While completing the pedulum experiment, you should measure the length of the pendulum to the middle of the pendulum bob to caculate the required values.
What part of a pendulum do you measure?A ruler, meter stick, or measuring tape are necessary in order to determine the length of a pendulum. Start the measurement at the point where the string pivots from its attachment at the string's upper end. As you reach the item dangling from the string, the pendulum bob, measure all the way down to its center.
The smallest time intervals are measured using a pendulum clock. A little stone or metallic ball suspended from a stiff stand by a thread is the basic component of a pendulum. Bob is the name of the metallic ball.
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A horizontal force of magnitude 35.0N pushes a block of mass 4.00kg across a floor where the coefficient of kinetic friction is 0.600. (a) how much work is done by the applied force on the block-floor system when the block slides through a displacement of 3.00m across the floor? (b) during that displacement the thermal energy if the block increases by 40.0J. what is the increase in thermal energy of the floor? (c) what is the increase in the kinetic energy of the block?
Answer to following (a) , (b) and (c) question are: 63.00 J, 40.0 J, 63.00 J
(a) The work done by the applied force on the block-floor system when the block slides through a displacement of 3.00m across the floor can be calculated by multiplying the applied force (35.0 N) and the displacement (3.00 m), with a coefficient of kinetic friction (0.600) for the system. Thus, the work done is 35.0N * 3.00m * 0.600 = 63.00 J.
(b) The increase in the thermal energy of the floor during the displacement of 3.00m is equal to the thermal energy of the block (40.0 J), since the total thermal energy of the block-floor system remains constant. Therefore, the increase in thermal energy of the floor is 40.0 J.
(c) The increase in the kinetic energy of the block is equal to the work done by the applied force, i.e., 63.00 J.
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you have an rc circuit with a time constant of 5.35 s. if the total resistance in the circuit is 231.2 k , what is the capacitance of the circuit (in f)? don't type the units into the answer box.
The capacitance of the circuit (in f) is 2.31×10⁻⁵F for the rc circuit with a time constant of 5.35 s. if the total resistance in the circuit is 231.2 k.
What is the capacitance of the circuit?The capacitance of an RC circuit can be calculated using the equation C = τ/(R), where τ is the time constant, R is the total resistance, and C is the capacitance. For this RC circuit, the time constant is 5.35s and the total resistance is 231.2 k. Therefore, the capacitance is 5.35s/(231.2k) = 2.31×10⁻⁵F.
Time constant of the RC circuit, τ = 5.35s
Total resistance in the circuit, R = 231.2 kΩ = 231200 Ω
Capacitance of the circuit = ?
We know that, Time constant (τ) of a RC circuit = R × C.
where, R is the resistance in ohms, C is the capacitance in farads. Substitute the given values in the above equation:
τ = RC
5.35 s = R × C231200 Ω × C = 5.35 s
C = 5.35 s / 231200 Ω
C = 2.31 × 10⁻⁸ F.
Therefore, the capacitance of the circuit is 2.31 × 10⁻⁸ F.
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The colors on an oil slick are caused by reflection and (explain why)
a. Diffraction
b. Interference
c. Refraction
d. Polarization
e. Ionization
"The colours on an oil slick are caused by reflection and interference." Correct option is B.
Different bands of the oil slick create different colours as the oil film progressively thins from the centre to the edges.
Interference is what gives an oil slick drifting on water or a soap bubble in the sun their vibrant colours. The colours that interact most positively are the ones that are most vibrant. Thin film interference is the name given to the phenomenon because it occurs when light reflected from various thin film surfaces interferes with one another.
The most crucial interfering principle is the superposition principle.
This hair colour procedure primarily uses jewel tones and rainbow colours, including burgundy, royal blue, deep purple, green, and deep red. Alternating the colours that give your hair an oil spill appearance is the best method to make your skin tone and hair look good together. Best choice is B.
