Answer:
3x=63
Step-by-step explanation:
3 coins means a coin is x and total expenditure is equal to 63
Multiply the following and combine terms where possible. -a(a-b-3)
Answer:
-a^2 +ab +3a
Step-by-step explanation:
-a(a-b-3)
Distribute
-a*a -a*(-b) -a *(-3)
-a^2 +ab +3a
Find the solution to the system of equations.
You can use the interactive graph below to find the solution.
\begin{cases} y=-2x+7 \\\\ y=5x-7 \end{cases}
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⎪
⎪
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⎪
⎪
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y=−2x+7
y=5x−7
x=x=x, equals
y=y=y, equals
Answer:
x=2
y=3
Step-by-step explanation:
y=−2x+7
y=5x−7
Set the two equations equal since they are both equal to y
−2x+7 =5x−7
Add 2x to each side
-2x+7+2x = 5x-7+2x
7 = 7x-7
Add 7 to each side
7+7 = 7x-7+7
14 =7x
Divide by 7
14/7 = 7x/7
2 =x
Now find 7
y = 5x-7
y = 5(2) -7
y = 10-7
y = 3
Given that y=y=y,
→ -2x+7 = 5x-7
Let's find the value,
→ -2x+7 = 5x-7
→ 7 = 5x+2x-7
→ 7 = 7x-7
→ 7+7=7x
→ 14 = 7x
→ x = 14/7
→ [x = 2]
Then we can find 7,
→ y = 5x-7
→ y = 5(2) -7 y = 10-7
→ [y = 3]
This is required answer.
Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Answer:
[tex]f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.[/tex]
Step-by-step explanation:
Given
[tex]9 < x < 10[/tex] --- interval
Required
The probability density of the volume of the cube
The volume of a cube is:
[tex]v = x^3[/tex]
For a uniform distribution, we have:
[tex]x \to U(a,b)[/tex]
and
[tex]f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.[/tex]
[tex]9 < x < 10[/tex] implies that:
[tex](a,b) = (9,10)[/tex]
So, we have:
[tex]f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex]
Solve
[tex]f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex]
[tex]f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex]
Recall that:
[tex]v = x^3[/tex]
Make x the subject
[tex]x = v^\frac{1}{3}[/tex]
So, the cumulative density is:
[tex]F(x) = P(x < v^\frac{1}{3})[/tex]
[tex]f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.[/tex] becomes
[tex]f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.[/tex]
The CDF is:
[tex]F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx[/tex]
Integrate
[tex]F(x) = [v]\limits^{v^\frac{1}{3}}_9[/tex]
Expand
[tex]F(x) = v^\frac{1}{3} - 9[/tex]
The density function of the volume F(v) is:
[tex]F(v) = F'(x)[/tex]
Differentiate F(x) to give:
[tex]F(x) = v^\frac{1}{3} - 9[/tex]
[tex]F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}[/tex]
[tex]F'(x) = \frac{1}{3}v^{-\frac{2}{3}}[/tex]
[tex]F(v) = \frac{1}{3}v^{-\frac{2}{3}}[/tex]
So:
[tex]f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.[/tex]
factor 9-x^2 completely
Answer:
-(x + 3)(x - 3)
Step-by-step explanation:
Using the difference of squares we can factor this expression.
[tex](9 - x^2)\\= (3^2 - x^2)\\= (3 + x)(3 - x)\\= -(3 + x)(-3 + x)\\= -(x + 3)(x - 3)[/tex]
Which function below has the following domain and range?
Domain: {-7, - 5,2, 6, 7}
Range: {0, 1,8}
Answer:
{(2,0),(-5,1),(7,8),(6,0),(-7,1)
If someone earns $10 every 15 minutes, how much do they earn in an hour?
Answer: 40
Step-by-step explanation:
You multiple 15X4=60
And now multiple 10x4=40
Answer:
40$
Step-by-step explanation:
There are 60 minutes in an hour so if we break it down:
$10 = 15 minutes
$10 = 15 minutes
$10 = 15 minutes
$10 = 15 minutes
-------------------------
Add them together and we get:
$40 = 60 minutes or 1 hour
Meaning they would make 40$ in 1 hour.
The measure of ∠1 is 39°. What is the measure of ∠2?
Answer:
141
Step-by-step explanation:
if the sum of the two angles equals 180 subtract 39 from 180 to get the remainder of 141 which is angle 2
find csc theta and sin theta if tan theta = 7/4 and sin theta less than 0
9514 1404 393
Answer:
sin(θ) = (-7√65)/65
csc(θ) = (-√65)/7
Step-by-step explanation:
The angle will have the given characteristics if its terminal ray passes through the 3rd-quadrant point (-4, -7). The distance from the origin to that point is ...
d = √((-4)² +(-7)²) = √65
The sine of the angle is the ratio of the y-coordinate to this value:
sin(θ) = -7/√65
sin(θ) = (-7√65)/65
The cosecant is the inverse of the sine
csc(θ) = (-√65)/7
When an individual inherits two identical alleles for the brown eyed gene (BB)which type of individual is this?
