Answer:
Written in Python:
evens = 0
odds = 0
oddtotal = 0
eventotal = 0
total = 0
mylst = []
tryag = "Y"
while tryag == "Y" or tryag == "y":
num = int(input("Input: "))
mylst.append(num)
tryag = input("Another Input (Y/y): ")
mylst.sort()
print("Minimum: "+str(mylst[0]))
print("Maximum: "+str(mylst[-1]))
for i in mylst:
total = total + i
if i%2 == 0:
evens = evens + 1
eventotal = eventotal + i
else:
odds = odds + 1
oddtotal = oddtotal + i
print("Evens: "+str(evens))
print("Odds: "+str(odds))
print("Even Average: "+str(eventotal/evens))
print("Odd Average: "+str(oddtotal/odds))
print("Total Average: "+str(total/(evens+odds)))
Explanation:
The following lines initializes useful variables to 0
evens = 0
odds = 0
oddtotal = 0
eventotal = 0
total = 0
This declares an empty list
mylst = []
tryag = "Y"
This is repeated until user stops the loop by entering strings other than y or Y
while tryag == "Y" or tryag == "y":
This prompts user for input
num = int(input("Input: "))
User input is appended to the list
mylst.append(num)
This prompts user to try again the loop
tryag = input("Another Input (Y/y): ")
This sorts the list from small to large
mylst.sort()
This prints 1. The minimum
print("Minimum: "+str(mylst[0]))
This prints 2. The maximum
print("Maximum: "+str(mylst[-1]))
The following iterates through the list
for i in mylst:
This calculates the total
total = total + i
This checks for even entry
if i%2 == 0:
This counts the number of even entries
evens = evens + 1
This sums the even entries
eventotal = eventotal + i
else:
This counts the number of odd entries
odds = odds + 1
This sums the odd entries
oddtotal = oddtotal + i
This prints 3. Sum of Even entries
print("Evens: "+str(evens))
This prints 4. Sum of Odd entries
print("Odds: "+str(odds))
This prints 5. Average of Even entries
print("Even Average: "+str(eventotal/evens))
This prints 6. Average of Odd entries
print("Odd Average: "+str(oddtotal/odds))
This prints 7. Total Average
print("Total Average: "+str(total/(evens+odds)))
This is the department that is responsible for hiring, firing, training, new employees for the business or corporation.
Group of answer choices
Human Resources
Information Technology
Advertising
Marketing
Answer:
Explanation:
human resources
hoped this helped
What question did the use of a telescope by Hubble answer?
A
Is Earth the center of the universe
B
Is the sun the center of the universe
C
How do the planets move in the solar system
D
Are there more galaxies beyond the Milky Way
Answer:
The Answer is D
Type the correct answer in the box. Spell the word correctly.
Under which menu option of a word processing program does a star appear?
A star appears under the
menu of the word processing program.
Reset
Next
Answer:
"a callout is a type of text box that also includes a line for pointing to any location on the document. A callout appears under the SHAPES menu of the word processing program. The answer that completes this statement is the word "shapes". Hope this answers your question."
Explanation:
The correct answer in the box is as follows:
A star appears under the shapes menu of the word processing program. What is the word processing program?The word processing program may be characterized as a type of MS software that is significantly used to create, edit, save, and print documents on a computer. It permits a user to create documents that mimic the format and style of the original document along with diverse functions.
The Shapes menu in the word processing program has numerous shapes like rectangles, Ellipses, and Freehand polygons. There are some other numbers of other shapes such as arrows, speech balloons, various stars, and others are also included in this menu tool.
If a user wants to add any specific shape, he/she is allowed to click Insert, click Shapes, select a shape, and then click and drag to draw the shape. That specific shape is now inserted in the word processing documents.
Therefore, a star appears under the shapes menu of the word processing program.
To learn more about Word processing documents, refer to the link:
https://brainly.com/question/1596648
#SPJ7
Who wants to play nitro type with me. My user is thievesGuildcuu
Answer:
I can
Explanation:
Answer:
Sure.
My user Name is: Queen Void.
