16. I don't want to go anywhere apart from
Nairobi.
A. instead
B. only
C. besides
D. than​

Answer:

1a) .68 moles 1b)4.1E-23 molecules.

2a) .37 moles 2b) 2.27E-23 molecules

Explanation:

1a) CO2 is equal to 44 grams (C→12 grams,O→16 grams[·2]) .30g/44g is .68 moles.

1b) multiply 1A by advogadros number (6.022E-23)

2a) NaCl is 58 grams. 22/58 is .37 moles.

2b) multiply 2A by advogadros number.

you'd answer #3 the same way #1 and #2

The branch of science that deals with chemicals and bonds are called chemistry. The moles are units to calculate the quantity required to use the element.

The correct answer is mentioned below.

According to the question, the moles to the option is as follows:-

[tex]n =\frac{M}{M.M}\\ \\\frac{30}{44} \\\\=0.681\\\\[/tex]

The number of molecules is [tex]0.68 *6022*10^{23} =4.09496*10^{23[/tex].

2. moles of 22 grams of NaCl is

[tex]\frac{22}{44}\\ \\=0.5\\\\[/tex]

Molecules will be [tex]0.5*6.022*10^{23} = 3.011*10^{23}[/tex]

3. moles of 50-gram ammonia

[tex]\frac{50}{17} \\\\2.94\\[/tex]

The number of molecules is [tex]2.94*6.022*10^{23} = 1770*10^{23[/tex]

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Answer:

Inverse proportion occurs when one value increases and the other decreases. For example, more workers on a job would reduce the time to complete the task. They are inversely proportional.

Answer:

A

Explanation:

Answer:D. Oxygen gas

Explanation: because the experiment showed

Answer:

The number of balloons is 948.8.

Explanation:

The number of balloons can be calculated as follows:

[tex] N = \frac{V_{f}}{V_{T}} [/tex]

Where:

[tex]V_{f}[/tex]: is the volume at 1.086 atm

[tex]V_{T}[/tex]: is the balloon volume = 2.414 L  

The volume at 1.086 atm can be found using Boyle's law:

[tex] P_{i}V_{i} = P_{f}V_{f} [/tex]

[tex] V_{f} = \frac{P_{i}V_{i}}{P_{f}} = \frac{169.1 atm*14.71 L}{1.086 atm} = 2290.5 L [/tex]

Now, the number of balloons is:

[tex] N = \frac{V_{f}}{V_{T}} = \frac{2290.5 L}{2.414 L} = 948.8 [/tex]

Therefore, the number of balloons is 948.8.

I hope it helps you!        

Answer:

a-Interatomic bonds

Explanation:

First of all, it is not a force. Let alone be molecular force.

Answer:

0.35 g.

Explanation:

We'll begin by calculating the number of mole of Fe(NO3)3 in 35 mL of 0.250 M Fe(NO3)3 solution.

This is illustrated below:

Molarity of Fe(NO3)3 = 0.250 M

Volume = 35 mL = 35/1000 = 0.035 L

Mole of Fe(NO3)3 =?

Molarity = mole /Volume

0.250 = mole of Fe(NO3)3 / 0.035

Cross multiply

Mole of Fe(NO3)3 = 0.25 x 0.035

Mole of Fe(NO3)3 = 8.75×10¯³ mole

Next, we shall determine the number of mole of KOH in 55 mL of 0.180 M

KOH solution. This is illustrated below:

Molarity of KOH = 0.180 M

Volume = 55 mL = 55/1000 = 0.055 L

Mole of KOH =.?

Molarity = mole /Volume

0.180 = mole of KOH /0.055

Cross multiply

Mole of KOH = 0.180 x 0.055

Mole of KOH = 9.9×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

3KOH + Fe(NO3)3 —> Fe(OH)3 + 3KNO3

From the balanced equation above,

3 moles of KOH reacted with 1 mole of Fe(NO3)3 to produce 1 mole of Fe(OH)3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

3 moles of KOH reacted with 1 mole of Fe(NO3)3.

Therefore, 9.9×10¯³ mole of KOH will react with = (9.9×10¯³ x 1)/3 = 3.3×10¯³ mole of Fe(NO3)3.

From the above illustration, we can see that only 3.3×10¯³ mole out of 8.75×10¯³ mole of Fe(NO3)3 given is needed to react completely with 9.9×10¯³ mole of KOH.

Therefore, KOH is the limiting reactant and Fe(NO3)3 is the excess reactant.

Next, we shall determine the number of mole of Fe(OH)3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of Fe(OH)3 as all of it is consumed in the reaction.

The limiting reactant is KOH and the mole of Fe(OH)3 produce can be obtained as follow:

From the balanced equation above,

3 moles of KOH reacted to produce 1 mole of Fe(OH)3.

Therefore, 9.9×10¯³ mole of KOH will react to produce = (9.9×10¯³ x 1)/3 = 3.3×10¯³ mole of Fe(OH)3.

Finally, we shall convert 3.3×10¯³ mole of Fe(OH)3 to grams. This can be obtained as follow:

Molar mass of Fe(OH)3 = 56 + 3(16 + 1) = 56 + 3(17) = 107 g/mol

Mole of Fe(OH)3 = 3.3×10¯³ mole

Mass of Fe(OH)3 =?

Mole = mass /Molar mass

3.3×10¯³ = Mass of Fe(OH)3 / 107

Cross multiply

Mass of Fe(OH)3 = 3.3×10¯³ x 107

Mass of Fe(OH)3 = 0.3531 ≈ 0.35 g.

Therefore, 0.35 g of Fe(OH)3 was produced from the reaction.

Answer:

The answer would be C.

Explanation:

I took a test with the same question.

The activation energy is very high. Hence, option C is correct.

Activation energy is the sufficient amount of energy necessary to initiate a chemical reaction.

When sodium hydroxide (NaOH) dissolves in water, it is distributed into positively-charged sodium ions and negatively - charged hydroxide ions.

These cations and anions move around in the water, free and independent of each other, though cations tend to be surrounded more closely by anions and vice versa.

Hence, when sodium hydroxide and water will react at room temperature, the activation energy is very high.

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Answer:

The evidence that demonstrated that the Chlorine in the stratosphere is believed to come primarily from CFCs ( Chlorofluorocarbons) rather than from natural sources such as volcanoes was due to the study conducted in which the amount of chlorine in the stratosphere over the past 20 years was measured and it was discovered that there was an increase over the years. This also corresponded with a rise in CFCs over the same period which shows that the chlorine in the stratosphere was from man made chemicals such as chlorofluorocarbons.

Chlorine in the stratosphere is primarily from man-made chemicals rather than from natural sources such as volcanoes is evident as follows;

Discussion;

Most of the chlorine in the stratosphere is there as a result of human activities, as the figure below illustrates.

Many compounds containing chlorine are released at the ground.

Volcanoes can emit large quantities of hydrogen chloride, but this gas is rapidly converted to hydrochloric acid, which dissolves in rain water, ice, and snow and does not reach the stratosphere.

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Answer:

Photometer

Explanation:

A photometer (photo comes from the Greek for light) measures the light coming from 140,000 stars in Kepler's stationary field of view. If a planet transits (passes in front of) any star the amount of light from the star is reduced enough so that the photometer senses it and relays the information back to the Kepler team.

Scientific instruments are tools used for researching the universe and natural sciences. A Photometer is sensitive enough to detect a planet transiting a star. Thus, option D is correct.

A Photometer is a device that converts light energy into electrical voltage by the photoelectric effect given by Einstein. It uses Quantum mechanics to convert the energy possessed by the photons and electrons. It follows Ohm's law to convert energy.

It is used to detect the planets transiting stars as they can detect the light energy as it uses the electromagnetic radiation of various wavelengths to convert them by the photodiode, resistor, and a multiplier.

Therefore, option D. a photometer is used to detect the planets in the universe transiting stars.

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Your question is incomplete, but most probably your full question was, What scientific instrument is sensitive enough to detect a planet transiting a star?

Answer:

The correct option is;

a. Delocalised electrons

Explanation:

The particles that enable electrical conductivity are the delocalised electrons

The metallic structure consists of identically shaped elements having positive ions that have a resultant alignment, surrounded by a vast array of deloclised electrons, which move freely in the metallic structure such that a metallic part usually has a high electrical conductivity.

Therefore, the freely moving delocalised electron in a metal give them the property of good conductors of electricity.

Answer:

C

Explanation:

The ions are first accelerated electrically, and then bended magnetically to sort them and record them.

Explanation:

Hi there!!

you asked to multiply these all right,

you can simply multiply it ,

=3cm × 4 cm × 1cm

= 12cm^2×1cm (4×3=12)

= 12cm^3 (12×1=12)

Therefore, theanswer is 12 cm^3.

Hope it helps..

Answer:

The shape of a molecule based on the number of electron pairs on the valence shell of its central atom

Explanation:

The improvement of the Sidgwick-Powell theory came to be known as the Valence Shell Electron Pair Repulsion theory (VSEPR). This theory approaches the determination of molecular shape from the perspective of the number of electron pairs on the valence shell of the central atom in the molecule.