Substituting the equation y = 4x + 1 into the equation 2y = -x – 1 will produce the equation ________.
Answer:
Step-by-step explanation:
Substituting y = 4x+1 into 2y = -x-1 gives the equation
2(4x+1) = -x-1
Solve the equation:
8x+2 = -x-1
9x = -3
x = -⅓
Substituting y = 4x+1 into 2y = -x-1 will produce the equation 2(4x+1) = -x-1
What are the equations?A mathematical statement known as an equation is made up of two expressions joined together by the equal sign. Based on the degree, there are four different main types of equations. Equations that are linear, quadratic, cubic, and polynomial
Given, the equation y = 4x + 1 and another equation 2y = -x – 1.
Substituting equation 1 into equation 2 we will get
2(4x+1) = -x-1
Solve the equation:
8x+2 = -x-1
9x = -3
x = -⅓
Therefore, The equation 2(4x+1) = -x-1 is created when y = 4x+1 is substituted into 2y = -x-1.
Learn more about equations here:
https://brainly.com/question/16255566
#SPJ2
If one root of the quadratic equation is 2x2 +kx -6= 0 is 2
find the value of k
This is ur answer plz mark brainliest
3-6÷12
simplyfication
Suppose the average commute time of your employees is unknown. The standard deviation of their commute time is estimated as 22.8 minutes. How many employees must be included in a sample to create a 99 percent confidence interval for the average commute time with a confidence interval width of no more than 12 minutes
Answer:
96 employees
Step-by-step explanation:
Given that the standard deviation = 22.8
The width in the question = 12
We solve for the margin of error E.
E = width / 2
= 12/2 = 6
At 99%
Alpha = 1-0.99
= 0.01
Alpha/2 = 0.01/2 = 0.005
Z0.005 = 2.576
Sample size n
= ((2.576x22.8)/2)²
= 95.8
= 96
The number of employees is 96
Thank you!
help with number 6 please. thank you.
Answer:
See Below.
Step-by-step explanation:
We are given that:
[tex]\displaystyle \frac{dT}{dt} = -k(T - T_0)[/tex]
And we want to show that:
[tex]\displaystyle T = T_0+Ae^{-kt}[/tex]
From the original equation, divide both sides by (T - T₀) and multiply both sides by dt. Hence:
[tex]\displaystyle \frac{dT}{T-T_0}= -k\, dt[/tex]
Take the integral of both sides:
[tex]\displaystyle \int \frac{dT}{T- T_0} = \int -k \, dt[/tex]
Integrate. For the left integral, we can use u-substitution. Note that T₀ is simply a constant. Hence:
[tex]\displaystyle \ln\left|T - T_0\right| = -kt+C[/tex]
Raise both sides to e:
[tex]\displaystyle e^{\ln\left|T-T_0\right|} = e^{-kt+C}[/tex]
Simplify:
[tex]\displaystyle \begin{aligned} \left| T- T_0\right| &= e^{-kt} \cdot e^C \\ \\ &= e^C\left(e^{-kt}\right) \\ \\ &=Ae^{-kt} & \text{Let $e^C = A$}\end{aligned}[/tex]
Since the temperature T will always be greater than or equal to the surrounding medium T₀, we can remove the absolute value. Hence:
[tex]\left(T - T_0\right) = Ae^{-kt}[/tex]
Therefore:
[tex]\displaystyle T = T_0+Ae^{-kt}[/tex]
Mandatory minimum character count of 20.
Clarissa has abudget of 1,200$ amonth to spend for rent n food she already spent 928 this month which inequality represents the amount she can still spend this month
Answer:
272$
Step-by-step explanation:
You really should be clearer with your questions, but if your looking for the balance she has 272$
What is the length of BD Round to one decimal place. Thanks!
Answer:
2.7
Step-by-step explanation:
ratios help
2.5 : 5.8 :: x : 6.2
2.5/5.8 = x/6.2
solve for x :
x = approx. 2.7
Given the following formula, solve for y.
Answer:
b) y=x -2(w+z)
Step-by-step explanation:
multiply both sides, move the terms and write on parametric form
CAN SOMEONE PLEASE ANSWER MY QUESTION?!
Answer:
0.02 m/sec
Step-by-step explanation:
26/30=0.89 —> 0.89 min —> 53.4 sec
42/50=0.84 meters
speed=0.84 / 53.4 = 0.015 m/sec = 0.02 m/sec
can someone please help me?
