Which equation matches the graph shown?
[tex]we conclude that option B:[/tex]
[tex]y + 5 = -\frac{1}{2}*(x - 3)^2[/tex]
[tex]Is the graphed function.[/tex]
Which equation matches the graph shown?On the graph we can see a parabola that opens downwards, so it has a negative leading coefficient.
We also can see that the vertex of the parabola is on the point (3, -5)
Then the equation of the parabola is something like:
y + 5 = a*(x - 3)^2
Where a is a negative real number.
The only option of this form is option B, so we conclude that option B:
[tex]y + 5 = -\frac{1}{2}*(x - 3)^2[/tex]
Is the graphed function.
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Mr. Wilkerson bought frozen treats for 34 children. Each child picked either a popsicle or an ice cream bar. Each popsicle cost $2 and each ice cream bar cost $5. If Mr. Wilkerson spent a total of $128, how many of each type of treat did he buy?
Answer: He bought 20 ice cream bars and 14 popsicle
Step-by-step explanation:
To solve this I used the elimination method, you could use substitution as well
Here are our two equations
x+y=34 Because the total number of ice creams bought must be given to 34 children and no more
2x+5y=128 because that is the cost for each ice cream and the amount he spent
For the elimination method we have to cancel out one of the variables, I decided to cancel out the x, so I multiplied the top equation by -2. So i got -2x-2y=-68
2x+5y=128 Then we get
3y=60 so
y=20
Now we can go back to the first equation and plug in y.
x+20=34
-20 -20
x=14
So he bought 14 popsicles and 20 ice cream bars.
Jenny asked 12 students how many courses they have taken so far at her college. Here is the list of answers.
16, 7, 21, 14, 9, 11, 22, 19, 17, 12, 5, 25
What is the percentage of these students who have taken fewer than 21 courses?
Answer: 75%
Step-by-step explanation:
Only 9 students have taken fewer than 21 courses
9/12 = 0.75 or 75%
Find the value of the variable(s). (9x + 12) 3x (4y - 10)
Answer:
2.07648468018
Step-by-step explanation:
4. Is 1,500,000 grams in 3 liters the same as 5 kilograms in 1 centiliter?
O No, because "grams per liter" measures volume, and "kilograms per centiliter" measures length.
No, because "grams per liter" measures concentration, and "kilograms per centiliter" measures area.
O Yes, because 1 kilogram = 1000 grams, and 1 liter = 100 centiliters.
Yes, because 1 gram per liter is the same as 1 kilogram per centiliter.
Answer:
O Yes, because 1 kilogram = 1000 grams, and 1 liter = 100 centiliters.
Yes, because 1 gram per liter is the same as 1 kilogram per centiliter.
Step-by-step explanation:
Rhombus LMNO is shown with its diagonals.
Rhombus L M N O is shown. Diagonals are drawn from point L to point N and from point M to point O and intersect at point P. All sides are congruent.
Angle MNO measures 112°. What is the measure of angle LMN?
Answer:
hope this help
Step-by-step explanation:
Answer:
90
51
10
Step-by-step explanation:
What is the reminder? Help
Answer:
6
Step-by-step explanations:
The remainder is what is left over after dividing whatever from d. So if you add one to d, then the remainder would increase from 5 to 6.
Hope this helps.
PLEASE HELP :( ASAP
Find the area.
A. 272 cm²
B. 175 cm²
C. 189 cm²
D. 195 cm²
Answer:
A. 272 cm^2
Step-by-step explanation:
The area of the rectangle is 17cm * 7cm = 119 cm^2
The area of the right triangle is (25-7) * 17cm * 1/2 = 153cm^2
Answer: 119+153 = 272 cm^2
Find the volume of a rectangular solid that
is 9 ft. by 12 ft. by 8 ft.
Help please
Answer:
864 ft³ is the volume
Step-by-step explanation:
Volume = width · height · length
= 12 · 9 · 8
= 864
Answer:
Step-by-step explanation:
Volume of rectangular solid = length * width * height
= 9 * 12 * 8
= 864 ft³
Jol 26, 12:24:35 PM
Solve for x. Round to the nearest tenth, if necessary.
5.7
71
Answer: 2
Submit Answer
attempt 1 out of 2
PLS HELP i really need to finish this
Answer:
x = 16.6
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan 71 = x /5.7
5.7 tan 71 = x
x=16.55400
Rounding to the nearest tenth
x = 16.6
Independent Practice
Find the first, fourth, and eighth terms of the sequence.
an=0.5 · 3n−1a subscript n baseline equals 0.5 times 3 superscript n minus 1 baseline
A.
