Y = 0.2(0.35)^t decay rate

Answer: rectangle.

Step-by-step explanation:

Given points: K(0,0) I(2,2) T(5,-5) E(7,-3)

Distance formula to find distance between [tex]A(a,b)[/tex] and [tex]B(c,d)[/tex]: [tex]AB=\sqrt{(d-b)^2+((c-a)^2}[/tex]

[tex]KI=\sqrt{(2-0)^2+(2-0)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]

[tex]KT=\sqrt{(5-0)^2+(-5-0)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]

[tex]TE=\sqrt{(7-5)^2+(-3+5)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]

[tex]IE=\sqrt{(7-2)^2+(-3-2)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]

i.e. KI = TE and KT= IE, so opposite sides equal.

It can be a parallelogram or rectangle. [if all sides are equal it would be square or rhombus]

[tex]IT=\sqrt{(5-2)^2+(-5-2)^2}=\sqrt{3^2+7^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]

[tex]KE=\sqrt{(7-0)^2+(-3-0)^2}=\sqrt{7^2+3^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]

IT= KE, i.e. diagonals are equal.

It means KIET is  a rectangle.

Answer:

[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]

Step-by-step explanation:

The question seem incomplete; however, the given parameter is assumed as

[tex]-3(2 + 4k) + 7(2k)[/tex]

Required

Simplify

[tex]-3(2 + 4k) + 7(2k)[/tex]

Start by opening the brackets

[tex]-3*2 -3* 4k + 7*2k[/tex]

[tex]-6 -12k +14k[/tex]

Collect Like Terms

[tex]-6 -12k +14k[/tex]

[tex]-6 + 2k[/tex]

Reorder the above expression

[tex]2k - 6[/tex]

The answer can be further simplified as

[tex]2(k - 3)[/tex]

Hence;

[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]

Answer:

1/5

Step-by-step explanation:

1/5

2/3+3/3+4/3

=2/5*3/6

= 1/5

I'm not sure.

Answer:

The answer should be 0.022

Answer:

I think its C because if I remember correctly zero of the function is just the x intercept

Answer:

Answers

product, and assign a number to each person. ... 0.82. 12–13. 9. 0.18. 1.00. Total. 50. 1.00. F requency. 0. 1. 2. 3. 4. 5. 6. 7. 8 ... 3.12 (a) x = 25661.3333, ˜x = 25514.5 (b) Skewed ... N(8.25, 0.0002857).

Answer:

the answer is c

Step-by-step explanation:

i just took the test

Answer:

d. -4

Step-by-step explanation:

Let's plug in g

8 - |2(-3.5) - 5|

8 - |-7-5|

8 - |-12|

The absolute value is always positive of any number,

8 - 12

= -4

Answer:

D. -4

Step-by-step explanation:

We are given this expression:

[tex]8-|2g-5|[/tex]

and asked to evaluate when g= -3.5 Therefore, we must substitute -3.5 in for g.

[tex]8-|2(-3.5)-5|[/tex]

First, multiply 2 and -3.5

2 * -3.5 = -7

[tex]8-|-7-5|[/tex]

Next, subtract 5 from -7.

-7-5= -12

[tex]8-|-12|[/tex]

Next, evaluate the absolute value of -12. The absolute value is how far away a number is from 0, and it is always positive. The absolute value of -12 is 12.

[tex]8-12[/tex]

Subtract 12 from 8.

[tex]-4[/tex]

The value of the expression is -4 and D is the correct answer.

Answer:

76 degrees.

Step-by-step explanation:

Let as consider O is the center of the circle . So from the figure it is clear that

[tex]\angle AOB=44^{\circ}[/tex]

[tex]\angle COD=118^{\circ}[/tex]

By central angle theorem, central angle subtended by an arc is twice of inscribed angle of the same arc.

We know that, [tex]\angle BAD=97^{\circ}[/tex] and angle BOD is the central angle subtended by arc BD.

[tex]\angle BOD=2\times \angle BAD[/tex]

[tex]\angle BOD=2\times 97^{\circ}[/tex]

[tex]\angle BOD=194^{\circ}[/tex]

Now,

[tex]\angle BOD=\angle BOC+\angle COD[/tex]

[tex]194^{\circ}=\angle BOC+118^{\circ}[/tex]

[tex]194^{\circ}-118^{\circ}=\angle BOC[/tex]

[tex]76^{\circ}=\angle BOC[/tex]

[tex]m(arc(BC))=76^{\circ}[/tex]

Therefore, the measure of arc BC is 76 degrees.

