You believe that the cytosolic protein p007 is involved in mediating growth hormone-stimulated proliferation in cells. You wish to establish a cell model using your cultured fibroblasts. Provide clear explanations to the following, each worth 2.5 pts each. a) Describe how you would transfect the growth hormone receptor DNA into your cells to create stable cell lines, and include a description of the benefits of using stable cell lines versus transiently transfected cell line. b) Describe how you would measure specific receptor binding of GH to your stable cell line. c) Describe how you would measure growth hormone-induced proliferation in your stable cell line. Make sure to include controls. d) Describe how you would use RNAi to demonstrate the requirement for p007 in growth-hormone stimulated proliferation. Make sure to include controls.

Answers

Answer 1

Answer:

Following are the answer to this question:

Explanation:

In option a:

There are many ways, which can be defined as follows:  

It keeping cells "qualified," use heat shock and handle ions like Ca and ice incubating.It uses Micro-injection with DNA.  It uses the biolistics or even the process of gene-gun.  

The stable cell charts indicate simple and definitive outcomes when their relationship to specific results. Moreover, relative to temporary cell lines, findings are more reliable and error-free. These lines also easily break and much less.

In option b:

Radio tests including linking tests could be used  

The Ligand Binding Assays is an analysis, that is based on the binding of ligands to antibodies, or other macromolecules. Its existence and distance of formed ligand-receptor complexes are defined using a system of measurement that is usually electrical or fluorescent.

In option c:

The method for measuring the levels of cell growth is accessible and the  Another way is to measure the metabolism within the same cell. So many color pigments were also accessible that can permeate an organism as well as react with some proteins as well as other factors, and that can effectively identify a color final product.  

Throughout relation to the amount of metabolism exercise, cell proliferation could be evaluated by researching one or even more cell markings. The BrdU limited liability assessment is a very well-published illustration.  

Its specific antibody can detect BrdU and high BrdUincorporations levels are linked to high levels of cell proliferation.  Command cell without DNA receptor growth hormone.

In option d:

The cell growth will stop after each use of RNA interference ( RNAi). The p007 formation as well as the effect on growth caused by the intrusion will be a goal. If development is delayed effectively, the theory will be tested successfully to a cell without any of the required DNA. The RNAi is the free cell


Related Questions

Characteristics of Living Things
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C. cell
D. organ
8. Storing energy obtained from food is an example of
A. evolution B. homeostasis
C. response
D. growth
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9. The passing of genes from one generation to another is
A homeostasis
B. response
C. growth D. heredity
10. The main function of reproduction is to
A. have enough male and female to reproduce
B. overpopulate
D. to be able to replace themselves.
C. grow
11. The milkweed plant feeding the caterpillar is an example of
A. interdependency.
C. preparing to die after a long life.
B. reproduction
D. heredity
12. Adaptation is very important to species because it allows them to
A. grow and become successful
C. Die
B. produce offspring better equipped to survive.
D. produce many offspring.

Answers

Answer:

bbbc

Explanation:

all of these were to long so

A research team discovered that a novel hormone X stimulates an enzyme that hydrolyzes proteins in the small intestine. However, when hormone X was added to a test-tube mixture containing the enzyme and proteins, no breakdown occurred.

Required:
a. Why is this the case?
b. Name ONE signal transduction pathway that hormone X is using to transfuse its signal. (write all the steps and intermediates)

Answers

Answer:

a. It is a hormone that acts upstream in the signaling pathway (i.e., acting as a ligand by binding to cell receptors)

b. Dopamine-mediated pathways  

Explanation:

It is well known that many cellular transduction pathways are activated via binding of signaling molecules (ligands) to receptors capable of triggering signaling cascades into the cell. For example, dopamine is a signaling hormone (neurotransmitter) involved in diverse brain processes (i.e., motor control, emotional response, etc). It is a neurotransmitter that binds to dopamine receptors and then stimulates the enzyme adenylate cyclase in a process that subsequently activates the production of the second messenger cyclic adenosine monophosphate (cAMP). Finally, cAMP acts as an intracellular signal transductor that play roles in many biological processes by transferring into the cell the effects of dopamine.