0.667; 4.5; 364.5
B.
3; 0.375; 0.0234375
C.
0.5; 13.5; 1093.5
D.
0.5; 121.5; 280.5
Answer:
C.
0.5; 13.5; 1093.5
Step-by-step explanation:
Check if -2 is the solution of equation 2 – x = 4x + 3
Answer:
7x the answer i think
Step-by-step explanation:
Answer:
[tex]\boxed {\boxed {\sf -2 \ is \ not \ a \ solution}}[/tex]
Step-by-step explanation:
We are asked to check is -2 is the solution of the following equation.
[tex]2-x= 4x+3[/tex]
We must substitute -2 in for x and solve both sides of the equation. If the two sides are equal, then -2 is the solution.
[tex]2- (-2) = 4(-2)+3[/tex]
Solve both sides of the equation according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
Let's start with the left side.
[tex]2+2= 4(-2)+3 \\[/tex]
[tex]4= 4(-2)+3[/tex]
Now solve the right side. Remember to multiply first.
[tex]4= -8+3[/tex]
[tex]4= -5[/tex]
[tex]4\neq -5[/tex]
4 is not equal to -5, so -2 is not the solution for this equation.
Andrew is an avid archer. He launches an arrow that takes a parabolic path.
The equation of the height of the arrow with respect to time is
y = -4.9x2 + 48x, where y is the height of the arrow in meters above
Andrew's bow and x is the time in seconds since Andrew shot the arrow.
Find how long it takes the arrow to come back to a height even with his bow
height.
Answer:
9.7959 sec
Step-by-step explanation:
For the arrow to reach the same height as the bow again, - 4.9x^2+48x=0, 48=4.9x, x=48/4.9=9.7959
The time arrow take to come back to a height even with his bow height is 9.79 seconds.
We have an equation of the height of the arrow with respect to time -[tex]y = -4.9x^{2} +48x[/tex] where y is the height of the arrow in meters above Andrew's bow and x is the time in seconds since Andrew shot the arrow.
We have to find out - how long it takes the arrow to come back to a height even with his bow height.
The motion of arrow in the above situation is an example of which type of motion?It is an example of two - dimensional Projectile motion.
We have the function that depicts the variation of height of the arrow with respect to time given by -
[tex]y=-4.9x^{2} +48x[/tex]
To find the time taken by the arrow to come to a height even with his bow height, we should equate y = 0.
[tex]y=-4.9x^{2} +48x=0\\-4.9x(x-9.79)=0\\-4.9x=0\;\;\;and\;\;\;x-9.79=0\\x =0\;\;\;and\;\;\;x=9.79[/tex]
Time cannot be 0, hence the time arrow take to come back to a height even with his bow height is 9.79 seconds.
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PLEASE ELP ME ITS URGENT!!! 25 POINTS!!!!!
Write 2.4 × 1012 in standard notation.
Answer:
2,400,000,000,000
Step-by-step explanation:
2.4 x 10^12 means that the decimal point is moved 12 places to the right (hence the power of 12)
So by moving the decimal point 12 times you get this: 2,400,000,000,000
The reason why there are only 11 zeroes is because the 4 was a decimal place to the right of 2, thus losing a zero.
I need help plz help
We know
[tex]\boxed{\sf cos\Theta=\dfrac{b}{h}}[/tex]
[tex]\\ \sf\longmapsto cos22=\dfrac{x}{47}[/tex]
[tex]\\ \sf\longmapsto 0.9=\dfrac{x}{47}[/tex]
[tex]\\ \sf\longmapsto x=47(0.9)[/tex]
[tex]\\ \sf\longmapsto x=42.3[/tex]
rearrange the equation so the r is the independent variable
Answer:
q = 3+1/2 r
Step-by-step explanation:
10q -5r = 30
Add 5r to each side
10q -5r+5r = 30+5r
10q = 30 +5r
Divide by 10
10q/10 = 30/10 +5r/10
q = 3+1/2 r
Mr. Ellington has a total of 32 students in his class , The ratio of girls to boys is 3:5, how many girls are in Mr . Ellington's class ?
Add the ratio: 3 + 5 = 8
Divide total students by that:
32/8 = 4
The ratio for girls is 3, multiply the 4 by 3:
4 x 3 = 12
There are 12 girls
Answer:
12
Step-by-step explanation:
If the ratio of girls to boys is 3:5, that means that for every 8 total students, 3 would be girls and 5 would be boys. Therefore 3/8 of the students are girls and 5/8 are boys. If 3/8 are girls, then:
[tex]\frac{3}{8}[/tex] of 32
= [tex]\frac{3}{8} * 32[/tex]
[tex]=\frac{3 * 32}{8} \\= \frac{96}{8} \\= 12[/tex]
There are 12 girls.
