Why is the level of glycerin initially decreases when heated ?​

Answers

Answer 1
Because glucerin is hotter so it decreases faster

Related Questions

What is the amount of force exerted by gas particles?

Answers

Answer:

Pressure is the force divided by the area on which the force is exerted, and temperature is measured with a thermometer. We gain a better understanding of pressure and temperature from the kinetic theory of gases, which assumes that atoms and molecules are in continuous random motion.

If a horse can trot with an average velocity of 13 km/h, how far can it travel in
8 hours?
A. 2 km
B. 104 km
C. 35 km
D. 78 k

Answers

13*8= 105 km
D=speed*times

Answer:

104 km

Explanation:

Displacement = Velocity x Time

                       = 13 x 8

                       = 104 km

1.what are the types of matter?
2.what are the states of matter?​

Answers

Answer:

1) Ans= Pure substances and mixtures are the two types of matter.

2)Ans=solid ,liquid and gas are the states of matter

Name another way that energy is made

Answers

Answer:

The three major categories of energy for electricity generation are fossil fuels (coal, natural gas, and petroleum), nuclear energy, and renewable energy sources. Most electricity is generated with steam turbines using fossil fuels, nuclear, biomass, geothermal, and solar thermal energy.

Explanation:

Solar

Wind

Geothermal

Hydrogen

TidaWave

Hydroelectric

Biomass

A light bulb uses 40.0 W of power when connected to a 110 V (DC) outlet. If the same bulb is connected to a European 220 V outlet, how much power will the bulb use?​

Answers

If the bulb's resistance doesn't change, the power it uses is proportional to the square of the voltage. So doubling the voltage quadruples the power.

On 220 V, the bulb uses (4 • 40w)= 160 W.

It glows very brightly.

For a very short time.

Because it also gets very hot, and burns out.

After a few seconds, it uses zero watts.

Answer:

160

Explanation:

Acellus

A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Positive x-axis, 5 m, then goes back, 6 m. What is his total displacement from his original position? Displacement is a vector quantity whilst, distance is a scalar quantity.

Answers

His total displacement from his original position is -1 m

We know that total displacement of an object from a position x to a position x', d = final position - initial position.

d = x' - x

If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.

Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.

His final position, x" after moving back 6 m is gotten from

x" - x' = -6 m

x" = -6 + x'

x" = -6 + 5

x" = -1 m

Thus, his total displacement from his original position is

d = final position - initial position

d = x" - x

d = -1 m - 0 m

d = -1 m

So, his total displacement from his original position is -1 m

Learn more about displacement here:

https://brainly.com/question/17587058

I'm completely stumped as to how to do this.
I know the components of f1 are f1x= 1600, f1y=0, f2x= 433 f2y=250 and f3x= 467

Answers

Explanation:

You have already determined the components of the known forces so I won't repeat your work here. Since the resultant force [tex]\vec{\textbf{R}}[/tex] and F1 are completely along the x-axis, we can conclude that

[tex]F_{2y} = F_{3y} \Rightarrow F_{3y} = F_3\cos{\theta} = 250\:\text{lb}[/tex]

We can now solve for the magnitude of [tex]F_3:[/tex]

[tex]F_3 = \sqrt{F_{3x}^2 + F_{3y}^2} = \sqrt{(467)^2 + (250)^2}[/tex]

[tex]\:\:\:\:=529.7\:\text{lb}[/tex]

The angle [tex]\theta[/tex] is then

[tex]\tan{\theta} = \dfrac{F_{3y}}{F_{3x}} = \dfrac{250}{467}[/tex]

or

[tex]\theta = 49.2°[/tex]

Please help me find the magnitude and direction of the resultant force​

Answers

1.41 is the magnitude and -45° is the direction

A 67 kg man stands at the front end of a uniform boat of mass 179 kg and of length, L = 2.5 m. Assume there is no friction or drag between the boat and water.
(a) What is the location of the center of mass of the system when the origin of our coordinate system (i) on the man's original location (ii) on the back end of the boat? [4 marks]
(b) If the man walks from the front end to the back end of the boat, by how much is the boat displaced? [3 marks]
(c) Now consider the man and his friend with identical mass of 67 kg are rowing the boat on a hot summer afternoon when they decide to go for a swim. The man jumps off the front of the boat at speed 3 m/s and his friend jumps off the back at speed 4 m/s. If the boat was moving forward at 1.5 m/s when they jumped, what is the speed of the boat after their jump?