If the gene encoding one of the proteins that forms cohesin were mutated such that cohesin could not perform its normal function, what would be the consequence? Check all that apply.

Answers

Answer:

The following apply:

- Chromosomes would not be able to condense.

- Chromosomes would not be able to properly align at the metaphase plate.

- The separation of sister chromatids would not likely occur specifically during anaphase A.

- The nuclear envelope would not be able to reform.

What are some of the main characteristics of skeletal muscle cells that make them distinct from the other two types of muscle cells Why are these characteristics important for understanding the function of skeletal muscle?

Answers

Answer:

They are voluntary , require force and fast.

Explanation:

Main characteristics of skeletal muscle cells are given below:

1) these muscles are voluntary which means it can be controlled by the human.

2) skeletal muscles requires force for its movement.

3) movement of skeletal muscle is fast.

Due to its structure, skeletal muscle provide support to the body and the body is able to move from one place to another. It also provide protection to the delicate organs of the body. It is also used as a storage of minerals and fats.

What are the
traditional
circulatory
endpoints of
resuscitation
in shock?​

Answers

Explanation:

traditional circulatory endpoints of resuscitation in shock include hypertension,tachycardia,decreased mentation and urine output

The diagram represents a food pyramid. The concentration of the pesticide DDT in individual
organisms at level D is higher than the concentration in individuals at level A because DDT is
A. produced by organisms at level C ingested by
those in level D
B. passed through levels A, B, and C to organisms
at level D.
C. excreted by organisms at level A as a toxic
waste.
D. synthesized by organisms at level D.

Answers

Answer:

The answer is "Choice b".

Explanation:

In the given question diagram is missing. so first, we define the diagram after that we explain why the above given choice is correct.  

In the attached file the food pyramid can be a divide into the level, in which the D pesticides use the "dichloro-diphenyl-trichloroethane ", which concentration is higher than its entities from the level of A because DDT is transferred with species at level D by levels A, B, and C, that's why the choice "b" is correct.  

Is the talc renewable?

Answers

Answer:

no.its nonrenewable.

talc is nonrenewable.

thanks.

What growth information leads to your answer? The colonies are able to grow on minimal medium containing no additional supplements. The colonies are able to grow on complete medium.

Answers

Answer:

A growth medium or culture medium is a solid, liquid or semi-solid designed to support the growth of a population of microorganisms or cells via the process of cell proliferation,[1] or small plants like the moss Physcomitrella patens.[2] Different types of media are used for growing different types of cells.[3]

The two major types of growth media are those used for cell culture, which use specific cell types derived from plants or animals, and microbiological culture, which are used for growing microorganisms, such as bacteria or fungi. The most common growth media for microorganisms are nutrient broths and agar plates; specialized media are sometimes required for microorganism and cell culture growth.[1] Some organisms, termed fastidious organisms, require specialized environments due to complex nutritional requirements. Viruses, for example, are obligate intracellular parasites and require a growth medium containing living cells.

In which of these stages is mitosis most important? A tiger cub is born. A tiger cub learns to walk. A tiger cub begins to grow. A tiger cub play-fights.

Answers

Answer:

A tiger cub begins to grow

Explanation:

because that's when they change the most

Answer:

A tiger club play fights

Explanation:

One main part of mitosis is the replacement of cells, so when the tiger gets hurt fighting, mitosis kicks in to replace the cells.

In the image, the arrow Is pointing to a celestial object. Which attribute disqualifies the object from being a planet?
A. It appears to have no moons.
B. It is spherical in shape.
C. Its neighborhood is not clear.
D. It has horizontal bands on its surface.

Answers

The correct answer is C. Its neighborhood is not clear.

Explanation:

One of the key features of a planet is that it clears its neighborhood; this means the planet gravitational force is strong enough that there are no other celestial bodies on its orbit or next to it except by its moons or satellites. This does not occur in the image presented because there are smaller celestial bodies near to the main or bigger celestial body. This likely occurs if the celestial body is not big enough to clear its neighborhood, and therefore it is not a planet.

