You play basketball at your school's
indoor stadium. You have two payment
options. Option A is to buy a membership
card for $20 and pay $2 each time you
go to the gym, t. Option B is to pay $4
each time you go. Write a a linear
equation to show how many trips to the
gym would the cost be the same?

Answer:

188 degrees

Step-by-step explanation:

The measure of the arc is the center angle, that is double of the circumference one

94 * 2 = 188 degrees

Answer:

[tex]A = \left[\begin{array}{cccc}1&-1&-3&-5\\4&2&0&-2\\7&5&3&1\end{array}\right][/tex]

Step-by-step explanation:

A = (aij)

i representa a linha e j a coluna.

Tipo 3x4

Isto implica que a matriz tem 3 linhas e 4 colunas.

aij = 3i – 2j.

Primeira linha:

[tex]a_{1,1} = 3(1) - 2(1) = 1[/tex]

[tex]a_{1,2} = 3(1) - 2(2) = -1[/tex]

[tex]a_{1,3} = 3(1) - 2(3) = -3[/tex]

[tex]a_{1,4} = 3(1) - 2(4) = -5[/tex]

Segunda linha:

[tex]a_{2,1} = 3(2) - 2(1) = 4[/tex]

[tex]a_{2,2} = 3(2) - 2(2) = 2[/tex]

[tex]a_{2,3} = 3(2) - 2(3) = 0[/tex]

[tex]a_{2,4} = 3(2) - 2(4) = -2[/tex]

Terceira linha:

[tex]a_{3,1} = 3(3) - 2(1) = 7[/tex]

[tex]a_{3,2} = 3(3) - 2(2) = 5[/tex]

[tex]a_{3,3} = 3(3) - 2(3) = 3[/tex]

[tex]a_{3,4} = 3(3) - 2(4) = 1[/tex]

Matriz:

A matriz é dada por:

[tex]A = \left[\begin{array}{cccc}1&-1&-3&-5\\4&2&0&-2\\7&5&3&1\end{array}\right][/tex]

Step-by-step explanation:

[tex](\sec A - \csc A)(1 + \cot A + \tan A)[/tex]

[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)[/tex]

[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)[/tex]

[tex]=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)[/tex]

[tex]=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)[/tex]

[tex]=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}[/tex]

[tex]=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}[/tex]

[tex]=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}[/tex]

[tex]=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}[/tex]

[tex]=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)[/tex]

[tex]=\sec^2A\csc A - \csc^2A\sec A[/tex]

Answer:

reflection

Step-by-step explanation:

B is the mirror image of A across a line between the two images

Answer:

18

Step-by-step explanation:

1/3 of 27 is 9. 9 times 2 is 18.

Given:

The graph that shows the ennoblement for college R between 1950 and 2000.

To find:

The two decades that has the greatest change in enrollment.

Solution:

From the given graph, it is clear that the change in the enrollment is:

From 1950 to 1960 is [tex]4-3.5=0.5[/tex] thousand.

From 1960 to 1970 is [tex]5-4.5=1.5[/tex] thousand.

From 1970 to 1980 is [tex]5.5-5=0.5[/tex] thousand.

From 1980 to 1990 is [tex]6.5-5.5=1[/tex] thousand.

From 1990 to 2000 is [tex]7-6.5=0.5[/tex] thousand.

The two decades 1960-1970 and 1980-1990 have the greatest change in enrollment.

Answer:1980 to 1990

Step-by-step explanation:

Answer:

at least 99

Step-by-step explanation:

each number starting from 2 can be moved 11 times per thing.

Answer:

x = 16, or if you didn't want the value for x,

2x + 3 = 35

Step-by-step explanation:

Three more: +3

Twice a number: 2x

Combined:

2x + 3 = 35.

Get rid of the 3 by subtracting it from both sides:

2x = 32

Get rid of the 2 by dividing it from both sides:

x = 16

Answer:

The number is 16.

Step-by-step explanation:

Let the unknown number be x.

Now we translate the sentence into an equation piece by piece.

Three more than twice a number is 35.

2x

Three more than twice a number is 35.

2x + 3

Three more than twice a number is 35.

2x + 3 = 35

Now we solve the equation.

Subtract 3 from both sides.

2x = 32

Divide both sides by 2.

x = 16

Answer: The number is 16.

P.S. Notice that x was a variable that was introduced solely to solve the problem. The original problem is a word problem, not an equation, and has no x in it. The correct answer makes no reference to x since x was used to solve the equation but is not part of the given problem. The person asking the question has no idea what x is. He just wants a number as an answer.

True

Step-by-step explanation:

[tex]P(t) = I^2(t)R[/tex]

Taking the derivative of P(t) with respect to time,

[tex]\dfrac{dP(t)}{dt} = 2I(t)\dfrac{dI(t)}{dt}R[/tex]

[tex]\:\:\:\:\:\:\:\:= 2(1)(-0.5)(500) = -500[/tex]

Answer:

The range is from 1.62 to 1.98.

Step-by-step explanation:

We have to solve for the percentage of the particular value if the range of the answer should be +/- 10% of the particular value.

The value given is 1.8, we thus want to find 10% of that: 1.8 * 10/100 = 0.18

Then, add this value to the original value of 1.8: 1.8+0.18 = 1.98

Furthermore, subtract .18 from from the original value of 1.8: 1.8-0.18 = 1.62

The range will be between these two numbers, so the range is from 1.62 to 1.98.

Answer:

19. 3x+5/2x+7 =5

or, 3x+5=5×(2x + 7)

or, 3x + 5 = 10x + 35

or, 5 - 35 = 10x - 3x

or, -30 = 7x

or, -30/7 = x

21. let x be the other number

we know,

or, x × 1/7 =2

or, x/7 =2

or, x = 14

therefore, the other number is 14.

Answer:

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

Step-by-step explanation:

Before building the confidence interval, we have to find the sample mean and the sample standard deviation.

Sample mean:

[tex]\overline{x} = \frac{381.3+394.8+396.1+380}{4} = 388.05[/tex]

Sample standard deviation:

[tex]s = \sqrt{\frac{(381.3-388.05)^2+(394.8-388.05)^2+(396.1-388.05)^2+(380-388.05)^2}{3}} = 8.58[/tex]

Confidence interval:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 3.1824

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 3.1824\frac{8.58}{\sqrt{4}} = 13.65[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 388.05 - 13.65 = 374.4

The upper end of the interval is the sample mean added to M. So it is 388.05 + 13.65 = 401.7

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

Answer:

usai964s46s694s4o6s64694s946649s469 opps

Answer:

[tex](x,y)=(7,5)[/tex]

Step-by-step explanation:

Megan's equation will be:

[tex]20x+35y=315[/tex]

[tex]x+y=12[/tex]

Substitute [tex]x=12-y[/tex] in the first equation:

[tex]20(12-y)+35y=315[/tex]

[tex]15y=75[/tex]

[tex]y=75/15[/tex]

[tex]y=5[/tex]

Find x:

[tex]x=12-5[/tex]

[tex]x=7[/tex]

Where x and y represent 30-second and 60-second ads sold, we find that Meghan's sales were:

[tex](x,y)=(7,5)[/tex]

hope this helps....

Answer:

[tex]f(g(2)) = 2[/tex]

Step-by-step explanation:

Given

[tex]x \to f(x)[/tex]

[tex]-6 \to 1[/tex]

[tex]-3 \to 2[/tex]

[tex]g(x) = f^{-1}(x)[/tex] --- inverse

Required

[tex]f(g(2))[/tex]

For two functions f(x) and g(x) where f(x) and g(x)are inverse;

[tex]f(g(x)) = x[/tex]

So, by comparison:

[tex]f(g(2)) = 2[/tex]

Answer: 14 cm

Step-by-step explanation:

Rectangle:

x + x + (x - 2) + (x - 2) = 52

2x + 2(x - 2) = 52

2x + 2x - 4 = 52

4x = 52 + 4

4x = 56

x = 14

gjgb go ftc in the class is not a short time to be be free and ear is not a short time to

Answer:

[tex]{ \tt{rate \: of \: change \: in \: A = 9}}[/tex]

Rate of change in function A is two times than that in function B

Answer:the answer is 9

Step-by-step explanation:

Answer:

n(t) = 11e^0.019t

Step-by-step explanation:

The estimated population in 2010 = 11,000,000 = initial population

The growth rate = 1.9% per year = 1.9/100 =

The exponential growth model follows the general form :

n(t) = ae^rt

a = Initial population ; r = growth rate ; t = period

Hence, we have ;

n(t) = 11e^0.019t in millions

Answer:

1) a)  accepting the new drug is better based on its effectiveness when in reality the drug ain't better than the drug in current use because of its side effects

b) Accepting and using the current drug in use when it is not as effective as the new drug

c) Type 1 error

2) a) rejecting the vitamin supplement based on not knowing the harmful side effects

b) Accepting the Vitamin supplement based on just health benefits it portrays without comparison with other supplement.

c) Type II error

3) Increase the significance level  ( A )

Step-by-step explanation:

1)

a) To make a type 1 error in this situation is accepting the new drug is better and prescribing it to the millions of people based only on its effectiveness when in reality the drug ain't better than the drug in current use because of its side effects

b) A type II error in context is :Accepting and using the current drug in use when it is not as effective as the new drug

c)  Type I error

2)

a) Type 1 error is rejecting the vitamin supplement based on not knowing the harmful side effects

b) Accepting the Vitamin supplement based on just health benefits it portrays without comparison with other supplement.

c) Type II error

3) If committing a type 1 error is much worse

Increase the significance level

Answer:

Atomic No.

Element

Atomic Wt.

Europium

To take a systematic sample, first choose any number between one and five and write it here: k-23

Using the atomic number to count off elements, let the k value you just chose represent the first element in your

sample. Then, count off every fifth element thereafter. For instance, if you chose k-2, your sample will include

Helium (2), Nitrogen (7), Magnesium (12), and so forth. List each atomic number and atomic weight, starting with k

and adding 5 to the atomic number cach time.

Atomic No. Element

Atomic Wt.

3. Lithium 6.94

63

Isla6

8

v४

16

oxygen

Erbium 167.26

13 nluminum 24.98 23 Tantalum

180.45

18 Argon

39.95

28

platinum

195.DK

23 Vanadium 50.94 83 Bismuth 208.48

Niin

28

86

158.69

Radium 226

33

Arsenic 74.92

93 Neptunium 237

38 Strontium

98

87.62

Californium 251

43 Technutium 98

103 Lawrencium 262

UR

cocaina [12.41

108

Hassium

277

Iodine 126.9

113

No element

o

658 Cerium 140:11 118 Unumactiun

63

294

Find the mean atomic weight of this sample and enter it here: x xytomate : 137

AP statistics

Step-by-step explanation:

Answer:

387287i32

Step-by-step explanation:

i did it

Given:

The numbers are [tex]\dfrac{3}{5},2,0,1,-0.45, 1.44[/tex].

To find:

All the values that cannot be probabilities.

Solution:

We know that,

[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]

The minimum value of favorable outcomes is 0 and the maximum value is equal to the total outcomes. So, the value of probability lies between 0 and 1, inclusive. It other words, the probability lies in the interval [0,1].

[tex]0\leq \text{Probability}\leq 1[/tex]

From the given values only [tex]\dfrac{3}{5}, 0, 1[/tex] lie in the interval [0,1]. So, these values can be probabilities.

The values [tex]2,-0.45, 1.44[/tex] does not lie in the interval [0,1]. So, these values cannot be probabilities.

Therefore, the correct values are [tex]2,-0.45, 1.44[/tex].

Answer:

1) 5.2, and 4.94117647

2) Steph curry

Step-by-step explanation:

Answer:

2.56% chance of being selected

Step-by-step explanation:

Given

[tex]n = 39[/tex] --- you and 38 others

Required

Chance of you being selected

To do this, we simply calculate the probability using:

[tex]Pr(x) = \frac{n(x)}{n}[/tex]

Where:

[tex]n(x)= 1[/tex] --- i.e you are just 1 person

So:

[tex]Pr(x) = \frac{1}{39}[/tex]

[tex]Pr(x) = 0.0256[/tex]

Express as percentage

[tex]Pr(x) = 2.56\%[/tex]

Answer:

Step-by-step explanation:

I always advise my students to make a table of information for these story problems because trying to keep track of the information otherwise is a nightmare. The table will look like this:

           d      =      r      *      t

m

c

m is motorcycle and c is car.

First thing we are told is that the ratio of m's speed to c's speed is 5:4; that means that we can divide 5/4 to find out how many times faster m is going than c.

5/4 = 1.25 so we have a couple of values to put into the table right away, along with the fact that they are both traveling the same distance of 160 miles.

             d      =     r      *      t

m        160     =   1.25r

c         160     =     r

The last thing we have to fill in is the time. If m travels a half hour less than c, c is driving a half hour more than m, right? Filling that in:

            d      =      r      *      t

m       160     =   1.25r   *     t

c        160     =      r       *  t + .5

Now we have our 2 equations. Looking at the top row of the table gives us the formula we need to solve this problem. It tells us, in other words, what we are going to be doing with these columns of numbers. Distance equals the rate times the time. For the motorcycle, the equation is:

160 = (1.25r)t  and that seems pretty useless since we still have 2 unknowns in there and you can only have 1 unknown in 1 equation. Let's see what the equation for the car is.

160 = (t + .5)r  Same problem.

Let's go back to the equation for the motorcycle and since we are looking for the rates of each, let's solve that equation for time in terms of rate (solve it for t):

[tex]t=\frac{160}{1.25r}[/tex] and sub that into the car's equation in place of t:

[tex]160=r(\frac{160}{1.25r})+.5r[/tex] and simplify. The r's to the left of the plus sign cancel out leaving us with:

[tex]160=(\frac{160}{1.25})+.5r[/tex] and divide those numbers inside the parenthesis to get:

160 = 128 + .5r and subtract 128 from both sides to get:

32 = .5r and finally divide by .5 to get

r = 64 miles/hour

The car goes 64 mph and the motorcycle goes 1.25 times that so,

m = 1.25(64) and

m = 80 mph

Answer:

the wording (punctuation) of the question can lead to different interpretations....

I assume that the question was >17 & even which is "5/19",

BUT... it can also be read as two questions

first >17 which is "10/19"

and second an even number which is "9/19"

BUT !!! I think that the question answer is 5/19

Step-by-step explanation:

Even Number  = 18/38 = 9/19

greater 17 = 20/38 = 10/19

Even & greater 17 = 10/38 = 5/19

Answer:

20

Step-by-step explanation: