X and Y are in partnership with capital contributions of $50000 and $30000 respectively.
The partnership agreement provides that profits are to be shared in proportion to capital
contributions and each partner is entitled to 10% interest on capital.
Profit for the year was $37000.
What was the total amount credited to Y’s current account at the end of the year?
A $10875 B $13875 C $18125 D $23125

Answers

Answer 1

Answer:

The correct answer is B. $13,875.

Step-by-step explanation:

Since X and Y are in partnership with capital contributions of $ 50000 and $ 30000 respectively, and the partnership agreement provides that profits are to be shared in proportion to capital contributions and each partner is entitled to 10% interest on capital, and profit for the year was $ 37000, to determine what was the total amount credited to Y’s current account at the end of the year the following calculation must be performed:

50,000 + 30,000 = 80,000

80,000 = 100

30,000 = X

30,000 x 100 / 80,000 = X

37.5 = X

37,000 x 0.375 = X

13.875 = X


Related Questions

The table below shows the results from a study that compared speed (in miles per hour) and average fuel economy (in miler per gallon) for cars. Find a quadratic model for the data.

0.008
y=13.472x
2
+0.746x−0.008

y
=
25.836
x
+
0.049
y=25.836x+0.049

y
=

.
008
x
2
+
0.746
x
+
13.472
y=−.008x
2
+0.746x+13.472

y
=
0.049
x
+
25.836
y=0.049x+25.836

Answers

Note that the  quadratic model for the data is  y = -0.008x² + 0.75x + 13.47.

How is this so  ?

Here are the steps on how to  find a quadratic model for the data.

Make a   scatter plot of the data. The points should form an inverted U-shape. This suggests a quadratic model.Use the quadratic regression feature on your graphing calculator to find an equation of the model.

Here is the output of the quadratic regression feature on my graphing calculator

y = -0.008x² + 0.75x + 13.47.

where  -

x is the speed in miles per hour

y is the fuel economy in miles per gallon.

Learn more about Quadratic equation at:

https://brainly.com/question/1214333

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find the HCF of the following number by listing the set of factors class 6 questions is 27 and 36​

Answers

Answer:

The factors of 27 are 1,3,9,27.

The factors of 36 are 1,2,3,4,6,9,12,36.

HCF=1,3,9

Given that the point (-2,8) is on the graph of an equation that is symmetric with respect to the x-axis, what other point is on the graph?

(Type an ordered pair)

Answers

(-2, -8) Imagine the point (-2,8) being reflected in a mirror, where the x axis is the mirror. Since the point is 8 above the x axis, the reflected point will be 8 below.

solve
f(x)=4x5−8x4+8x2−4x

Answers

Given:

The function is:

[tex]f(x)=4x^5-8x^4+8x^2-4x[/tex]

To find:

The roots of the given equation.

Solution:

We have,

[tex]f(x)=4x^5-8x^4+8x^2-4x[/tex]

For roots, [tex]f(x)=0[/tex].

[tex]4x^5-8x^4+8x^2-4x=0[/tex]

[tex]4x(x^4-2x^3+2x-1)=0[/tex]

[tex]4x((x^4-1)+(-2x^3+2x))=0[/tex]

[tex]4x((x^2+1)(x^2-1)-2x(x^2-1))=0[/tex]

On further simplification, we get

[tex]4x(x^2+1-2x)(x^2-1)=0[/tex]

[tex]4x(x-1)^2(x+1)(x-1)=0[/tex]

[tex]4x(x+1)(x-1)^3=0[/tex]

Using zero product property, we get

[tex]4x=0[/tex]

[tex]x=0[/tex]

Similarly,

[tex]x+1=0[/tex]

[tex]x=-1[/tex]

And,

[tex](x-1)^3=0[/tex]

[tex]x=1[/tex]

Therefore, the zeroes of the given function are [tex]-1,0,1[/tex] and the factor form of the given function is [tex]f(x)=4x(x+1)(x-1)^3[/tex].

if the hypotenuse of an isosceles right triangle has a length of 5 centimeters what is the length of one of the legs

Answers

Answer:

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

Step-by-step explanation:

[tex]a^{2} +b^{2} = 5 ^{2}[/tex]

a = b

[tex]2a^{2} = 5 ^{2}[/tex]

[tex]2a^{2} = 25\\[/tex]

[tex]a^{2} = \frac{25}{5}[/tex]

a = [tex]\frac{5}{\sqrt{5} }[/tex]

must rationalize...

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

I need help solving this

Answers

Answer:

E. 248

Step-by-step explanation:

1 to 500 in set A, 250 to 750 in set B

500 - 250 = 250

100 and 200 are divisible by 100.

250 - 2 = 248

Based on the graph of the trigonometric function,
what is the period?

