x = 1/4. y = 2/3. z = 4*1/5

Work out the value of X x y x z

Give your answer as a fraction in its simplest form.

Answer:true, false, false, true

Step-by-step explanation:

Economies of scale occur when average cost declines with an increase in output. This occurs up to output level Q1.

Diseconomies of scale occur when average cost increases with an increase in output. This begins at output level Q3.

The phenomenon known as economies of scale occurs when the size or magnitude of the production generated by a business increases while the average cost per unit of output decreases.

The Long Run Average Cost Curve demonstrates how a firm's average expenses change over time. The shift from point A to point B illustrates how the cost per unit decreases as the curve slopes down. Because of economies of scale, the average cost grows less proportionally to output over the downward sloping region of the curve.

Minimum efficient scale is the level of output where economies of scale have been fully exploited.

A competitive firm produces at the minimum point of ATC in the long run and thus achieves productive efficiency.

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omgggg thats what she said

Answer:

I was willing to pay $20 more for the toy than I actually paid.

Step-by-step explanation:

Let us take the maximum bid be y

So,

(y × 60) ÷ 100 = 30

60y/100 = 30

60y/100 × 100 = 30 × 100

60y = 3000

60y/60 = 3000/60

y = 50

60% of $50 is $30

So,

50 - 30 = 20

Thus, I was willing to pay $20 more for the toy than I actually paid.

Answer: We can set up the equation 21 stickers/pack + 24 stickers/pack + x stickers/pack = 15 stickers.

We can solve this equation to find that x, the number of stickers in each pack, is equal to 6 stickers/pack. Answer: 6

Answer: 20

Step-by-step explanation:

24 + 21 = 45

45 + 15 = 60

60 / 3 = 20

The value of p is 0.16. So the option b is correct.

A local entrepreneur takes a random sample of 100 people.

Of the urban participants, 22 buy a real tree.

Of the rural participants, 28 buy a real tree.

Let p1 = the proportion of all people who live in rural communities and buy a real Christmas tree.

Let p2 = the proportion of all people who live in urban communities and buy a real Christmas tree.

We have to find the p-value

p1 = X1/N1

p1 = 28/100

p1 = 0.28

p2 = X2/N2

p2 = 22/100

p2 = 0.22

p = (X1 + X2)/(N1 + N2)

p = (28+22)/(100+100)

p = 0.25

Below are the null and alternative Hypothesis,

Null Hypothesis, H0: p1 = p2

Alternate Hypothesis, Ha: p1 > p2

Test statistic

z = (p1 - p2)/√(p*(1-p)*(1/N1 + 1/N2))

z = (0.28-0.22)/√(0.25*(1-0.25)*(1/100 + 1/100))

z = 0.9798

P-value Approach

P-value = 0.16

Hence, the option A is correct. 0.16 is the p-value.

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Answer:

$8 per person

Step-by-step explanation:

32 divided by 4 is 8

32 : 4 = 8 : 1

(x-2)(x²+9) is set of factors corresponds to a third-degree polynomial with rational coefficients.

What is polynomial?

In arithmetic, a polynomial is an expression consisting of indeterminates and coefficients, that involves solely the operations of addition, subtraction, multiplication, and positive-integer powers of variables.

Main body:

as the polynomial with rational coefficients that has zeros x=2 and x=3i

(x-2) and (x-3i) are factors of third-degree polynomial.

so ,

⇒(x-2)(x-3i)

solving (x-3i)

x = 3i

squaring both sides,

x² = -9

so , (x²+9) is a factor.

hence , (x-2)(x²+9) is set of factors corresponds to a third-degree polynomial with rational coefficients.

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The probability that exactly four complaints will be received during the next eight hours is 15.41%.

A discrete probability distribution called the Poisson distribution provides the likelihood that an event will occur a specific number of times over the course of a given period of time or location. The formula for this distribution is given by [tex]P(X=x)=\frac{e^{-\mu}\times \mu ^x}{x!}[/tex] where x is the number of successes, μ is the mean, and e is Euler's number.

Given n = 8 hours then, μ = 0.7n = 0.7×8 = 5.6.

Then, the probability that exactly four complaints are received is,

[tex]\begin{aligned}P(X=4)&=\frac{e^{-5.6}\times5.6^4}{4!}\\&=0.1541\end{aligned}[/tex]

The required answer is 15.41%.

