Answer:
105571.2 m/s
Explanation:
Using the formula connecting linear and angular velocity;
V = rω
r = radius of the circular path
ω = angular velocity
Since
1 rpm = 2π60 rad/s
800 rpm = 800 * 2π60 rad/s = 301632 rad/s
Substituting values;
V = 35/100 * 301632 rad/s
V= 105571.2 m/s
PLEASE HELP WITH THIS QUESTION
What of Newton's 3 laws is represented in this picture?
Answer:
The first law states that an object at rest will stay at rest, and an object in motion will stay in motion unless acted on by a net external force. Mathematically, this is equivalent to saying that if The second law states that the rate of change of momentum of a body over time is directly proportional to the force applied, and occurs in the same direction as the applied force. the net force on an object is zero, then the velocity of the object is constant. The third law states that all forces between two objects exist in equal magnitude and opposite direction: if one object A exerts a force FA on a second object B, then B simultaneously exerts a force FB on A, and the two forces are equal in magnitude and opposite in direction
Explanation:
A car has a kinetic energy of 103kJ.
The speed of the car is 13.1 m/s.
Calculate the mass of the car.
Give your answer to 2 significant figures.
Answer: 1200kg
Explanation:
KE = (1/2)mv^2
103kJ = 103000J
103000J = (1/2) * m * (13.1m/s)^2
Solve for m
A car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
A car has a kinetic energy of 103 kJ. The speed of the car is 13.1 m/s,
The kinetic energy of the car = 1/2 × mass × velocity
103000 =0.5 × mass × (13.1) ²
The mass of the car = 1200 Kilogram
Thus, if a car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
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In the Vector Addition Lab, the following data was collected for determining the displacement from the door of the Physics classroom to another location in the building: 2 m, West; 14.0 m, South; 25.0 m, East; 11.0 m, North; and 2 m, West. The magnitude of the resultant displacement from the physics classroom to the assigned location is closest to ___ meters. (Round to the nearest integer.)
Answer:
21 m
Explanation:
Since the displacement from the door is 2 m West, we have our vector as -2i. The vector representing 14.0 m South is -14.0j. The vector representing 25.0 m East is 25.0i. The vector representing 11.0 m North is 11.0j. And, the vector representing 2.0 m West is -2.0i.
So, to get our position vector at the other location, we add all the vectors together.
So, r = -2i + (-14.0j) + 25.0i + 11.0j - 2i
= -4i + 25.0i - 14.0j + 11.0j
= 21.0i -3j m
Now, if we assume the position vector for the door is at the origin, we have r₀ = 0i + 0j m
So, our displacement from the door is r - r₀ = 21.0i - 3.0j - (0i + 0j) = 21.0i - 3.0j
So, the magnitude of the resultant displacement |r - r₀| = √(21.0² + 3.0²)
= 3.0√(7.0² + 1)
= 3.0√(49 + 1)
= 3.0√50
= 3.0 × 7.0711
= 21.2
≅ 21 m to the nearest integer
A motor has an internal resistance of 12.1 Ω. The motor is in a circuit with a current of
4.0 Amps
What is the voltage?
Answer:
Explanation:
V = I * R
V = 4 * 12.1 = 48.4 v
A positively charged rod is brought close to a neutral metal sphere. Explain what
happens to the charges in the neutral sphere as the rod comes close, touches the
sphere, and then moves away. Is the metal sphere still neutral at the end of this
encounter?
Answer:
No, the metal sphere becomes positively charged because electrons are transferred from the sphere to the rod.
If a rod attached to the approaching charge if the rod consists of "stiff" spring-like bonds for which atoms undergo small oscillations. What can we say, about these springlike bonds when the charge is first, furthest away and second, closest to the source charge
Answer: hello options related to your question is missing attached below is the missing part of your question
answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )
Explanation:
When the Charge is first, Furthest away and second and closest to the source charge. The spring like bonds can be said to have No charge of the length of the bonds expected because the rod did not touch the charge source when Furthest away the bond with charge will be less effective
Types of energy transformation
Answer:
This is the types of energy transformation
Explanation:
hope it helps
What state of matter did the earth need to be in order for planetary differentiation to occur?
Answer: Gas, liquid, or solid?
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick
5. What type of chemical reaction is shown?
1 point
2 AgNO3 + CuCl2
-
2 AgCl + 2 Cu(NO3)2
Synthesis
Decomposition
Singe Replacement
Double Replacement
Combustion
Answer:
double Replacement
Explanation:
The mutual replacement of radical and ions between the two compounds or molecules is called double replacement.
