any 5
algebraic formulas
Answer:
a2 – b2 = (a – b)(a + b)
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 – 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4
Answer:
a2 – b2 = (a – b)(a + b)
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 – 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)
Y and x have a proportional relationship, and y=4 when x=12
Answer:
multiply 4 by 12 okay bro
Answer:
y = [tex]\frac{1}{3}[/tex] x
Step-by-step explanation:
Given that y and x are proportional then the equation relating them is
y = kx ← k is the constant of proportion
To find k use the condition y = 4 when x = 12 , then
4 = 12k ( divide both sides by 12 )
k = [tex]\frac{4}{12}[/tex] = [tex]\frac{1}{3}[/tex]
y = [tex]\frac{1}{3}[/tex] x ← equation of proportion
What are the root(s) of the quadratic equation whose related function is graphed below?
Answer:
0 and 4
Step-by-step explanation:
roots are where the graph intersects at x axis
The roots of the quadratic equation whose related function is graphed are 0 and 4, the correct option is C.
What is the quadratic equation?A quadratic equation is a second-order equation written as ax2 + bx + c = 0 where a, b, and c are coefficients of real numbers and a ≠ 0.
If b2 – 4ac > 0 roots are real and different. As the discriminant is >0 then the square root of it will not be imaginary. It has two cases.
If b2 – 4ac is a perfect square then roots are rational. As the discriminant is a perfect square, so we will have an integer as a square root of the discriminant. Hence, the roots are rational numbers.
The shape of the graph is a downward parabola on the positive x-axis therefore the roots of the graph are positive.
From the given option the roots of the equation are 0 and 4 both are positive.
Hence, the roots of the quadratic equation whose related function is graphed are 0 and 4.
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what value of x is in the solution set of -5-15>10+20x
Answer:
-3/2 >x
Step-by-step explanation:
-5-15>10+20x
Combine like terms
-20 > 10 +20x
Subtract 20 from each side
-20 -10 > 10+20x-10
-30> 20x
Divide by 20
-30/20 >20x/20
-3/2 >x
Answer:
-3/2 > x
Step-by-step explanation:
-5 - 15 > 10 + 20x
^ ^
-20
-20 > 10 + 20x
-10 -10
---------------------
-30 > 20x
----- -------
20 20
-3/2 > x
Hope this helped.
hi pls help.you do not have to do all 3. just either one will be ok pls explain as well:) thank you
Answer:
[tex]{7a^{5}b^{5} c\\[/tex]
Step-by-step explanation:
[tex]\frac{28a^{8}b^{6} c^{3} }{4a^{3}bc^{2} }[/tex]
→ First look at the first term of each expression and see if they can be simplified, and they can
[tex]\frac{7a^{8}b^{6} c^{3} }{a^{3}bc^{2} }[/tex]
→ Now look at the a terms, since a larger one is at the top, you subtract
[tex]\frac{7a^{5}b^{6} c^{3} }{bc^{2} }[/tex]
→ Now simplify the b and c terms
[tex]{7a^{5}b^{5} c[/tex]
Four times an angle is equal to half of its supplement. Find the measures of both angles.
Answer:
The bigger angle is 144 degrees and the smaller one is 36 degrees
find the radius of a circle for which an arc 6 cm long subtends an angle of 1/3 radians at the center?
plz some one can help to solve the question??
Step-by-step explanation:
Eueydhhdgdgdbdbddbdbhd
Answer:
Hello,
[tex]R=\dfrac{18}{\pi}\ (cm)[/tex]
Step-by-step explanation:
[tex]Formula: \ L=\theta*R\\[/tex]
[tex]R=\dfrac{6}{\dfrac{\pi}{3} } =\dfrac{6*3}{\pi} =\dfrac{18}{\pi}\ (cm)[/tex]
f(x) = 2x + 7 with domain: x = {2, 3, 5, 9}
Answer:
2(2)+7=11
2(3)+7=13
2(4)+7=15
2(5)+7=17
2(9)+7=25
Step-by-step explanation:
2(2)+7
4+7=11
2(3)+7
6+7=13
2(4)+7
8+7=15
2(5)+7
10+7=17
2(9)+7
18+7=25
Find the place value of 8 in 2456.1387.
Tenths
Hundredths
Thousandths
Thousands
Answer: Third Choice. Thousandths
Step-by-step explanation:
Concept:
Here, we need to know the order and name of each place value.
Please refer to the attachment below for the specified names.
Solve:
STEP ONE: Orde and name each place
2 ⇒ One Thousands
4 ⇒ Hundreds
5 ⇒ Tens
6 ⇒ Ones
.
1 ⇒ Tenths
3 ⇒ Hundredths
8 ⇒ One Thousandths
7 ⇒ Ten Thousandths
STEP TWO: Find the number [8] in the number
As we can see from the list above, 8 is at the right of the decimal point, thus, the place value is Thousandths.