A graduate student studying biology at the University of Nebraska has identified a new species of spider found only in Eastern Nebraska around Omaha. The graduate student determines that the spider has six homologous pairs of chromosomes. How many chromosomes would a cell in that spider have during metaphase of mitosis?

Answers

Answer:

12 chromosomes

Explanation:

Mitosis is a type of cell division that involves the formation of two genetically identical daughter cells. The two daughter cells are genetically identical in the sense that they contain the same number of chromosomes as the parent cell. Mitosis involves four stages namely: Prophase, Metaphase, Anaphase and Telophase.

In the metaphase stage as stated in this question, homologous chromosomes align at the equator of the cell called cell plate, before each chromatids are pulled apart by microtubules at the Anaphase stage.

According to the question, the spider being worked on has 6 pairs of chromosomes, which will align at the cell's equator during metaphase stage of mitosis. Since the replicated chromosomes (chromatids) are yet to separate to opposite poles of the cell, the cell will still contain 12 chromosomes at the metaphase stage.

N.B: Each chromosome contains 2 chromatids or replicated chromosome, which will be separated at the Anaphase stage. Each chromatid will be an individual chromosome after cytokinesis.

PLEASE ANSWER QUICK!The Greek roots of the word prokaryote mean “before nucleus.” Describe the way that DNA is organized in prokaryotic cells without the help of a nucleus. How does this approach differ from the way that eukaryotic cells organizes their DNA

Answers

Answer:

Prokaryotic cells' DNA are located in the cytoplasm of the cell rather than in the nucleus, like in eukaryotic cells. DNA aids in protein synthesis and determines functions of the cell in cells, regardless of being within the membrane of a nucleus or not.

-----

I hope this helps a little.

The word prokaryote in Greek means before kernel (nucleus). Unlike the eukaryotic cells, the nuclear material is located in the cytoplasm of the cell in a nucleoid.

What are the characteristics of prokaryotic cells?

The prokaryotic cells are the primitive karyons that are defined by the lack of the true nucleus and organelles. Unlike the eukaryotes, the organelles lack the membrane that covers them but has a tough cell wall.

The prokaryotes include archaea and bacteria which are unicellular and microscopic organisms that are simple and have their genetic material organized into nucleoids in the center of the cell. They have the ability to live in harsh conditions.

Therefore, the eukaryotes and prokaryotes differ in the arrangement of the genetic material.

Learn more about prokaryotes, here:

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g dGDP is made from ________ by the ribonucleotide reductase. This enzyme is inactive when ______ is bound to its master regulatory pocket.

Answers

Answer:

1.  GTP dephosphorylation

2.  hydrolyzed or removed

Explanation:

GDP, (Guanosine diphosphate) is a biological term, that is made of composition including pyrophosphate group, a pentose sugar ribose, and the nucleobase guanine and it is made from GTP ( Guanosine triphosphate ) dephosphorylation by the ribonucleotide reductase. This enzyme is inactive when hydrolyzed or removed, and then eventually bound to its master regulatory pocket.

What makes up the backbone of a DNA molecule? nucleic acids RNA molecules sugars and phosphates ribose and deoxyribose

Answers

Base, sugar and phosphate and deoxyribose make up a nucleotide on a DNA molecule

Answer:

sugars and phosphates

Explanation:

gradpoint

Which two layers are approximately the same age?
core sample 1
core sample 2

Answers

Complete question:

Examine the following diagrams. Columns I and II contain rock layers A, B, C, D, E, and F. Both columns were taken from the same dig site at different locations. Which two layers are of approximately the same age? (Note: The diagrams are attached).

Answer:

C and D  

Explanation:  

Layers C and D apparently contain the same fossilized organisms in the same substrate. Their appearance is very similar. By knowing that certain organisms used to live in a certain period of time, if we find two strata that show the same fossilized organisms, then we can estimate that these two strata are the same age. Fossilized organisms are used to estimate the age of a rocky stratum.

