(X-y^2)(6x-y^2) find the product

Answer:

p ≥ 1,000,000,000

Step-by-step explanation:

since it says "at-least" that is implying that, that is the estimate and there is most likely more people and it is not exactly 1,000,000,000 so we need to use ≥ to show that it could be greater than or equal to 1,000,000,000.

Answer:

Step-by-step explanation:

2/3 - 1/2 ?=?

4/6 - 3/6 = 1/6 ft more

Answer:

D) The number that is 5 to the right of -6 on the number line

Hope this helps :)

Answer:

No, it is not a linear function, rather a rational function

Step-by-step explanation:

Because the term on the left-hand side contains both x and y, then neither variable varies directly with the other, hence, it's a rational function:

2yx=4

yx=2

y=2/x

Enter a problem...

Calculus Examples

Popular Problems Calculus Find the Domain and Range f(x)=5x-3

f

(

x

)

=

5

x

−

3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

x

|

x

∈

R

}

The range is the set of all valid

y

values. Use the graph to find the range.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

y

|

y

∈

R

}

Determine the domain and range.

Domain:

(

−

∞

,

∞

)

,

{

x

|

x

∈

R

}

Range:

(

−

∞

,

∞

)

,

{

y

|

y

∈

R

}

Answer:

we need 6 cups of cranberry juice for 12 gallons of punch

Step-by-step explanation:

We need to break up the given expression into two separate fractions so that when they are added together, we will get the original expression.

Note that the denominator is made up of two factors, [tex](2x - 1)[/tex] and [tex](x^2 + 1).[/tex] But note that the 2nd factor is a 2nd order polynomial so as a rule, the numerator of the fraction containing this factor must be an (n - 1)-order polynomial, where n is the order. With that in mind, we can write the general form of the partial fractions as follows:

[tex]\dfrac{x + 7}{(2x - 1)(x^2 + 1)} = \dfrac{Ax + B}{x^2 + 1} + \dfrac{C}{2x - 1}[/tex]

[tex]\:\:\:\:=\dfrac{2Ax^2 + Bx - Ax - B + Cx^2 + C}{(2x - 1)(x^2 + 1)}[/tex]

Here, we combined the two fractions to form the equation above. Next, we compare the numerators on either side. Note that we satisfy the equality if we impose the following conditions:

[tex]2A + C = 0\:\:\:\:\:\:\:\:\:\:\:\:\:\:(1)[/tex]

[tex]2B - \:A = 1\:\:\:\:\:\:\:\:\:\:\:\:\:\:(2)[/tex]

[tex]-B + C = 7\:\:\:\:\:\:\:\:\:\:\:\:\:\:(3)[/tex]

To find the values of the constants A, B and C, we need to solve this system of equations. We start by multiplying Eqn(3) by 2 and then adding it to Eqn(2) to get

[tex]-A + 2C = 15\:\:\:\:\:\:\:\:\:\:\:\:\:\:(4)[/tex]

Then, multiply Eqn(1) by -2 to get

[tex]-4A - 2C = 0\:\:\:\:\:\:\:\:\:\:\:\:\:\:(5)[/tex]

Add Eqn(4) to Eqn(5) and we will get

[tex]-5A = 15 \Rightarrow A = -3[/tex]

Now that we know the value of A, we can use this in Eqn(2) to get

[tex]2B - (-3) = 1 \Rightarrow B = -1[/tex]

Next, to solve for C, we use the value of A in Eqn(1) to get

[tex]2(-3) + C = 0 \Rightarrow C = 6[/tex]

Therefore, the given expression can be written as

[tex]\dfrac{x + 7}{(2x - 1)(x^2 + 1)} = \dfrac{6}{2x - 1} + \left(\dfrac{-3x - 1}{x^2 + 1}\right)[/tex]

As a check, let's combine the two fractions together:

[tex]\dfrac{x + 7}{(2x - 1)(x^2 + 1)} = \dfrac{6}{2x - 1} + \left(\dfrac{-3x - 1}{x^2 + 1}\right)[/tex]

[tex]= \dfrac{6x^2 + 6 - 6x^2 - 2x + 3x + 1}{(2x - 1)(x^2 + 1)}[/tex]

[tex]= \dfrac{x + 7}{(2x - 1)(x^2 + 1)}[/tex]

As expected, we got the original expression.

