Answer:
the answer is C ----- it is the rate of change of velocity per unit time
Explanation:
acceleration
[tex] = \frac{velocity(v)}{time(t)} [/tex]
which is the correct equation for the elastic potential energy stored in a spring
A EPE = mv
B EPE = 1/2kx^2
C EPE = F(delta)t
D EPE = -kx
(B)
Explanation:
[tex]pe = \frac{1}{2} k {x}^{2} [/tex]
The equation of the elastic potential energy stored in the spring can be represented as: EPE = (1/2)kx². Therefore, option (B) is correct.
What is elastic potential energy?The elastic potential energy can be described as the total energy obtained as a result of deformation in the shape of an object. The elastic potential energy implies any object which is capable of regaining its actual shape and size after deformation.
The deformation is only possible as a result of the gained potential energy which is called the elastic potential energy. The elastic potential energy can be stored energy of a compressible or stretchable in other words stored energy of perfectly elastic materials.
The mathematical equation of the elastic potential energy formula is given by:
U = 1/2 (Force × Displacement)
U = (1/2) (kx) (x)
U = (1/2)kx²
Where k is the spring constant and x is the displacement as a result of applied external force.
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¿A qué velocidad debe circular un auto de carreras para recorrer 87 km en 20 min? (pasar a metros por segundo m/s)
Answer:
Velocidad en m / s = 72,25 m / s
Explanation:
Dado
Distancia a recorrer por el coche de carreras = 87 Km
1 km = 1000 m
Por lo tanto, 87 km = 87000 m
Tiempo necesario para viajar 87 km / 87000 metros = 20 minutos o 20 * 60 = 1200 segundos
Velocidad en m / s = 87000/1200
Velocidad en m / s = 72,25 m / s
A mass hanging from a pendulum at the end of a string of negligible mass. The string has a length of 0.84 m. With the string hanging vertically, the object is given an initial velocity of 1.4 m/s parallel to the ground and swings upward on a circular arc. Eventually, the object comes to a momentary halt at a point where the string makes an angle θ with its initial vertical orientation and then swings back downward. Find the angle θ.
Explanation:
tan(theta)=(v^2)/(length of string × g)
=(1.4^2)/(0.84 × 9.8m/s )
=1.96/(8.232)
=0.2380952381
theta=arctan(0.2380952381)
=13.4°
goodie morning
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what is nitric acid?
Answer:
Nitric acid, also known as aqua fortis and spirit of niter, is a highly corrosive mineral acid. The pure compound is colorless, but older samples tend to acquire a yellow cast due to decomposition into oxides of nitrogen and water. Most commercially available nitric acid has a concentration of 68% in water.
Explanation:
Good morning...
Nitric acid production is mainly driven by fertilizer industry. Nitric acid is used in the production of ammonium nitrate and calcium ammonium nitrate which find applications as fertilizers.
2 Ten identical lengths of wire are laid closely side-by-
side. Their combined width is measured and found
to be 14.2 mm. Calculate:
a the radius of a single wire
b the volume in mm' of a single wire if its length is
10.0 cm. (Volume of a cylinder = ferih, where r =
radius and h = height.
Answer:
(a) 0.71 mm
(b) 0.158 cubic cm
Explanation:
The width of one wire is the diameter of the wire.
(a) Let the diameter of each wire is d.
So, 10 d = 14.2 mm
d = 1.42 mm
radius of each wire, r = d/2 = 1.42/2 = 0.71 mm
(b) Length, L = 10 cm
The volume of the single wire is given by
[tex]V =\pi\times r^2\times h \\\\V =3.14\times 0.071^2\times 10\\\\V =0.158 cm^3[/tex]
An electron with a charge of -1.6 x 10-19 C experiences a force of 9.2 x 10-15 N. What is the intensity of the electric field?
Answer:
Explanation:
[tex]E=\frac{q}{F}[/tex] where q is the charge of the electron and F is the electrostatic force. Filling in:
[tex]E=\frac{-1.6*10^{-19}}{9.2*10^{-15}}[/tex] which gives you an electric field magnitude of
E = -1.7 × [tex]10^{-5[/tex] C/N
An object is placed closer to the lens than f for a diverging lens. The image will be located:
a) between f and 2f
b) between the lens and f
c) A or B or C
d) farther than 2f
Tom is throwing an baseball at an aluminum can,
present an argument about the likely kinetic energy of the ball before and after.
describe the evidence that would support the argument.
present an argument about the likely kinetic energy of the can before and after.
describe the evidence that would support the argument.
