Answer:
The repetition principle is important in scientific research, because the observational indexes are random variables, which require a certain amount of samples to reveal their changing regularity. ... Repetition is multiple trials, when replication is when you redo the entire experiment.
Explanation:
Explanation:
If you repeat the steps in an experiment, this gives us a better judgement and a clearer overall conclusion and results. :)
Which of the following choices is not an example of a giant molecule
Explanation:
A substance containing a large number of atoms which are covalently bonded, is called a giant molecule or a giant covalent lattice. There are four examples of molecules made from non-metals which form giant structures. They are silicon, silicon dioxide and two forms of the element carbon called diamond and graphite polymers are a different kind of large molecule.
Please mark me as brainliest .
Meiotic recombination produces new genetic information in sister chromatids.This Happens During prophase I. Order the stages of prophase I chronologically: ____ Diplotene.-The synaptonemal complex dissociates; homologous pairs remain attached (chiasmata).
Answer:
See the answer below
Explanation:
The various stages of propase I of meiosis I in chronological order would be
1. Leptotene
2. Zygotene
3. Pachytene
4. Diplotene
5. Diakinesis
The leptotene stage is characterized by the thickening or condensation of the genetic material in the nucleus such that 'thick thread' structures is formed.
At the zygotene stage, the thickness advances and structures can be seen as chromosomes under the microscope. Homologous chromosomes are seen pairing up (synapsis) through the formation of synaptonemal complex to form tetrads or bivalents.
At pachytene, an exchange of chromosomal segments between synapsed homologous chromosomes occur in a process known as crossing over. The exchange point along the synapsed chromosomes are known as the chiasmata. After the crossing over, homologous chromosomes begin to separate but remains joined at the chiasmata.
At diplotene, the dissolution of the synaptonemal complex occur and homologous chromosomes still held together by the chiasmata begin to repel one another. The chiasmata becomes terminalized.
At Diakinesis, chromosomal condensation is completed and the cell is conditioned to progress to metaphase I of meiosis I.
I want to understand what is a strome !!!???
Answer:
Do you mean the Stroke?
Explanation:
If you mean Stroke, it is a spongey transparent substance in a plant cell that helps support its function
Which of these actions is likely to prevent the spread of pathogens in the environment?
Washing hands once a week
Coughing out loud
Touching wounds
Washing fruits
Answer:
A or D
Explanation:
Coughing out loud and Touching wounds will spread it, not prevent it, Its most likely D, because only washing your hands once a week is basically useless and will prevent little- to nothing so washing fruits is your best bet I would go with D
Write T next to the statements that are true. Write F next to the statements that are false. Then write
corrected versions of the statements that are false.
a Stems carry food from the roots to the leaves.
b The parts of a plant that make food are usually green.
c Roots are the only organs in a plant that need water.
Answer:
a= T
b=T
c=F
Explanation:
the answer is correct
Humans are know to have 46 chromosomes in each somatic cell. The domesticated cat, on the other hand, has 38 chromosomes in somatic cells. Given this predict the number of chromosomes found in the following cat cells:
Sperm cell:
Egg cell:
Daughter cell from mitosis:
Daughter cell from meiosis 1:
Daughter cell from meiosis 2:
Answer:
Sperm cell: 19 chromosomes
Egg cell: 19 chromosomes
Daughter cell from mitosis: 38 chromosomes
Daughter cell from meiosis 1: 19 chromosomes
Daughter cell from meiosis 2: 19 chromosomes
Explanation:
There are two major divisions that occur in living organisms namely: meiosis and mitosis. Meiosis is called a reduction division because it reduces the chromosomal number of offsprings by half while mitosis is called multiplication division because it maintains the same number of chromosome in the parent cell.
According to this question, a cat has 38 chromosomes in its somatic/body cells. It will possess the following chromosome numbers after the type of division:
- Sperm cell: 19 chromosomes because sperm are gametes formed via meiotic division, hence, 38 chromosomes are reduced by half i.e. 38/2 = 19.
- Egg cell: 19 chromosomes because egg cells are gametes formed via meiotic division, hence, 38 chromosomes are reduced by half i.e. 38/2 = 19.
Daughter cell from mitosis: 38 chromosomes because mitosis maintains the number of chromosomes as parent.
Daughter cell from meiosis 1: 19 chromosomes because the actual reduction from diploid (38 chromosomes) to haploid (19 chromosomes) takes place in meiosis 1 due to separation of homologous chromosomes.
Daughter cell from meiosis 2: 19 chromosomes because sister chromatids, which becomes individual chromosomes, are separated at this stage.