Step-by-step explanation:
D. RAMONA SAVED THE MOST IN 2006
D. Ramona saved the most in 2006
Which proportion correctly shows the equivalence of two fractions?
A)
19∕95 = 57∕76
B)
32∕116 = 9∕29
C)
18∕36 = 72∕144
D)
18∕36 = 144∕72
Answer:
32/166=9/29 if two ratio are equivalent to other
Nick nas cup of syrup. He uses cup of syrup to make a bont of granota
PartA: How many bow's or granola can Nick make with cup of syrup? (4 points)
Part 8: on your own paper, draw a fraction model that shows the total number of bouts of granola that Nick can make with cup of syrup. Make sure to label the model seks
explain your model in detail to descnbe how this model visually shows the solution for Part A. (6 points). I’ll make u brainless if u help
Answer:
Step-by-step explanation:
its easyk
C = ſa²+b² Please describe the Mathematical order of Operation
Step-by-step explanation:
C + ſa6+b5 bescribe the Mathematical order of Operation
Lakisha wants to buy some bitcoins. The exchange rate is $1 USD to 0.004 bitcoin. How many bitcoins can she buy with $400?
Answer:
1.6 Bitcoins
Step-by-step explanation:
Given data
We have the rate as
$1 USD to 0.004
Hence $400 will buy x bitcoins
Cross multiply to find the value of x
1*x= 400*0.004
x=1.6
Hence $400 will get you 1.6 Bitcoins
answer plz no explanation needed
Answer:
x is 1. i looked it up so that's all you need
Which statement describes the end behavior of this function? g(x) = 1/2|x - 3| - 7
A. As x approaches positive infinity, g(x) approaches negative infinity.
B. As x approaches negative infinity, g(x) approaches negative infinity.
C. As x approaches positive infinity, g(x) approaches positive infinity.
D. As x approaches negative infinity, g(x) is no longer continuous.
Answer:
C. As x approaches positive infinity, g(x) approaches positive infinity.
Step-by-step explanation:
We are given the following function:
[tex]g(x) = \frac{|x-3|}{2} - 7[/tex]
End behavior:
Limit of g(x) as x goes to negative and positive infinity.
Negative infinity:
[tex]\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} \frac{|x-3|}{2} - 7 = \frac{|-\infty-3|}{2} - 7 = |-\infty| = \infty[/tex]
Positive infinity:
[tex]\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{|x-3|}{2} - 7 = \frac{|\infty-3|}{2} - 7 = |\infty| = \infty[/tex]
So in both cases, it approaches positive infinity, and so the correct option is c.
Not sure whether the answer is 9 or -11, so please help
!!!HELPPP PLEASEEE!!! For this problem I thought it meant to subtract 0.1492 - 0.1515 = -0.0023 however my answer was incorrect. How do I solve this problem then? Help Please!
Answer:
0.1492-0.1515= -0.0023
What system of equations is shown on the graph below
Answer:
A.
Step-by-step explanation:
x-2y=4 has a x-intercept of 4, a slope of 1/2, and a y-intercept of -2. 2x+y=4 has a x-intercept of -2, a slope of 2, and a y-intercept of -4.
You are dividing a rectangular garden into 2 equal sections by
placing a wooden plank diagonally across it, from one corner to
the opposite comer. The garden measures 4 feet by 6 feet. What
length diagonal plank should you buy, and why?
Diagonal planks are available in 1-foot increments (you can
buy a 1-foot board, or a 2-foot board, or a 3-foot board, and
so on...)
• You can cut the plank down from the size you buy to the
exact size, but you want to waste as little wood as possible.
Answer:
You can cut the plank down from the size you buy to the
exact size, but you want to waste as little wood as possible.
Hi, hiw do we do this question?
[tex]\displaystyle \int\sec x\:dx = \ln |\sec x + \tan x| + C[/tex]
Step-by-step explanation:
[tex]\displaystyle \int\sec x\:dx=\int\sec x\left(\frac{\sec x+ \tan x}{\sec x + \tan x}\right)dx[/tex]
[tex]\displaystyle = \int \left(\dfrac{\sec x\tan x + \sec^2x}{\sec x + \tan x} \right)dx[/tex]
Let [tex]u = \sec x + \tan x[/tex]
[tex]\:\:\:\:\:\:du = (\sec x\tan x + \sec^2x)dx[/tex]
where
[tex]d(\sec x) = \sec x\tan x\:dx[/tex]
[tex]d(\tan x) = \sec^2x\:dx[/tex]
[tex]\displaystyle \Rightarrow \int \left(\frac{\sec x\tan x + \sec^2x}{\sec x + \tan x}\right)\:dx = \int \dfrac{du}{u}[/tex]
[tex]= \ln |u| + C = \ln |\sec x + \tan x| + C[/tex]