Answer:
The question relates to the conservation of energy principle, the conservation of the linear momentum, and Newton's Laws of motion
Part A
1) Tom throwing a baseball at a can
The initial velocity of the baseball = v₂
The initial kinetic energy of the baseball, K.E.₂ = (1/2)·m₂·v₂²
∴ The final kinetic energy of the baseball, K.E.₂' = (1/2)·m₂·v₂'² < (1/2)·m₂·v₂²
Therefore, the energy of the ball before the collision is lesser than the energy of the ball after the collision
2) The evidence that would likely support the claim is that the baseball's height above the ground reduces rapidly immediately after the collision which is due to the reduced velocity, and therefore, the reduced (kinetic) energy
The final velocity of the baseball v₂' < v₂
Part B
1) The argument
The initial velocity of the can = v₁ = 0 (The can is initially at rest)
The initial kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² = 0
The final velocity of the can v₁' > v₁ = 0
∴ The final kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² > 0
Given that the velocity of the can increases from zero to a positive value after collision with the baseball, the kinetic energy of the can is increased from zero before the collision to a positive value after the collision
2) An evidence in support of the argument is the motion of the can which was initially at rest which is an indication of increase in energy podded by the can
Explanation:
i will mark brainliest if you get it right.
Answer:
Satellite D
Explanation:
It has more mass
Which of the following metals is the most important in atomic research
Uranium
Beryllium
Silver
Copper
Answer:
Uranium
Explanation:
The most important in atomic research is Uranium, Uranium Can be used as fuel for nuclear power plants and the nuclear reactors that run naval ships and submarines, so option A is correct.
What are atoms?The atom is the smallest unit of matter that may be divided without generating particles with an electrical charge. Additionally, it is the tiniest material with characteristics similar to chemical elements. As a result, the atom acts as the basic building block of chemistry.
Space makes up the majority of an atom. The rest is made up of a positively charged nucleus made up of protons and neutrons that are surrounded by a cloud of negatively charged electrons. The nucleus is small and dense when compared to electrons, which are the lightest charged particles in nature. Electric forces, link electrons to the nucleus of atoms, causing them to be drawn to any positive charge.
Uranium that has been "enriched" to have a higher concentration of U-235 can power nuclear power plants, and It can also be applied to nuclear weapons.
Therefore, uranium is the most important in atomic research.
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HELP PLEASE ?? can u answer this multiple choice for me please?
Answer:
.04 kg m/s
Explanation:
Momentum is simply mass multiplied by velocity given by p = mv. You can consider momentum as mass in motion.
Before the collision, the data given for the toy train:
v = 0.5m/s
m = 75g
We need to convert grams into the SI unit of mass, kg.
75g / 1000g * 1kg = 0.075kg
Using p = mv, we can determine:
p = 0.075kg * 0.5m/s = 0.0375 kg m/s
Rounding to the value of 1 sig-fig, it comes out to be 0.04 kg m/s.
Wire B has twice the length and twice the radius of wire A. both wires are made from the same material. if wire A has a resistance R, what is the resistance of wire B?
Answer:
Hello There!!
Explanation:
1/2R because wire B has twice the radius,it has four times the cross-sectional area of wire A.
hope this helps,have a great day!!
~Pinky~
When should a bar graph be used?
A. When the independent variable is composed of categories and does not show a
relationship
B. When the independent variable is continuous and does not show a relationship to the
dependent variable.
C. When the independent variable is continuous and shows a causal link to the
dependent variable,
D. When there is no independent variable.
Answer:
B. When the independent variable composed of categories and does not show a relationship to the dependent variable
Explanation:
A bar graph, is a graph used for presenting data grouped into categories, which are the independent variables of the graph, and the measurement of each category, which are represented as rectangular bars having lengths proportional to the value of the category, on a chart
In the bar graph or chart, there is no direct relationship between the categories, which are the x-values and the dependent variables , which are the length of the bars, the y-values, as the length of the rectangular bar in one category, cannot be obtained from another category through a relationship
Therefore, the correct option is option is when the independent variable composed of categories and does not show a relationship to the dependent variable
Gold is more active than copper? A. True B. False
Answer:
false
Explanation:
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Let's say that the teacher raised the lawn bowling ball to a height of 1.6 meters before they released it . THE LAWN BOWLING BALL HAS A MASS OF 4KG . Remember that " g " ALWAYS equals 9.8 m / s² . Calculate the gravitational potential energy of the lawn bowling ball at this position
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a ball of mass 0.2 kg is dropped from a height of 20m on impact to the ground it loses in 30 joule of energy calculate the height it reaches on rebound
Answer:
5 m
Explanation:
We'll begin by calculating the original potential energy. This can be obtained as follow:
Mass (m) = 0.2 Kg
Height (h) = 20 m
Acceleration due to gravity (g) = 10 m/s²
Energy (E₀) =?