Compute the decimal representation for each of the following numbers.
a. (1100110)2
b. (346)7
c. (1024)8
d. (3B2)16
e. (AF72)16
f. (120121)3
g. (A22)11
Answer:
[tex](1100110)_2= 102_{10[/tex]
[tex](346)_7= 181_{10[/tex]
[tex](1024)_8 = 532_{10[/tex]
[tex](3B2)_{16} = 946_{10[/tex]
[tex](AF72)_{16}= 44914_{10[/tex]
[tex](120121)_3= 421_{10[/tex]
[tex](A22)_{11} = 1234_{10}[/tex]
Explanation:
Required
Convert to decimal
To do this we get the position of individual digits (starting from the rightmost digit).
Then each digit is multiplied by the base raise to power its position.
Lastly, we sum the results of the products.
Following the above steps, we have:
[tex]a.\ (1100110)_2[/tex]
[tex]= 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 0 * 2^3 + 1 * 2^2 + 1 * 2^1 + 0 * 2^0[/tex]
[tex]= 1 * 64 + 1 * 32 + 0 * 16 + 0 * 8 + 1 * 4 + 1 * 2 + 0 * 1[/tex]
[tex]= 64 + 32 + 0 + 0 + 4 + 2 + 0[/tex]
[tex]= 102[/tex]
Hence:
[tex](1100110)_2= 102_{10[/tex]
[tex]b.\ (346)_7[/tex]
[tex]= 3 * 7^2 + 4*7^1 + 6 * 7^0[/tex]
[tex]= 3 * 49 + 4*7 + 6 * 1[/tex]
[tex]= 147 + 28 + 6[/tex]
[tex]= 181[/tex]
Hence:
[tex](346)_7= 181_{10[/tex]
[tex]c.\ (1024)_8[/tex]
[tex]= 1 * 8^3 + 0 * 8^2 + 2 * 8^1 + 4 * 8^0[/tex]
[tex]= 1 * 512+ 0 * 64 + 2 * 8 + 4 * 1[/tex]
[tex]= 512+ 0 + 16 + 4[/tex]
[tex]= 532[/tex]
Hence:
[tex](1024)_8 = 532_{10[/tex]
[tex]d.\ (3B2)_{16[/tex]
[tex]= 3 * 16^2 + B * 16^1 + 2 * 16^0[/tex]
[tex]= 3 * 256 + B * 16 + 2 * 1[/tex]
B represents 11, so we have:
[tex]= 3 * 256 + 11 * 16 + 2 * 1[/tex]
[tex]= 768 + 176 + 2[/tex]
[tex]= 946[/tex]
Hence:
[tex](3B2)_{16} = 946_{10[/tex]
[tex]e.\ (AF72)_{16[/tex]
[tex]= A * 16^3 + F * 16^2 + 7 * 16^1 + 2 * 16^0[/tex]
[tex]= A * 4096 + F * 256 + 7 * 16 + 2 * 1[/tex]
A represents 10 and F, 15; So, we have:
[tex]= 10 * 4096 + 15 * 256 + 7 * 16 + 2 * 1[/tex]
[tex]= 40960 + 3840 + 112 + 2[/tex]
[tex]= 44914[/tex]
Hence:
[tex](AF72)_{16}= 44914_{10[/tex]
[tex]f.\ (120121)_3[/tex]
[tex]= 1 * 3^5 + 2*3^4 + 0*3^3 + 1*3^2 + 2*3^1 + 1*3^0[/tex]
[tex]= 1 * 243 + 2*81 + 0*27 + 1*9 + 2*3 + 1*1[/tex]
[tex]= 243 + 162 + 0 + 9 + 6 + 1[/tex]
[tex]= 421[/tex]
Hence:
[tex](120121)_3= 421_{10[/tex]
[tex]g.\ (A22)_{11[/tex]
[tex]= A * 11^2 + 2 * 11^1 + 2 * 11^0[/tex]
[tex]= A * 121 + 2 * 11 + 2 * 1[/tex]
A represents 10, so we have:
[tex]= 10 * 121 + 2 * 11 + 2 * 1[/tex]
[tex]= 1210 + 22+ 2[/tex]
[tex]= 1234[/tex]
Hence:
[tex](A22)_{11} = 1234_{10}[/tex]
The Electronic Age began in the
A. 1940s
B. 1970s
C. 1980s
D. 1990s
Answer:
1940
Explanation:
On his website, Mario has a video that visitors must click to play. He wants the video to play automatically when the page loads. What attribute should Mario add to the
A. controls
B. loop
C. autoplay
D. play
Answer:
C: AutoPlay
Explanation:
it is C because the definition of AutoPlay is: a functionality that causes a video, audio file, etc. to play automatically, without action from a user.
PLEASE ANSWER QUICK
How can improving one’s reasoning skills also improve one’s performance on the job?
A. If one can improve one’s reasoning, one can also improve one’s physical fitness and athletic performance.
B. If one can improve one’s reasoning, one can perform anything.
C. High-performing workers always work reasonable schedules.
D. High-performing workers are able to analyze sophisticated streams of data and solve complex problems.
Answer: C
Explanation:
Write a program to display the following diamond-shape like pattern based on the height given by the user. Assume that the user will always enter a positive odd number.
Answer:
try:
size = int(input("Enter a number: "))
except ValueError:
print("must be a number")
if size==0:
print("number must be greater than zero.")
elif size%2==0:
print("number must be odd.")
else:
obj = '#'
mid_size = round(size/2)
s = size - mid_size
count = 2
counts = 1
for i in range(size+1):
if i<=mid_size:
print(" " *(size - i) + (obj+" ") * i)
elif i>mid_size:
print(" " * (s + counts) + (obj + " ") * (i - count))
count += 2
counts += 1
Explanation:
The python source code uses a try and except statement to check for value error and print a diamond shape of the object "#" determined by the input number.
What is something about online conferencing that you understand better now.
What did you learn?
Answer:
man this question is really about your personal experience but i'll try my best to answer this
Explanation:
onnline Web Conferencing is used by businesses and now schools who went to online because of the virus. for businesses i learned they use it to present and share with online collaboration on different applications including documents, web sites, data files, video, emails, and reduce the time and cost of business travel for meetings. i understand now that online conferencing can be used for Applications for web conferencing include meetings, training events, lectures, or presentations from a web-connected computer to other web-connected computers.
If a priority queue is being implemented using an unordered list, what is the Big-O complexity of the Enqueue operation?
Answer:
the answer is O(1)
Explanation:
A priority queue is a type of queue whereby each of the elements are linked with a priority and the elements are served according to their priority.
The word enqueue means to add elements to the back of the queue
For this question, while using an unordered list, O(1) is the big-O complexity of the enqueue operation. O(1) is a natural Choice for queues.
Someone help me for about how to avoid online scams please I need help no trolls
Answer:
1. (for emails) Block spam messages.
2. Look at who sent whatever it is and make sure it is the exact email for the brand.
3. If someone is putting a lot of emojis in a comment or somthing its fake.
4. Make sure to read the fine print.
5. Do not giveaway personal information like zip code, address, social security number.
nder a Huffman encoding ofnsymbols with frequenciesf1, f2, . . . , fn, what is the longest a codewordcould possibly be
Answer:
The longest codeword that could possibly be for "n" symbol is n-1 bits.
Explanation:
From the given information:
Suppose we are to consider a set of frequencies [tex]\mathtt{f_1,f_2,f_3 ...,f_n}[/tex], for which f is a symbol for the length n. Therefore, the longest codeword that could possibly be for "n" symbol is n-1 bits.
However, during the encoding for "n" in conjunction with n-2, then the possibilities for n are; [tex]\mathtt{\dfrac{1}{2}, \dfrac{1}{4}, ... \dfrac{1}{2^{n-2}}}[/tex]
We can conclude that the longest codeword that could possibly be for "n" symbol is n-1 bits.
The 1950s brought the television and interest in using television as a teaching device. In 1952, the _____________________________ decided to set aside 242 educational channels.
Answer:
Federal Communications Commission
Explanation:
The 1950s brought the television and interest in using television as a teaching device. In 1952, the Federal Communications Commission decided to set aside 242 educational channels.
The Federal Communication Commission were in charge of determining which type of programs were to be aired based in different factors such as current state of the nation etc.
label parts of camera
Answer:
Viewfinder.
Pentaprism.
Focusing Screen.
Condenser Lens.
Digital Sensor.
Shutter. ...
Display. ...
Electronics.
Explanation:
A computer has _____IP address(es).
a) many
b) one
Answer:
one................