Life history can be illustrated through fossilized organisms trapped or converted into rocks. These fossils are known as index or guide fossils, of animal or vegetal nature, and they can apport information about the rocky stratum in which they are located or incrusted. These fossils are used to determine the age of the rocky sediments or the environmental conditions under which they were deposited.

 

Answer:both of them are

Explanation:

What are some pros and cons of using a dispersant versus bacteria to deal with a very large spill and how would each one impact the environment

Answers

Answer:

it is toxic to the health

Explanation:

Dispersants create a toxic environment for fish by releasing harmful oil break-down products into the water. ... Dispersants and dispersed oil have also been shown to have toxic effects on bird eggs that are similar or worse than from untreated oil.

Which of the following is not a function of Mitosis? A. Growth and development B. Produce genetically identical daughter cells C. Produce genetically different daughter cells D. Replace damaged cells

Answers

C. Produce genetically different daughter cells, is not a function of mitosis

What is the relationship between DNA mutation and sickle-cell anemia? (1 point)
O Sickle-cell anemia and DNA mutations are correlated without any causal relationship.
O Sickle-cell anemia causes a DNA mutation.
O A DNA mutation causes sickle-cell anemia.
O A DNA mutation is correlated with but does not cause sickle-cell anemia.

Answers

Answer:

A DNA mutation causes sickle-cell anemia.

Explanation:

Sickle cell anemia is caused by a single code letter change in the DNA. This in turn alters one of the amino acids in the hemoglobin protein. Valine sits in the position where glutamic acid should be. The valine makes the hemoglobin molecules stick together, forming long fibers that distort the shape of the red blood cells, and this brings on an attack.

Every interaction with the outside world is because of A) epithelial tissue B) connective tissue C) nervous tissue D) muscular tissue

Answers

Answer:

A cutaneous membrane is a multi-layered membrane composed of epithelial and connective tissues. The apical surface of this membrane exposed to the external environment and is covered with dead, keratinized cells that help protect the body from desiccation and pathogens....

Describe at least 2 benefits and 2 drawbacks there might be for animal cells (including humans) to make their own food through photosynthesis.

Answers

Answer:

Explanation:

Benefits

Animals will not depend on plant source again for their food but have it produced directly by themselves because photosynthesis will allow animal produce their own food

Animal will get a direct source of energy for their activities. Energy is derived from food consumed after the food has been broken down in the body system of animal. Animal photosynthesis will give animals access to direct source of energy as the product their food.

Demerit

Animal lacks chlorophyll the green. Pigment in plant that light hit on absorption that will enable them to photosynthesis.

Animal lacks ways or mechanism of regulating Carbondioxide in take as in the case of C4 plant and crassulacean metabolic pathway (CAM).

Animals such as human will not have access to varieties of food but stick to photosynthate produced by them.

What percentage of the nation’s demand for electricity could be produced in the future by wind energy?

Answers

Answer:

5-10%

hope this is helpful

assuming hardy weinberg equilibrium what is the probability that sarah who is phenotypically normal with no family history and tom

Answers

Answer:

The probability of having a disorder is 50 %.

Explanation:

The offspring has that genetic disorder if the Sarah who is phenotypically normal with no family history and tom has a genetic disorder so there is 50 percent chance that the children of Sarah and tom has that genetic disorder. if the disorder linked with Y chromosome of male so this disorder is present in the sons but if the disorder linked with X chromosome of male so this disorder is present in the daughters.

In most organisms, the end product of glycolysis is pyruvate. Pyruvate still contains a substantial amount of energy, which can be further extracted. Whether the organisms are operating under aerobic or anaerobic conditions determines the metabolic pathway that pyruvate undergoes to produce more ATP. In this tutorial, you will identify the end products of these metabolic pathways.

Answers

Answer:

Pyruvate helps in the production of ATP.

Explanation:

The molecule of pyruvate converted into acetyl CoA. Then each molecule which is produced during glycolysis loses electron and carbondioxide releases. After the breakdown of pyruvate, the electrons loses by pyruvate are transferred to NAD+ in order to produce NADH, which will be used by the cell to produce energy molecule such as ATP. So we can say that pyruvate plays a vital role in the formation of ATP molecule.