Answer:

90 degrees

Step-by-step explanation:

Add them together. 58+32=90

90 degrees

add them togather

Answer:

(a) (f o g)(x) =  x^2 - 15x + 54

(b) (g o f)(x) = x^2 + 3x - 9

(c) (f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d) (g o g)(x) = x - 18

Step-by-step explanation:

f(x) = x^2 + 3x

g(x) = x - 9

(a)

(f o g)(x) = f(g(x)) = (g(x))^2 + 3(g(x)) = (x - 9)^2 + 3(x - 9)

(f o g)(x) = x^2 - 18x + 81 + 3x - 27

(f o g)(x) = x^2 - 15x + 54

(b)

(g o f)(x) = g(f(x)) = f(x) - 9 = x^2 + 3x - 9

(c)

(f o f)(x) = f(f(x)) = (x^2 + 3x)^2 + 3(x^2 + 3x)

(f o f)(x) = x^4 + 6x^3 + 9x^2 + 3x^2 + 9x

(f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x

(d)

(g o g)(x) = g(g(x)) = x - 9 - 9 = x - 18

Answer:

5

Step-by-step explanation:

Answer:

5 (Follow PEMDAS left—>right)

Answer:

Q2: -17

Q3: a) -5/2  b) g = -13

Step-by-step explanation:

2w+7 = -9

2w = -9 - 7

w = -16/2

w = -8

---

15 - 4w

= 15 - 4(-8)

= 15 - 32

= -17

----------------------

Q3:

a) 3/4(16m-24) = -48

16m -24 = -48 ÷ 3/4

16m = -64 + 24

16m = -40

m = -5/2

b) -20 = 1/6(36+12g)

-20 = 1/6 × 6(6+2g)

(cross out the 6 from 1/6 and 6)

-20 = 6 + 2g

-20-2g= 6

-2g = 6+20

-2g = 26

g = 26/-2

g = -13

Answer:

26 nickels

Step-by-step explanation:

Given that

Total contributed = $1.69

Number of coins = 5

based on the above information,

The number of nickels to be contributed is

Here first we have to determine the prime factors of 169 i.e 13 and 13

This represents that there are 13 member gives their $0.13 per person so it would be $1.69

Also there are 13 cents out of which 3 cents would be 3 pennies the remaining 10 cents would be 2 nickels

So the 13 people contributed to 2 nickels

Therefore,  it would be

= 13 × 2

= 26 nickels

Answer:

Nijah has 6 stickers left.

Step-by-step explanation:

Starting stickers:

45

2/5 are given away:

[tex]\frac{2}{5}[/tex] * 45

[tex]\frac{2}{5}[/tex] * [tex]\frac{45}{1}[/tex]

[tex]\frac{90}{5}[/tex]

18

1/3 of the remaining are given away:

[tex]\frac{1}{3}[/tex] * 18

[tex]\frac{1}{3}[/tex] * [tex]\frac{18}{1}[/tex]

[tex]\frac{18}{3}[/tex]

6

Nijah has 6 stickers left.

Answer:

18

Step-by-step explanation:

Find the part she gave to her sister

45 *2/5 = 18

The part remaining is

45 - 18 = 27

She gives 1/3 to Brett

27 * 1/3 = 9

She has 27 - 9 = 18

She has 18 remaining

[tex]t=\sqrt{\dfrac{ab-s}{r+ak}}\\\\t^2=\dfrac{ab-s}{r+ak}\\\\rt^2+akt^2=ab-s\\\\akt^2-ab=-rt^2-s\\\\a(kt^2-b)=-(rt^2+s)\\\\a=-\dfrac{rt^2+s}{kt^2-b}\\\\a=-\dfrac{rt^2+s}{-(b-kt^2)}\\\\a=\dfrac{rt^2+s}{b-kt^2}[/tex]

Answer:

29.53 ≤ x + 5 ≤ 56.15

Step-by-step explanation:

A $5 in-store coupon for every person who buys a flea control product which ranges between $29.53 to $56.15. This means that if you bought a flea control product you would be given an additional $5 that means that for buying a flea product, $5 is given to you. If you have $x, and you bought a flea product you would have x + 5. The inequality that represents this situation is given as:

29.53 ≤ x + 5 ≤ 56.15

Answer:

5z

Step-by-step explanation:

As product = multiplication =>

5 x z --> 5(z)

[tex]\text{Find the product of 5 and z}\\\\\text{The key term in this questions is product, and in math it translates to}\\\text{the answer when multiplled}\\\\\text{In this case, you would multiply them together to get your "product"}\\\\\text{Solve:}\\\\5\cdot z\\\\\boxed{5z}[/tex]

Answer:

56

Step-by-step explanation:

you have to find the LCM of 7 AND 8.

which is 56

Answer:

The answer is 56

Step-by-step explanation:

Answer:

3 Over 15

Step-by-step explanation:

i got 100.

