Which equaiton reprsents a line that passes through the two points in the table? A.y+1=5/4(x+1) B.y+6=4/5(x+5) C.y-6=4/5(x-5) D.y-1=5/4(x-1)

The Answer is:

C.) (x+2)(x+3)

Answer:

(x-2)(x+3)

Step-by-step explanation:

1. Start by setting up the synthetic division. The numbers 1, -4, -11, and 30 go on the inside on the division. To get the number on the outside, set x-5 equal to 0. solve and get 5.

2. bring the one down. multiply the one and the five and place the number you get underneath the -4 in the next column. From there, add the two numbers in the column.

3. After adding those two numbers, put the number you get (which should be 1) directly below the 5. Now multiply that number and the 5 again.

4. Repeat these steps until you fill the spaces under the next two columns. If you do it correctly, the number at the bottom of the very last column should be 0. This zero is known as the remainder. The remainder is not needed to complete this problem.

 Now that you have finished synthetic division, it is time to set up the new equation you got.

5. The 1 on the bottom left will be your [tex]x^{2}[/tex] value, the next 1 will be your x value, and the -6 will be your c. You should get the equation [tex]x^{2} + x -6[/tex]

6. From here, factor the polynomial. The factors must add up to the middle value (1) and multiple to c (-6). The factors -2 and 3 add up to 1 and multiply to -6

Therefore, your answer will be (x-2)(x+3)

Answer:

m = 4

Step-by-step explanation:

m = -29 + 33

Answer:

the answer is m=4

hope this helps

have a good day :)

Step-by-step explanation:

33+-29=4

Given:

The data values are:

21, 32, 17, 24, 15, 30, 28 and 26.

To find:

The first quartile, third quartile, and interquartile range.

Solution:

We have,

21, 32, 17, 24, 15, 30, 28, 26

Arrange the data values in ascending order.

15, 17, 21, 24, 26, 28, 30, 32

Divide the data set in two equal parts.

(15, 17, 21, 24), (26, 28, 30, 32)

Divide each parenthesis in two equal parts.

(15, 17), (21, 24), (26, 28), (30, 32)

Now, the first quartile is:

[tex]Q_1=\dfrac{17+21}{2}[/tex]

[tex]Q_1=\dfrac{38}{2}[/tex]

[tex]Q_1=19[/tex]

The third quartile is:

[tex]Q_3=\dfrac{28+30}{2}[/tex]

[tex]Q_3=\dfrac{58}{2}[/tex]

[tex]Q_3=29[/tex]

The interquartile range is:

[tex]IQR=Q_3-Q_1[/tex]

[tex]IQR=29-19[/tex]

[tex]IQR=10[/tex]

Therefore, the first quartile is 19, third quartile is 29 and the interquartile range is 10.

Answer:

6 sqrt(3) = x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp/ hyp

sin 60 = x/12

12 sin 60 =x

12 ( sqrt(3)/2) =x

6 sqrt(3) = x

Answer:

x=6[tex]\sqrt{3}[/tex]

Step-by-step explanation:

take 60 degree as reference angle

using sin rule

sin 60=opposite/hypotenuse

[tex]\sqrt{3[/tex]/2=x/12

do cross multiplication

2*x=12*[tex]\sqrt{3}[/tex]

x=12[tex]\sqrt{3}[/tex] /2

x=6[tex]\sqrt{3}[/tex]

Answer: 4'6 2'4

Step-by-step explanation:

Answer:

Mean= 44.2

Median=45

Mode=6

Range=50

Step-by-step explanation:

Mean= (10x1 +30x2 + 40x3 +50x2 +60x4)/12

= 530/12

=44.17

=44.2

Median= 40+50 /2

=45

Mode= 6

Range= 60-10

=50

Answer:

y-8x+7=0

Step-by-step explanation:

slope(m)=8

using slope intercept form of equation of staright line we get

y=mx+b

y=8*x+b

y-8x=b ................  eq(i)

since the line include the point (2,9) it satisfies the euation,

here x=2 and y=9

equation: y-8x=b

9-8*2=b

9-16=-b

-7=b

substituting the value of b in eq(i) we get

y-8x=-7

y-8x+7=0   is a required equation of the line.

Answer:

-3

Step-by-step explanation:

This is a quadratic equation. Therefore, one way we can solve this is by using the quadratic formula, [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex] and [tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex].

a, b, and c represent the coefficients in our equation [tex]x^2-5x-24=0[/tex]. a represents the coefficient of the term with degree of 2, which is 1. b represents the coefficient of the term with degree of 1, which is -5. c represents the coefficient of the term with degree of 0, which is -24.

Let us plug them in the equation! Let us start with this one: [tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{5+\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5+\sqrt{25+96} }{2} =\\\frac{5+\sqrt{121} }{2} =\\\frac{5+11}{2} =\\\frac{16}{2} =\\8[/tex]

Oops! We are looking for the other solution. Let us plug in the values in this equation instead: [tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{5-\sqrt{(-5)^2-4*1*(-24)} }{2} =\\\frac{5-\sqrt{25+96} }{2} =\\\frac{5-\sqrt{121} }{2} =\\\frac{5-11}{2} =\\\frac{-6}{2} =\\-3[/tex]

I hope this helps! Let me know if you have any questions :)

Answer:

choose B is the greatest variablity

Answer:

-5

Step-by-step explanation:

12-7=5

7-12=-5

If this helps please mark as brainliest

Arithmetic

7-12

Meaning, 12 less than 7.