Answers

Answer:

Explanation:

ai. com=(67*0+179*1.25)/(179+67)=0.91m

ii. com=(67*2.5+179*1.25)/(179+67)=1.59m

b. 0.91=(67(2.5-d)+179(1.25-d))/(179+67)

   d=0.68m

c. 1.5=(67*-3+67*-4+179*v)/(67+67+179)

    v=5.24m/s

The answers to your question are ;

A) Location of the center of the mass of system when origin of coordinate system is

i) On the original location of man = 0.91 m

ii) On back end of boat = 1.59 m

B) The boat is displaced by = 0.68 m

C) speed of boat after their jump ( V ) = 5.24 m/s

Given data :

mass of man = 67 kg

mass of boat = 179 kg

length of boat = 2.5 m

assumptions : No friction/drag force

Solutions

A) determine location of center of mass

i) On the man's original location = 0

= ( mass of man * 0 + mass * 1.25 ) / ( mass of boat + mass of man)

=  ( 0 + 179 * 1.25 ) /  ( 179 + 67 )

= ( 0 + 223.75 ) / ( 246 ) = 0.9096  ≈ 0.91 m

ii) On the back end of the boat

= ( mass of man * length of boat + mass of boat * 1.25 ) / ( mass of boat + mass of man )

= (  67 * 2.5 + 179 * 1.25 ) / ( 179 + 67 )

= ( 167.5 + 223.75 ) / ( 246 ) = 1.590 m

B) By How much is the boat displaced ( d )

0.91 ( location of center of mass from man's original location )

0.91  = (  67 *  (2.5 - d) +  179 (  1.25 - d ) ) / ( 179 + 67 )

        = ( 67 * ( 2.5 - d ) + 223.75 - 179d )) / ( 246 )

∴ d ≈ 0.68 m

C) Determine speed of boat after the jump

Initial speed of boat = 1.5 m/s

hence speed after the jump ( v )

speed of first man = 3 m/s

speed of second man = 4 m/s

1.5 m/s = ( 67 * -3 + 67 * -4 + 179 * v ) / ( 67 + 67 + 179 )

           = ( - 201 + -268 + 179v ) / ( 313 )

∴ v ≈ 5.24 m/s

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Question 3 A woman sitting in a stationary car notices a man cycling past her at 40 km/hr. Five seconds after he passes her car, she starts following after him. What is the shortest possible distance in which she will catch up to the cyclist if he maintains hrs speep and she obeys the speed limit of 70 km/hr? The car has a maximum acceleration

Answers

The shortest possible distance in which she catches up with the man is 129.7 m.

The given parameters:

speed of the man, v₁ = 40 km/hr

speed of the woman, v₂ = 70 km/hr

time when the woman started moving, t₁ = 5 seconds

To find:

the shortest distance when she catches up with the man

Convert the given speed in km/h to m/s

3.6 km/h = 1 m/s40 km/h = 40/3.6 = 11.11 m/s70 km/h = 70/3.6 = 19.44 m/s

Calculate the distance moved by the man before she started following him.

Distance moved by the man = speed x time

                                                = 11.11 m/s  x  5 s

                                                = 55.55 m

Let the time the woman catches up with the man = t

Apply the following simple principle to calculate the time.

The man is moving forward and the woman is moving forward to close the gap between them, thus both speeds are working against each other.

[tex](v_2-v_1)t = 55.55 \ m[/tex]

the difference in the speed is because they are working against each other.

[tex](19.44 - 11.11)t = 55.55\\\\8.33t = 55.55\\\\t = \frac{55.55}{8.33} \\\\t = 6.67 \ s[/tex]

The time when the woman catches up with the man = 6.67 s

The shortest distance at which the woman catches up with the man is calculated as;

Shortest distance = woman's speed x time when she catches up

                               = 19.44 m/s    x  6.67 s

                               = 129.7 m

Thus, the shortest possible distance in which she catches up with the man is 129.7 m.