Hope this helps!! :)
Please let me know if you have any questions
Find the length of each side and the
perimeter.
(5n -17) cm
(2n + 1) cm
n cm
7n-16
Step-by-step explanation:
Sry can u give me the picture
1. The product of two consecutive numbers is 42. What are the numbers?
Answer:
6, 7
Step-by-step explanation:
6 x 7 = 42
Find m so that the equation msin²x+cos²x=m-1 has a solution on the interval (0;π/4)
msin²x+cos²x=m-1
since the interval are 0 and π/4
Therefore
msin²(0)+cos²(0)=m-1
m(0)+1=m-1
1=m-1
m=2
use π/4 now
msin²(π/4)+cos²(π/4)=m-1
m(1/2)+(1/2)=m-1
m+1=2(m-1)
m+1=2m-2
-m=-3
m=3
Therefore
m=2 or 3
evaluate the expression. check all possible sets that the solution may belong in. 40-5^2
Answer:
15
Step-by-step explanation:
following PEMDAS, we don't have () so we move on to exponents
5^2 is equal to 5 x 5 which is 25
40-25=15
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{40 - 5}\mathsf{^2}\\\\\\\large\textsf{5}\mathsf{^2}\\\large\textsf{= 5}\times\large\textsf{5}\\\large\textsf{= \bf 25}\\\\\\\large\textsf{= 40 - 25}\\\\\\\large\textsf{= \bf 15}\\\\\\\\\\\\\boxed{\boxed{\huge\textsf{Therefore your answer is: \bf 15}}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\textsf{Amphitrite1040:)}[/tex]
please help me
its urgent :)
Step-by-step explanation:
i Will help wit Shape A and Next Try to figure out Shape B
shape A Looks the Shape XY coordinate, which Horizontal & Vertical Line
Shape A Coordinate
X = 7, 8.5, 7,5, 7.5,
Y = 7, 7, 6.5 , 5
if you wanna to understand this coordinate between X & Y try plotting with Horizontal or Vertical Line at your Shape And you Would be Understanding about these coordinate meaning
what does the rational form of the ratio a:b look like
Answer:
a/b
Step-by-step explanation:
The rational form of a:b or simply a/b is in the simplest form.
Answer:
Step-by-step explanation:
the answer is option 2 from the above sheet
The price of 5 kg of rice is ₹83.75. How many kilograms of rice can you buy for ₹670?
Answer:
40 kg
Step-by-step explanation:
[tex]\frac{5}{83.75} :\frac{y}{670}[/tex]
y · 83.75 = 5 · 670
83.75y = 3350
83.75y ÷ 83.75 = 3350 ÷ 83.75
y = 40
The amount of rice you can buy for ₹670 is given by the equation
A = 40 kilograms
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the amount of rice for ₹670 be A
Now , the equation will be
The amount for 5 kg of rice = ₹ 83.75
So , the amount for 1 kg of rice = amount for 5 kg of rice / 5
The amount for 1 kg of rice = 83.75 / 5
The amount for 1 kg of rice = ₹ 16.75
So , the amount of rice for ₹ 670 = 670 / amount for 1 kg of rice
The amount of rice for ₹ 670 = 670 / 16.75
The amount of rice for ₹ 670 = 40 kilograms
Therefore , the value of A is 40 kilograms
Hence , the amount of rice is 40 kg
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(Picture) Could someone help me solve this I need to use Inverse Operations but I don't fully understand? I'll mark brainliest, 10 Points.
Answer:
[tex]x = - 8[/tex]
Step-by-step explanation:
First,Step write the given equation.
[tex] \frac{x}{2} + 7 = 3[/tex]
In Algebra, we learn how to solve for a missing term called a variable. We must use inverse operations to undo terms to isolate our variable. Inverse operations means that we do the opposite of the given.
Opposite of Addition is Subtraction, vice versa.Opposite of Multipication is Division, vice versa.For example, say we have a equation
[tex]x + 2 = 3[/tex]
We would subtract 2 from both sides. E.g( remember the golden rule of algebra). What we do to one side, we do the other. This applies when we solving for a variable.
This means that
[tex]x = 1[/tex]
And if we substitute 1 in for x, it is indeed true.
[tex]1 + 2 = 3 = 3[/tex]
Now, back to the question.
[tex] \frac{x}{2} + 7 = 3[/tex]
First, we subtract 7 from both sides to get rid of the 7 on the left side. Also remeber to undo terms that aren't included in the variable when solving these problems.
So now we got
[tex] \frac{x}{2} = - 4[/tex]
Then we multiply 2 by both sides since that the opposite of division.