Why are so many of the same genes found in almost all living organisms

Answers

Answer:

Molecular homology occurs when different species inherit similar molecules, such as nucleic acids or proteins, from an evolutionary common ancestor. In many cases, especially for essential housekeeping genes involved in protein synthesis or DNA replication, genes are homologous across most, if not all, living organisms. Hope this helps!

Explanation:

b) How will you describe any three (3) major components of the environment to a named
class puyil?​

Answers

Answer:

Hydrosphere, atmosphere and biosphere are the three major components of the environment.

Explanation:

Hydrosphere, atmosphere and biosphere are the three major components of the environment. hydrosphere refers to water bodies such as ocean, sea, ponds and lakes etc that is present in our environment. atmosphere refers to the gaseous layer which is present above the earth surface. in this layer oxygen, nitrogen and carbondioxide etc are present. biosphere refers to all living organisms such as human, animals, plants and microbes etc which are present on earth surface..

Which of the following properties is the temperature at which a liquid turns to gas? (3 points)
оа
Magnetism
Ob
Thermal conductivity
ос
Melting point
Boiling point
Od

Answers

thermal conductivity

Answer:

Boiling point

Explanation:

I did the test

Centrioles have pulled the chromosomes all the way to the spindle poles, the process of cleavage furrowing appears to be about to begin. What kind of a cell is this?

Answers

Answer:

An animal cell in the telophase

Explanation:

Telophase is one of the stages of cell division in animal cell .

In the animal cell during telophase, Centrioles have pulled the chromosomes all the way to the spindle poles, the process of cleavage furrowing appears to be about to begin because the nuclear membrane and nucleoli reform, cytokinesis is almost coming to completion and the chromosomes eventually uncoil to chromatin. Usually cytokinesis occurs during telophase.

RNA polymerase is an enzyme that copies (1 point)
o DNA into DNA.
O RNA into mRNA
O mRNA into tRNA.
DNA into RNA

Answers

Answer:Copies DNA into RNA

Explanation:

Which type of nuclear power reactor is used in only 1 percent of all power plants?

Answers

Answer:

Breeder reactors

Explanation:

The type of nuclear power reactor that is used in only 1 percent of all power plants would be Breeder reactors.

Design a controlled experiment to test the effect of water temperature on goldfish. be sure to include your hypothesis, independent variable, dependent variable as well as experimental group and control group.

Answers

Answer:

In this experiment, indepedent variable will be temperature and dependent variable will be the respiratory rate of goldfish. Temperature affects the respiratory rate of goldfish, as it's respiratory rate decreases with decrease in temperature of water, the experiment is as follows:

Take two glass containers filled with water A and B and put one goldfish in each container.Measure the temperature of the water using a thermometer.Count mouth movement of both the fishes in certain time.Now put some ice in container B that will decrease the temperature of water and measure the temperature again.Now count the mouth movement of both the fishes for the same time it was counted earlier.

The result will be that respiratory rate of goldfish decreases with the decrease in temperature in container B in comparison to container A goldfish.

An experiment meant to determine the cause of an effect, the effect is the independent variable, while the cause is the dependent variable

A controlled experiment to test the effect of water temperature on goldfish is designed as follows:

The experimental group are: The gold fish in a glass Jar X filled with fresh water and with the lid left open (the treatment of temperature reduction is applied to the experimental group)

The control group are: A second gold fish (selected at random) of the same size, in another glass jar Y filled to the same level with fresh water collected from the same source of the first gold fish

Independent variable: The independent variable is the temperature of the water which will be varied by placing ice cube gradually into the glass jar B

Dependent variable: The number times the gold fish gulp air by rising to the surface, and or the number of time goldfish opens its mouth, which indicates that the goldfish is breathing

The hypothesis: The breath rate of goldfish decreases with decrease in temperature because the goldfish metabolic rate decreases and the water holds more dissolved air and therefore oxygen at a reduced temperature

The Experiment Design:

