Answer:1
Step-by-step explanation:2
2
The value of a when the function f(x) = 3|xl is written in the standard form of an absolute value function is 3.
What is meant by an absolute function ?An absolute function is defined as a function which consists of an algebraic expression that is within absolute value symbols.
Here,
The standard form of the absolute value function is written by,
f(x) = a|x|
Given that,
f(x) = 3|x|
Comparing this with the standard form, we get,
a|x| = 3|x|
Therefore, a = 3
Hence,
The value of a when the function f(x) = 3|xl is written in the standard form of an absolute value function is 3.
To learn more about absolute function, click:
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Find the missing term in the following pattern.
320, 160, 80 blank space then, 20, 10
40
Step-by-step explanation:
Each number is followed by a number that is half its value, so the sequence goes like
320, 160, 80, 40, 20, 10.
Solve for the following equation for x. l x/4 + 3 l < 6
Answer:
this is the answer I got! i don't know if it helps, but I hope it does
Find the value of x. What is the value of x?
Answer:
x = 16
Step-by-step explanation:
The product of the lengths theorem is a property that can be sued to describe the relationships of the sides between the tangents and secants in a circle. One of these products states the following;
The distance between the point of tangency and its intersection point with the exterior secant squared is equal to the product of the exterior secant times the interior secant.
This essentially means the following equation can be formed;
[tex](AB)^2=(DC)(CB)[/tex]
Substitute,
[tex]12^2=x*9[/tex]
Simplify,
[tex]144=9x[/tex]
Inverse operations,
[tex]\frac{144}{9}=x\\\\16=x[/tex]
Answer:
[tex]\boxed{\sf x=7}[/tex]
Step-by-step explanation:
By Targent-secant theorem...
[tex]\sf 9(x + 9) = {12}^{2} [/tex]
Use the distributive property to multiply 9 by x+9.
[tex]\sf 9x+81= {12}^{2} [/tex]
Now, let calculate 12 to the power of 2 and get 144.
[tex]\sf 9x+81=144[/tex]
Subtract 81 from both sides.
[tex]\sf 9x=63[/tex]
Divide both sides by 9.
[tex] \sf \cfrac{ 9x}{9} = \cfrac{63}{9} [/tex]
[tex]\sf x=7[/tex]
math help plz
how to divide polynomials, how to understand and step by step with an example provided please
Answer:
hiiiiiii....!!! how r u
For any number n>1, is
|(.5 +.2i)^n|
A. greater than 1?
B. less than 1?
C. equal to 1?
PLZ HELP
Answer:
B. Less than 1
Step-by-step explanation:
You could plug in values of n greater than 1 and see what happens....
Example n=2 gives |(.5+.2i)^2|
Simplifying inside gives |(.5)^2+2(.5)(.2i)+(.2i)^2|
=|.25+.2i+.04i^2|=|.25+.2i-.04|=|.21+.2i|.
Applying the absolute value part gives sqrt(.21^2+.2^2)=sqrt(.0441+.04)=sqrt(.0841)=.29
This value is less than 1.
We should also be able to do the absolute value first then the power.
|.5+.2i|=sqrt(.25+.04)=sqrt(.29)
So |.5+.2i|^2=.29 which is what we got long way around.
Anyways (sqrt(.29))^n where n is greater than 1 will result in a number greater than 0 but less than 1.
Kevin will start with the integers 1, 2, 3 and 4 each used exactly once and written in a row in any order. Then he will find the sum of the adjacent pairs of integers in each row to make a new row, until one integer is left. For example, if he starts with 3, 2, 1, 4, then he takes sums to get 5, 3, 5, followed by 8, 8, and he ends with the final sum 16. Including all of Kevin's possible starting arrangements of the integers 1, 2, 3 and 4, how many possible final sums are there?
Hello,
there are 5 differents sums:
16,18,20,22,24.