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A car has an intial velocity of 50 km hr after 5 h, its final velocity is 70 km hr. solve for the car acceleration
Answer:
4 km/hr^2
Explanation:
We can use the formula for acceleration:
a = (v_f - v_i) / t
where:
a = acceleration
v_f = final velocity
v_i = initial velocity
t = time taken
Substituting the given values, we get:
a = (70 km/hr - 50 km/hr) / 5 hr
a = 20 km/hr / 5 hr
a = 4 km/hr^2
Galena's specific gravity is 7.5, that of quartz 2.65, and that of liquid mercury 13.6. Given equal-sized samples (volumes) of galena and quartz, which will feel heavier? Choose one: A. galena B. The same volume of water will feel heavier than both of them. C. They will feel about equal. D. quartz
Given equal-sized samples (volumes) of galena and quartz, the Galena sample will feel heavier because of its higher specific gravity. Thus, the correct option is A.
What is the Specific gravity of a substance?Specific gravity is the ratio of the density of a substance to the density of a standard substance in physics. It's typically applied to liquids and solids, but it may also be applied to gases. The most often utilized standard material for liquids and solids is water at 4°C. A substance's specific gravity is dimensionless and is often represented by the Greek symbol ρ.
Relative Density of the given substances:
Galena's specific gravity is 7.5, Quartz's specific gravity is 2.65, and Liquid mercury's specific gravity is 13.6. An object with a specific gravity greater than 1 sinks in water, while one with a specific gravity less than 1 floats in water. The specific gravity of water is 1.0. An object with a specific gravity greater than 1 sinks in water, while one with a specific gravity less than 1 floats in water.
We can conclude from the values above that liquid mercury is heavier than galena, which is in turn heavier than quartz. Therefore, since both quartz and galena are being measured with equal sizes or volumes, galena will feel heavier than quartz.
Therefore, the correct option is A.
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determine whether each geologic feature is being caused by tensional, compressional, or shear stresses by analyzing the directions of the forces being applied.
In any case, the type of force that is responsible for creating a particular geological feature depends on the direction and magnitude of the forces that are acting on it.
Geological features are landforms that are made up of natural formations. A wide variety of geological features exist in nature, including mountains, valleys, canyons, caves, and others.
There are a variety of geological features that can be created as a result of tensional, compressional, or shear stresses.
Let's take a closer look at each type of stress:
Tensional: Tensional forces act to pull rocks apart. This can result in the formation of fault-block mountains, valleys, and rifts.
Compressional: Compressional forces act to push rocks together. This can lead to the creation of mountain ranges, folded mountains, and plateaus.
Shear Stresses: Shear stresses act to twist or bend rocks. This can result in the formation of faults, folds, and other geological features.
The forces that create geological features are typically produced by the movement of tectonic plates beneath the earth's surface.
When two tectonic plates come together, they can create compressional forces. When they move apart, they can create tensional forces.
When they slide past each other, they can create shear stresses. Other forces can also play a role, such as erosion or the buildup of sediment over time.
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When a ball bounces against a wall there will be large change in velocity in short period of time. This means the ____ is large, hence the net ___ must be proportionately large as well.
A change in velocity in short period of time means the acceleration is large, hence the net force must be proportionately large as well.
What is a force?A force is a physical quantity that induces a body to undergo an alteration in speed, direction of motion, or shape. A force can be classified as a push or a pull. When forces are equal, the forces are balanced and the object is not moving. Otherwise, if the forces are not equal, making it unbalanced will not give the object any movement.
The force that induces the change in the speed or direction of an object is referred to as a net force. The net force is equal to the product of the mass of the object and its acceleration. Newton (N) is the unit of measurement for force.
When a ball bounces against a wall, there will be a large change in velocity in a short period of time. This means the acceleration is large, hence the net force must be proportionately large as well.
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A 200 g air-track glider is attached to a spring. The glider is pushed 10.0 cm against the spring, then released. A student with a stopwatch finds that 10 oscillations take 12.0 s. What is the spring constant? A 200 g ball is tied to a string. It is pulled to an angle of 8.00degree and released to swing as a pendulum. A student with a stopwatch finds that 10 oscillations take 12.0 s. How long is the string?
The spring constant of spring is 39.9 N/m and the length of the string is about 47.5 meters.