Learn more here: https://brainly.in/question/9541933?tbs_match=3

You push yourself on a skateboard with a force of 30 N east and accelerate at 0.5 m/s² east. Find the mass of theskateboard if your mass is 58 kg.​

Answers

Answer:

2Kg

first you find the total mass of both the person und skateboard

f = m*a

30 = m* 0.5

m= 30/ 0.5

m= 60 kg

then you subtract the mass of the person from the total mass

m1 - m2

60 - 58

= 2 kg

Taking into account the Newton's second law, the mass of the skateboard is 2 kg.

Newton's Second Law establishes the relationship between the forces acting on an object and the acceleration it experiences. This law says that the acceleration that an object experiences when subjected to a net force (force applied to the body) is proportional to that force.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

F = Force [N] m = Mass [kg] a = Acceleration [m/s²]

In this case, you know:

F= 30 N m= ? a= 0.5 m/s²

Replacing:

30 N= m× 0.5 m/s²

Solving:

m= 30 N÷0.5 m/s²

m= 60 kg

The mass of the sistem is the sum of the mass of the skateboard and the mass of the mass of your body:

Mass= mass of the skateboard + mass of your body

In this case:

60 kg= mass of the skateboard + 58 kg

Solving:

mass of the skateboard= 60 kg - 58 kg

mass of the skateboard= 2 kg

Finally, the mass of the skateboard is 2 kg.

Learn more about the Newton's second law:

brainly.com/question/23845187?referrer=searchResults brainly.com/question/13959891?referrer=searchResults

What is an electricity?

Answers

Explanation:

Electricity is the flow of electrical power or charge.

Decide whether the following statement makes sense (or is clearly true) or does not make sense (or is clearly false), and why.
In the distant past, the cosmic microwave background consisted primarily of infrared light.
A) The statement is true. The cosmic background was released when the universe had the temperature of about 3000 K. That is similar to the temperature of a red star, which emits mostly in infrared wavelengths. Then that wavelength was redshifted.
B) The statement is false. The cosmic background was released when the universe had the temperature of about 30 K. That is similar to the temperature of a molecular gas cloud, which emits mostly in radio wavelengths. Then that wavelength was only redshifted.
C) This statement does not make sense. The cosmic background was released when the universe had the temperature of about 15,000 K. That is similar to the temperature of the blue star, which has peak at about 200 nm, in the ultraviolet wavelength. Then that wavelength was only redshifted.
D) This statement makes sense. The cosmic background was released when the universe had the temperature of about 6000 K. That is similar to the temperature of the Sun, which has peak at about 500 nm, in the visible wavelength. Then that wavelength was redshifted.

Answers

Answer:

A - True and should be 3000kk in (A)

Explanation:

Hope this helps. goodluck......

A scientist obtains images of a particular star, which appears as four separate stars.
Which phenomenon causes the star to appear this way?
O redshift
gravitational lensing
O principle of equivalence
O gravitational time dilation

Answers

Answer:

gravitational lensing

Explanation:

Answer:

Gravitational lensing

Explanation:

Convert each of the following speed into m/sec:
(i) 72 km/h
(ii) 12.6 km/h
(iii) 23.4 km/h
(iv) 306 km/h

Answers

Answer:

(i) 20 m/s

(ii) 3.5 m/s

(iii) 6.5 m/s

(iv) 85 m/s

Explanation:

1(kilometer/hour) = 1000(meters) / 3600(seconds) can also be expressed as 1(kilometer/hour) = 5/18 (meters/second), which is its simplified form. To convert km/h to m/s, directly multiply the given value of speed by the fraction 5/18.

This information is from: https://www.cuemath.com/measurement/km-h-to-m-s/

what happens to the value of g when we move from equator to the pole.the weight of an object is greater at poles than at equator .
why?​

Answers

We know that the size of the Earth is not a perfect sphere, it’s flattened near the poles and bulged near the equator. Since, the equator is bulged, the radius is greater. Since the radius is greater the gravity is lesser than compared to poles.