Answers

Answer:

[tex]\displaystyle 4[/tex]

Explanation:

[tex]\displaystyle y = 3sin\:(\frac{\pi}{2}x + \frac{\pi}{2}) \\ y = 3cos\:\frac{\pi}{2}x[/tex]

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{4} \hookrightarrow \frac{2}{\frac{\pi}{2}}\pi[/tex]

You will need the above information to help you interpret the graph. So, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-5, 0],[/tex] from there to [tex]\displaystyle [-1, 0],[/tex] they are obviously [tex]\displaystyle 4\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle 4.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex] in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

find the 10 degree value can u help me on it ​

Answers

Solution:-10

As <AGQ and <EQG are corresponding interior angles

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}[/tex]

<AGQ=<PQR=60°<BHF=<PRQ=75°

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}[/tex]

According to angle sum property

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+<PQR=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}[/tex]

f(x) = x2 – 12x – 29
f(3) = (x+ ?)+ ?

Answers

Answer:

-6 and - 65

Step-by-step explanation:

X-12x-29, by completing the square we get (x-6)^2-65

Helpppp Please! Please!

Answers

∠DCA=∠BCA
∠B=∠D
CA=AC
△DCA≌△BCA (AAS)

NO=NQ
OP=QP
NP=PN
△NOP≌△NQP (SSS)

∠FOW=∠KIB
∠OFW=∠IKB
FW=KB
△FOW≌△KIB (AAS)

Hope my answer helped u :)

Is student is reading a book about 370 words per minute convert this rate to words per hour

Answers

answer:
22,200 words per hour
step-by-step explanation:
60 minutes per hour
370 words per minute
370(60)
22,200

Answer: 22,200 words per hour.

Step-by-step explanation:

You can set up a proportion for this: 370 words/per 1 min= x words/ per 60 mins. Cross multiply and you get 22,200=1x which basically equals to 22,200 words per hour or 60 mins.

Simplify for me please

Answers

6^21

it would equal about 2.19^10 just as the original equation

hope this helps:))

I just need the numbers can anyone help me with this ??

Answers

Step-by-step explanation:

Hello!

In order to graph this, a point would have to go through (-6, 1). Then, since it says it needs a slope of 5 (or, to make things a bit easer, we could see it as 5/1) we'd need the next point to be 5 up and 1 across.

One possible solution:

(-6, 1) -> (-5, 6)

One possible solution (-6,1) —-> (-5,6)

PLEASE HELP! URGENT. the law of cosines is a2+b2-2abcosC=c2. Find the value of 2abccosC.

Answers

Answer:

D

Step-by-step explanation:

2ab*cos(C)=a^2+b^2-c^2

2ab*cos(C)=5^2+4^2-2^2=25+12=37

Answer:

The answer is 37

Step-by-step explanation:

The curve y=(k-6)x^2-8x+k cuts the x-axis at two points and has a minimum point. Find the range of values of k.

Answers

Answer:

Hello,

answer:  -2 < k < 8

Step-by-step explanation:

As there are 2 roots: Δ>0

As there is a mininum, k-6 <0 ==> k<6,

minimum :y'=0 ==> (k-6)*2x-8=0 ==> x=4/(k-6)

[tex]\Delta=8^2-4*k*(k-6)\\=64-4k^2+24k\\=-4(k^2-6k+9)+36+64\\=100-4(k-3)^2\\=4(8-k)(k+2)\\\\\Delta\ is\ positive\ for\ -2 < k < 8[/tex]

The solution of this equation has an error. Which of the following steps has an error?

Step 1: -2x + 8 - 3x = 7
Step2:–5x+8=7
Step3:-5x = 15
Step4:
x = -3

O Step 2

O Step 1

O Step 3

Answers

3rd step

Solution:-

[tex]\\ \sf\longmapsto -2x+8-3x=7[/tex]

[tex]\\ \sf\longmapsto -2x-3x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x=7-8[/tex]

[tex]\\ \sf\longmapsto -5x=-1[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-1}{-5}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{1}{5}[/tex]

Chocolate beans are packed in 250 g and 750 g packages. The number of 250 g packages and 750 g packages are in the ratio 1 : 2. If two of the 750 g packages are replaced into 250 g packages, then the ratio becomes 5 : 3. Find

a) the original number of 250 g packages,

b) the total mass of the chocolate beans.

Answers

Answer:

a) 4 packages

b) 7000 g or 7 kg

Step-by-step explanation:

x is the number of 250g packages and y is the number of 750g packages.

2x = y

3(x + 2 x (750 : 250)) = 5(y - 2)

3(x + 6) = 5(y - 2)

3(x + 6) = 5(2x - 2)

3(x + 6) = 5(2(x - 1))

3(x + 6) = 5 * 2 * (x - 1)

3(x + 6) = 10(x - 1)

3x + 18 = 10x - 10

(3x + 18) + 10 = (10x - 10) + 10

3x + 28 = 10x

28 = 10x - 3x

28 = 7x

x = 28/7

x = 4

y = 2 * 4 = 8

(250 * 4) + (750 * 8) = 7000 g

A boy is flying a kite from the terrace of his house. The kite is 175 m above the terrace. If the terrace is 80 m from the ground floor, findthe distance between the kite and the basement which is 8 m below the ground level.