What is spring constant?Mass of the air-track glider (m) = 200 g = 0.2 kg
Displacement of the air-track glider (x) = 10.0 cm = 0.1 m
Number of oscillations (n) = 10
Time taken for 10 oscillations (t) = 12.0 s
T = 2π√(m/k)
where, T is the time period of oscillation. Substituting the given values, we get:
12 s = 2π√(0.2 / k)
Solving for k, we get:
The spring constant is 39.9 N/m.
Mass of the ball (m) = 200 g = 0.2 kg
Angle of displacement (θ) = 8.00°
Number of oscillations (n) = 10
Time taken for 10 oscillations (t) = 12.0 s
T = 2π√(L/g)
where, T is the time period of oscillation and g is the acceleration due to gravity. Substituting the given values, we get:
12 s = 2π√(L/9.8)
Solving for L, we get:
L = (12/2π)² × 9.8 = 47.5 m
Therefore, the length of the string is 47.5 meters.
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What two planets are coming together?
The two planets that are coming together are Saturn and Jupiter. On December 21st, 2020, the two planets will be at their closest point, an event known as the Great Conjunction.
To observe the Great Conjunction, look in the direction of the southwest sky shortly after sunset. The two planets will appear to be close together and will look like one bright star. Make sure to look for them with binoculars or a telescope if you can, as you'll get a better view.The Great Conjunction occurs because Saturn and Jupiter have different orbital periods. Jupiter completes its orbit around the Sun every 11.86 Earth years, while Saturn takes 29.5 Earth years. This means that their orbits don't intersect and they don't come this close together very often. The next time the two planets will come this close together will be in 2080, so be sure to take advantage of this rare opportunity to witness this event in 2020.For more questions on Great Conjunction
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spherical capacitor contains a charge of 3.20nCwhen connected to a potential difference of250V. If its plates are separated by vacuum and theinner radius of the outer shell is 4.60cm.
A) Calculate the capacitance.
B) Calculate the radius of the inner sphere.
C) Calculate the electric field just outside the surface of theinner sphere.
A) The capacitance of the spherical capacitor is 1.45 pF (picofarads), B) The radius of the inner sphere is 3.60 cm. and C) The electric field just outside the surface of the inner sphere is [tex]2.36 * 10^6 V/m[/tex] (volts per meter).
To calculate the capacitance, we can use the formula C = Q/V, where Q is the charge and V is the potential difference. Plugging in the values, we get [tex]C = (3.20 * 10^{-9} C)/(250 V) = 1.28 * 10^{-11} F[/tex].
However, since the capacitor is a spherical one, we need to use the formula for the capacitance of a spherical capacitor, which is [tex]C = (4\pi \epsilon_0)(r_1 r_2)/(r_2-r₁)[/tex], where r₁ and r₂ are the radii of the two shells and ε0 is the permittivity of free space.
Rearranging the formula and plugging in the values, we get [tex]r_1 = (C/4\pi \epsilon_0)(r_2-r_1)/r_2,[/tex] which gives us r₁ = 3.60 cm.
To calculate the electric field just outside the surface of the inner sphere, we can use the formula
E = [tex]\frac{Q}{4\pi\epsilon_0 r^2}[/tex], where r is the radius of the inner sphere.
Plugging in the values, we get [tex]E = (3.20 * 10^{-9} C)/(4\pi\epsilon_0(0.0460 m)^2) = 2.36 * 10^6 V/m.[/tex]
This electric field arises due to the charge on the inner sphere and induces an opposite charge on the outer shell of the capacitor.
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the end result of a theory that is not verified is
Unproven theories ultimately cannot be regarded as scientific facts or principles and are not generally recognised by the scientific community.
A well-supported explanation of a natural occurrence in science that has passed rigorous examination and is backed by empirical data is referred to as a theory. A hypothesis, however, cannot be regarded as a scientific fact or principle if it is not backed up by empirical data or if it has not undergone extensive testing and verification. The scientific community frequently rejects unproven notions with scant empirical backing and may even label them as pseudoscientific or non-scientific. This is so that scientific theories and findings may be evaluated and verified frequently. Science does this by using evidence-based reasoning and critical thinking. Unproven theories are therefore eventually not regarded as being a part of the corpus of scientific knowledge.