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With all this information, and reading our question carefully, we can decipher the following:

9(n-3) = 3 + (9n + 3n)

9n - 27 = 3 + (9n +3n) (Step 1. Distributive Property)

9n - 27 = 3 + 12n       (Step 2. Combine like terms; 9n + 3n = 12n)

-9n                  -9n    (Step 3. Subtract 9n from both sides to isolate the variable)

______________

  -27 = 3 + 3n            

     -3      -3               (Step 4. Subtract 3 from both sides)

________________

-30 =       3n                        

 -----         ----

  3            3              (Step 5. Divide 3 from both sides)

________________

 -10 = n

Therefore, n = -10

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stem                            leaf

0                               7, 7, 8, 8

1                                   3 , 3

2                                   5, 2

What is stem and leaf plot ?

A stem and leaf plot, also known as a stem and leaf diagram, arranges data in a way that makes it simple to see how often certain sorts of values occur. It is a graph that displays ordered numerical data. A stem and a leaf are divided into each piece of data.

A stem and leaf plot is shown as a customized table with the first or final digit of each data value divided into a stem and the remaining digit in a leaf. The stem and leaf plot key is the symbol " | " that is used to display stem and leaf values.

For instance, the stem and leaf plot key is used to represent 46 as 4 on the stem and 6 on the leaf.

in 2|5 , 2 is the stem side and 5 is the leaf side

in 0|7 , 0 is the stem side and 7 is the leaf side

in 1|3 , 1 is the stem side and 3 is the leaf side

in 0|8 , 0 is the stem side and 8 is the leaf side

in 2|2 , 2 is the stem side and 2 is the leaf side

in 0|7 , 0 is the stem side and 7 is the leaf side

in 1|3 , 1 is the stem side and 3 is the leaf side

in 0|8 , 0 is the stem side and 8 is the leaf side

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a) The amounts that the team needs to sell is given as follows:

b) The advantage and disadvantage is given as follows:

The amounts needed are found applying the proportion, considering the costs and the number of candles.

A package of 5 candles for $18, hence the number of candles needed to earn $1404, in packages, is given as follows:

5 candles - $18

n candles - $1404

Applying cross multiplication, we have that:

18n = 5 x 1404

n = 5 x 1404/18

n = 390 candles.

With a single candle, the number of candles is calculated as follows:

1404/4 = 351 candles.

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A true average strain in a way that converys information about precision and reliability (24.33, 27.67)

From given information we have:

the sample size n = 20

the mean failure strain x(bar) = 26.0

the standard deviation s = 3.4

Assuming a normal distribution for failure strain, we need to estimate true average strain in a way that converys information about precision and reliability.

A 95% confidence interval is necessary; other confidence intervals can be calculated in a similar way.

c = 0.95 or 95%

In the table with the critical values for t distributions in the appendix, locate the row beginning with degrees of freedom.

Here, the degree of freedom :

df = 20 - 1

df = 19

and  α = (1-c)/2

          = 0.025

To find the t-value:

t_(α/2) = 2.145

Therefore, the error margin is:

E = t_(α/2) × s/√n​

E = 2.145× 3.4/√19

E ≈ 1.67

And the confidence interval would be,

(x{bar} - E, x{bar} + E) = (24.33, 27.67)

Therefore, the confidence interval is: (24.33, 27.67)

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c is the answer. jdjsisiao

Answer:

There is 1/32 pound food for each fish

Step-by-step explanation:

24 fish = 3/4 pound food

1 fish = (3/4)/24 pound food = 1/32 pound food

(Problem solved by using unitary method)

Ф {0, [3√3/2(3√3-π)]}

The poster above has good diagrams ; so , I will just go through the calculations .

The region of integration is with in the circle x ^2+y^2=2y but outside the circle   x^2+y^2=1.

I would convert to polar . With polar , we have  x^2+y^2=r^2 ,x=rcosФ and        y=rsinФ
We thus have the first circle becomes x^2+y^2=2y ⇒r^2=2rsinФ Divide through by r,  and you get r=2sinФ(1).  
This is the upper circle in the previous posters diagrams .

The other equation of a circle becomes :
x^2 + y^2 =  1  ⇒ r^2 = 1 ⇒ r =  1   (2)      
These two curves intersect at :
r= 2sinФ =1 ⇒     sinФ=1/2  ⇒Ф= [tex]\alpha[/tex]/6 or 5[tex]\pi[/tex]/6    
From the previous poster's diagrams , we can see that there is as much mass on either side of the positive. y axis or
Ф=[tex]\pi[/tex]/2 axis in polar ; so , the X  coordinate of the center of mass is zero  
X=0 We can also see from his diagrams that the mass and moment of mass is symmetrical about the Ф=[tex]\pi[/tex]/2
we only need to integrate from Ф=[tex]\pi[/tex]/6 to Ф=[tex]\pi[/tex]/2  ( the answers from to are the same and double )
The differential of area in polar coordinates is
d A=rdrdФ  They say the area mass density is inversely proportional to the distance from the origin .