Hope you understand

A car speeds up from 0.0 m/s to 14.0 m/s
in 3.25 s.
The acceleration of the car is:
A. 14.0 m/s2
B. 4.31 m/s2
C. 45.5 m/s2
D. 10.8 m/s2​

Answers

Explanation:

Its speed is zero at the beginning of the 3.25 s and 14 m/s at the end.

I'm thinking you probably wanted to find the car's acceleration.

Acceleration =(change in speed) / (time for the change).

Acceleration =(14m/s )/ (3.25s) .

Acceleration = 4.31m/s² .

I hope it will help you so.

Have a great day.

Be safe and be happy.

So your answer option (b) when you approximate
Hope I have helped

A racecar races on a circular race track. Calculate the average racing speed given that
distance around the track is 2500 m and the racecar does it in 40 seconds.

Answers

Answer:

Below

Explanation:

You can use this formula to find the average speed or velocity of an object

     speed = displacement / elapsed time

Plugging in our values....

     speed = 2500 m / 40 seconds

               = 62.5 m/s

*if your teacher required you to round to significant figures, you would round this number to 60, as 40 seconds only has 1 significant figure (the number with the least amount of sig figs determines the number of sig figs in the final answer)*

Hope this helps! Best of luck <3

plzzzzzzzzzzzz somebody help, plzzzzzzzz this is important. where are the geniuses out there please help. Thanks in advance .
Four forces act as shown in the
diagram below, calculate their
resultant.
12N
10N
40
30
60°
15N
9N​

Answers

iAnswer:

The resultant vector force = 6.96i - 9.27j

The magnitude = 11.6N

The direction= -53.1 °

Explanation:

i= 10×cos(30) + 15×cos(-60) + 9×cos(-90) + 12×cos(140) = 6.96

j= 10×sin(30) + 15×sin(-60) + 9×sin(-90) + 12×sin(140) = -9.27

In the construction of a bridge kinetic energy was used and now has what kind of energy?Solar Energy, Gravitational Potential Energy, Mechanical Energy, Thermal Energy​

Answers

Answer:

potential energy

Explanation:

Based on energy transformation

The length, breadth and height of a box is 50cm, 20cm and 10cm respectively then find surface area of its base and volume.

Answers

Surface area of base: 1000cm^2
When calculating surface area of just the base, we ignore the height. Therefore, we just multiply the length and height values.
50cm x 20cm = 1000cm^2

Volume = 10,000cm^3
Volume of a box is calculated by multiplying length by breadth by height.
50cm x 20cm x 10cm = 10,000cm^3

Hope this helped!

I just hope this pic will help you

in the same viewing window. Compare the magnitudes of f (x) and g(x) when x is close to 0. Use the comparison to write a short paragraph explaining why

Answers

Answer:

Due to inertia of restttttttrestrestrestrest

Which Scientist discovered
atomic Theory?​

Answers

Answer:

John dalton discovered

value of g is independent of

Answers

the lord of the greeks answer d

Answer:

mass

Explanation:

The value of g (acceleration due to gravitation) is independent of the mass of the object.

Visible light travels at a speed 3.0 × 108 of m/s. If red light has a wavelength of 6.5 × 10–7 m, what the frequency of this light?

Answers

Answer:

speed /wavelength = frequency

f = 3×10*8 /6.5×10*7

f = 4.62

9.1 x 105 – 7.2 x 105
=

Answers

Answer:

1.9 x 10⁵

Explanation:

I ASSUME your question is supposed to read

9.1 x 10⁵ – 7.2 x 10⁵ =

9.1 - 7.2 = 1.9 and the powers are the same so just tag them along

its the same as

910000 - 720000 = 190000

1.9 x 105 could be another possibility if the question is actually posed correctly.

Which of the following is NOT an important phenomenon that commonly erodes and weathers exposed rock outcrops to form sedimentary material?
a) Lightning
b) Wind
c) Rain
d) Freezing/Thawing

Answers

Answer:

Explanation:

While each of these can cause erosion and weathering, lightning is probably the least important as it occurs less frequently and affects a much smaller surface area when it strikes.