Answer:

yes

Step-by-step explanation:

it is c,

Answer:

The answer is A

Step-by-step explanation:

This shows a mirroring effect over the vertical y axis.

Choices B and C are a translation (aka shifting)

Choice D is a reflection but over the horizontal x axis.

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

Answer:

[tex]\huge\boxed{d = 4 }[/tex]

Step-by-step explanation:

41 = 12d - 7

Adding 7 to both sides

41+7 = 12d

48 = 12 d

Dividing both sides by 12

4 = d

OR

d = 4

Answer:

[tex]\large \boxed{{d=4}}[/tex]

Step-by-step explanation:

[tex]41 =12d-7[/tex]

Add 7 on both sides.

[tex]41 +7=12d-7+7[/tex]

[tex]48=12d[/tex]

Divide both sides by 12.

[tex]\displaystyle \frac{48}{12} =\frac{12d}{12}[/tex]

[tex]4=d[/tex]

Answer:

white: 1/3, blue: 1/4, red: 5/12

Step-by-step explanation:

Take the amount of balls each color has and divide by 12.

White:

4/12 = 1/3

Blue:

3/12 = 1/4

Red:

5/12 (can't simplify)

Answer:

3/44 or 0.068

Step-by-step explanation:

(3/12 × 2/11 × 1/10)+(5/12 × 4/11 × 3/10)+(4/12 × 3/11 × 2/10)

=3/44

Answer:

The answer is "all the choices were wrong"

Step-by-step explanation:

Given value:

[tex]\bold{26x^3y 47z^5r^3}[/tex]

In the given question all the choices were wrong because it is not equivalent to given equation:

In choice A) [tex]( 26x^3y 47z^5r^3 )^2[/tex] in the value is whole squared, that's why it is wrong.

In choice B) [tex](26xy)^{12} (47zr)^{12}[/tex] when we open its value it will give different values, that's why it is wrong.

In option C and D( [tex]26^{12} x^{32} y^{12} 47^{12} z^{52} r^{32}[/tex] and [tex]26x^{32} y^{12}47z^{52} r^{32}[/tex]) both values will give different values.  

Answer:

it's C

Step-by-step explanation:

I just did it

Answer:

The answer is s^26/pq59

Step-by-step explanation:

Answer:

p^ -1 q ^ -59  s ^26

or without negative exponents

s^ 26 /(p q^ 59)

Step-by-step explanation:

When multiplying , we can add the exponents when the bases are the same

p^0 q ^ -60 r^-1 s^25  * p^-1 qrs

When there is no exponent written, there is an implied 1

p^ (0+-1) q^(-60+1) r ^( -1 +1) s ^ ( 25+1)

p^ -1 q ^ -59 r ^0 s ^26

r^0 = 1

p^ -1 q ^ -59  s ^26

If you need  the negative exponents written as positive

a^-b = 1/ a^b

s^ 26 /(p q^ 59)

Answer:

Step-by-step explanation:

The question is not properly written. Here is the correct question.

You are the owner of Decorama Flooring. Tod and Claudia have asked you to give an estimate for tiling four rooms of their house. The living room is 15 feet*23 feet, dinning room is 12ft*18ft, the kitchen is 9ft*11 ft and the study room is 10ft*12 ft how many square ft of tiles are required for each room. (multiply length by the width).

We must understand that a floor tile is rectangular in nature.

Area of a rectangle = Length * width

To get the amount of square feet required for each room, we must multiply the length and width of each of the rooms together as shown.

For the living room;

Length = 15 feet and Width = 23 feet

Amount of square feet of tiles needed for the living room = 15feet * 23 feet

= 345 ft²

For the dining room;

Length = 12 feet and Width = 18 feet

Amount of square feet of tiles needed for the dining room = 12feet * 18 feet

= 216 ft²

For the kitchen;

Length = 9 feet and Width = 11 feet

Amount of square feet of tiles needed for the kitchen = 11feet *9feet

= 99 ft²

For the study room;

Length = 10 feet and Width = 12 feet

Amount of square feet of tiles needed for the study room = 10feet * 12 feet

= 120 ft²

Answer:

24

Step-by-step explanation:

Answer

24!

Step-by-step explanation:

Person above me is correct :)

Answer:

3 kg

Step-by-step explanation:

given data

weights bag1 = 45 kg

weights bag2 = 63 kg

solution

we will take here first  HCF of 75 and 69

factor of 75 = 3 × 5 × 5

factor of 69 = 3 × 23

so here HCF of 75 and  69 = 3

so that here maximum weight required, to measure the weight of rice exact 3 times

so correct option is 3.  3 kg

Answer:

  4.  9 kg

Step-by-step explanation:

The greatest common factor of 45 kg and 63 kg is 9 kg.

