron

Explanation:

Valence electron(s) are the electron(s) located on the outermost shell of an atom. Valency is simply defined as the combining power of an atom.

Chlorine (Cl) atom has 7 valence electron. This implies that Cl needs just one electron to complete it's octet configuration. It will be difficult for Cl to lose any of it's valence electron(s). Cl can either gain or share 1 electron to become stable.

Thus, considering the options given in the question above, option C gives the correct answer to the question.

In an ELISA, the compound 4-chloro-1-naphthol is used because:_______
a. it turns color in the presence of an enzyme that is bound to the secondary antibody
b. it helps the primary antibody bind to the protein
c. it helps the secondary antibody to bind to the protein
d. all of the choices

Answers

Answer:

a. It turns color in the presence of an enzyme that us bound to the secondary antibody.

Explanation:

The compound chloronapthenel is used in the reaction because it changes the color in the presence of an enzyme. It is strong organic compound which is used in biochemical processes.

What can be found on the periodic table?
A. the name of molecules formed by the element
B. the number of isotopes an element has
C. the date an element was discovered
D. the number of protons an element has​

Answers

Answer:

I think the answer is..

The name of molecules formed by the element.

I hope it will help you !

I think it’s A, none of the other letters showed up when I looked at the periodic table

What does quantization refer to?

Answers

Answer:

Quantization is the process of constraining an input from a continuous or otherwise large set of values (such as the real numbers) to a discrete set (such as the integers).

Explanation:

Quantization refers to the situation where an electromagnetic field consists of discrete energy parcels, photons.

What is Quantatization in Chemistry ?

In Chemistry , the concept that a system cannot have any possible energy value but instead is limited to certain specific energy values (states). This states depend on the specific system in question.

Under this system, Energy could be gained or lost only in integral multiples of some smallest unit of energy, a quantum (the smallest possible unit of energy).

Hence, Quantization refers to the situation where an electromagnetic field consists of discrete energy parcels, photons.

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The color cyan has a frequency of 5.902x10^14 What is the wavelength in nm ? Record your answer with 2
decimals.

Answers

The wavelength of the color cyan is 508 nm.

To solve the problem, we use the following equation that relates the frequency (ν) and the wavelength (λ) of a wave:

c = λ x ν

Given:

c = speed of light = 3.00 x 10⁸ m/s (is a constant)

ν = 5.902 x 10¹⁴ Hz = 5.902 s⁻¹

We introduce the data to calculate the wavelength in m:

λ = c/ν = (3.00 x 10⁸ m/s)/(5.902 s⁻¹) = 5.08 x 10⁻⁷ m

We know that 10⁻⁹m = 1 nm, so we convert λ to nm:

λ = 5.08 x 10⁻⁷ m x 1 nm/10⁻⁹m = 508 nm

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Consider the reaction below. How much heat is absorbed if 5.00 moles of nitrogen react
with excess oxygen?
2 N2 (8) + O2(g) → 2 N20 (8) AHrxn- +163.2 kJ

Answers

Explanation:

The given chemical reaction is:

[tex]2 N_2 (g) + O_2(g) -> 2 N_20 (g) delta Hrxn= +163.2 kJ[/tex]

When two moles of nitrogen reacts with oxygen, it requires 163.2kJ of energy.

When 5.00 mol of nitrogen requires how much energy?

[tex]5.00 mol x \frac{163.2 kJ }{2 mol} \\=408 kJ[/tex]

Hence, the answer is 408 kJ of heat energy is required.

A tank contains oxygen gas at 2.551 atm. What is the pressure in mmHg?

Answers

The force exerted on the container by the particles of the matter is called pressure. The tank containing oxygen gas at 2.551 atm will have a pressure of 1939 mm Hg.

What is pressure?

Pressure is the property used to estimate the force experienced by the system due to the liquid or the gas held in it. The pressure of the gas can be calculated by the ideal gas and force and area.

The pressure is created due to the collision of the particles of the gases and liquids on the wall perpendicularly. It is estimated in Pascal (Pa) as the standard unit along with atm and mmHg.

It is known that 1 atm = 760 mm Hg

Given,

The pressure of oxygen gas = 2.551 atm

Using the conversion factor the pressure from atm to mm Hg is calculated as,

1 atm = 760 mm Hg

2.551 atm = (2.551 atm × 760 mm Hg) ÷ 1 atm

= 1938.76 mmHg

Therefore, 1939 mm Hg is the pressure of the oxygen gas.

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calculate the total consumer surplus in the amusement park market if they a 12

Answers

Answer:

The total consumer surplus is 240.

Explanation:

If p=12 then q=20

0.5×(36−12)×20=240

here's the graph to help you see the change.

Please help me fast! Pleaseee

Answers

I think 2 answer is write

What volume (in liters) of a solution contains 0.14 mol of KCl?
1.8 M KCl
Express your answer using two significant figures.

Answers

Answer:

[tex]\boxed {\boxed {\sf 0.078 \ L }}[/tex]

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

[tex]molarity= \frac{moles \ of \ solute}{liters \ of \ solution}[/tex]

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

moles of solute = 0.14 mol KCl molarity= 1.8 mol KCl/ Lliters of solution=x

Substitute these values/variables into the formula.

[tex]1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}[/tex]

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

[tex]\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}[/tex]

[tex]1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl[/tex]

[tex]1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl[/tex]

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

[tex]\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}[/tex]

[tex]x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}[/tex]

The units of moles of potassium chloride cancel.

[tex]x= \frac{0.14 }{1.8 L}[/tex]

[tex]x=0.07777777778 \ L[/tex]

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

[tex]x \approx 0.078 \ L[/tex]

There are approximately 0.078 liters of solution.

If you add a solution of NaOH to a solution of H₂CO₃, two reactions occur, one after the other. Write the chemical equations for these two reactions. (Hint: NaOH dissociate into Na+ and OH-, and the hydroxide ion is the actual base).

Answers

We have a solution of NaOH and H₂CO₃

First, NaOH will dissociate into Na⁺ and OH⁻ ions

The Na⁺ ion will substitute one of the Hydrogen atoms on H₂CO₃ to form NaHCO₃

The H⁺ released from the substitution will bond with the OH⁻ ion to form a water molecule

If there were to be another NaOH molecule, a similar substitution will take place, substituting the second hydrogen from H₂CO₃ as well to form Na₂CO₃

2. The reaction of a triglyceride with methanol in the presence of a strong base to form
methyl esters and glycerol is called
O A. transesterification.
O B. saponification.
O C. ester formation.
O D. dehydration condensation.

Answers

Answer:

The answer it's A. transesterification

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