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three forces applied to a trunk that moves leftward by 3.010 m over a frictionless floor. The force magnitudes are F1 = 5.86 N, F2 = 9.180 N, and F3 = 3.850 N, and the indicated angle is θ = 67.8°. During the displacement, what is the net work done on the trunk by the three forces? (Note that there are other forces acting on the block, but we only care about the net work done by these three forces.) And by how much does the kinetic energy of the trunk increase (enter a positive value) or decrease (negative value)?
The kinetic energy of the trunk increases by ½ mvf² = ½ m(10.65 m/s)²= 71.44 J during the displacement.
Net work = ΔK
W = Fd cosθ
W1 = F1d cosθ = (5.86 N)(3.010 m) cos(67.8°) = 6.99 J
W2 = F2d cosθ = (9.180 N)(3.010 m) cos(67.8°) = 10.97 J
W3 = F3d cosθ = (3.850 N)(3.010 m) cos(67.8°) = 4.58 J
Net work = W1 + W2 + W3 = 6.99 J + 10.97 J + 4.58 J = 22.54 J
Therefore, the net work done on the trunk by the three forces is 22.54 J.
ΔK = ½ mvf² - ½ mvi²
Since the trunk moves a distance of 3.010 m and is initially at rest, we can use the equation:
vf² = 2ad
where a is the acceleration of the trunk, which is given by:
a = ΣF / m
where ΣF is the net force on the trunk, which we can find using:
ΣF = F1 + F2 + F3
ΣF = (5.86 N + 9.180 N + 3.850 N) = 18.89 N
Therefore, the acceleration of the trunk is:
a = ΣF / m = 18.89 N / m
Since the trunk moves leftward, the acceleration is also leftward, so we can use a negative value for a.
Substituting the values for a and d, we get:
vf² = -2(-18.89 N / m)(3.010 m) = 113.51 (m/s)²
Taking the square root, we get:
vf = 10.65 m/s
Therefore, the change in kinetic energy of the trunk is:
ΔK = ½ mvf² - ½ mvi² = ½ m(10.65 m/s)²- 0 = ½ mvf²
Kinetic energy is a type of energy that an object possesses by virtue of its motion. It is defined as the energy an object has due to its motion and is proportional to the mass of the object and the square of its velocity. The formula for kinetic energy is KE = 1/2mv^2, where m is the mass of the object and v is its velocity.
Kinetic energy is a scalar quantity and has units of joules in the International System of Units (SI). It is a fundamental concept in physics and is used to describe many physical phenomena, including the motion of particles, the behavior of gases, and the motion of waves. In many cases, kinetic energy can be transformed into other forms of energy. For example, when a ball is thrown upwards, its kinetic energy is gradually converted into gravitational potential energy as it moves higher and higher.
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In outer space will a liquid in a beaker exert a pressure on the bottom or on the sides of a beaker?
Answer:
Yo dude, if you had a beaker of liquid in outer space, it wouldn't push down on the bottom or the sides of the beaker like it would on Earth. In space, there's no gravity to make the liquid settle down, so it forms a round shape because of surface tension. So basically, the liquid would just float around in a ball inside the beaker. If you moved the beaker around, the liquid would just roll around with it like a bouncy ball.
you live on an island in the pacific. an earthquake of magnitude 8.5 off the coast of japan, 8000 km away, generates a tsunami with a wavelength of 200 km. the average water depth between your island and japan is 4900 m. if a tsunami warning is issued for your island, how many hours will you have before the waves arrive?
If a tsunami warning is issued for the island, they will have approximately 11.7 hours before the waves arrive.
What is Magnitude?
Magnitude is a measure of the strength or intensity of a physical quantity or phenomenon, such as an earthquake or a sound wave. It is often expressed using a numerical scale, with higher values indicating greater strength or intensity. In the case of earthquakes, magnitude is typically measured using the Richter scale or the moment magnitude scale, which take into account the amplitude of seismic waves and the energy released by the earthquake.
To calculate the time it takes for a tsunami to travel from Japan to the island, we can use the following formula:
t = (2 * pi * d) / g * ln(1 + sqrt(h/d))
where t is the time it takes for the tsunami to travel, d is the average water depth, h is the wave height, and g is the acceleration due to gravity (9.8 m/s^2).