Electron pairs on the valence shells of atoms leads to repulsion. Repulsion between two lone pairs is greater than repulsion between a lone pair and a bond pair which is also greater than repulsion between two bond pairs.

Lone pairs cause more repulsion, hence they distort molecules from the ideal shape predicted based on their electron domain geometry.

Answer:

[tex]\large \boxed{\text{a)188.4 g; b) 98.67 $\, \%$}}[/tex]

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:                      98.08           392.18

             2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂

To solve the stoichiometry problem, you must

a) Mass of Cr₂(SO₄)₃

(i) Mass of pure H₂SO₄

[tex]\text{Mass of pure} = \text{165 g impure} \times \dfrac{\text{85.67 g pure} }{\text{100 g impure}} = \text{141.36 g pure}[/tex]

(ii) Moles of H₂SO₄

[tex]\text{Moles of H$_{2}$SO}_{4} = \text{141.36 g H$_{2}$SO}_{4} \times \dfrac{\text{1 mol H$_{2}$SO}_{4}}{\text{98.08 g H$_{2}$SO}_{4}} = \text{1.441 mol H$_{2}$SO}_{4}[/tex]

(iii) Moles of Cr₂(SO₄)₃

The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄ [tex]\text{Moles of Cr$_{2}$(SO$_{4}$)}_{3} = \text{1.441 mol H$_{2}$SO}_{4} \times \dfrac{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}}{\text{3 mol H$_{2}$SO}_{4}} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3}[/tex]

(iv) Mass of Cr₂(SO₄)₃ [tex]\text{Mass of Cr$_{2}$(SO$_{4}$)}_{3} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3} \times \dfrac{\text{392.18 g Cr$_{2}$(SO$_{4}$)}_{3}}{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}} = \textbf{188.4 g Cr$_{2}$(SO$_{4}$)}_{3}\\\text{The mass of Cr$_{2}$(SO$_{4}$)$_{3}$ formed is $\large \boxed{\textbf{188.4 g}}$}[/tex]

b) Percentage yield

It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

[tex]\text{Percentage yield} = \dfrac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \, \% = \dfrac{\text{185.9 g}}{\text{188.4 g}} \times 100 \, \% = \mathbf{98.67 \, \%}\\\\\text{The percentage yield is $\large \boxed{\mathbf{98.67 \, \%}}$}[/tex]

Answer:

The correct options are;

1. 1,600

2. 100 Watts

A 23-30 watt CFL provides 1,600 lumens and is equivalent to a 100 Watts incandescent bulb

Explanation:

Brightness is measured in lumens and watts measure energy usage therefore with the use of an energy saving light bulb, the same lumination can be obtained at a lower energy usage.

According to a comparison chart for LED Lights vs. Incandescent Light Bulbs vs. Compact Fluorescents (CFLs) from USAI lightening website 23-30 watts CFL has a light output of 1,600 and is therefore produces enough light as a 100 Watts Incandescent Light Bulb

Also according to energy.gov website, CFLs save up to 75% energy such that a 23-30 watt CFL can produce the same illumination as a 100 watt incandescent bulb

Therefore we have, a 23-30 watt CFL provides 1,600 lumens and is equivalent to a 100 Watts incandescent bulb.

Answer:

1600 lumens, 100 watt incandescent

Explanation:

100% on edge (:

Answer:

44 neutrons

Explanation:

To find the neutrons of an atom subtract the atomic number from the mass of the atom

in this case

80-36=44

tge number of neutrons that are in that atom is 48

Heat is transferred through convection by the movement of a liquid or gas and is denoted as option D.

this is defined as the process of heat flow through a fluid which include a liquid or gas.

This process doesn't involve contact between the object unlike in conduction. A typical example is the heat flow which occurs in the atmosphere thereby making it the most appropriate choice.

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Answer:

0.009871

Explanation:

[tex] 9.871\times 10^{-3} = 0.009871[/tex]

Answer:

.009871

Explanation:

This question is incomplete, here´s the complete question.  

How does the percentage of monounsaturated and polyunsaturated fatty acids in olive oil compare to that of canola oil? Match the words in the left column to the appropriate blanks in the sentences on the right.

Olive oil has about ____ monounsaturated fats, while canola oil has about ___.

Olive oil has about ___ polyunsaturated fats, while canola oil has about ___.

6%

10%

30%

84%

5%

65%

Answer:

Olive oil has about 84% monounsaturated fats, while canola oil has about 65%.

Olive oil has about 5% polyunsaturated fats, while canola oil has about 30%.

Explanation:

Olive and canola oil are the major sources of monounsaturated fatty acids. Although vegetable oils usually have high concentrations of polyunsaturated fatty acids and less monounsaturated fats, olive and canola oils have comparatively less polyunsaturated fatty acids, and more monounsaturated fatty acids.