This can be written as : p=k/r. We can thus say the differential of mass is
d M=PDA=

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Answer: the number is -16

Step-by-step explanation: if you add 17 to -49, you will get -32. you do this because it is 17 less than NOT more than. that would be called inverse operations. then, you divide that number by 2 to get -16. again, you use inverse operations because you are going backwards to try and find the number.

Answer: -16

Step-by-step explanation: So, to solve, we should write an equation. It should look like this:

2x - 17 = -49

So, using inverse operations, we would add 17 to - 49, which is -32, then divide that by 2, which would be -16. I hope this helped!

P.S. our new equation would look like 2(16) - 17 = -49

32-17 = 49

32 + -17 = 49

49 = 49

It checks out.

Answer:

the answer would be e because you can't determine the side length

Answer: (B)

Step-by-step explanation:

Step 1: Find minimum values of the third side.

53-17 = 36

Step 2: Find maximum values of the third side.

17+53 = 70

Step 3: Find equation

36 < x < 70

The required answer is the domain is time (t) and the range is a distance (d) i.e. Option 2.

What are domain and range?

The value range that can be plugged into a function is known as its domain. In a function like f, this set represents the x values f(x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.

From the given question, and the above definition of domain and range,

the time (t) acts as an x-values or input value and the distance (d) acts as a y-value or output value

Hence, the domain is time (t) and the range is a distance (d) i.e. Option 2.

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The correct option that describes the vertical asymptote is; B: There is a vertical asymptote at x = 4 because Limit of g (x) as x approaches 4 minus = infinity and limit of g (x) as x approaches 4 plus = infinity

A vertical asymptote of a graph is defined as a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a.

A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;

In a graph, these vertical asymptotes are given by dashed vertical lines.

An example is a value of x for which the denominator of the function is 0, and the function approaches infinity for these values of x.

We are given the function;

g(x) = 2(x + 4)²/(x² - 16)

Simplifying the denominator gives;

(x² - 16) = (x + 4)(x - 4)

Thus, our function is;

g(x) = 2(x + 4)²/[(x + 4)(x - 4)]

(x + 4 ) will cancel out to give;

g(x) = 2(x + 4)/(x - 4)

Vertical asymptote:

Point in which the denominator is 0, so:

(x - 4) = 0

x = 4

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Graph (C) which has points (0, 400) and (16, 0) represent the solution to the given situation of Rashawn.

In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way.

The relationships between two or more items are frequently represented by the points on a graph.

Graphs and charts are useful visual aids because they make information accessible and quick to understand.

Therefore, it is not unexpected that print and electronic media frequently use graphs.

When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.

So, Rashawn consumed 25 pages of his book daily till it was finished. There were 400 pages in his book.

400 / 25 = 16 days is the estimated number of days he needs to finish the book.

He will have 400 pages finished in 0 days and 0 pages in 16 days.

As a result, the situation is represented by a graph with a line segment in the first quadrant.

Days are shown on the x-axis, and Pages left are listed on the y-axis.

The line segment's ends are (0, 400) and (16, 0).

Therefore, graph (C) which has points (0, 400) and (16, 0) represent the solution of the given situation of Rashawn.

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Complete question:
Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.

Which sketch represents this situation?

a) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 400 end ordered pair and begin ordered pair 25 comma 0 end ordered pair.

b) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 16 end ordered pair and begin ordered pair 400 comma 0 end ordered pair.

c) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 400 end ordered pair and begin ordered pair 16 commas 0 ends ordered pair.

d) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y-axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 25 ends ordered pair and begin ordered pair 400 commas 0 ends ordered pair.

(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

What is the property of slopes of parallel lines and perpendicular lines?

If two lines are given and they are parallel to each other then the slopes are equal and for perpendicular lines, the product of their slopes is equal to -1.

(7) The line AB is passing through the points (-1, 5/2) and (3/2, -1/2).

   Slope = y2 - y2/x2 - x1

              = (-1/2 - 5/2)/(3/2-(-1))

              = -6/5

   As line AB and line CD are parallel in nature so the slope of line CD is also -6/5.

(8) The line AB is passing through the points (1/2, 1) and (5/2, 5/2).

    Slope = y2 - y2/x2 - x1

              = (5/2 - 1)/(5/2-1/2)

              =3/2/2

             = 3/4

    Line CD is passing through points (1, 1) and (2, 3).