7-12=-5

Answer:

B. [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

Step-by-step explanation:

No. of students from first grade = 15

No. of students from second grade = 5

There are 5 rows of seats

Each row contains 5 seats

Total seats = 25

No. of ways for second-grade students to occupy the first row (i.e first 5 seats) = [tex]^{5} P_{5}[/tex]

Remaining seats = 20

So, now we are left with 15 first grade students  

So, No. of ways for first-grade students occupy remaining seats = [tex]^{20} P_{15}[/tex]

Using the counting rule principle,

No. of ways for the students can be seated if all of the second-grade students occupy the first row = [tex]^{5} P_{5}[/tex] × [tex]^{20} P_{15}[/tex]

So, Option B is the correct answer

Hence, no. of ways for the students can be seated if all of the second-grade students occupy the first row is ×

There are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

A permutation in math is the number of ways in which a set of data or objects can be ordered or arranged, where the order matters.

Given that, a school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second-grade travel in the bus.

Since you have to place all first-grade students in the first three rows,

Therefore,

For the 15 first-graders of the first three rows (15 seats), we have ¹⁵P₁₅ since all 15 places have to be occupied by all 15 first-graders.

Then we have 10 remaining seats left to be assigned to the 5 second-graders = ¹⁰P₅

We then multiply the permutation numbers of those two arrangements to get the total ways:

¹⁵P₁₅ x ¹⁰P₅

Hence there are ¹⁵P₁₅ x ¹⁰P₅ possible way to seat, if all of the second-grade students occupy the first row.

Learn more about permutation click;

https://brainly.com/question/30649574

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Answer:

a

Step-by-step explanation:

follow the proportions

Answer:

A

Step-by-step explanation:

Answer:

scale factor: 2

translation: (x+2, y+7)

Step-by-step explanation:

Answer:

y = 6·sin(3·(x - 1)) + c

Step-by-step explanation:

The general form of an equation for a sinusoidal function is presented ad follows;

y = a·sin(b·(x - h) + c

Where;

a = The amplitude of the equation

T = The period = 2·π/b

h = The phase shift

c = The vertical shift

From the question, we have;

a = 6,

2·π/3 = 2·π/b

∴ b = 3

h = 1

We get;

y = 6·sin(3·(x - 1)) + c.

Answer:

A = 24

Step-by-step explanation:

Use the problems provided info!

A = B+8

C = 2B

72 = B+8+2B+B

72-8 = 4B

6434 = 4B/4

16 = B

A = 24

B = 16

C = 32

Answer:

3 x 5 is the gcf of 45 and 75. gcf(45,75) = 15.

Step-by-step explanation:

hope this helped! yw :}

Answer:

C

Step-by-step explanation:

2ab * sqrt[3](192ab^2) - 5 * sqrt[3](81 a^4b^5) =

= 2ab * sqrt[3](4^3 * 3 * a * b^2) - 5 * sqrt[3](3^3 * 3 * a^3 * a * b^3 * b^2)

= 2ab * 4 sqrt[3](3 * a * b^2) - 5 * 3 * a * b * sqrt[3](3 * a * b^2)

= 8ab * sqrt[3](3 * a * b^2) - 15ab * sqrt[3](3 * a * b^2)

= -7ab * sqrt[3](3ab^2)

Answer: C

Answer:

I dont see the whole question

Step-by-step explanation:

Answer:

Remember the relation:

Distance = Speed*Time.

Then if we define:

y = distance

x = time

Speed = 50km/hr

Then we can write the relation between distance and time is:

y = (50km/hr)*x

This is the equation we need to graph.

To graph it, we can just find two points of that equation, and then draw a line that connects them:

For example if we have x = 0hr then:

y = (50km/hr)*0hr = 0km

then we have the point (0hr, 0km)

If now we use the point x = 1hr, then:

y = (50km/hr)*1hr  = 50km

Then we also have the point (1hr, 50km)

Now we can draw these two points and connect them by a line, that line is the graph of the equation.

The graph of the equation can be seen below:

Step-by-step explanation:

Translation: (x,y)↦( 9, -12)

Scale factor: 2

Translation:

(x,y)↦( 9, -12 )

Scale factor:

2 is the required answer.

Answer:

C    The mean or median

Step-by-step explanation:

Answer:

XY=6

Step-by-step explanation:

13-7=6

Answer:

XY = 6

Step-by-step explanation:

We know that the whole line (XZ) is equal to 13, and we know that YZ + XY is equal to XZ.

XZ = XY + YZ

13 = XY + 7

6 = XY

Hope this helped :)

Answer:

En contraste con el seno, el coseno permite diferenciar triángulos obtusángulos de triángulos acutángulos.

Step-by-step explanation:

Por Geometría Euclideana sabemos que la suma de todos los ángulos internos de un triángulo es igual a 180°, si el triángulo no es rectángulo, entonces acutángulo o obtusángulo.

Un triángulo es acutángulo cuando todos sus ángulos son agudos, es decir, cuyas medidas sean mayores que 0° y menores que 90°, mientras que un triángulo es obtusángulo cuando uno de sus ángulos es mayor que 90° y menor que 180° y los dos ángulos restantes son agudos.

El seno es una función periódica y acotada entre -1 y 1, que es positiva entre 0° y 180°, significando que esta función trigonométrica es demasiado "débil" para diferenciar a un triángulo obtusángulo de uno acutángulo. En cambio, el coseno es una función periódica y acotada entre -1 y 1, que es positiva entre 0° y 90°, y negativa entre 90° y 180°, convirtiéndola en un criterio "fuerte" para diferenciar triángulos obtusángulos de triángulos acutángulos.

Step-by-step explanation:

yes friend and your answe is wring

Answer:

2m+8

Step-by-step explanation: