You have ​$95 in your bank account. Each week you plan to deposit ​$9 from your allowance and ​$10 from your paycheck. The equation b​=95+(10+9​)w gives the amount b in your account after w weeks. How many weeks from now will you have ​$220 in your bank​ account?

There will be ​$220 in the account after ___ weeks

You Have $95 In Your Bank Account. Each Week You Plan To Deposit $9 From Your Allowance And $10 From

Answers

Answer 1

Answer:

7 weeks

Step-by-step explanation:

b​=95+(10+9​)w

Combine like terms

b​=95+(19​)w

Let b = 220

220 = 95 + 19w

Subtract 95 from each side

220-95 = 19w

125 = 19w

Divide each side by 19

125/19 = w

6.578947368

Round up

After 7 week


Related Questions

the length of a rectangle is 8 cm longer than its width. find the dimensions of the rectangle if its area is 108cm
!!no links!!

Answers

Answer:

[tex]4+2\sqrt{31}\text{ by } -4+2\sqrt{31}[/tex]

Or about 15.136 centimeters by 7.136 centimeters.

Step-by-step explanation:

Recall that the area of a rectangle is given by:

[tex]\displaystyle A = w\ell[/tex]

Where w is the width and l is the length.

We are given that the length is 8 centimeters longer than the width. In other words:

[tex]\ell = w+8[/tex]

And we are also given that the total area is 108 square centimeters.

Thus, substitute:

[tex](108)=w(w+8)[/tex]

Solve for w. Distribute:

[tex]w^2+8w=108[/tex]

Subtract 108 from both sides:

[tex]w^2+8w-108=0[/tex]

Since the equation is not factorable, we can use the quadratic formula:

[tex]\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = 1, b = 8, and c = -108. Substitute and evaluate:

[tex]\displaystyle \begin{aligned} w&= \frac{-(8)\pm\sqrt{(8)^2-4(1)(-108)}}{2(1)} \\ \\ &=\frac{-8\pm\sqrt{496}}{2}\\ \\ &=\frac{-8\pm4\sqrt{31}}{2} \\ \\ &=-4 \pm 2\sqrt{31} \end{aligned}[/tex]

So, our two solutions are:

[tex]w=-4+2\sqrt{31} \approx 7.136 \text{ or } w=-4-2\sqrt{31}\approx -15.136[/tex]

Since width cannot be negative, we can eliminate the second solution.

And since the length is eight centimeters longer than the width, the length is:

[tex]\ell =(-4+2\sqrt{31})+8=4+2\sqrt{31}\approx 15.136[/tex]

So, the dimensions of the rectangle are about 15.136 cm by 7.136 cm.

Can you answer this math homework? Please!

Answers

Answer:

y + 2.3 = 0.45x

y = 0.45x - 2.3

-2y = 4.2x - 7.8

-2(0.45x - 2.3) = 4.2x - 7.8

-0.90x + 4.6 = 4.2x - 7.8

-0.90x - 4.2x = -7.8 - 4.6

-5.1x = - 12.4

x = -12.4 / -5.1

x = 2.4

y + 2.3 = 0.45x

y = 0.45(2.4) - 2.3

y = 1.08 - 2.3

y = -1.2

solution is : (2.4, - 1.2)

Step-by-step explanation:

The two lines intersect at answer A. (2.4, -1.2)

What type of line is PQ¯¯¯¯¯¯¯¯?




A. median

B. angle bisector

C. side bisector

D. altitude

Answers

Answer:

angle bisector

Step-by-step explanation:

Since the line divided the top angle into two equal pieces we call this an angle bisector.

The reliability coefficient of scores in an end of semester examination. If the variance of the exam score is 100. What is the standard error of measurement ?

Answers

Answer:

I Will explained you youuuuuu<uuuuuuuuuu

9. what is the measure of QSR

Answers

Answer:  C) 142 degrees

=======================================================

Explanation:

Extend segment MN such that it intersects side ST. Mark the intersection as point A. See the diagram below.

We're given that angle MNT is 72 degrees. The angle TNA is equal to 180-(angle MNT) = 180 - 72 = 108 degrees, since angles MNT and TNA add to 180.

For now, focus entirely on triangle TNA. We see from the diagram that T = 34 and we just found that N = 108. Let's find angle A

A+N+T = 180

A+108+34 = 180

A+142 = 180

A = 180-142

A = 38

So angle NAT is 38 degrees.

----------------------------

Since segment MA is an extension of MN, and because MN || SQ, this means MA is also parallel to SQ.

We found at the conclusion of the last section that angle NAT was 38 degrees. Angles QST and NAT are corresponding angles. They are congruent since MA || SQ. This makes angle QST to also be 38 degrees

----------------------------

The angles QSR and QST are a linear pair, so they are supplementary

(angle QSR) + (angle QST) = 180

angle QSR = 180 - (angle QST)

angle QSR = 180 - 38

angle QSR = 142 degrees

6. The right triangles ABC and DEF are
similar. The hypotenuse of AABC
measures 28 cm and the hypotenuse
of A DEF measures 7 cm. If one of the
legs of AABC measures 16 cm, what
does the corresponding leg of ADEF
measure?
F 1 cm
H 12 cm
G 4 cm
J 64 cm

Answers

Answer:

G. 4 cm

Step-by-step explanation:

28 divided by 7 equals 4.

So, 16 divided by 4 equals 4, which is the answer.

4 is the multiple that relates AABC to ADEF.

The table below represents the function f, and the following graph represents the function g.
*
-6
un
4
-3
-2.
-1
0
1
f(x) 8
-2
-8 -10
-8
-2
8.
22
у
4
12
6
- 2
2
4
6
2
-4
6
Complete the following statements.
The functions fand g have

Answers

The functions f and g have different axis of symmetry

The y-intercept of f is higher than the y-intercept of g

Over the interval [-6, -3], the average rate of change of f is more rapid than the average rate of change of g

The known value in the question includes the following

The given table of f(x) and x, from which we have;

The point of the minimum value, which is the vertex = (-3, -10)

The axis of symmetry, of a parabola is the vertical line passing through the vertex such that the y-values at equal distance from the line on either side are equal is the line x = -3

The y-intercept, which is the point the graph intercepts with the y-axis or where x = 0 is the point (0. 8)

Over the interval [-6, -3], the average rate of change of f = (-10 - 8)/(-3 -(-6)) = -6

From the graph of g(x), we have;

The axis of symmetry is the line x = -3

The y-intercept = (0, -2)

Over the interval [-6, -3], the average rate of change of g ≈ (6 - (-2))/(-3 -(-6)) = 8/3

Therefore, we have the correct options as follows;

The functions f and g have different axis of symmetry

The y-intercept of f is higher than the y-intercept of g

Over the interval [-6, -3], the average rate of change of f is more rapid than the average rate of change of g

Learn more about parabola here;

https://brainly.com/question/22213822

Can someone please help me with this I’m struggling

Answers

Answer:

Equation:  [tex]70=(x+3)x[/tex]

x = -10 or x = 7

x = 7 (width can't be negative)

x + 3 = 10

Step-by-step explanation:

Represent the width of the rectangle by  x.  "The length of a rectangle EXCEEDS the width by 3" means the length is 3 LONGER than the width, so the length is represented by the expression  x + 3.

Area = (length)(width)

70 = (x + 3)x

Multiply out the right side.

[tex]70=x^2+3x\\x^2+3x-70=0[/tex]

Factor the left side.

[tex](x+10)(x-7)=0[/tex]

Each binomial could equal 0, so

[tex]x+10=0 \text{ or }x-7=0\\x=-10\text{ or }x=7[/tex]

The negative solution does not make sense as the width of a rectangle.

x = 7, making the length, x + 3 = 10

Answer:

Pls mark this as brainiest

Step-by-step explanation:

Area of the rectangle = length x breadth

consider 'x' to be width

therefore length = x+3

area = (x+3)*x

Area = 70 square

x = 7

x+3 = 7+3

      = 10

verification

7 x 10

= 70

How do you solve this problem?

Answers

9514 1404 393

Answer:

  -19.2

Step-by-step explanation:

Fill in the given values and do the arithmetic.

