1. Describe data and process modeling concepts and tools.

Answer:

Explanation:

Click the File tab.

Click Print, or press the control p keyboard command.

On the Print screen, select the printer and other settings.

Click Print.

Clarissa should modify the file /root/.profile.

Runtime environment variables

Therefore, in the context, Clarissa wishes to modify the run time environment variable which can be used for all the new logins and also for the new instances for the BASH shell. So for this, Clarissa should modify the /root/.profile file command.

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Following are the description of the wrong choice:

Therefore, the "/root/.profile" file should be changed by Clarissa.

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Answer:

The statement is:

For number = 0 to 5

Explanation:

Given

The incomplete pseudocode

Required

The loop statement to complete the pseudocode

To loop from 0 to 5, we make use of:

For number = 0 to 5

Where:

number is the integer variable declared on line 1

So, the complete pseudocode is:

Declare Integer number

For number = 0 to 5

Display number

End For

Explanation:

hope it helps you

pls mark this ans brainlist ans

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: 155 kHz.

Given the following data:

Note: μs represents microseconds.

Conversion:

1 μs = [tex]1[/tex] × [tex]10^{-6}[/tex] seconds

645 μs = [tex]645[/tex] × [tex]10^{-6}[/tex] seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

[tex]Frequency = \frac{1}{Period}[/tex]

Substituting the value into the formula, we have;

[tex]Frequency = \frac{1}{645\; * \;10^{-6}}[/tex]

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

Conversion:

1 hertz = 0.001 kilohertz

1550.3876 hertz = X kilohertz

Cross-multiplying, we have;

X = [tex]0.001[/tex] × [tex]1550.39[/tex]

X = 155039 kHz

To 3 significant figures;

Frequency = 155 kHz

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Answer:

CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator.

Explanation:

There are six basic components of a microcomputer which includes CPU, Program memory, Data memory, Output ports,  Input ports and Clock generator. CPU is the central processing unit which is considered as the brain of the computer. It is the part of a computer that executes instructions. Data memory is the place where data is stored that is present in the CPU.

Answer:

Explanation:

A computer that is easy to operate is called User Friendly

Answer:

Direct memory access (DMA) is a process that allows an input/output (I/O) device to send or receive data directly to or from the main memory, bypassing the CPU to speed up memory operations and this process is managed by a chip known as a DMA controller (DMAC).

Explanation:

A defined portion of memory is used to send data directly from a peripheral to the motherboard without involving the microprocessor, so that the process does not interfere with overall computer operation.

In older computers, four DMA channels were numbered 0, 1, 2 and 3. When the 16-bit industry standard architecture (ISA) expansion bus was introduced, channels 5, 6 and 7 were added.

ISA was a computer bus standard for IBM-compatible computers, allowing a device to initiate transactions (bus mastering) at a quicker speed. The ISA DMA controller has 8 DMA channels, each one of which associated with a 16-bit address and count registers.

ISA has since been replaced by accelerated graphics port (AGP) and peripheral component interconnect (PCI) expansion cards, which are much faster. Each DMA transfers approximately 2 MB of data per second.

A computer's system resource tools are used for communication between hardware and software. The four types of system resources are:

DMA channels are used to communicate data between the peripheral device and the system memory. All four system resources rely on certain lines on a bus. Some lines on the bus are used for IRQs, some for addresses (the I/O addresses and the memory address) and some for DMA channels.

A DMA channel enables a device to transfer data without exposing the CPU to a work overload. Without the DMA channels, the CPU copies every piece of data using a peripheral bus from the I/O device. Using a peripheral bus occupies the CPU during the read/write process and does not allow other work to be performed until the operation is completed.

With DMA, the CPU can process other tasks while data transfer is being performed. The transfer of data is first initiated by the CPU. The data block can be transferred to and from memory by the DMAC in three ways.

In burst mode, the system bus is released only after the data transfer is completed. In cycle stealing mode, during the transfer of data between the DMA channel and I/O device, the system bus is relinquished for a few clock cycles so that the CPU can perform other tasks. When the data transfer is complete, the CPU receives an interrupt request from the DMA controller. In transparent mode, the DMAC can take charge of the system bus only when it is not required by the processor.

However, using a DMA controller might cause cache coherency problems. The data stored in RAM accessed by the DMA controller may not be updated with the correct cache data if the CPU is using external memory.

Solutions include flushing cache lines before starting outgoing DMA transfers, or performing a cache invalidation on incoming DMA transfers when external writes are signaled to the cache controller.

Answer:

See explanation

Explanation:

DMA [tex]\to[/tex] Direct Memory Access.

The peripherals of a computer system are always in need to communicate with the main memory; it is the duty of the DMA to allow these peripherals to transfer data to and from the memory.

The first step is that the processor starts the DMA controller, then the peripheral is prepared to send or receive the data; lastly, the DMA sends signal when the peripheral is ready to carry out its operation.

Answer:

Code:-

#include <iostream>

using namespace std;

int main()

{

   // take array size from user

   int n;

   cout << "Enter array size:";

   cin >> n;

   // Declare array size with user given input

   int a[n];

   // take array elements from user & store it in array

   cout << "Enter array elements:";

   for(int i=0 ; i < n ; i++){

       cin >> a[i];

   }

   /* ----- Solution Starts ----- */

   // i & j for checking disarray & count is for counting no. of disarray's

   int i=1, j=0, count=0;

   for(int k=0; k < n ; k++){

       if(a[i] > a[j]){

           // if disarray found then increament count by 1

               count++;

               }

               // increament i & j also to check for further disarray's

               i++;

       j++;

       }

       // Print the disarray count

   cout << "Pairs of disarray in given array:" << count;

   /* ----- Solution Ends ----- */

   return 0;

}

Output:-

Answer:

The description of the given question is summarized below.

Explanation:

Answer:

The OSI Model (Open Systems Interconnection Model) is a conceptual framework used to describe the functions of a networking system. The OSI model characterizes computing functions into a universal set of rules and requirements in order to support interoperability between different products and software.

Answer:

Gantt charts

Explanation:

Gantt charts control all aspects of your project plan from scheduling to assigning tasks and even monitoring progress. A Gantt chart shows your tasks across a timeline and puts them in phases for better organization.

Following are the steps of the polynomial-time algorithm:

In a minimum amount of time, this algorithm will determine the best strategy to supply all shops.

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Answer:

false

Explanation:

My teacher quized me on this

The importance of planning a web page according to the question is provided below.

A well-designed company's website may contribute to making even your potential consumers a favorable immediate impression.

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Answer:

i dont know

Explanation:

Answer:

Answer:

#include <iostream>

using namespace std;

struct entry

{

int number;

entry* next;

};

void orderedInsert(entry** head_ref,entry* new_node);

void init_node(entry *head,int n)

{

head->number = n;

head->next =NULL;

}

void insert(struct entry **head, int n)

{

entry *nNode = new entry;

nNode->number = n;

nNode->next = *head;

*head = nNode;

}

entry *searchNode(entry *head, int n)

{

entry *curr = head;

while(curr)

{

if(curr->number == n)

return curr;

curr = curr->next;

}

}

bool delNode(entry **head, entry *ptrDel)

{

entry *curr = *head;

if(ptrDel == *head)

{

*head = curr->next;

delete ptrDel;

return true;

}

while(curr)

{

if(curr->next == ptrDel)

{

curr->next = ptrDel->next;

delete ptrDel;

return true;

}

curr = curr->next;

}

return false;

}

void display(struct entry *head)

{

entry *list = head;

while(list!=NULL)

{

cout << list->number << " ";

list = list->next;

}

cout << endl;

cout << endl;

}

//Define the function to sort the list.

void insertionSort(struct entry **h_ref)

{

// Initialize the list

struct entry *ordered = NULL;

// Insert node to sorted list.

struct entry *current = *h_ref;

while (current != NULL)

{

struct entry *next = current->next;

// insert current in the ordered list

orderedInsert(&ordered, current);

// Update current

current = next;

}

// Update the list.