Which location is most vulnerable to primary succession?
O A. A newly paved parking lot
O B. An overgrazed prairie
O C. A well-maintained ranch
O D. A newly formed island
BUBMIT
PREVIOUS
o
A
TO
Answer:
A. A newly paved parking lot
Explanation:
Match each enzyme namewith the correct descriptive phrase.
a. Ads through an adenylylated DNA intermediate
b. Catalyzes mitochondrial DNA replication
c. Catalyzes most nucleotide incorporations in bacterial DNA replication
d. Catalyzes formation of a double-strand DNA break
e. Cleaves RNA in a DNA — RNA hybrid molecule
f. Uses a tRNA primer in synthesis of retroviral DNA
1. Topoisomerase Il
2. DNA ligase
3. DNA polymerase γ
4. Reverse transcriptase
5. DNA polymerase I
6. DNA polymerase Ill
Answer:
The correct answer is -
a. 2
b. 3
c. 6.
d. 1
e. 5
f. 4
Explanation:
Topoisomerase II is the enzyme that catalyzes the formation of double-strand DNA breaks.
DNA ligase is the enzyme that catalyzes through adenylated DNA intermediate
DNA polymerase gamma is n enzyme that acts on the Mitochondrial DNA replication.
The reverse transcriptase uses a tRNA primer during catalytic reaction in the synthesis of retroviral DNA
DNA pol I breaks RNA in a DNA-RNA hybrid molecule in their catalytic reaction.
DNA pol IIIused in catalyzing and acts as major enzyme, the most nucleotide incorporations in bacterial DNA replication
nucleotides are the basic
unit for which macro molocules
The correct answer to question is Nucleic Acids, (DNA) AND (RNA).
hope this helps let me know.
What is the difference between lymph and lymph vessels
Answer:
A thin tube that carries lymph (lymphatic fluid) and white blood cells through the lymphatic system. Also called lymphatic vessel. Anatomy of the lymph system, showing the lymph vessels and lymph organs including lymph nodes, tonsils, thymus, spleen, and bone marrow.
Susan went to an oncologist because some cancerous cells had been detected within her breast
tissue. Which of the following is NOT a warning signal for cancer?
Answer:
Cancerous
Explanation:
Cancerous doesn't mean cancer
Describe how oxygen is transported in blood, and explain how temperature, pH, BPG, and affect oxygen loading and unloading.
Solution :
The flow of oxygen in the blood is been transported by two ways :
1. in plasma 1.5%
2. bound to hemoglobin 98.5%
As the oxygen loads in the body, affinity of the Hb makes the oxygen loading very efficient in the blood. The Hb molecule gets saturated when all the 4 hemes are oxygen binded.
The decreased pH weakens the hemoglobin oxygen binding in the tissues.
Higher temperatures in the oxygen means a lower affinity and thus more oxygen is released and so the oxygen unloads.
Increase in the temperature, the BPG and the modification of the structure in the hemoglobin decreases the affinity for the oxygen and further enhances the unloading of the oxygen in the blood.
Umm.. Hi there! Can someone please help me out with this? (only for those who know the answer)
Bcoz I really need this rn :(
even though it is multiple choice, I still need your explanation for your answers. Thanks!!
DUEEEE AFTERRR LUNCHH! :(:(:(:(
If your answer is NONSENSE it will be deleted as soon as possible!
But if your answer is CORRECT, HELPFUL, HAS AN EXPLANATION, I'll chose your answer as the BRAINLIEST ANSWER!
Answer:
(b)(c)(a)(b)(d)(d)Explanation:
1.
I saw the similarity that there are 7 periods in a periodic table and 7 days in a week.
2.
The periodic table tells us both the symbol and atomic number of the elements.
3.
days as there are 7days in a week.
4.
vertical columns are called groups.
5.
seeing the periodic table we can locate it postion that is group 16 period 2.
CONCLUSION :-
1. all the given points tell the properties of periodic table.
Flows of energy and cycles of nutrients link the biotic and abiotic components of ecosystems into a/an __________ system, ultimately structuring the feeding relationships, or __________ structure of organisms that inhabit them.
Answer:
The correct answer is - dynamic and trophic.
Explanation:
A/an dynamic system is linked to lows of energy and cycles of nutrients link the biotic and abiotic components of ecosystems that structure the feeding relationships, or trophic structure of organisms that inhabit them. The trophic structure is the position of the organism in the ecosystem and food chain.
The correct answer is - dynamic and trophic.
During which dates of the cycle does the level of estrogen in the blood increase most rapidly? What happens to the uterus during this time?
Question 5 options:
The greatest rise in estrogen levels happens as the corpus luteum expands. This increase acts on the anterior pituitary to inhibit the release of FSH and trigger the release of GnRH from the hypothalamus. (This leads to an increase in LH levels.) The endometrium begins to thicken.
The greatest rise in estrogen levels happens as the follicle matures. This increase acts on the posterior pituitary to inhibit the release of FSH and trigger the release of GnRH from the hypothalamus. (This leads to an increase in LH levels.) The endometrium begins to fall away.
The greatest rise in estrogen levels happens as the follicle matures. This decreases the acts on the anterior pituitary to increase the release of LH and trigger the release of GnRH from the hypothalamus. (This leads to an increase in FSH levels.) The endometrium begins to thicken.
The greatest rise in estrogen levels happens as the follicle matures. This increase acts on the anterior pituitary to inhibit the release of FSH and trigger the release of GnRH from the hypothalamus. (This leads to an increase in LH levels.) The endometrium begins to thicken.
Answer:
option (D) is your right answer
What is the role of DNA polymerase enzymes in replication?
(A) unzipping the double helix by breaking down the hydrogen bonds
(B) adding the free nucleotides to the complementary strand of DNA
(C) splitting the DNA molecule
(D)connecting the fragments on the lagging strand of DNA
Answer:
A
Explanation:
the function of DNA polymerase is to unzip the double helix structure of DNA by breaking down the weak hydrogen bond
Answer:
(B) adding the free nucleotides to the complementary strand of DNA
Explanation:
A DNA polymerase is an enzyme capable of creating new DNA molecules by sequentially adding nucleotides to the three prime (3')-end of a DNA strand. A DNA strand is a polynucleotide chain composed of a linear series of nucleotides, each consisting of a deoxyribose sugar, and phosphate, and a base (i.e., thymine, guanine, cytosine and adenine). Before a cell starts to divide, it needs first to replicate its genetic material by using DNA polymerases that duplicate the cell's DNA during the interphase (S phase). During this process (DNA replication), an enzyme known as helicase unwinds the DNA molecule, which is made up of two antiparallel strands oriented in opposite 3′-5′ directions to each other. Subsequently, each strand is used as a template for its replication through DNA polymerases that can add nucleotides (one at time) to an existing short fragment of RNA, i.e., the primer sequence, which is paired with the template DNA strand.
The fish 'Exocoetus' has well developed fins for gliding in the water. What is the name
of these fins that are used to glide over water?
Answer:
Pectoral fins
The kinetics analyses of an enzyme are measured as a function of substrate concentration in the presence and in the absence of 2mM inhibitor
[S] (microM): 3, 5, 10, 30, 90
Velocity (micromol/min) No Inhibitor: 10.4, 14.5, 22.5, 33.8, 40.5
Velocity (micromol/min) With Inhibitor: 4.1, 6.4, 11.3, 22.6, 33.8
Required:
What are the values of Vmax and Km in the absence of inhibitor? In its presence?
Answer:
take the reciprocal of the values as 1/S and 1/V and plot the values on lineweaver-burk plot.
so the re-arranged data is as following
1/S 1/V (no inhibitor) 1/V (with inhibitor)
0.333 0.096 0.244
0.2 0.068 0.156
0.1 0.044 0.088
0.033 0.029 0.044
0.011 0.024 0.029
and the plotted lineweaver-burk plot with the equation of straight line would be....
where, first line represents the velocity of reaction with no inhibitor and second line represent the velocity in presence of inhibitor. X-axis has the substrate concentration as 1/S and y-axis has the velocity as 1/V.
as per the plot, equation of line on the lineweaver-burk plot, Y = mx + c, where c = 1/Vmax and m = Km/Vmax.
so solve for the given equations.
First, equation of line in the absence of inhibitor is Y = 0.23x + 0.021
so Vmax = 1/0.021 = 47.6 micromol/min
and Km/Vmax = 0.23, or Km = 0.23 x 47.6
Km = 10.95
Km do not have a unit, so 10.95 x 10-6 or as per your values round it up to 1 decimal point as 1.1 x 10-5
so value of Vmax = 47.6micromol/min and Km = 1.1 x 10-5 in the absence of inhibitor.
similarly, equation of line in the presence of inhibitor is given as Y = 0.67x + 0.021
so Vmax = 1/0.021 = 47.6 micromol/min
and Km/Vmax = 0.67
or Km = 0.67 x Vmax = 0.67 x 47.6 = 31.89
Km do not have a unit, so 31.89 x 10-6 or 3.1 x 10-5
so value of Vmax = 47.6micromol/min and Km = 3.1 x 10-5 in the absence of inhibitor.
how does Fibrocartilage receive it's nutrients?