Wind is not very effective by itself, but it can carry abrasives which work to degrade rock surfaces. It covers a very large area at once so the net effect can be moderate to large especially desert areas where plants are not readily available to disrupt the flow.

Rain covers huge areas and is quite common.

Freezing/Thawing cycles cover large areas and are quite common in the temperate and arctic latitudes and even in tropical altitudes.

Attached is a photo taken atop Half Dome in Yosemite National Park showing two of thousands of divots in the rock there caused by lightning strikes. The current in the lightning heats the stone causing water trapped in it to flash to steam. The increased pressure inside the stone can overwhelm the material strength and blow rock chunks over a fairly good sized area. This is a fairly rapid weathering and erosion when it occurs, but that is typically limited to a few dozen days per year and occurs mostly on high ground where lightning is more likely to strike earth.

A positively charged glass rod is bought close to a suspended metal needle. What
can we say about the charge on the needle given that the needle is
a) attracted ?
b) repelled ?

Answers

Answer:

attracted

Explanation:

opposite charges attract each other when the rub against each other

Answer:

This depends because the electrostatic force obeys the principle that states that force between both of the particles does not get affected by the charges of the other thus if the needle is getting attracted it possess negative charges( the opposite charge) .And if they repel it means they have the same charges ( positive charges).

60.96-mile distance in kilometers

Answers

Answer:

98.105610 Kilometers

Explanation:

Rounded to 8 digits

Answer:

98.11 km

Explanation:

60.96 mi (5280ft/mi)(12 in/ft)(2.54 cm/in)(1 m/ 100cm)(1 km/1000 m) = 98.10561024 km

however, reporting this precision to the nearest hundred millionth of a kilometer is silly as we only know the mile dimension to the nearest hundredth of a mile.

A hundredth of a mile is 5280/100 = 52.8 ft or just over 16 m

It would only be a little bit of a presumption to give our precision to the nearest 10 meters as I have done.

This also fits neatly into the significant digits rule. Both the original dimension and the converted dimension have four significant digits.

Driving home from school one day, you spot a ball rolling out into the street . (See the figure below) You brake for 1.50 s , slowing your 950-kg car from 16.0 m/s to 9.50 m/s.

a)What was the magnitude of the average force exerted on your car during braking?

b)What was the direction of the average force exerted on your car during braking?

c)How far did you travel while braking?

Answers

Answer:

a) 4116.67 N

b) negative (assuming car is traveling in positive direction)

c) 19.125 m

Explanation:

Part A)

We can find the average force exerted on the car by using Newton's 2nd Law: F = ma.

We have the mass (950 kg) but we do not have the acceleration. Let's solve for this using kinematics.

We have the time during braking, the initial and final velocity, and we need to find the acceleration. To do this, we can use the following equation: v = v₀ + at.

v (final velocity) = 9.50 m/sv₀ (initial velocity) = 16.0 m/st (time) = 1.50 s a = ?

Substitute these values into the equation.

v = v₀ + at9.50 m/s = 16.0 m/s + a (1.50 s) 9.50 = 16.0 + 1.50a -6.50 = 1.50a a = -4.333333... m/s²

The car's acceleration during the braking period is -4.33 m/s², assuming the car is traveling in the positive direction.

Now, we can use this to plug into Newton's 2nd Law to find the force exerted on the car.

F = maF = (950 kg) (-4.33...) F = -4116.666667 N

The magnitude of the average force exerted on the car while braking is the absolute value, so it is 4116.67 N.

Part B)

The direction of the average force is denoted in the negative sign. It is opposite the direction of the car's motion. Assuming that the car is traveling in the positive direction, the direction of the average force exerted on the car is in the negative direction since this force is slowing the car down while braking.

Part C)

We can find the distance traveled during the braking period by using another kinematic equation.

We have the initial and final velocity, and the time traveled, so we can use this equation: Δx = v_avg · t.

Note that v_avg is the same thing as (v + v₀) / 2.

Substitute the known values into the equation.

Δx = [(9.50 + 16.0)/2] · 1.50 Δx = 12.75 · 1.50Δx = 19.125 m

The car traveled 19.125 m while braking.

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