write using exponents
(3)(3)(3)(3)(x)(x)(y)

Answers

Answer 1
i couldn’t write the exponents
Write Using Exponents(3)(3)(3)(3)(x)(x)(y)

Related Questions

If f(x) = 7x- 6, which of the following is the inverse of kx)?​

Answers

Step-by-step explanation:

[tex]f(x) = 7x - 6[/tex]

[tex] \: [/tex]

Inverse

[tex]y = 7x - 6[/tex]

[tex]x = 7y - 6[/tex]

[tex]x + 6 = 7y[/tex]

[tex]y = \frac{x + 6}{7} [/tex]

[tex] {f}^{ - 1} (x) = \frac{x + 6}{7} [/tex]

1.) -3x-8=-14
2.) 4x-6=14
3.)-3-3x=-30
4.) -5x+5=5

Answers

-3x-8=-14 Answer: x=2
4x-6=14 Answer x=5
-3-3x=-30 Answer x=9
-5x+5=5 Answer x=0

Answer:

1.) x = 2

2.) x = 5

3.) x = 9

4.) x = 0

Step-by-step explanation:

1.) -3x - 8 = -14

-3x = -6

x = 2

2.) 4x - 6 = 14

4x = 20

x = 5

3.) -3 - 3x = -30

-3x = -27

x = 9

4.) -5x + 5 = 5

-5x = 0

x = 0

1. When do we use the method of Difference of two squares?
*
(Factoring polynomials)

Answers

Answer:

a

Step-by-step explanation:

Write in slope-intercept form an equation of the line that passes through the given points. (0,−1),(−8,−2)

Answers

y=8x+14

0-(-8)/-1-(-2)= 8/1 =8
8=m

-2=2(-8)+b
-2=-16+b
+16 +16
14=b

find the value of 4x-6y when x=3 and y= -2

Answers

Answer:

here the answer is 24

Step-by-step explanation:

answerrrrrerrr issss hereeeeeee

Answer:

0

Step-by-step explanation:

4 multiply by x(3) = 12

6 multiply by y(2) = 12

12 -12 =0

If you can walk 1/4 mile in 1/2 hour, how far could you walk in one hour?

Answers

Answer:

1/2 + 1/2 = 1

1/4 + 1/4 = 1/2

So you would walk 1/2 mile in 1 hour

Answer:

1/2

Step-by-step explanation:

1/4*2  multiply 1/4 by 2 because its you walk 1/4 in half a hour so times that by 2 for a full hour.

Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12

Answers

Answer:

i think it is 49:9

Step-by-step explanation:

because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9

Answer:

28:12

Step-by-step explanation:

Multiply both 7 and 3 by 4 and you get the ratio 28:12.

Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how
many logs (g) she needs to keep the fire burning for 18 hours. She assumes all logs are the same.
How many logs does Teresa need to maintain the fire for 18 hours?

Answers

Answer:

27

Step-by-step explanation:

6/4 = 1.5

1.5 * 18 = 27

in your own words explain the phrases "claming first and second place respectively"​

Answers

Answer:

If we divide twice the qualifier of Jose by 4 it results in less than 8. What is Jose's highest grade?

QUESTION: What fraction of 1/2 is 1/3?
PLEASE READ: First to answer gets brainly— MUST include how they got the answer, ill skim through it to double check if its right

Answers

Answer:

1/6

Step-by-step explanation:

questions which include 'of 'usually means "×" (multiplication sign) so when u multiply them it gives 1/6

A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST

Answers

Answer:

The kinetic energy of the car is 43,200 Joules.

Step-by-step explanation:

KE = (1/2)mv^2

KE = (1/2)(600 kg)(12 m/s)^2

KE = (1/2)(600 kg)(144 m^2/s^2)

KE = 43,200 kg*m^2/s^2 = 43,200 Joules

Answer:

Step-by-step explanation:

KE= 1/2mv^2

KE = 1/2(600) 12^2

KE = 300 * 144 = 43200J

1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84​

Answers

Answer:

4x - 12 = 84

Step-by-step explanation:

The last answer choice is correct because when you cross-multiply:

[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]

you get 4x - 12 = 84.

Therefore, the last option is correct.

Answer:

D would be the answer (4x-12=84)

Step-by-step explanation:

4/7=12/x-3

=>1/7=3/x-3

=>x-3=21

Multiplying both sides by 4

4(x-3)=4x21

=>4x-12=84

Hope this helped :)

Please help xxxxxxxx

Answers

Answer:

a. [tex]\bold{45000\times \:10^7}[/tex]b. [tex]\bold{3500}[/tex]

Step-by-step explanation:

a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]

[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]

[tex]=45000\times \:10^7[/tex]

b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]

[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]

[tex]\frac{10^5}{10^2} = 10^3[/tex]

[tex]\frac{7\times \:10^3}{2}[/tex]

[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]

[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]

[tex]\frac{2^3}{2}=2^2[/tex]

[tex]7\times \:2^2\times \:5^3=3500[/tex]

Help me pls i give brain

Answers

Answer:

4 3/4

Step-by-step explanation:

8 1/2=8 2/4

8 2/4-3 3/4= 4 3/4

help!! !,
is it right or not ​

Answers

Answer:

No

Step-by-step explanation:

The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number

Yep!!! Your correct

write a peacewise function for the graph
please help me

Answers

Answer:

[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]

Step-by-step explanation:

If you look at the graph you see that:

before 0, the graph has same y as it has x, or y=x.

after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.

Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.

Find the value of x.

Answers

Answer:

i think the answer should be 8

Step-by-step explanation:

50 POINTS PLS HELP ME I'LL MARK BRAINLIEST

Find a polynomial of degree n that has only the given zeros. (There are many correct answers.)


x = −3, 8; n = 3



Thank you so much!!

Answers

Answer:

Step-by-step explanation:

Here we need to find a 3rd degree polynomial that has only two distinct zeros:  {-3, 8}.  

Focusing on the zero x = 8 and assuming that this 8 has a multiplicity of 2, we come up with the following polynomial in which the factor x - 8 shows up twice:

f(x) = a(x - 8)(x - 8)(x + 3), or f(x) = a(x - 8)^2(x + 3)

One such polynomial is thus

f(x) = a(x - 8)^2(x + 3), where 'a' is a constant coefficient.  This polynomial has a double zero at x = 8 and a third zero at x = -3.

Step-by-step explanation:

The polynomial has degree 3 and two zeros: - 3 and 8.

Since it has degree 3 it should have 3 zero's.

Two possible scenarios

1. -3 has multiplicity of two:

a(x + 3)²(x - 8) - is the factored form of the polynomial where a is the constant

2. 8 has multiplicity of two:

a(x + 3)(x - 8)² - is the factored form of the polynomial

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Prove that ~

[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]


by using first principle of differentiation ~​

Answers

Answer:

METHOD I:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

Substituting these in eqn. (i)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

sec x can be written as 1/ cos(x)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

Taking LCM

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

By Cosines sum to product formula, i.e.,

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

2/ h can also be written as 1/(h/ 2)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

We have limₓ→₀ (sin x) / x = 1.

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

h→0 means h/ 2→0

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

METHOD II:

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

sec x can also  be written as (cos x)⁻¹

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

Any base with negative exponent is equal to its reciprocal with same positive exponent

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

The inner function that remains is cos x whose derivative is -sin x.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

cos²x can also be written as (cos x).(cos x)

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

sin x/ cos x is tan x, while 1/ cos x is sec x

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x

Hence, Proved!

find the value of x. only type the “number”

Answers

Step-by-step explanation:

5x - 6 = 3x + 2

5x - 3x = 2 + 6

2x = 8

x = 8/2

x = 4

Solve for x x^2 + 6x + 1 = 0

Answers

Answer:

x = -.1715 ≈ - .172    or x = -5.83

Step-by-step explanation:

x² + 6x + 1 = 0

x² + 6x = -1

Complete the square   Add to both sides (1/2 of the x-term, then square it.)

x² + 6x + 9  = -1 + 9

(x + 3)(x + 3) = 8

(x + 3)² = 8

[tex]\sqrt{(x + 3)^{2}[/tex]  = [tex]\sqrt{8}[/tex]

 x + 3 = ±  [tex]\sqrt{8}[/tex]

  x = -3 ± [tex]\sqrt{8}[/tex]

   x = -3 + [tex]\sqrt{8}[/tex]   or x = -3 - [tex]\sqrt{8}[/tex]

   x = -.1715 ≈ - .172    or x = -5.83

Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =​

Answers

Step-by-step explanation:

f(x) = -3x - 8

f(-3) = -3(-3) - 8

f(-3) = 9 - 8

f(-3) = 1

find the slope of the line

Answers

Answer:

3 i belive  100 pecent tho

Step-by-step explanation:

Write 2.04 × 10 ⁴ as an ordinary number

Answers

Answer:

20400

Step-by-step explanation:

its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400

Maddie is packing moving boxes. She has one 3 cubic-foot box and one 6 cubic-foot box. How many cubic feet of clothing can she fit in the two boxes?

Answers

Answer:

She can fit 9 cubic feet of clothing in the two boxes.

Step-by-step explanation:

6 cubic feet + 3 cubic feet = 9 cubic feet.

-Lexi

Answer:

9 ft^3

Step-by-step explanation:

Add together the box capacities:  3 ft^3 + 6 ft^3 = 9 ft^3.

Maddie can pack a total of 9 ft^3 of clothing into these two boxes.

What is 4 times 3/4 multiples by 3/4

Answers

Answer:

9/4

hope it helps.................

solve pls brainliest

Answers

Answer:

first put 2 in the numerator for the first blank and 2/9 in the second blank

Step-by-step explanation:

1/3 equals 3/9 and 3/9-1/9=2/9

Answer:

[tex]\frac{3}{9}[/tex]

Step-by-step explanation:

pls helppppppp ill give brainliest ​

Answers

Answer:

2n-3

Step-by-step explanation:

three less so -3

Julie runs three less than 2 times what Hannah ran

Hannah ran n miles

so Julie ran three less than 2n

Anne goes out to buy lunch every Friday. On average she spends around $18 each time. How much money can she save in one year if she stops going out for lunch each week?

Answers

So according to a search there is 52 weeks in a year, and Anne spends $18 each week so I did 52 x 18 which gave me $936. Anne would have saved $936 in one year if she stops going out for lunch each week
(Tried my best!)

Please helppppppppppppp

Answers

Answer:

101

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

Suplemetary angles

180-79=101

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