General equation : AB+CD = AD +B
if a car is taken from the garage driven for 100km before returning to the garage after 2 hours what is it average speed?
Answer:
50km/h
Explanation:
Average Speed = Distance/Time
100km/2h = 50km/h
What is the sum of a systems potential and kinetic energy is equal to?
a. Total Energy
b. Mechanical Energy
c. Thermal Energy
d. Hyper Energy
Answer:
Explanation:
TE = KE + PE which is total energy available to a system is equal to its potential energy plus its kinetic energy, and that total energy will remain throughout the entire "trip", whatever it might be. So a is your answer.
give an example of a body with uniform acceleration
Answer:
A ball rolling down the slope.
A bicycle rider is riding the bicycle on tthe slope where both pedals are engaged.
Amelia is doing an experiment in which she is
going to burn various solid chemicals to see the
colors of flames they produce. For this laboratory
experiment, what types of safety precautions
should she take?
tie hair back
leave open flame unattended to get a drink
only burn the amount of chemicals as
directed by the lab procedure
put out the flame with water from the eyewash
station
Answer:
tie hair back
only burn the amount of chemicals as
directed by the lab procedure
Explanation:
The correct safety precautions for Amelia to take from the options would be to tie her hair back and to only burn the amount of chemicals recommended by the lab procedure.
With her hair left flowing freely, Amelia runs the risk of the hair catching flame while trying to burn the chemicals according to the procedure. Hence, tying her hair up into one neat bunch will limit the risk of it catching fire while working in the lab.
Also, burning less or more than the amount of chemicals recommended by the procedure may be dangerous or hinder Amelia from getting the right result.
Answer:
1,3
Explanation:
just did it
What is the three-body problem? Explain at a level so an 8th grader could understand
Answer:
In physics and classical mechanics, the three-body problem is the problem of taking the initial positions and velocities (or momenta) of three point masses and solving for their subsequent motion according to Newton's laws of motion and Newton's law of universal gravitation.[1] The three-body problem is a special case of the n-body problem. Unlike two-body problems, no general closed-form solution exists,[1] as the resulting dynamical system is chaotic for most initial conditions, and numerical methods are generally required.
Hope this answer is right!
how can you account for the differences in the entropies of combination of methyl propane (-1465J/mol K) and butane (1465J/mol K)
Explanation:
The change in entropy is a measure of temperature. When the temperature of a compound or a system increases, there will be more randomness in the system.
The boiling point is directly related to the number of carbon atoms but is indirectly proportional to the branching in a hydrocarbon.
Butane and methyl propane, both have 4 carbon atoms.
But, butane has 4 carbon atoms in a straight chain while methyl propane has 3 carbon atoms in a straight chain and 1 methyl substituent which makes it a branched hydrocarbon.
Thus, the boiling point of methyl propane will be less than the butane. Likewise, the pattern in entropies will be seen.
Calculate the electric potential at point A, the middle of the rectangle, and at point B, the middle of the right-hand side of the rectangle. How would you find the electric potential?
Answer:
With the help of formula.
Explanation:
We can calculate the electric potential of any point through the formula of electric potential which is given below.
Electric potential = Coulomb constant x charge/ distance of separation.
Symbolically it can be written as, V = k q/ r where
V = electric potential
k = Coulomb constant
q = charge
r = distance of separation
If we have all these data, we can simply put the data in the formula and we will get the value of electric potential.
A piece of iron has a mass of 30 g and its volume is 6.2 cm3. What is its density?
Answer:
Density = 4.84 g/cm³
Explanation:
Given the following data;
Mass = 30 g
Volume = 6.2 cm³
To find the density of the piece of iron;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Substituting into the equation, we have;
[tex]Density = \frac{30}{6.2}[/tex]
Density = 4.84 g/cm³
Which variable is represented by the following symbol? λ
a. Wavelength
b. Amplitude
c. Frequency
d. Velocity
Answer:
A
Explanation:
Wavelength is represented by lambda
A 50.0 kg object is moving east at an unknown velocity when it collides with a 60.0 kg stationary object. After collision, the 50.0 kg object is traveling at a velocity of 6.0 m/s 50.0degree N of E and the 60.0 kg object is traveling at a velocity of 6.3 m/s 38degree S of E.
What was the velocity of the 50.0 kg object before collision?
p=m•v is the formula.
The principle of conservation of momentum states that:
momentum before collision = momentum after collisionMomentum = mass * velocityMomentum before collision:
Velocity of 50.0 kg object = v m/s
Momentum of 50.0 kg object = 50 * v
Momentum after collision:
Velocity of the 50.0 kg object = 6.0 m/s 50.0degree N of E
Velocity of the 60.0 kg object = 6.3 m/s 38degree S of E.