-------------------------------------------------------
Dim i As Integer, j As Integer, k As Integer, l As Integer, u As Integer, v As Integer, nb As Integer
Dim mat(4, 4) As Integer
nb = 0
For i = 1 To 4
For j = 1 To 4
If j <> i Then
For k = 1 To 4
If k <> j And k <> i Then
l = 10 - k - j - i
If l > 0 And l < 5 And l <> i And l <> j And l <> k Then
mat(1, 1) = i
mat(1, 2) = j
mat(1, 3) = k
mat(1, 4) = l
For u = 2 To 4
For v = 1 To 4 - u + 1
mat(u, v) = mat(u - 1, v) + mat(u - 1, v + 1)
Next v
Next u
'Call visu(mat())
nb = nb + 1
Print nb,
mat(4, 1)
End If
End If
Next k
End If
Next j
Next i
End
Sub visu (m() As Integer)
Dim i As Integer, j As Integer
For i = 1 To 4
For j = 1 To 4 - i + 1
Print m(i, j);
Next j
Next i
End Sub
find a number such that when it is multiplied by 7 and 17 is subtracted from the product the result is the same as when it is multiplied by 3 and 19 added to the product .
Answer:
9
Step-by-step explanation:
Let the number be X
From the problem we have the following equation:
7x - 17 = 3x + 19
-> 4x = 36
-> x = 9
Answer:
9
Step-by-step explanation:
that is the procedure above
A Sociology instructor gives students points for each discussion-board post and points for each reply to a post. Ana wrote 6 posts and 8 replies and received 114 points. Jae wrote 5 posts and 4 replies and received 79 points. Determine how many points a discussion post is worth and how many points a reply is worth?
Answer:
5 points per post and 2 points per replies
During a recent election, 54 of every 100 registered voters in a certain city voted. If there were 157,400 registered voters in that city, how many people voted?
What is the average (with 0 decimal places) across all schools for the total score? Group of answer choices 1287 1215 1221 1229
Answer:
See explanation
Step-by-step explanation:
Required
The average
The data whose average is to be calculated are not given.
However, the formula to calculate the average is:
[tex]\bar x = \frac{\sum x}{n}[/tex]
Assume the data is:
[tex]1287\ 1215\ 1221\ 1229[/tex]
This means that the number of schools is 4
So:
[tex]\bar x = \frac{1287+ 1215+ 1221+ 1229}{4}[/tex]
[tex]\bar x = \frac{4952}{4}[/tex]
[tex]\bar x = 1238[/tex]
The average of the assumed data is 1238
Bob had 10 more cars than Paul. Paul had 15 cars.
Answer:
Bob had 25 cars
Step-by-step explanation:
10+15=25
Carin opened a money market account with a
deposit of $3,000. This account earns 2% simple
interest annually. How many years will it take for
her $3,000 deposit to earn $420 in interest, assum-
ing she does not withdraw any of the money?
Answer:
7
Step-by-step explanation:
For simple interest,
I = prt
where I = interest,
p = principal (amount deposited)
r = annual rate of interest
t = time in years
We have r = 2% = 0.02
p = $3,000
I = $420
We need to find t
I = prt
420 = 3000 * 0.02 * t
420 = 60t
t = 420/60
t = 7
Answer: 7 years
what is 3/2 divided by 1/8
helppp
Answer: 12
Step-by-step explanation:
The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.
Wires manufactured for a certain computer system are specified to have a resistance of
between 0.11 and 0.16 ohm. The actual measured resistances of the wires produced by
Company A have a normal probability distribution, with a mean of 0.14 ohms, and a
standard deviation of 0.003 ohms. What is the probability that a randomly selected wire
from Company A’s production lot will meet the specifications?
Answer:
8d68d68fu9d6rf0d
c9yd7xpjd
puf68d6rif7
.4.1 Here are the data from Exercise 2.3.10 on the num-ber of virus-resistant bacteria in each of 10 aliquots: 14 14 15 26 13 16 21 20 15 13 (a) Determine the median and the quartiles. (b) Determine the interquartile range. (c) How large would an observati
Answer:
(a)
[tex]Q_1 = 14[/tex]
[tex]Median = 15[/tex]
[tex]Q_3 = 20[/tex]
(b) [tex]IQR = 6[/tex]
Step-by-step explanation:
Given
[tex]14\ 14\ 15\ 26\ 13\ 16\ 21\ 20\ 15\ 13[/tex]
[tex]n = 10[/tex]
Solving (a): Median and the quartiles
Start by sorting the data
[tex]Sorted: 13\ 13\ 14\ 14\ 15\ 15\ 16\ 20\ 21\ 26[/tex]
The median position is:
[tex]Median = \frac{n + 1}{2}[/tex]
[tex]Median = \frac{10 + 1}{2} = \frac{11}{2} = 5.5th[/tex]
This implies that the median is the average of the 5th and the 6th data;
So;
[tex]Median = \frac{15+15}{2} = \frac{30}{2} = 15[/tex]
Split the dataset into two halves to get the quartiles
[tex]Lower: 13\ 13\ 14\ 14\ 15\[/tex]
[tex]Upper: 15\ 16\ 20\ 21\ 26[/tex]
The quartiles are the middle items of each half.