Answers

175 m above the terrace + 80 m from terrace to ground + 8m from ground to basement:

175 + 80 + 8 = 263 meters

solve for x *show work*​

Answers

Answer:

x = 14

Step-by-step explanation:

The sum of the interior angles of a six sided figure is 720

10x + 8x-16+12x-8 +7x+2 +9x+4 +6x+10 = 720

Combine like terms

52x-8=720

Add 8 to each side

52x-8+8 = 720+8

52x = 728

Divide by 52

52x/52 = 728/52

x = 14

Step-by-step explanation:

here's the answer for thy question

please answer this!!​

Answers

triangle is always 180

both sides are equal so both sides are 51
51+51=102

180-102=78

can i get some help please

Answers

The sum of the interior angles in a triangle is 180 degrees.

72 + 35 + <1 = 180

107 + <1 = 180

<1 = 73 degrees

Hope this helps!

Answer:

<1 = 73

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

72+ 35+ <1 = 180

Combine like terms

107 + <1 =180

Subtract 107 from each side

<1 = 180-107

<1 = 73

dilations geometry!

Answers

Answer:

A' (0,20)

B' (30,-20)

C' (-10,-40)

Answered by GAUTHMATH

Write these sums as decimals:

2/100 + 3/1,000 =

1/10 + 4/10,000 =

Answers

Answer:

1 ) 0.023

2 ) 0.1004

Step-by-step explanation:

2 / 100 + 3 / 1000

= 0.02 + 0.003

= 0.020 + 0.003

= 0.023

1 / 10 + 4 / 10,000

= 0.1 + 0.0004

= 0.1000 + 0.0004

= 0.1004

A rectangular drawing is enlarged by 30%. The original dimensions of this drawing are 16cm x 24cm.
Determine the scale factor, as a fraction that represents this enlargement. What are the new, enlarged
dimensions?

Answers

Answer:

Step-by-step explanation: Scale [tex]\frac{130}{100} = \frac{13}{10}[/tex]

New dimensions [tex]16 * 1.3 --- 24*1.3 =20.8 cm * 31.2 cm[/tex]

Manish writes the functions g(x) = ^3 sqrt - x - 72 and h(x) = -(x+72)^3

Which pair of expressions could Manish use to show that g(x) and h(x) are inverse functions?

Answers

Here we want to find the expressions we need to use to see if the functions g(x) and h(x) are inverses of each other.

The correct option is the last one, counting from the top.

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Two functions f(x) and g(x) are inverses if:

f( g(x) ) = x

g( f(x) ) = x

In this case, we have the functions:

g(x) = ∛(-x) - 72

h(x) =  -(x + 72)^3

Then the expressions we need to check are:

g( h(x) ) = ∛(-h(x)) - 72 = ∛(+(x + 72)^3) - 72 = (x + 72) - 72 = x

h( g(x) ) = -(g(x) + 72)^3 = -(∛(-x) - 72 + 72)^3 = -(∛(-x) )^3 = x

So we found that the two expressions needed are:

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Then the correct option is the last one, counting from the top.

If you want to learn more, you can read:

https://brainly.com/question/10300045

Answer:

GUYS ITS C THAT IS THE ANSWER

Which equation represents a parabola that has a focus of (0,0) and a directix of y = 2?​

Answers

Answer: D

Step-by-step explanation:

[tex]a=0,\ b=0,\ k=2\\equation\ of\ the\ parabola:\\\\y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\\\y=-\dfrac{x^2}{4}+1 \\\\x^2=-4(y-1)\\\\Answer\ D[/tex]

Help please, I need with the question​

Answers

Answer: [tex]\frac{4}{3}[/tex]

Step-by-step explanation:

tangent of ∠PLM = [tex]\frac{opposite}{adjacent} =\frac{4}{3}[/tex]

Answer:

PLM=4/3

Step-by-step explanation:

Please help!!!.......thx

Answers

Step-by-step explanation:

sin and tan are the only ones with p positive valued

If f(1) = 4 and f(n) = f(n − 1) + 5 then find the value of f(5).

Answers

Answer:

25

Step-by-step explanation:

f(5)=5(5-1)+5

f(5)=5(4)+5

f(5)=20+5

f(5)=25

Answer:

f(5) = 24

Step-by-step explanation:

f(1) = 4

f(n) = f(n − 1) + 5

Let n = 2

f(2) = f(2 − 1) + 5 = 4+5 = 9

Let n = 3

f(3) = f(3 − 1) + 5 = f(2)+5 = 9+5 = 14

Let n = 4

f(4) = f(4 − 1) + 5 = f(3)+5 = 14+5 = 19

Let n = 5

f(5) = f(5 − 1) + 5 = f(4)+5 = 19+5 = 24

if the cost of 2:dozen copies is Rs 720 , find the cost of 72 copies .

Answers

Answer:

Rs 2160

Step-by-step explanation:

1 dozen = 12 copies

2 dozen = 24 copies ( 2*12)

72÷12 = 6 dozen

72 copies = 6 dozen

1 dozen = Rs 720÷2

1 dozen Rs 360

6 dozen = 360*6

6 dozen = 72 copies = Rs 2160

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