[tex] \frac{x}{2} \times 2 = x = -4 \times 2 = - 8[/tex]
So this means that
[tex]x = - 8[/tex]
If we plug this in, this is true.
[tex] \frac{ - 8}{2} + 7 = 3[/tex]
factorize = n!+(n-1)!
Answer:
Hello,
Step-by-step explanation:
n! + (n-1)!
=(n-1)! * n+ (n-1)!
=(n-1)! * (n+1)
help please help......
Answer:
[tex]{ \sf{( \sec \theta - \csc \theta)(1 + \tan \theta + \cot \theta) }} \\ = { \sf{( \sec \theta + \tan \theta \sec \theta + \cot \theta \sec \theta) - ( \csc \theta - \csc \theta \tan \theta - \csc \theta \cot \theta)}} \\ = { \sf{( \sec \theta + \sec \theta \tan \theta + \csc \theta) - ( \csc \theta - \sec \theta - \csc \theta \cot \theta)}} \\ = { \sf{ \sec \theta \tan \theta + \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}[/tex]
One of the legs of a right triangle measures 12 cm and its hypotenuse measures 20
cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
Answer:
cm
Submit Answer
attempt 1 out of 2
PLS HELP
Answer:
16
Step-by-step explanation:
First use the Pythagorean theorem a^2+b^2=c^2.
12^2+b^2=20^2. Solve the exponents: 144+b^2=400. Then, subtract the 144 from 400. That would be 256. Therefore b^2=256. Then you find the square root of 256=16.
Step-by-step explanation:
using pythogoras theory
hyp^2=opp^2+adj^2
you have been given the hyp and the opp so lets make the unknown x
20^2=12^2+x^2
400 =144+x^2
make x the subject of the formula
400-144=x^2
266=x^2
x=the square root of 266
HELP ME WITH THIS PLS IM FAILING REALLY BAD ITS PYTHAGOREAN THEOREM
Answer:
50 km
Step-by-step explanation:
c = √a^2+b^2
=√30^2+40^2
= √900 + 1600
=√2500
= 50 km
Answer:
50km
Step-by-step explanation:
If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.
Answer:x²-3 x+4/ 2x-3 units
Step-by-step explanation:
Area = Length * Width sq. units
x^2 - 3x + 4 = Length * 2x - 3
=>Length = x^2- 3 x + 4/ 2 x − 3 units
cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto PN
Answer:
Step-by-step explanation:
Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB
=> MP là đường trung bình của tam giác DAB => MP//BD và MP=[tex]\frac{1}{2}[/tex]BD (1)
Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC
=> QN là đường trung bình của tam giác DBC => QN//BD và QN=[tex]\frac{1}{2}[/tex]BD (2)
Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN
và độ dài MP = độ dài QN = [tex]\frac{1}{2}[/tex]BD
=> vecto MP = vecto QN
Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN
ayudenme pls aaaaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
aslo bien jjjjjjj
Step-by-step explanation:
What is the constant of proportionality in the equation x 2
—- = ——
Y 9
Answer:
The Constant is 9/2
lvan earned $8 each time he walks his neighbor's dog. he already walked the dog 5 times.
How many more times does her need to walk the dog to earn enough money to buy a game that costs $88
__? more times
find the angle measures given the figure is a rhombus.
Answer:
92
Step-by-step explanation:
180-88
Complete the tables, and the graph… HELPPP
Answer:
answer is - 1
Step-by-step explanation:
- x + y = 3
x = 4
- ( - 4 ) + y = 3
4 + y = 3. take 4 to the right
y = 3 - 4
y = - 1
I hope this answers your question.
The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value of a population?
To obtain an estimate of a parameter of a population, we use confidence intervals.
Confidence intervals:
The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.
Thus, you should select the highest sample size in the options.
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draw two intersecting line segment AB and CD intersecting O. Measure the size of each pair of vertically opposite angles. Verify each pair of vertically opposite angles are equal.
When two line segments intersects, a set of vertically opposite angles are formed. So that by comparison of angles formed in the attachment, a set of vertically opposite angles formed are: >AOC and >BOD; then >AOD and >BOC.
A pair of vertically opposite angles are formed when two lines meet at a point. And the pair of vertically opposite angles formed are said to have equal size.
From the given question, line segment AB intersecting CD at point O would produce a set of vertically opposite angles. So that each pair has equal size.
From the attached diagram, it can be observed that;
m>AOC = m>BOC = m>AOD = m>BOD = [tex]90^{o}[/tex]
But;
m>AOC ≅ m>BOD = [tex]90^{o}[/tex] (vertically opposite angle property)
also,
m>AOD ≅ m>BOC = [tex]90^{o}[/tex] (vertically opposite angle property)
Therefore it can be verified that each pair of vertically opposite angles are equal.
NB: The required diagram to the question is herewith attached to this question for more clarifications and reference.
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