E₀ = mgh
E₀ = 0.2 × 10 × 20
E₀ = 40 J
Next, we shall determine the new energy of the ball.
Energy (E₀) = 40 J
Energy lost (Eₗ) = 30 J
New energy (E) =?
E = E₀ – Eₗ
E = 40 – 30
E = 10 J
Finally, we shall determine height of the ball on rebound. This can be obtained as follow:
New energy (E) = 10 J
Mass (m) = 0.2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) =?
E = mgh
10 = 0.2 × 10 × h
10 = 2 × h
Divide both side by 2
h= 10 / 2
h = 5 m
Thus, the height of the ball on rebound is 5 m
In what direction does the force of friction act?
A. Perpendicular to the surface, pointing up
B. Perpendicular to the surface, pointing down
C. Along the surface, in the direction opposite to the motion
D. Along the surface, in the same direction as the motion
A 5-kg box is pushed with a horizontal force of 100 N across a floor. What power output is neede d to push the box a distance of 60 meters in 2 minutes? (A) 10 W (B) 25 W (C) 30 W (D) 50 W
Answer:
(D) 50 W
Explanation:
Given the following data;
Mass = 5 kg
Force = 100 N
Distance = 60 N
Time = 2 minutes
Conversion:
1 minute = 60 seconds
2 minutes = 60 * 2 = 120 seconds
To find the power output required to push the box;
First of all, we would determine the work done in pushing the box.
Work done = force * distance
Workdone = 100 * 60
Workdone = 6000 Joules
Next, we find power output;
Power = workdone/time
Power = 6000/120
Power = 50 Watts
what revovles around the sun and is made out of rock,ice,gas,and dust?
Answer:
Comets are cosmic snowballs of frozen gases, rock and dust that orbit the Sun. When frozen, they are the size of a small town. When a comet's orbit brings it close to the Sun, it heats up and spews dust and gases into a giant glowing head larger than most planets.Hope this is fine for you,,!!If a train traveled 400 miles north and traveled back 275 miles south and the total trip took 5 hours to complete, what was the average velocity of the train in mph?
The average velocity is 25 mph north.
Average velocity = displacement/time
Displacement =
(400 mi north) + (275 mi south)
Displacement = 125 mi north
Average V = (125 mi north) / 5 hours.
Average V = 25 mph north
A force of 20 N acted on a 5 kg object, moving it a distance of 4 m. How much work was done on the object?
Answer:
400J
Explanation:
The work done by the force on the object is 80 J.
What is work ?The work is defined by the product of force and displacement. Its unit of measurement is joule. And the formula is,
Work = Force ×Displacement
Or mathematically it is W = F.d
In the question given data ,[tex]F = 20N , d = 4m\\[/tex]
putting in the above formula ,W = 20 × 4
W = 80 J
Hence the work done by the force is 80J.
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A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the iron cube was 20.0 ˚C. The cube of iron raised the temperature of the water to 45.0 ˚C. If the iron cube has a mass of 133 g, what is the specific heat capacity of iron?
Answer:
451.13 J/kg.°C
Explanation:
Applying,
Q = cm(t₂-t₁)............... Equation 1
Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.
Make c the subject of the equation
c = Q/m(t₂-t₁).............. Equation 2
From the question,
Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C
Substitute these values into equation 2
c = 1500/[0.133(45-20)]
c = 1500/(0.133×25)
c = 1500/3.325
c = 451.13 J/kg.°C
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Option C: Later in the day, less power is developed in lifting each box
Answer:
Later in the day, less power is developed in lifting each box.
power= workdone÷time
A radio station transmitted a radio wave with frequency of 25MHz the value of the frequency is equivalent to? *
Question
A radio station transmitted a radio wave with frequency of 25MHz the value of the frequency is equivalent to? Leave answer in Hz and in standard form.