*h_ref = ordered;

}

//Define the function to insert and traverse the ordered list

void orderedInsert(struct entry** h_ref, struct entry* n_node)

{

struct entry* current;

/* Check for the head end */

if (*h_ref == NULL || (*h_ref)->number >= n_node->number)

{

n_node->next = *h_ref;

*h_ref = n_node;

}

else

{

//search the node before insertion

current = *h_ref;

while (current->next!=NULL &&

current->next->number < n_node->number)

{

current = current->next;

}

//Adjust the next node.

n_node->next = current->next;

current->next = n_node;

}

}

int main()

{

//Define the structure and variables.

char ch;int i=0;

entry *newHead;

entry *head = new entry;

entry *ptr;

entry *ptrDelete;

//Use do while loop to countinue in program.

do

{

//Define the variables

int n;

int s;

int item;

char choice;

//Accept the user choice

cout<<"Enter your choice:"<<endl;

cout<<"a. Add a number"<<endl

<<"b. Delete a number"<<endl

<<"c. Search for a number"<<endl

<<"d. Display the whole list of numbers"<<endl;

cin>>choice;

//Check the choice.

switch(choice)

{

//Insert an item in the list.

case 'a' :

// cin>>item;

cout<<"Enter the element:"<<endl;

cin>>item;

//To insert the first element

if(i==0)

init_node(head,item);

//To insert remaining element.

else

{

ptr = searchNode(head,item);

//Check for Duplicate data item.

if(ptr==NULL)

{

insert(&head,item);

}

else

{

cout<<"Duplicate data items not allowed";

cout<<endl<<"EnterAgain"<<endl;

cin>>item;

insert(&head,item);

}

}

insertionSort(&head);

i=i+1;

break;

//Delete the item from the list

case 'b' :

int numDel;

cout<<"Enter the number to be deleted :"<<endl;

cin>>numDel;

//Locate the node.

ptrDelete = searchNode(head,numDel);

if(ptrDelete==NULL)

cout<<"Element not found";

else

{

if(delNode(&head,ptrDelete))

cout << "Node "<< numDel << " deleted!\n";

}

break;

//Serach the item in the list.

case 'c' :

cout<<"Enter the element to be searched :";

cout<<endl;

cin>>s;

ptr = searchNode(head,s);

if(ptr==NULL)

cout<<"Element not found";

else

cout<<"Element found";

break;

//Display the list.

case 'd' :

display(head);

break;

default :

cout << "Invalid choice" << endl;

break;

}

//Ask user to run the program again

cout<<endl<<"Enter y to countinue: ";

cin>>ch;

}while(ch=='y'||ch=='Y');

return 0;

}

output:

Answer:

x = 1

y = 1

Explanation:

The apply method has the axis argument which enables it to use the applied function either across the rows or columns, by passing the value 1 to the axis argument, the mean of at each index is calculated, (across the column) such that the length of the AVG column is equal to the lengtb of the original dataframe.

The drop method is used in pandas to remove row or column entry from a dataframe. To remove columns from a data table, the value 1 is passed to the axis argument of the drop method. Hence, passing 1 to the axis argument removes all 6 columns leaving only the AVG column in result_df.

Answer

Medical Training

From operating MRI equipment to performing complex surgeries, AR tech holds the potential to boost the depth and effectiveness of medical training in many areas. Students at the Cleveland Clinic at Case Western Reserve University, for example, will now learn anatomy utilizing an AR headset allowing them to delve into the human body in an interactive 3D format.

it is also use in retail ,. Repair & Maintenance,Design & Modeling,Business Logistics etc

Answer and Explanation:

In C programming language:

char fun(int*a, int*b){

printf("enter two integers: ");

scanf("%d%d",a,b);

int e;

printf("please enter a character: ");

e=getchar();

return e;

}

int main(int argc, char *argv[]) {

int d;

int f;

int g;

fun();

printf("%d%d%d", d, f, g);

}

We have declared a function fun type char above and called it in main. Note how he use the getchar function in c which reads the next available character(after the user inputs with printf()) and returns it as an integer. We then return the variable e holding the integer value as char fun() return value.