The experiment is conducted by measuring the initial temperature and breathing rate of both fishes

The temperature of the fresh water in jar X is decreased gradually by adding ice cubes and recording the temperature and breathing rate of the goldfish

A similar experiment from an online source (Maryland School improvement website) the following results where obtained

[tex]\begin{array}{|c|cc|} \underline {Breathing \ rate}&&\underline {Water \ Temperature } \\&&\\ (Dependent \ Variable)&&(Independent \ Variable)\ \\&&\\103&&78.8 ^{\circ}F\\78&&68^{\circ}F\\55&&57.2^{\circ}F\\28&&46.4^{\circ}F\\4&&35.6^{\circ}F\end{array}\right][/tex]

From the experiment, it can be seen that the in the experimental group dependent variable, which is the breathing rate of the goldfish reduces as the temperature which is the dependent variable is reduced

Learn more about experimental variables here:

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Why were the British willing to bet the Oregon Territory with the Americans The physics of wind instruments is based on the concept of standing waves. When the player blows into the mouthpiece, the column of air inside the instrument vibrates, and standing waves are produced. Although the acoustics of wind instruments is complicated, a simple description in terms of open and closed tubes can help in understanding the physical phenomena related to these instruments. For example, a flute can be described as an open-open pipe because a flutist covers the mouthpiece of the flute only partially. Meanwhile, a clarinet can be described as an open-closed pipe because the mouthpiece of the clarinet is almost completely closed by the reed.1. Consider a pipe of length 80.0 cm open at both ends. What is the lowest frequency f of the sound wave produced when you blow into the pipe? 2. A hole is now drilled through the side of the pipe and air is blown again into the pipe through the same opening. The fundamental frequency of the sound wave generated in the pipe is now:______.a. the same as before. b. lower than before.c. higher than before.3. If you take the original pipe in Part A and drill a hole at a position half the length of the pipe, what is the fundamental frequency of the sound that can be produced in the pipe?4. What frequencies, in terms of the fundamental frequency of the original pipe in Part A, can you create when blowing air into the pipe that has a hole halfway down its length?4-1. Recall from the discussion in Part B that the standing wave produced in the pipe must have an antinode near the hole. Thus only the harmonics that have an antinode halfway down the pipe will still be present.A. Only the odd multiples of the fundamental frequency.B. Only the even multiples of the fundamental frequency.C. All integer multiples of the fundamental frequency.E. What length of open-closed pipe would you need to achieve the same fundamental frequency as the open pipe discussed in Part A?A. Half the length of the open-open pipe.B. Twice the length of the open-open pipe.C. One-fourth the length of the open-open pipe.D. Four times the length of the open-open pipe.E. The same as the length of the open-open pipe.F. What is the frequency of the first possible harmonic after the fundamental frequency in the open-closed pipe described in Part E?F-1. Recall that possible frequencies of standing waves that can be generated in an open-closed pipe include only odd harmonics. Then the first possible harmonic after the fundamental frequency is the thirdharmonic. When factoring 6x27x20 by grouping, how should the middle term be rewritten? It should be written as 8x15x. It should be written as 2x5x. It should be written as x8x. It should be written as x7x. 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How are proteins carbohydrates and fats related to the discipline of chemistry Marlo wrote a narrative about a mechanic. Read the beginning of the story below: (1) Rick was crouched beside a motorcycle with a wrench in his hand. (2) The floor of the garage was covered in grease stains, and he was only adding to the mess. (3) A slick of coolant poured from the broken Harley. (4) Even though Rick was great with cars, he was out of his depth working on his dads motorcycle. Which sentence introduces the setting of the narrative? A. sentence 1 B. sentence 2 C. sentence 3 D. sentence 4 If 4 pounds of cherries cost $10, what is the unit price Find the missing probability. P(A)=7/20,P(AB)=191/400,P(AB)=49/400 ,P(B)=? A. 7/8 B. 1/4 C. 117/400 D. 19/40 People began to study classical thought during the RenaissanceWWW.better themselves.earn moneyimprove the Churchearn respect 1. 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