So:
[tex]Lower: 13\ 13\ 14\ 14\ 15\[/tex]
[tex]Q_1 = 14[/tex] ---- 14 is the middle item
[tex]Upper: 15\ 16\ 20\ 21\ 26[/tex]
[tex]Q_3 = 20[/tex] ---- 20 is the middle item
Solving (b): The interquartile range (IQR)
This is calculated as:
[tex]IQR = Q_3 - Q_1[/tex]
[tex]IQR = 20 - 14[/tex]
[tex]IQR = 6[/tex]
Solving (c): Incomplete details
It says I need too put 20 characters in too ask the question so ignore this part
In a mixture of 240 gallons, the ratio of ethanol and gasoline is 3:1. If the ratio is to be 1:3, then find the quantity of gasoline that is to be added.
Answer:
480 gallons.
Step-by-step explanation:
Given that in a mixture of 240 gallons, the ratio of ethanol and gasoline is 3: 1, if the ratio is to be 1: 3, to find the quantity of gasoline that is to be added the following calculation must be performed:
240/4 x 3 = Ethanol
240/4 = Gasoline
180 = Ethanol
60 = Gasoline
0.25 = 180
1 = X
180 / 0.25 = X
720 = X
720 - 180 - 60 = X
480 = X
Therefore, 480 gallons of gasoline must be added if the ratio is to be 1: 3.
1. You measure 24 textbooks' weights, and find they have a mean weight of 75 ounces. Assume the population standard deviation is 3.3 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight.
2. You measure 37 backpacks' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 10.1 ounces. Based on this, construct a 95% confidence interval for the true population mean backpack weight.
3. You measure 30 watermelons' weights, and find they have a mean weight of 37 ounces. Assume the population standard deviation is 4.1 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean watermelon weight.
4. A student was asked to find a 99% confidence interval for widget width using data from a random sample of size n = 16. Which of the following is a correct interpretation of the interval 11.8 < μ < 20.4?
A. There is a 99% chance that the mean of a sample of 16 widgets will be between 11.8 and 20.4.
B. The mean width of all widgets is between 11.8 and 20.4, 99% of the time. We know this is true because the mean of our sample is between 11.8 and 20.4.
C. With 99% confidence, the mean width of all widgets is between 11.8 and 20.4.
D. With 99% confidence, the mean width of a randomly selected widget will be between 11.8 and 20.4.
E. There is a 99% chance that the mean of the population is between 11.8 and 20.4.
5. For a confidence level of 90% with a sample size of 23, find the critical t value.
Answer:
(73.845 ; 76.155) ;
(41.633 ; 48.367) ;
1.273 ;
C. With 99% confidence, the mean width of all widgets is between 11.8 and 20.4. ;
1.717
Step-by-step explanation:
1.)
Given :
Mean, xbar = 75
Sample size, n = 24
Sample standard deviation, s = 3.3
α = 90%
Confidence interval = mean ± margin of error
Margin of Error = Tcritical * s/√n
Tcritical at 90% ; df = 24 - 1 = 23
Tcritical = 1.714
Margin of Error = 1.714 * 3.3/√24 = 1.155
Confidence interval = 75 ± 1.155
Confidence interval = (73.845 ; 76.155)
2.)
Given :
Mean, xbar = 45
Sample size, n = 37
Sample standard deviation, s = 10.1
α = 95%
Confidence interval = mean ± margin of error
Margin of Error = Tcritical * s/√n
Tcritical at 95% ; df = 37 - 1 = 36
Tcritical = 2.028
Margin of Error = 2.028 * 10.1/√37 = 3.367
Confidence interval = 45 ± 3.367
Confidence interval = (41.633 ; 48.367)
3.)
Given :
Mean, xbar = 37
Sample size, n = 30
Sample standard deviation, s = 4.1
α = 90%
Margin of Error = Tcritical * s/√n
Tcritical at 90% ; df = 30 - 1 = 29
Tcritical = 1.700
Margin of Error = 1.700 * 4.1/√30 = 1.273
5.)
Sample size, n = 23
Confidence level, = 90%
df = n - 1 ; 23 - 1 = 22
Tcritical(0.05, 22) = 1.717
2. The prices, in dollars per unit, of the three commodities X, Y and Z are x, y and z,
respectively
Person A purchases 4 units of Z and sells 3 units of X and 3 units of Y.
Person B purchases 3 units of Y and sells 2 units of X and 1 unit of Z.
Person C purchases 1 unit of X and sells 4 units of Y and 6 units of Z.
In the process, A, B and C earn $40, $50, and $130, respectively.
a) Find the prices of the commodities X, Y, and Z by solving a system of linear
equations (note that selling the units is positive earning and buying the units is
negative earning).
Answer:
Price of X is $24.81
Price of Y is $3.66
Price of Z is $11.36
Step-by-step explanation:
for person A, we know that earns $40, then we can write the equation:
-4*z + 3*x + 3*y = $40
For person B, we know that earns $50, then:
1*z + 2*x - 3*y = $50
For person C, we know that earns $130, then:
6*z - 1*x + 4*y = $130
Then we have a system of equations:
-4*z + 3*x + 3*y = $40
1*z + 2*x - 3*y = $50
6*z - 1*x + 4*y = $130
To solve the system, we need to isolate one of the variables in one of the equations.
Let's isolate z in the second equation:
z = $50 - 2*x + 3*y
now we can replace this in the other two equations:
-4*z + 3*x + 3*y = $40
6*z - 1*x + 4*y = $130
So we get:
-4*($50 - 2*x + 3*y) + 3*x + 3*y = $40
6*($50 - 2*x + 3*y) - 1*x + 4*y = $130
Now we need to simplify both of these, so we get:
-$200 + 11x - 9y = $40
$350 - 13*x + 28*y = $130
Now again, we need to isolate one of the variables in one of the equations.
Let's isolate x in the first one:
-$200 + 11x - 9y = $40
11x - 9y = $40 + $200 = $240
11x = $240 + 9y
x = ($240 + 9y)/11
Now we can replace this in the other equation:
$350 - 13*x + 28*y = $130
$350 - 13*($240 + 9y)/11 + 28*y = $130
Now we can solve this for y.
- 13*($240 + 9y)/11 + 28*y = $130 - $350 = -$220
-13*$240 - (13/11)*9y + 28y = - $220
y*(28 - (9*13/1) ) = -$220 + (13/11)*$240
y = ( (13/11)*$240 - $220)/(28 - (9*13/1) ) = $3.66
We know that:
x = ($240 + 9y)/11
Replacing the value of y, we get:
x = ($240 + 9*$3.66)/11 = $24.81
And the equation of z is:
z = $50 - 2*x + 3*y = $50 - 2* $24.81 + 3*$3.66 = $11.36
Then:
Price of X is $24.81
Price of Y is $3.66
Price of Z is $11.36
5/6 ÷ 1/3 - 2/3 (2/5)
Answer:
[tex] \frac{67}{30} \: \text{or} \:2 \frac{7}{30} [/tex]
Step-by-step explanation:
5/6 ÷ 1/3 - 2/3 (2/5)
= 5/6 ÷ 1/3 - 2/3 × 2/5= 5/2 - 2/3 × 2/5= 5/2 - 4/15= 67/30 or 2 7/30Hope it helps you! ＼(^ᴥ^)／
Lendo 15 páginas por dia, Marcos leu um livro em
9 dias.
Para ler esse mesmo livro em 3 dias, quantas páginas
ele deveria ler por dia?
Answer:
Olha a foto.
Step-by-step explanation:
Which table represents a linear function?
Х
1
2
3
4
y
3
6
12
24
х
1
2
3
4
у
2.
5
9
14
х
1
2
3
4
у
-3
-5
-7
-9
х
1
2
3
4
у
-2
-4
-2
0
Answer:
3
Step-by-step explanation:
x 1，2，3，4
y-3，-5，-7，-9
[tex]y = - 3 - (x - 1) \times 2[/tex]
The linear function is given by y = 7x - 4
A linear function is in the form:
y = mx + b
where y, x are variables, m is the rate of change and b is the y intercept
From the table, using the points (1, 3) and (4, 24):
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-3=\frac{24-3}{4-1}(x-1)\\\\ y=7x-4[/tex]
The linear function is given by y = 7x - 4.
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40 points! Need help finding.
The cordent plan of the answer is 2
Answer:
The scale factor will just be 2
Step-by-step explanation:
The length of PQ is twice as larger than the length of AB.
so from 12 to 6 or 6 to 12, we multiply 6 by 2 which equals to 12
3x+7>10
Solve for x.
Answer: x>1
Step-by-step explanation:
To solve for x, we want to isolate x.
3x+7>10 [subtract both sides by 7]
3x>3 [divide both sides by 3]
x>1
Therefore, we know that x>1.
Answer:
Step-by-step explanation:
3x + 7 > 10
3x > 10 - 7
3x > 3
x > 1
x ∈ ( 1, ∞ )
A cardboard box without a lid is to have a volume of 4,000 cm3. Find the dimensions that minimize the amount of cardboard used. (Let x, y, and z be the dimensions of the cardboard box.)
In what ratio of line x-y-2=0 divides the line segment joining (3,-1) and (8,9)?
[tex] \large{ \tt{❁ \: USING \: INTERNAL \: SECTION \: FORMULA: }}[/tex]
[tex] \large{ \bf{✾ \: P(x \:, y \: ) = ( \frac{m_{1}x_{2} + m_{2}x_{1}}{m_{1} + m_{2}} \: ,\: \frac{m_{1}y_{2} + m_{2}y_{1}}{m_{1} + m_{2}}) }}[/tex]
[tex] \large{ \bf{⟹ \: ( \frac{8m + 3n}{m + n} , \: \frac{9m -n}{m + n}) }}[/tex]
Since point P lies on the line x - y - 2 = 0 ,[tex] \large{ \bf{ ⟼\frac{8m + 3n}{m + n} - \frac{9m - n}{m + n} - 2 = 0 }}[/tex]
[tex] \large{ \bf{⟼ \: \frac{8m + 3n - 9m + n}{m + n} - 2 = 0 }}[/tex]
[tex] \large{ \bf{⟼ \: \frac{4n - m}{ m + n} - 2 = 0 }}[/tex]
[tex] \large{⟼ \: \bf{ \frac{4n - m}{m + n }} = 2} [/tex]
[tex] \large{ \bf{⟼ \: 4n - m = 2m + 2n}}[/tex]
[tex] \large{ \bf{⟼ \: 4n -2 n = 2m + m}}[/tex]
[tex] \large{ \bf{⟼2n = 3m}}[/tex]
[tex] \large{ \bf{⟼ \: 3m = 2n}}[/tex]
[tex] \large{ \bf{⟼ \: \frac{m}{n} = \frac{2}{3} }}[/tex]
[tex] \boxed{ \large{ \bf{⟼ \: m : \: n = 2: \: }3}}[/tex]
Hence , The required ratio is 2 : 3 .-Hope I helped! Let me know if you have any questions regarding my answer and also notify me , if you need any other help! :)
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
Tim did a survey at a large shopping centre. He asked 400 visitors to the centre to choose the main reason for their visit. The reasons were shops, free parking, food court and location.
From the people taking part in the survey, one person is chosen at random to get a prize. Find the probability a female who chose location gets the prize.
shops free park. food location total
male 88 24 40 21 173
female 110 38 56 23 227
total 198 62 96 44 400
Answer:
23 / 400 = 0.0575
Step-by-step explanation:
Given the distribution :
_____shops__ free park. food _: location total
male 88 24 40 21 173
female 110 38 56 23 227
total 198 62 96 44 400
From the table of the distribution Given, we obtain :
n(Female n location) = 23
n(Total) = 400
Hence, the probability that a female who chose location gets the prize will be ;
n(Female n location) / n(Total) = 23 / 400 = 0.0575
y’all what are the answers
Answer:
Step-by-step explanation:
If the current through a circuit is 2 A and the resistance of a light bulb in the circuit is 10 Ohms what is tge voltage difference across the light bulb
Answer:
v = ir
2 times 10 = 20v
Step-by-step explanation:
i think it is the one
What is the value of h in the figure below? In this diagram, ABAD ~ ACBD.
Д.
С
0
20
А. 80
В. 16
ОО ооо
С. 60
D. 5
Е. 8
о
Е.
Answer:
[tex]h=\sqrt{16(4)}[/tex]
[tex]h=8[/tex]
[tex]ANSWER:E) 8[/tex]
-------------------------------
~HOPE IT HELPS
~HAVE A GREAT DAY!!