Momentum of 50.0 kg object = 50 * 6 = 300 kgm/s
Momentum of 50.0 kg object = 60 * 6.3 = 378 kgm/s
Total momentum after collision = 678 kgm/s
From the principle of conservation of momentum:
50 kg * v = 678 kgm/s
v = 678 kgm/s / 50 kg
velocity, v = 13.56 m/s
Therefore, the velocity of the 50.0 kg object before collision was 13.56 m/s.
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A test car and its driver, with a combined mass of 600 kg, are moving along a straight,horizontal track when a malfunction causes the tires to stop rotating. The car skids to a halt with constant acceleration, leaving skid marks on the road during the whole time it skids. Which two of the following measurements, taken together, would allow engineers to find the total mechanical energy dissipated during the skid?
A. The length of the skid marks
B. The contact area of each tire with the track.
C. The coefficent of static frction between the tires and the track.
D. The coefficent of static frction between the tires and the track.
Answer:
The two of the following measurements, when taken together, would allow engineers to find the total mechanical energy dissipated during the skid
B. The contact area of each tire with the track.
C. The co-efficent of static friction between the tires and the track.
D. The co-efficent of static friction between the tires and the track.
Explanation:
please helpppp... thank u ❤️
Answer:
For Ryan:
[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]
For the football kicked:
[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]
Answer:
the highest point for the first question is 0 meters per second
the answer for question 2 is 45 degrees
The specific heat capacity of sea water is 4100 J/Kg°C and the boiling point of 100.6 °C. (i) Calculate the energy required to raise the temperature of 0.900 kg of this sea water from 10 °C up to its boiling point. Also mention the equation to be used. *
Answer:
334.314 (kJ)
Explanation:
1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.
2) according to the formula above:
Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).
A 75kg hockey player is skating across the ice at a speed of 6.0m/s. What is the magnitude of the average force required to stop the player in 0.65s?
Answer:
692.31 N
Explanation:
Applying,
F = ma............... Equation 1
Where F = Average force required to stop the player, m = mass of the player, a = acceleration of the player
But,
a = (v-u)/t............ Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............ Equation 3
From the question,
Given: m = 75 kg, u = 6.0 m/s, v = 0 m/s (to stop), t = 0.65 s
Substitute these values into equation 3
F = 75(0-6)/0.65
F = -692.31 N
Hence the average force required to stop the player is 692.31 N
Let's say you cut open a log of wood with an axe, what type of simple machine are you using? Does it matter how sharp it is?
yes it matters because if it's not sharp it would take all day
Answer:
an axe is a type of machine called a wedge. it does matter how sharp your axe is. if your axe is not sharp then you will have a harder time cutting wood.
Explanation:
What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
Derive the relation between wavelength, frequency and speed of sound.
Explanation:
sorry I need some points foe this
Loops spaced further apart create a stronger electromagnet. True or False
Answer:
False
Explanation:
Electromagnetic strength is inversely proportional to separation distance
what current flows between a voltage of 120v across a resistance of 30Ω?
Answer:
4 amp
Explanation:
From ohm's law,
V=IR
so,
I=V/R
I=120/30
I=4amp ans..
I just... I don't know man I suck at physics :(
A tour guide shouts across a canyon. At a temperature of 20 °C, her echo is heard 2.00 s later. How wide is the canyon?
The answer is 340 m I just don't know how to get that....
Explanation:
Sound travels from the tour guide to the other of the canyon and then back, thus hearing the echo. The time of 2.0 s represents the time it takes the sound to make a round trip, therefore it takes 1.0 s for the tour guide's voice to reach the other side of the canyon. At 20°C, the speed of sound is 343 m/s therefore the width of the canyon is
[tex]x = vt = (343\:m/s)(1.0\:s) = 343\:m[/tex]
The canyon in the given question is 340 m wide.
What is echo?Echo is a reflection of sound that comes to the listener after the direct sound, but with a delay. The delay is inversely proportional to the separation between the source and the listener of the reflecting surface.
To hear the echo, the following conditions must be met:
There must be a minimum of 17 meters between the sound source and the reflecting surface, and there must be at least 0.1 seconds between the original sound and its echo.
Given parameters:
When a tour guide shouts across a canyon, her echo is heard 2.00 s later. That means, in two seconds the sound goes to other wall of canyon and reflected back.
At a temperature of 20 °C, velocity of sound is 340 m/s.
So, the wide is the canyon be = velocity of sound × time/2
= 340 m/s ×2 s/2s = 340 m.
Hence, the wide is the canyon be 340 m.
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