    Slope = y2 - y2/x2 - x1

              = (3 - 1)/(2-1)

              =2/2

             = 1

  As the product of their slopes is not equal to -1.

  So lines are neither parallel nor perpendicular.

(9) Slope of AB can be computed as (-2, 1) and (-5, 5)

     Slope = 5 - 1/-5 + 2

                = 4/-3.

  The slope of line passing through the point P = -4/3 as we have to draw the parallel line.

 Point P = (-1, 3)

Equation of the line :

      y - 3 = -4/3(x + 1)

    3y +9 = -4x - 4

   3y = -4x - 13

Now we can draw the line

(10) Slope of line AB = -4/3

    So the slope of the line passing through point P should be 3/4 in order to be perpendicular to line AB.

     Equation of the line passing through point P:

       y - 3 = 3/4(x - (-1))

       y - 3 = 3/4(x+1)

Hence,

(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

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Answer: 84 bells

Step-by-step explanation:

12 + 9x8

84

Using the slope, the required value of k is 48.

In mathematics, the steeper direction of a line is overall processed by the slope or gradient of the line.

A line's slope can be used to determine how steep it is.

Theoretically, the gradient is calculated as "rise over run" (change in y divided by change in x).

Given is a line that crosses through the origin:

y = mx

Let,s take x = -12 and y = -2.

y = mx

-2 = -12m

m = -2/12

m = -1/6

m is the slope.

The equation now:

y = mx

y = -1/6x

Now, insert:
x = k and y = 8

y = mx

8 = -1/6x

x = 6*8

x = 48

Therefore, using the slope, the required value of k is 48.

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Answer:

y = -1/2x - 2

Step-by-step explanation:

y = mx+b, m = -1/2, and b (the y-intercept) is -2.

The proof that  Δ SVW ≅ Δ UTW is given by ASA congruence criterion.

Two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure. These triangles can be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with each other.

The symbol of congruence is’ ≅’.

Given:W is the midpoint of SU

⇒ SW = WUTU ⊥ SU and SU ⊥ SV

To prove:Δ SVW ≅ Δ UTW

Proof:In Δ SVW and Δ UTWSW = UW (given)

∠S ≅ ∠U (given)

∠ SVW ≅ ∠ UTW (vertically opposite angle)

Therefore, Δ SVW ≅ Δ UTW (by ASA congruence criterion)

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There are two angles for the sine function such that sin θ = - 0.093: (i) 185.3°, (ii) 354.7°.

In this problem we must determine two values of the angle of the sine function such that its result is - 0.093. According to the features of the trigonometric function, sine is negative for angles between 180° and 360°.

Since trigonometric functions are trascendent functions, we can only obtain approximate values of the angle by means of inverse trigonometric functions and numerical methods. There are two possible solutions:

sin⁻¹ - 0.093

θ₁ ≈ 185.336° or θ₂ ≈ 354.664°

θ₁ ≈ 185.3° or θ₂ ≈ 354.7°

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Answer:

Step-by-step explanation:

To find the percentage increase in the dog's weight, you can use the following formula:

percentage increase = (final value - initial value) / initial value x 100%

In this case, the initial value is 40 pounds and the final value is 48 pounds, so the percentage increase is:

percentage increase = (48 - 40) / 40 x 100% = 8 / 40 x 100% = 20%

Therefore, the dog's weight increased by 20%.

Error Analysis 1:(x-3)/(x+7)

Error Analysis 2:(x(x-7)(x+3))/2(x+1)(x+9)(x+5)

Error analysis is a procedure that is usually used to identify the cause of the issue when pupils continually make mistakes. The method entails going over a student's work and looking for patterns of misinterpretation. Mathematical errors can occur for a variety of reasons and can be factual, procedural, or conceptual. The study of the kind and quantity of mistake, or uncertainty, that might be present in the solution to a problem is known as error analysis in mathematics. This issue is particularly common in practical disciplines like statistics and numerical analysis. The teacher can examine a student's errors on a worksheet, test, or progress monitoring tool to do an error analysis for mathematics. In order to grade each problem, the teacher should mark each wrong digit in the student's response, starting from the RIGHT, going to the LEFT for addition, subtraction, and multiplication problems.

Error Analysis 1:

(x²-x-6)/(x²+9x+14)

=(x-3)(x+2)/(x+2)(x+7)

=(x-3)/(x+7)

Error Analysis 2:

(x²-6x-27)/(2x²+2x)÷(x²+14x+45)/(x²)

=(x(x-7)(x+3))/2(x+1)(x+9)(x+5)

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