  45 = 9×5

  63 = 9×7

A 9 kg weight could be used to weigh these amounts exactly.

_____

Comment on the problem statement

Appropriate formatting is helpful. It is difficult to tell that your answer choices are not 1.6, 2.35, 3.3, and 4.9. None of those makes any sense. With minimal formatting effort, you could list them as ...

1. 6 kg

2. 35 kg

3. 3 kg

4. 9 kg

Even better, the choices could be identified using letters and/or a separator other than a decimal point: A) 6 kg, B) 35 kg, and so on. The idea is to make it very clear what the numbers of the choices are. Less confusion is better.

Answer:

23

Step-by-step explanation:

6x + 11 + 7x + 143 = 180

13x + 154 = 180

13x = 26

x = 2

m<RPS = 6(2) + 11 = 23

Part (a)

BC = opposite side (furthest leg from the reference angle)

AB = adjacent side (closest leg from the reference angle)

AC = hypotenuse (always opposite the 90 degree angle)

=============================================

Part (b)

i. False. Angle B is 90 degrees as shown by the square angle marker.

ii. False. Side AB is opposite angle C. Note how "C" is part of "BC", so that means we cannot have BC be opposite C.

iii. True. Leg AB is the closer leg to angle A. We have "A" in "AB" to see this without having to draw the diagram. Refer to part (a) above.

iv. False. The longest side of any right triangle is always the hypotenuse. The longest side of any triangle is always opposite the largest angle.

==============================================

Part (c)

cos(theta) = adjacent/hypotenuse = AB/AC

tan(theta) = opposite/adjacent = BC/AB

Refer back to part (a) to determine the opposite,adjacent and hypotenuse side lengths.

==============================================

Part (d)

The reference angle has changed, so the opposite and adjacent sides swap. The hypotenuse remains the same regardless of what reference angle you pick.

sin(C) = opposite/hypotenuse = AB/AC

cos(C) = adjacent/hypotenuse = BC/AC

tan(C) = opposite/adjacent = AB/BC

Note the tangent ratio is the reciprocal of what we found back in part (c).

Answer & Step-by-step explanation:

(a)

The hypotenuse is on line CA (the hypotenuse is always opposite the 90° angle (marked by a little square))

The adjacent is on the line BA (adjacent is next to the given angle, but NOT the hypotenuse)

The opposite is on the line CB (this is opposite the given angle)

(b)

i.   false (b is a right angle)

ii.  false (the side opposite C is BA)

iii. true

iv. false (the side opposite B is the hypotenuse, and the hypotenuse is always the longest side in a triangle)

(c)

cosine ratio: [tex]cos=\frac{adjacent}{hypotenuse}[/tex]

tangent ratio: [tex]tan=\frac{opposite}{adjacent}[/tex]

The cosine and tangent ratios of the given angle:

[tex]cos0=\frac{AB}{CA} \\\\tan0=\frac{CB}{AB}[/tex]

(d)

Remember SOH-CAH-TOA:

Sine=Opposite/Hypotenuse

Cosine=Adjacent/Hypotenuse

Tangent=Opposite/Adjacent

Using the angle C, plug in the appropriate sides:

[tex]sinC=\frac{BA}{CA}\\\\ cosC=\frac{CB}{CA}\\\\ tanC=\frac{BA}{CB}[/tex]

:Done

When [tex]\theta[/tex] terminates in quadrant III, both [tex]\cos\theta[/tex] and [tex]\sin\theta[/tex] are negative, and

[tex]\sin^2\theta+\cos^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac{12}{13}[/tex]

When [tex]\varphi[/tex] terminates in quadrant II, [tex]\cos\varphi[/tex] is negative and [tex]\sin\varphi[/tex] is positive, so

[tex]1+\tan^2\varphi=\sec^2\varphi\implies\sec\varphi=-\dfrac{17}{15}[/tex]

which gives

[tex]\cos\varphi=\dfrac1{-\frac{17}{15}}=-\dfrac{15}{17}[/tex]

[tex]\tan\varphi=\dfrac{\sin\varphi}{\cos\varphi}=-\dfrac8{15}\implies\sin\varphi=\dfrac8{17}[/tex]

Now,

[tex]\sin(\theta+\varphi)=\sin\theta\cos\varphi+\cos\theta\sin\varphi=-\dfrac{21}{221}[/tex]