Answer:

58%

Step-by-step explanation:

Step-by-step explanation:

figure B is a scaled copy of figure B

by scale factor : 1/2

Answer:

6 dollars and 4 cents

Step-by-step explanation:

Answer:

ayo i think is ufo trying to communicate hey alien we come in peace

Step-by-step explanation:

[tex]\cos \theta(\tan \theta + \cot \theta)\\\\=\cos \theta \tan \theta + \cos \theta \cot \theta \\\\=\cos \theta \left (\dfrac{\sin \theta}{\cos \theta} \right)+ \cos \theta \left(\dfrac{\cos \theta}{\sin \theta} \right)\\\\\\=\sin \theta + \dfrac{\cos^2 \theta}{\sin \theta}\\\\=\dfrac{\sin^2 \theta + \cos^2 \theta}{\sin \theta}\\\\=\dfrac 1{\sin \theta}\\\\=\csc \theta[/tex]

Answer:

2

Step-by-step explanation:

either the four friends give you the money first then you give it to the three friends That is one Or youcan ask your parental figure to own you three dallors then you will have more money at the End.

Answer:

70.2

Step-by-step explanation:

28.08 / 0.4 = 70.2

The weight of the boy in the robot costume is 351/8 lb or 43 7/8 lb.

To find the weight of the boy, we need to subtract the weight of the costume from the total weight of the boy in the costume.

Total weight of boy and costume = 50 7/8 lb

Weight of costume = 3 1/2 lb

To find the weight of the boy, we can subtract the weight of the costume from the total weight:

Weight of boy = Total weight - Weight of costume

Convert both the total weight and the weight of the costume to improper fractions:

Total weight = 50 + 7/8 = 400/8 + 7/8 = 407/8 lb

Weight of costume = 3 + 1/2 = 6/2 + 1/2 = 7/2 lb

Now, subtract:

Weight of boy = (407/8) lb - (7/2) lb

To perform subtraction, we need to have a common denominator, which is 8 in this case:

Weight of boy = (407/8) lb - (56/8) lb

Now, subtract the fractions:

Weight of boy = (407 - 56)/8 lb

Weight of boy = 351/8 lb

To learn more about fraction click on,

https://brainly.com/question/15898930

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Step-by-step explanation:

Given that :

Total length of the track = 630 m

Distance covered by Sweeti by walking = 2/7 of the running track

2/7 of 630 m

⇛ (2/7)×630

⇛ (2×630)/7

⇛ 1260/7

⇛ 180 m

Distance covered by walking = 180 m

Remaining distance =

Total distance - Distance covered by walking

⇛630 m - 180 m

⇛ 450 m

The total distance covered by running by Sweeti is 450 m.

Read more:

Similar Question

You can burn about 450 calories if you run 5 miles. How many miles will you need to run to burn 630 calories? Justify your reasoning.....

https://brainly.com/question/20123561?referrer

Answer:

Step-by-step explanation:

a) The height of the springboard above the water should be h(0) : Read, the height at t = 0

h(0) = -5(0) + 10(0) + 3

h(0) = 0 + 0 + 3

h(0) = 3

a) 3 meters

b)  The time it takes the diver to hit water should be, the positive 0 solution for t.  Remember, in a quadratic equation,  there are two values for t where a parabola crosses the horizontal axis, which in this case would be t.  Just by looking at the function, h(t) = -5t2 + 10t + 3 , one should be able to see that it cannot be factored easily, so it requires the Quadratic Formula to find the zeros ; x = -b ±√(b2-4ac)  / 2a

Substitute t for x, and use the coefficients for a, b, c:

t  =  (-10 ± √((102 - 4(-5)(3)))/2(-5)

t = (-10 ±√(100 + 60))/-10

t = (-10 ±√160)/-10) ; Now factor the 160 to simplify:

t = (-10 ±√(10*16))/-10

t = (-10 ±4√10)/-10 ; Factor out leading coefficient of -2 from the numerator:

t = -2(5 ± 2√10)/-10

t = (5 ± 2√10)/5

Using a calculator to find the zeros, and disregarding the negative zero (because t starts at 0):

t ≈ 2.265

b) approx. 2.265 seconds for diver to hit water.

c) To find this, set the function equal to 3 to find what other value for t would be equal to 3 (we know one is 0).