  [tex]\displaystyle x\ \blacksquare\ y=\frac{x}{y}-xy\\\\4\ \blacksquare\ 5=\frac{4}{5}-4\cdot5=0.8-20\\\\\boxed{4\ \blacksquare\ 5=-19.2}[/tex]

Question 4 of 5
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used
Match each explicit formula to its corresponding recursive formula.
(8) = 5(5)(1-1)
(n) = 3 +5(n-1)
(3) = 5+3(1-1)
7(n) = 3(5)(n-1)
$(n) = 5 +5(n-1)
f(1) = 5
(*) = 3;(n - 1), for 3
(1) = 5
(n) = f(n-1) +5, for n?
f(1) = 5
f(n) = f(n-1) + 3, for n?

Answers

Given:

The recursive formulae.

To find:

The correct explicit formulae for the given recursive formulae.

Solution:

If the recursive formula of a GP is [tex]f(n)=rf(n-1), f(1)=a, n\geq 2[/tex], then the explicit formula of that GP is:

[tex]f(n)=ar^{n-1}[/tex]

Where, a is the first term and r is the common ratio.

The first recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=3f(n-1)[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of a GP with a=5 and r=3. So, the required explicit formula is:

[tex]f(n)=5(3)^{n-1}[/tex]

Therefore, the required explicit formula for the first recursive formula is [tex]f(n)=5(3)^{n-1}[/tex].

If the recursive formula of an AP is [tex]f(n)=f(n-1)+d, f(1)=a, n\geq 2[/tex], then the explicit formula of that AP is:

[tex]f(n)=a+(n-1)d[/tex]

Where, a is the first term and d is the common difference.

The second recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+5[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=5. So, the required explicit formula is:

[tex]f(n)=5+(n-1)5[/tex]

[tex]f(n)=5+5(n-1)[/tex]

Therefore, the required explicit formula for the second recursive formula is [tex]f(n)=5+5(n-1)[/tex].

The third recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+3[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=3. So, the required explicit formula is:

[tex]f(n)=5+(n-1)3[/tex]

[tex]f(n)=5+3(n-1)[/tex]

Therefore, the required explicit formula for the third recursive formula is [tex]f(n)=5+3(n-1)[/tex].

What should be done so that the expression will have a value of 28?

6 + 2 + 32 × 2

Answers

Answer:

6+2+(32×2)

6+2+(64)

8+64

72

difference between 72 and 28

72-28

=44

add 44 to make the value 28

A block has a mass of 880g and a volume of 80 cm Calculate the density​

Answers

Answer:

Density formula (p=m÷v). ---[ p= Density, m= Mass, v= volume]

so, 880g/80cm³

=11gcm³

880 divided by 80= 11glcm3

Ben is 4 times as old as Ishaan. 6 years ago, Ben was 6 times as old as Ishaan.
How old is Ishaan now?

Answers

Answer:

Ishaan is currently 15 years old.

Step-by-step explanation:

Let B represent Ben's current age and I represent Ishann's current age.

Ben is four times as old as Ishaan. In other words:

[tex]B=4I[/tex]

Six years ago, Ben was six times as old as Ishaan. In other words:

[tex]B-6=6(I-6)[/tex]

Solve for I. Substitute:

[tex](4I)-6=6(I-6)[/tex]

Distribute:

[tex]4I-6=6I-36[/tex]

Subtract 4I from both sides and add 36 to both sides:

[tex]2I=30[/tex]

And divide both sides by two. Hence:

[tex]I=15[/tex]

Ishaan is currently 15 years old.

Answer:

Age of Ishaan = 15 years

Step-by-step explanation:

Let Ishaan's age = x years

Age of Ben = 4 * x = 4x years

6Years ago:

Age of Ishaan = x - 6

Age of Ben = 4x - 6

6 years ago, Ben was 6 times as old as Ishaan

So, Age of Ben = 6 * Ishaan's age

     4x - 6 = 6 *(x-6)

4x - 6 = 6x - 36

Add 36 to both sides

4x - 6 + 36  = 6x  

4x + 30 = 6x

Subtract '4x' from both sides

30 = 6x - 4x  

30 = 2x

2x = 30

Divide both by 2 sides

x = 30/2

x = 15

How to find a parallel sides of trapezium length 7.3mm and 5.3mm ,and it's height is 5mm calculate the area of a trapezium

Answers

Answer:

31.50 mm²

Step-by-step explanation:

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Characteristics of a trapezoid

It has 4 vertices and edges

If both pairs of its opposite sides of a trapezoid are parallel, it becomes a parallelogram

Area of a trapezoid =  1/2 x (sum of the lengths of the parallel sides) x height

1/2 x ( 7.3 + 5.3) x 5 = 31.50 mm²

Find out the values of x and y from the following ordered pairs.
(x + y, 2) = (13, 2x – y)

Answers

Answer:

(x, y) = (5,8)

Step-by-step explanation:

Comparing the ordered pairs we get, x+y=13 and 2=2x-y. Solving it we will get, x=5 and y=8

Simplify the variable expression by evaluating its numerical part.
p-7+56 - 12
A. p + 51
B. p+37
O c. p-51
D. p + 49

Answers

The answer to this is B. p+37

Please help me answer this question.

Answers

Answer:

total candy = 54 bags

y=17

x=37

Step-by-step explanation:

5x + 4y = 253

x-y = 20

x = 20+y

5(20+y) + 4y = 253

100 + 9y = 253

9y = 153

y=17

x=37

i need help ASAP please

Answers

Answer:

reflection over Y axis

Step-by-step explanation:

Answer:

I believe it is D) a reflection over the Y-axis

Step-by-step explanation

it is going over the Y-axis as if it is a sort of mirror, if it were going over the x-axis it would be flipped upside down, if it was A the shape would be going over the original shape. I don't know how to explain C. (I hope this helped and I hope it was correct lol)

what is the formula to calculate VAT percentage

Answers

Answer:

Take the gross amount of any sum (items you sell or buy) – that is, the total including any VAT – and divide it by 117.5, if the VAT rate is 17.5 per cent. (If the rate is different, add 100 to the VAT percentage rate and divide by that number.)

Answer:

divide by 117.5 if the rate different, add 100 to the percentage and divide by the number therefore multiply by 100 to get the total

Step-by-step explanation:

the formula to calculate vat percentage

Zoe and Hanna share tips in the ratio 3:7
Last week Zoe received £24
How much did Hanna receive last week?

Answers

Answer:

56

Step-by-step explanation:

Zoe : hanna

3         7

Zoe got 24

3*8 = 24

so multiply each side by 8

Zoe : hanna

3*8         7*8

24           56

Hanna got 56

Find the distance between the
following points using the
Pythagorean theorem: (5, 10)
and (10, 12)

Answers

Answer:

[tex]\displaystyle d = \sqrt{29}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

Step-by-step explanation:

*Note:

The distance formula is derived from the Pythagorean Theorem.

Step 1: Define

Identify

Point (5, 10)

Point (10, 12)

Step 2: Find distance d

Substitute in points [Distance Formula]:                                                         [tex]\displaystyle d = \sqrt{(10 - 5)^2 + (12 -10)^2}[/tex][√Radical] (Parenthesis) Subtract:                                                                   [tex]\displaystyle d = \sqrt{5^2 + 2^2}[/tex][√Radical] Evaluate exponents:                                                                       [tex]\displaystyle d = \sqrt{25 + 4}[/tex][√Radical] Add:                                                                                                  [tex]\displaystyle d = \sqrt{29}[/tex]

the polygons in each pair are similar. find the missing side length.​

Answers

Given:

The polygon in the given figure are similar.

To find:

The missing side length.​

Solution:

We know that the corresponding sides of similar figures are proportional.

The given polygons are similar, so the their corresponding sides are proportional.

[tex]\dfrac{x}{15}=\dfrac{32}{40}=\dfrac{32}{40}[/tex]

So, the missing values in the equation of proportion are 15, 40, 32 respectively.

On solving the above equation, we get

[tex]\dfrac{x}{15}=\dfrac{4}{5}=\dfrac{4}{5}[/tex]

[tex]\dfrac{x}{15}=\dfrac{4}{5}[/tex]

[tex]x=\dfrac{4}{5}\times 15[/tex]

[tex]x=12[/tex]

Therefore, the value of x is 12.

Help anyone can help me do this question,I will mark brainlest.​

Answers

Answer:

Answer is in attached image

I hope it help...

write the equation of the line that goes through points (0,4) (6,16)

Answers

Answer: Y= 2x

Step-by-step explanation:

Answer:

y=2x-4

Step-by-step explanation:

firstly find the gradient

m=y2-y1/x2-x1

16-4/6-0

12/6

m=2

then use the equation to find the answer

y-y1=m(x-x1)

y-4=2(x-0)

y-4=2x-0

y=2x-4

Complete the missing parts of the
table for the following function. (picture) please answer all asap

Answers

Answer:

x=-1  y = 1/3

x = 1  y = 3

x = 3  y = 27

Step-by-step explanation:

y = 3^x

Let x = -1

y = 3^-1 = 1/3^1 = 1/3

Let x = 1

y = 3^1 = 3

Let x = 3

y = 3^3 = 27

GIVE FULL STEP BY STEP OF THIS MATHS WORD PROBLEM
Sohanlal is a gardener. He is paid ₹160 daily, find how much money will he
get in the month of September?

Answers

Answer:

Step-by-step explanation:

days in september=30

salry paid per day=Rs.160

salary paid in 30 days=160×30=Rs.4800

Answer:

4800

Step-by-step explanation:

In the month of September there are only 30 days. So assuming Sohanlal works the entire month of September we will multiply how much he makes daily which is 160 times the amount of days he works which is 30. this will look like this:

160 × 30 = 4800

Dan invests £18790 into his bank account. He receives 5.9% per year simple interest. How
much will Dan have after 2 years? Give your answer to the nearest penny where appropriate.

Answers

Answer: £21007.22

Step-by-step explanation:

First, find the interest amount using the formula SI = (P × R × T) / 100.

SI = interest amount P = principle amount = £18790R = interest rate(in percentage) = 5.9T = time(in years) = 2

SI = (P × R × T) / 100 = (18790 × 5.9 × 2)/100 = 221722/100 = £2217.22

The total amount = principle amount + interest amount

= £18790 + £2217.22 = £21007.22

4 raised to power two minus 8u minus 9=0​

Answers

Answer: u = [tex]\frac{7}{8}[/tex] or 0.875

Step-by-step explanation:

Let us convert this statement to a question

[tex]4^{2}[/tex]-8u-9 = 0

16-8u-9 = 0

-8u = 0+9-16

-8u = -7

u = -7 ÷ -8

u = [tex]\frac{7}{8}[/tex] or 0.875

(x⁴ + 3x³ – 2x² + 5) + (2x⁴ – 5x³ + 4x – 15).

Answers

Answer:

[tex]\left(x^4+3x^3-2x^2+5\right)+\left(2x^4-5x^3+4x-15\right)[/tex]

[tex]=[/tex] [tex]x^4+3x^3-2x^2+5+2x^4-5x^3+4x-15[/tex]

[tex]=x^4+2x^4+3x^3-5x^3-2x^2+4x+5-15[/tex]

[tex]=x^4+2x^4-2x^3-2x^2+4x+5-15[/tex]

[tex]=3x^4-2x^3-2x^2+4x+5-15[/tex]

[tex]=3x^4-2x^3-2x^2+4x-10[/tex]

[tex]OAmalOHopeO[/tex]


Question 4(Multiple Choice Worth 4 points)
.
(08.03)Solve the system of equations and choose the correct answer from the list of options.
X + y = -3
y = 2x + 2

a- five over 3, four over 3
b-negative five over 3, negative four over 3
c- negative 3 over 5 negative 3 over 4
D- 3 over 4, 3 over 5

Answers

Answer:

Hello,

Answer B (-5/3,-4/3)

Step-by-step explanation:

I am going to use the substitution 's method.

[tex]\left\{\begin{array}{ccc}x+y&=&-3\\y&=&2x+2\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\x+2x+2&=&-3\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\3x&=&-5\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&2*(-\dfrac{5}{3})+2\\\end {array} \right.\\\\\\\boxed{\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&-\dfrac{4}{3}\\\end {array} \right.\\}[/tex]

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