Help anyone can help me do the question,I will mark brainlest.
Answer:
a) 30
b)600pi
Step-by-step explanation:
For the first questions, since the arc is 240°, the area of the sector and circumference will be 240/360 or 2/3 of the total of the circles'. Therefore 125.6 x 3/2 is the circumference, which is 188.4. When we divide this by 6.28, we get 30
Now, since the area is pi r^2 where we know that r=30, we get 900pi as the area of the whole thing, however since the sector is 2/3 of the whole circle, 2/3 x 900pi = 600pi
The sum of twice a number and 13 is 75.
Answer:
The value of this number is 31.
Step-by-step explanation:
To solve this you could set up an equation and solve for x.
Sum means add, so you are going to add 2n and 13 to get 75.
2n + 13 = 75
Subtract 13 from both sides.
2n = 62
To get n alone, divide by 2 on both sides.
n = 31
The value of this number is 31.
Have a nice day, please mark brainliest if possible! :)
Write the equivalent expression for the following radical expressions. Simplify numerical expressions
when possible. (1 point)
please help asap
Answer:
Step-by-step explanation:
8) [tex]\sqrt{x^{3}} = x\sqrt{x}[/tex]
9) [tex]\sqrt[3]{3^{6} } = 3^{2} = 9[/tex]
10) [tex](x^{\frac{1}{2} } )^{9} = x^{2} \sqrt{x}[/tex]
11) [tex]7^{2} = 49[/tex]
12) [tex]27^{\frac{2}{3} } = \sqrt[3]{27} ^{2} = 9[/tex]
13) 9x[tex]\sqrt[3]{3xy^{2} }[/tex]
A person walks away from a pulley pulling a rope slung over it. The rope is being held at a height 10 feet below the pulley. Suppose that the weight at the opposite end of the rope is rising at 4 feet per second. At what rate is the person walking when s/he is 20 feet from being directly under the pulley
The image of this question is missing and so i have attached it.
Answer:
dd/dt = 4.47 ft/s
Step-by-step explanation:
From the image attached, let's denote the following;
d = horizontal distance beneath pulley
h = height of pulley
l = diagonal from the pulley to the head of the person
v = velocity of rope rising
Using pythagoras theorem;
l² = d² + h²
Differentiating with respect to time and considering h = c^(te) gives;
2l(dl/dt) = 2d(dd/dt)
We are given;
d = 20 ft
h = 10 ft
v = 4 ft/s
We know that velocity in this case is change in diagonal distance with time. Thus;
v = dl/dt = 4 ft/s
From earlier, we saw that;
2l(dl/dt) = 2d(dd/dt)
Thus, reducing it gives
(dl/dt)(l/d) = dd/dt
Now, l² = d² + h²
l = √(d² + h²)
Also, v = dl/dt = 4
Thus;
4(√(d² + h²))/d = dd/dt
4(√(20² + 10²))/20 = dd/dt
dd/dt = 4.47 ft/s
Given HM = 24 and mHK = 66 , find x and y
Answer:
x=24,y=33
hopefully this answer can help you to answer the next question
Write an
equation
in slope y-intercept form B(-4,-3),m =Undefined
Answer:
x=-3
Step-by-step explanation:
Item 1 Which fraction is equivalent to 3.47? 3_23/50 3_47/100 3_12/25 I don't know.
Answer: 3 and 47/100
Step-by-step explanation:
Please help right now ASAP!!!make sure your right
Answer:
Step-by-step explanation:
Explain what it means for a solution of an equation to be extraneous.
Answer:
Extraneous Solutions An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation. Example 1: Solve for x, 1 x − 2 + 1 x + 2 = 4 (x − 2) (x + 2).
20) solve:
[tex] {8}^{2} + 2 = [/tex]
21) solve:
[tex]4(2x + 5y = [/tex]
22) simplify the expression
[tex]4( {2}^{2} + 30) - 4 = [/tex]
Match the answers……………..
9 in 8956 = 900
9 in 95675 = 90000
9 = 9 in 124569
9 in 68795 = 90
90000 = 9 in 2549652.........
hope it helps...
I need help ASAP!!!Please explain your answer
Answer:
Step-by-step explanation:
There are 2 possibilities. Either you need to know the angles connect to the common side (that would give you ASA) or you need to know GF = UT. The latter would give you SAS
Please help me. if I don’t complete my course I’m getting sent back to my parents house, and I need to complete this course
This is similar polygons, and the lessons I get don’t help