-5tt + 10t + 3 = 3

-5t2 + 10t = 0 ; factor out t

t(-5t + 10) = 0

We know t = 0:

We also know that -5t + 10 = 0

-5t = -10

t = 2

c) 2 seconds. This is the time that diver would equal height of t=0 which is where he started, and where he equals the height of the springboard.

d and e) The peak of the dive (parabola), is determined using the formula h = -b/2a (Derived from the Quadratic Formula) to find the y value (in this case, the h value, answering e) and then using that result in the function to find the x value (in this case, the t value answering d) of the point where the parabola (dive path) reaches a maximum(height), or minimum(in upward opening parabolas).

h = -10/2(-5)

h = -10/-10

h = 1

h(1) = -5(1)2 + 10(1) + 3

h(1) = -5 + 10 + 3

h(1) = 8

d) At t = 1 second, diver will have reached peak of dive.

e) At t = 1 second, diver will have reached a maximum height of 8 meters.

Answer:

[tex]\huge\boxed{C)\ -\dfrac{1}{5}}[/tex]

Step-by-step explanation:

The reciprocal of 5: [tex]\dfrac{1}{5}[/tex]

The negative reciprocal of 5: [tex]-\dfrac{1}{5}[/tex]

Answer:

82.5 miles in 1 1/2 hours

Step-by-step explanation:

Using the information the question gives us we can find the appropriate answer to this question by dividing the miles per hour by two, and then add that number to the additional miles per hour.

55 miles = one hour

2 hours = 110 miles

1 1/2 hours = 55 ÷ 2 = 27.5

55 + 27.5 = 82.5 miles

82.5 miles

Hope this helps

Answer:

8/64 = 0.125 = 12.5%

Step-by-step explanation:

8/64 = 0.125 = 12.5%

Answer:

Part A: f(x) = 1.50x/g(x) = 0.01(3)^x-1

Part B: Option A:  $9 

Part C: Option B:  $1,771.47

Part D: The eighth bushel picked is when the exponential function exceeds the linear function.

Step-by-step explanation:

Part A: Write a function to model each option.

Option A:  f(x) = 1.50x, where x is the number of bushels of apples picked

Option B: g(x) = 0.01(3)^x-1, where x is the number of bushels of apples picked.

--------------------------------------------------------------------------------------------------------------

Part B: If Rachel picks six bushels of apples, which option should she choose?  

Option A:  $9    Option B:  $2.43   

Option A is better since what the number is would be higher.

1.50x6 = 9. If I were to do the same for option b, option a would end up higher.

--------------------------------------------------------------------------------------------------------------

Part C: If Rachel picks twelve bushels of apples, which option should she choose?  

Option A:  $18 Option B:  $1,771.47

After calculating both of them by multiplying by 12 for each, option B ends up to be much better.

--------------------------------------------------------------------------------------------------------------

Part D: How many bushels of apples does Lucy pick to make option B better for her than option A?

The eighth bushel picked is when the exponential function exceeds the linear function.

Answer:

2, -6

Step-by-step explanation:

x^2 + 4x - 12

A = 1

B = 4

C = -12

i used the "X" method to solve for the solutions. i think it's easier than using the quadratic formula but it doesn't always work

for the "X" method you have to multiply your A value and your C value together so 1 x (-12) = -12. that is going to be the top part of the X

the bottom part of the x will be your B value which is 4

we have to find multiples of -12 that will also add to 4

so -2 and 6 multiply to -12 but also add to 4 so we know these numbers will work

i added added two drawings to show how i found the solutions using the "X" method and the quadratic formula

Answer:

x2 the left side and x3 the right side of the equation

Answer:

X = -2

First you cross multiply, and then you expand to get 15x+6

after that its basic algebra with adding/subtracting from each side, simplifying, and then divide both sides by -13.

Answer:

if its me then i will bye the store. but the answer is 50%

Step-by-step explanation:

Answer:

no its not since some dots are above each other and fail the vertical line test

Hope This Helps!!!

Answer:

no the x value repeat

Step-by-step explanation:

Answer:

x = 4, -6

Step-by-step explanation:

x = 4, -6

Answer:

8.7

Step-by-step explanation:

8.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.7

Answer:

y = 8x + 12

Step-by-step explanation:

y = (2x + 3)4

Distribute the 4 to the 2x  and 3

y = 8x + 12

^ Expanded form

if there is any doubt leave a comment

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$2000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ t=years\dotfill &4 \end{cases} \\\\\\ A=2000e^{0.08\cdot 4}\implies A=2000e^{0.32}\implies \boxed{A\approx 2754.26}[/tex]