Answer:
B) one
Explanation:
Information technology
Answer:
Study or use of systems
Explanation:
especially, computers, telecommunications for storing retrieving and sending some informations
Answer:
Information technology is the use of computers to store, retrieve, transmit and manipulate data, or information, often in the context of business or other enterpise.
Which input value causes the loop body to execute a 2nd time, thus outputting "In loop" again? { String s = "Go"; while ((!s.equals("q"))&& (!s.equals("")) System.out.println("In loop"); 5 - scnr.nextO;
a) "Quit"
b) "q" only
c) "Q only
d) Either "q" or "Q"
Answer:
a) "Quit"
c) "Q only
Explanation:
Given
String s = "Go";
while ((!s.equals("q"))&& (!s.equals(""))) {
System.out.println("In loop");
s = scnr.next();
}
Required
What input causes another execution
Analyzing the while condition
while ((!s.equals("q"))&& (!s.equals("")))
This can be split into:
!s.equals("q")) && (!s.equals(""))
Meaning
When s is not equal to "q" and when s is not an empty string
In other words,
the loop will be executed when user input is not "q" and user input is not empty.
So, from the list of given options: The loop both will be executed when:
a) Input is "Quit"
c) Input is Q only
Input of q will terminate the loop, hence b and d are incorrect
To italicize text located within a text box, which grouping would you use? Effects Text Font Typography
Answer:
Font
Explanation:
It seems like the only real answer from reading the lesson
Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text
THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED
(Assume that the length of the text-it is 47 characters long- is known before the search starts).
Answer:
Total number of character comparison = 43
Explanation:
Using the Brute force algorithm
The string of n characters is known as text, and the string of m characters is known as the pattern.
From the given information:
The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED
The pattern (m) = GANDHI
The total no of characters that we have in the text = 47
The total number of characters in pattern = 6
For a brute force algorithm;
Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1
= 47 – 6 + 1
= 47 – 5
= 42
Thus; the algorithm will attempt the trial 42 times.
Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.
On each attempted trial, the algorithm will make one unsuccessful comparison.
However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.
Hence, we can calculate the total number of character comparison as follows:
Total number of character comparison = [tex]\mathbf{\bigg ( ( 42 - (no. \ of \ failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \ comparisons) ) \bigg ) }[/tex]
Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )
Total number of character comparison = 41 + 2
Total number of character comparison = 43
Acrostics, acronyms, and rhymes are a few examples of __________. A. a visual strategy B. the misinformation effect C. memory reconstruction D. a mnemonic device Please select the best answer from the choices provided A B C D
Answer:
The answer is D) A mnemonic device
Answer:
D
Explanation:
I hope this helps! Sorry if it is wrong ;-;
True or false: Simultaneous multithreading (SMT) uses threads to improve resource utilization of a dynamically scheduled, out-of-order processor.
Answer:
True
Explanation:
Simultaneous multithreading or otherwise called, SMT that is a technique that us used for improving the total and overall efficiency of superscalar CPUs with hardware multithreading. Simultaneous Multithreading allows different types of independent threads, ability to execute and then eventually take optimum and much better use of the resources that is provided by modern processor architectures. Multithreading can not only allow multiple threads to be executed simultaneously in a single CPU core, it also allows multiple tasks some of which are different page tables, different I/O permissions, and others to be executed
Using range(1,101), make two list, one containing all even numbers and other containing all odd numbers. How can I do this on Python
Answer:
even = []
odd = []
for i in range(1,101):
if i % 2 == 0:
even.append(i)
else:
odd.append(i)
Using range(1,101), the list of even and odd number can be done in python as follows;
odd_numbers = []
even_numbers = []
for i in range(1, 101):
if i%2 == 0:
even_numbers.append(i)
else:
odd_numbers.append(i)
print(even_numbers)
print(odd_numbers)
The variable odd_numbers is initialise with an empty list
The variable even_numbers is initialise with an empty list.
Then we loop through the range 1 to 101 as required.
If the looped numbers is divided by 2 without a remainder then the number is appended to the empty list even_numbers.
Else if it has a remainder, the looped number are appended to the empty list, odd_numbers.