Answer:
These cells receive nutrients through a double diffusion barrier but rely on anaerobic respiration due to low oxygen concentration.
During which days of the menstrual cycle does the level of FSH increase?
Question 1 options:
FSH increases before the menstrual cycle is finished around day 27.
FSH rarely increases during the menstrual cycle, it stays level unless the follicle has been implanted.
FSH increases during the follicular stage of the ovarian cycle (between day six and day fourteen).
FSH increases during the follicular stage of the ovarian cycle (between day one and day six) and then peaks on the 13th day.
Answer:
option (C) is correct answer
Which organisms transform nitrogen to a form that is useful to plants?
Answer:
nitrogen-fixing bacteria is the answer
Explanation:
Nitrogen-fixing bacteria are a type of organisms that transform nitrogen to a form that is useful to plants.
Consider the following research question.
Research Question: Why is yeast used to bake bread?
Which hypothesis is based on this research question?
A. Yeast is a living organism.
B. Some people try to lose weight by cutting bread out of their diet.
C. A comparison of rye bread to wheat bread indicates that rye bread
is more enjoyable to eat.
O D. Yeast added to bread dough produces a gas, and this causes the
dough to rise, making the finished bread look like a sponge.
Answer:
d
Explanation:
All living things are made of cells discovered throught what
Answer:
A microscope
Explanation:
Because Microscopes magnify small objects. Some microscopes can even be used to observe an object at the cellular level, allowing scientists to see the shape of a cell, its nucleus, mitochondria, and other organelles.
If I increase the amount of sleep I get then I will be able to run faster what is the independent and dependent variable
__________________ moves the respiratory medium over the respiratory surface.
Group of answer choices
perfusion
percolation
ventilation
diffusion
Answer:
ventilation
Explanation:
Breathing, also known as ventilation, is the process of moving air or water in order to facilitate the gas exchange between the external and internal (body) environment, mostly to eliminate carbon dioxide (CO2) and bring in oxygen (O2). For example, fish are aquatic animals that need to run water over their gills to get the O2 that they need to survive (gills are organs that create a large surface area for ventilation). Moreover, insects ventilate their tracheal system to get O2. Finally, terrestrial vertebrates (i.e., amphibians, reptiles, birds, and mammals) use organs called lungs to exchange O2 and CO2 between their cells and the external environment.
Mitosis and Meiosis lab conclusion
Answer:
Conclusion. To sum up, Mitosis and Meiosis are cell division processes which aids with our daily life. Without the process of meiosis and mitosis, cells would not be able to replicate. Also genetic variation and cell growth would not be possible.
"During cytokinesis of an animal cell, a cell plate grows from the center moves outward"
True
False
Answer:
True
Explanation:
Which of the following is not a hormone and neurotransmitters except
A) epinephrine
B)dopamine
C) serotonin
D) acetylcholine
Imagine that there is a mutation in the cyclin gene such that its gene product is nonfunctional. What kind of effect would this mutation have on a skin cell in the area of a cut
Answer:
The correct answer is - The cell would be unable to produce.
Explanation:
Cyclin is a protein that helps in cell division to complete the various stages. It has an essential function, however, cyclin does not play role in enzymatic reactions bit bind with cyclin-dependent kinase enzyme they form maturation promoting factors which can phosphorylate specific proteins and result in many different stages of the cell cycle.
Mutation in cyclin gene that did not allow to produce cyclin protein will cease the cell cycle and there would be no future daughter cell and the cell would not be able to produce.
Alkaptoneuria is a recessive genetic disorder found among North American populations at a frequency of about 1 in 500,000 births. How frequently would you expect this defect to be expressed among children of second cousin marriages
Answer:
The correct answer is - 1/41,493
Explanation:
Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:
2pq + 2pqF. ( where F is the inbreeding coefficient).
The frequency of the two different hoozygotes in inbred population can be calculated as:
p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.
Given: Frequency of Alkaptonuria (q 2) = 1:500, 000
=> q = 1/707
p = 706/707 ( Approx values)
solution:
Inbreeding coefficient (F) = 1/64
Therefore,
Frequency of Alkaptonuria in second cousins= q 2 + pqF
= 1/500, 000 + (706/707 x 1/707) x (1/64)
= 1/500, 000 + 1/45, 248
= 1/41,493 (approx)