Fasilitas untuk pengaturan batas kertas pada Microsoft Word adalah

B.View

Office 92 sering disebut juga dengan

A.Office 3.0

An IS manager can keep up with the endless demand for more software to support new information systems by thinking outside the box.

To think outside the box, the IS manager should try the following strategies:

Thus, the IS manager must realize that there are always solutions to every software problem outside the mainstream box.

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Answer:

The pivot is selected randomly in quick sort.

Answer:

Error reports

Explanation:

To manage a modern IT environment characterized by hybrid complexity and exponential data growth — and to make that same IT a driver of growth and innovation for the business — you need to build intelligence into every layer of your infrastructure.

Change management plays a major role in transforming a client  business into a data-driven, intelligent enterprise in: data culture and literacy.

Data culture and literacy refer to all the processes involved in analyzing and understanding data within the framework of an organization.

The employees within such organizations are trained to read and understand data. It becomes a part of the organization's culture.

So data culture and literacy should be used when trying to transform a client  business into a data-driven, intelligent enterprise.

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Answer:

input process and output hehe

Answer:

the answer is priming read

Explanation:

hope it helps u

Answer:

please mark me brainlist

Explanation:

This algorithm works for n number of strings in python3

Input:

83217

8213897

683147

Output:

837

from itertools import product

import pdb

import numpy as np

def neigh(index):

N = len(index)

for ri in product((0, -1), repeat=N):

if not all(i == 0 for i in ri):

yield tuple(i + i_rel for i, i_rel in zip(index, ri))

def longestCommonSubSequenceOfN(sqs):

numberOfSequences = len(sqs); # to know number of sequences

lengths = np.array([len(sequence) for sequence in sqs]); # to know length of each sequences placed in # array

incrLengths = lengths + 1; # here we are taking no .of sequences +1

lengths = tuple(lengths); # making lengths into tuple to make it mutable

inverseDistances = np.zeros(incrLengths);

ranges = [tuple(range(1, length+1)) for length in lengths[::-1]]; # finding ranges from 1 to each lengths

for tupleIndex in product(*ranges):

tupleIndex = tupleIndex[::-1];

neighborIndexes = list(neigh(tupleIndex)); # finding neighbours for each tupled index value and # store them in list

operationsWithMisMatch = np.array([]); # creating array which are miss matched

for neighborIndex in neighborIndexes:

operationsWithMisMatch = np.append(operationsWithMisMatch, inverseDistances[neighborIndex]);

#appending newly created array with operations miss match and inverseDistances

operationsWithMatch = np.copy(operationsWithMisMatch);

# copying newly generated missmatch indexs

operationsWithMatch[-1] = operationsWithMatch[-1] + 1;

# incrementing last indexed value

chars = [sqs[i][neighborIndexes[-1][i]] for i in range(numberOfSequences)];

# finding a string(chars) with neighbour indexes and checking with other sequences

if(all(elem == chars[0] for elem in chars)):

inverseDistances[tupleIndex] = max(operationsWithMatch);

else:

inverseDistances[tupleIndex] = max(operationsWithMisMatch);

subString = ""; # resulted string

mainTupleIndex = lengths; # copying lengths list to mainTupleIndex

while(all(ind > 0 for ind in mainTupleIndex)):

neighborsIndexes = list(neigh(mainTupleIndex));

#generating neighbour indexes with main tuple index in form of list

anyOperation = False;

for tupleIndex in neighborsIndexes:

current = inverseDistances[mainTupleIndex];

if(current == inverseDistances[tupleIndex]): # comparing indexes in main tuple index and inverse #distance tuple index

mainTupleIndex = tupleIndex;

anyOperation = True;

break;

if(not anyOperation): # if anyoperation is False then we are generating sunString

subString += str(sqs[0][mainTupleIndex[0] - 1]);

mainTupleIndex = neighborsIndexes[-1];

return subString[::-1]; # reversing resulted string

sequences = ["83217", "8213897", "683147"]

print(longestCommonSubSequenceOfN(sequences)); #837