Then we print the even_numbers and odd_numbers.
learn more about python here; https://brainly.com/question/14157737?referrer=searchResults
For the sake of maximizing hardware utilization in a multicore system with a many to many threading model, the relationship of the number of user threads U to the number of kernel threads K to the number of CPU cores P should be:
Answer:
"U > K > P" would be the appropriate answer.
Explanation:
When performing or executing the software, user threads (U) could easily be accomplished and therefore are typically wide in the amount to provide excellent or excellent performance. Multiple kernel threads could indeed be appointed to every other core as well as try to emulate the algorithm for scheduling.If you need to download something for a class, first
Answer:
left click, then click save image
Explanation:
Answer:
first try to do it on kami, then on Google docs, then on doc-hub
Which choices correctly describe an Else
statement? Check all that apply.
a conditional statement that will show
different information if the answer to the If
statement is true
a conditional statement that will show
different information after the If statement
answer is false
a statement that contains the code to be
executed when the If value is false or zero
a conditional statement that runs a piece of
code when all program statements are true
Answer: B C
Explanation:
Answer:B,C,D
Explanation:
An IEEE 802.1D port goes through four states when transitioning to the forwarding state. What is the correct order?
Answer:
Blocking, listening, learning and forwarding.
Explanation:
An IEEE 802.1D is the media access control (MAC) Bridges standardized by the IEEE group which includes bridging, Spanning tree and other protocols.
An IEEE 802.1D port goes through four states when transitioning to the forwarding state. The correct order are blocking, listening, learning and forwarding.
Corina has added animations to objects on a particular slide within a presentation. She needs to reorder the animations. How should she achieve this goal?
A. Use the Preview button.
B. Access the Advanced timeline.
C. Use the Animation pane.
D. Delete and recreate the animations in the correct order.
I think it's B but im not 100% sure sorry if im wrong
Answer: C
Explanation:
Write code which takes a sentence as an input from the user and then prints the length of the first word in that sentence.
Hint: think about how you know where the first word ends - you may assume that the sentence contains more than one word.
Input a code in the following:
/* Lesson 3 Coding Activity Question 4 */
import java.util.Scanner;
public class U2_L3_Activity_Four{
public static void main(String[] args){
/* Write your code here */
}
}
import java.util.Scanner;
public class U2_L3_Activity_Four {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a sentence.");
String sent = scan.nextLine();
int count = 0;
for (int i = 0; i < sent.length(); i++){
char c = sent.charAt(i);
if (c != ' '){
count++;
}
else{
break;
}
}
System.out.println("The first word is " + count +" letters long");
}
}
We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!
Following are the java code to the given question:
import java.util.Scanner;//import package
public class U2_L3_Activity_Four //defining a class U2_L3_Activity_Four
{
public static void main(String[] args) //defining main method
{
String s;//defining String variable
int x,v=0;//dclaring integer variable x,v
Scanner obx = new Scanner(System.in);//creating Scanner class Object
System.out.println("Enter a sentence.");//print message
s = obx.nextLine();//input string value
for (x = 0; x < s.length(); x++)//defining loop to count string length
{
char c = s.charAt(x);//defining char variable that hold char value
if (c != ' ')//defining if that check space value
{
v++;
}
}
System.out.println("The first word is " + v +" letters long");//print length of first word
}
}
Output:
Please find the attached file.
Program Explanation:
Import package.Defining a class U2_L3_Activity_Four, inside the class main method is declared.Defining a string variable "s" and an integer variable "x,v=0", and a scanner class object is created that inputs string value.In the next step, a for loop is defined that checks the first word in the string value and prints its length value.Learn more:
brainly.com/question/16092924
Write function that ask for input from a user. Use this input as input for the countdown function that we wrote using the while loop. If the user types 'end', the program exits, otherwise it keeps going.
Answer:
Written in Python:
def myfunction():
userinput = input("User input: ")
while(userinput != "end"):
countdown(userinput)
userinput = input("User input: ")
Explanation:
This line defines the function
def myfunction():
This line prompts user for user input
userinput = input("User input: ")
The following while loop checks if userinput is not "end". It continues execution until user input "end"
while(userinput != "end"):
countdown(userinput) If yes, the input is passed to the countdown function for execution
This line prompts user for another user input
userinput = input("User input: ")
Please note the above code segment assumes that countdown() function has already been written and defined