Answer:
2.5 x 10⁷Hz
Explanation:
The measured frequency is 25MHz
To convert this to Hz, we simply change the M, which means mega, to its equivalent value which is 10⁶.
Therefore, we have;
25MHz = 25(10⁶) Hz
=> 25MHz = 25 x 10⁶ Hz
Now express this value in standard form as follows;
25 x 10⁶ Hz = 2.5 x 10¹ x 10⁶
=> 25 x 10⁶ Hz = 2.5 x 10⁷ Hz
Therefore, the value of 25MHz is equivalent to 2.5 x 10⁷Hz
The value of the frequency of the radio wave is equivalent to 2.5 × 10⁷ Hertz.
Given the data in the question;
Frequency of radio wave; [tex]f = 25MHz[/tex]
Frequency is the number of occurrences of a repeating event per unit of time. The SI unit for frequency is the hertz (Hz)
We know that;
[tex]1MHz\ ( Megahertz) = 1000000 Hz\ ( Hertz )[/tex]
so
[tex]25MHz = x[/tex]
We cross multiply
[tex]x = \frac{25MHz\ *\ 1000000Hz}{1MHz} \\\\x = 2.5 * 10^7 Hz[/tex]
Therefore, the value of the frequency of the radio wave is equivalent to 2.5 × 10⁷ Hertz.
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Which one of the following is an example of a solution?
a. Sand particles in water
b. Orange Squash
c. Vinegar
d. Paint
Answer:
it is maybe A but i'm not 100% sure
Explanation:
its the only one that is mixed
Una persona pesa 700 N al nivel del mar. ¿Cuándo sube a un avión a 10000 m de altura pesará más, igual o menos?
Answer:
La persona pesa menos
Explanation:
Generalmente, definimos el peso como la fuerza gravitacional que actúa sobre un objeto.
Dado que la constante gravitacional depende del cuadrado de la distancia medida desde el centro de la Tierra, podemos concluir que el peso de un objeto disminuye a medida que aumenta la distancia entre el objeto y el centro de la Tierra (mayor altitud).
Por lo tanto, la persona que pesa 700 N al nivel del mar pesará menos cuando esté en un avión a una altitud de 10,000 m.
1) Use SolidWorks (SW) FEA to apply a bending load of 600 lbf on the right end of the stepped shaft as shown below. This is the same geometry as H01. Estimate stress concentration factor Kt for bending from your FEA. Provide a hardcopy color plot of your FEA showing maximum von Mises stress.
Solution :
Given :
L = 1 in
d = 0.75 in
D = 1 in
Fillet radius, r = 0.063 in
[tex]$K_{t_{bending}=\frac{\sigma_{FEA_{bending }}}{\sigma_{Nominal_{bending }}}$[/tex]
We know that :
[tex]$\sigma_{b} = \frac{32M}{\pi d^3}$[/tex]
[tex]$\sigma_{b} = \frac{32 \times (2998.63 \times 25.4)}{\pi (0.75 \times 25.4)^3}$[/tex]
[tex]$=112.27 \ N/mm^2$[/tex]
[tex]$\sigma_{FEA} = 1.3 \times 10^8 \ N/m^2$[/tex]
[tex]$=1.3 \times 10^8 \times 10^{-6}$[/tex]
[tex]$=1.3 \times 10^2$[/tex] MPa
= 130 MPa
Therefore, the stress concentration factor is :
[tex]$k_t=\frac{130}{112.27}$[/tex]
= 1.157922
The rate at which electric
charges flow through a
circuit
Answer:
The answer is Current.
4. A cell membrane contains all of the following EXCEPT:*
O glycolipids
phospholipids
sphingolipids
steroids
none of the above
Answer:
The correct answer is - none of the above.
Explanation:
Cell membranes or plasma membranes of the cell are composed mainly of fatty-acid-based lipids and proteins. Membrane lipids are of two types majorly, glucolipids, phospholipids, and sterols (generally cholesterol).
Sphingolipids are also a structural component of the cell membrane that helps in segregation into distinct membrane domains. Glycolipids are present on the surface of the plasma membrane.
Which statement about the mass and the weight of an object is correct?
A They are both affected by changes in the acceleration of free fall.
B They are both forces.
C They have different units.
D Weight is calculated by dividing mass by the acceleration of free fall.
Answer:
HOPE IT HEPLED U !!!!
Explanation:
i think it's (C) They have different units ....