Answer:

rabbit

Explanation:

Answer:

rabbit

Explanation:

the rabbit is the consumer because the sun "produces" the tree and mushroom, the rabbit comes along and eats the mushroom which was produced by the sun.

Answer:

Virus is living due to reproduction and non-living due to crystal appearance.

Explanation:

Characteristics that viruses display is the ability of reproduction in which they increase in population which is a living character and have DNA or RNA which help them to make exact copies of itself. Virus is parasitic in nature because it causes harm to the living host such as humans, animals and plants. Some characteristics that viruses don't display are that they are not like living cells, have no membrane around them, no organelles such as mitochondria, golgi bodies, endoplasmic reticulum and lysosomes etc. Viruses are present in crystal form outside the cell.

Answer:

603000 J

Explanation:

The following data were obtained from the question:

Energy required (Q) =...?

Mass (M) = 10000 g

Specific heat capacity (C) = 2.01 J/g°C

Overheating temperature (T2) = 121°C

Working temperature (T1) = 91°C

Change in temperature (ΔT) =.?

Change in temperature (ΔT) =T2 – T1

Change in temperature (ΔT) = 121 – 91

Change in temperature (ΔT) = 30°C

Finally, we shall determine the energe required to overheat the car as follow:

Q = MCΔT

Q = 10000 × 2.01 × 30

Q = 603000 J

Therefore, 603000 J of energy is required to overheat the car.

Answer:On a hot dry day humidity will be less.when humidity decreases rate of evaporation increases

Answer:

The water that evaporates from a desert cooler takes in energy from the environment for filling up for the loss of energy during EVAPORATION making the environment cold.

Therefore, on a hot dry day, the Evaporation is more which means the environment will be colder.

Explanation:

I hope it is okay.

I learnt it last year, so I went back to my book and explained it better in my own way.

Thanks.

Answer: just trust me its c

Explanation: i dont cap

Answer:

The noble as structures attained are helium and argon

Explanation:

The electron configuration of chlorine atom is 1s²2s²2p⁶3s²3p⁵

The elecron configuation of hydrogen is 1s¹

The electron configuration of argon atom is 1s²2s²2p⁶3s²3p⁶

The elecron configuation of helium gas is 1s²

Therefore, in the hydrogen chloride molecule the hydrogen and the chlorine each share one electron from the other atom to attain the the stable noble gas structure of helium for hydrogen and argon for chlorine.

Answer:

occur if two of the ions form an insoluble ionic compound, which precipitates out of solution

Explanation:

When two ionic compounds are dissolved in water, a double replacement reaction takes place if two of the ions form an insoluble ionic compound, which precipitates out of solution. In double displacement reaction ions switch partners. And hence, produce an insoluble precipitate.

Answer:

The SI unit of volume is the cubic meter (m 3 ), which is the volume occupied by a cube that measures 1 m on each side. This very large volume is not very convenient for typical use in a chemistry laboratory. A liter (L) is the volume of a cube that measures 10 cm (1 dm) on each side.

Answer:

Hope it helps!!!

............

In the Lewis structure, the Ca atom donates its two valence electrons to two F atoms.

The bonding in calcium fluoride (CaF₂) involves the transfer of electrons from calcium (Ca) to fluorine (F), resulting in the formation of ionic bonds.

Each F atom gains one electron to achieve a stable electron configuration of eight electrons in its outermost energy level. The electrostatic attraction between the positively charged Ca ion (Ca²⁺) and the negatively charged F ions (F⁻) holds the compound together.

It's important to note that the diagram represents a simplified 2-dimensional representation of the compound's structure. In reality, the compound adopts a three-dimensional crystal lattice structure, with each Ca ion surrounded by eight F ions and each F ion surrounded by four Ca ions.

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Answer:

The correct option is;

It contains 6.02 × 10²³ particles of a given substance

Explanation:

A mole of substance is the standard scientific unit of measurement for the quantity of the substance which is made up of a large number of small particles such as molecules, ions, atoms, electrons or other entities.

The General Conference on Weights and Measures defines the mole as the amount of a substance that contains 6.02214076 × 10²³ units of entities

The number 6.02214076 × 10²³, is also known as Avogadro's number.

The statement which correctly describes the mole is; it contains 6.02 × 10^23 particles of a given substance.

The mole refers to the amount of substance that contains the same number of elementary entities as 12 g of carbon - 12. According to Avogadro's law, the number of elementary entities in a substance is 6.02 × 10^23. These elementary entities could be atoms, ions, molecules etc.

Therefore, the statement which correctly describes the mole is; it contains 6.02 × 10^23 particles of a given substance.

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