Magnitude of the earthquake: 8.5
Wavelength of the tsunami: 200 km = 200,000 m
Average water depth: 4,900 m
To calculate the wave height, we can use the following formula:
h = (M / 5) * (D / 10)^1/2
where M is the magnitude of the earthquake and D is the distance between the earthquake epicenter and the observation point (in this case, the island). Note that this formula is an approximation and may not be accurate for all cases.
Using the given values, we get:
D = 8,000 km = 8,000,000 m
h = (8.5 / 5) * ((8,000,000 / 10)^1/2) = 2,738.6 m
Substituting these values into the formula for t, we get:
t = (2 * pi * 4,900) / 9.8 * ln(1 + sqrt(2,738.6/4,900)) = 11.7 hours
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a particle's velocity is described by the function vx=kt2 , where vx is in m/s , t is in s , and k is a constant. the particle's position at t0=0s is x0 = -5.40 m . at t1 = 2.00 s , the particle is at x1 = 5.80 m .
A particle's velocity is described by the function vx=kt2 , where vx is in m/s , t is in s , and k is a constant. The particle's position at t0=0s is x0 = -5.40 m. At t1 = 2.00 s , the particle is at x1 = 5.80 m. The value of k is 2.80 m/s2.
The given equation describes the velocity of a particle in terms of a constant, k, and time, t. The velocity, vx, is given in m/s. The initial position of the particle at t0=0s is x0=-5.40 m, and at t1=2.00 s the particle is at x1=5.80 m. To find the value of the constant k, we can solve the equation for the change in velocity Δvx.
Δvx = vx1 – vx0 = k(t12 – t02)
Δvx = 5.80 – (-5.40) = 11.20 m/s
k = (11.20 m/s) / (2.002 s2) = 2.80 m/s2
Now that we have found the value of the constant k, we can use it to find the velocity of the particle at any time t. For example, at t2=4.00 s the velocity of the particle is vx2=11.20 m/s. This can be calculated using the equation vx2 = k(t22) = 2.80(4.002) = 11.20 m/s.
From the velocity equation, we can also calculate the position of the particle at any time t. The position of the particle at t2=4.00 s is x2= 11.20(4.00) = 44.80 m. We can also calculate the position of the particle at any other time t, by simply substituting in the corresponding value of t into the equation.
In conclusion, the equation vx = kt2 describes the velocity of a particle in terms of a constant, k, and time, t. Using this equation, we can calculate the velocity and position of the particle at any given time.
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Complete Question:
A particle’s velocity is described by the function vx = [tex]kt^2m/s[/tex], where k is a constant and t is in s. The particle’s position at [tex]t_0[/tex] = 0s is [tex]x_0[/tex] = -5.40 m. At [tex]t_1[/tex] = 2.00 s, the particle is at [tex]x_1[/tex] = 5.80 m. Determine the value of the constant k. Be sure to include the proper units
Taking the following list on an item-by-item basis (i.e., without considering the other listed factors), a maintenance expenditure should be capitalized if the expenditure:
increases the salvage value of the asset.
extends the useful life of the asset.
A maintenance expenditure should be capitalized if it increases the salvage value of the asset or extends the useful life of the asset.
An expenditure is a payment made in return for a product or service. Capital expenditure is money spent by a company on long-term assets like equipment and buildings.
Capitalizing refers to recording a cost or expense on the balance sheet for a future period rather than recognizing it immediately in the current period.
Capitalizing expenditure means the company will recognize the expenditure as an asset, which will be amortized over its useful life as opposed to expenses in the current period.
Therefore, a maintenance expenditure should be capitalized if the expenditure increases the extends the useful life of the asset.
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You are the process engineer at Corvallis Automobiles Inc., and you have received an order to turn a cylindrical bar on an engine lathe to the dimensions specified in Fig. 1. For this order you will use cylindrical bar stock that is 48-inches long and 4-inches in diameter. The 48-inch length bar will be chucked in the lathe and supported at the opposite end using a live center. You are planning to complete the operation in one pass using a cutting speed of 400 ft./min. and a feed of 0.010 in./rev. Determine the following: a) The required depth of cut (in inches) b) The material removal rate (in cubic inches per minute)
c) The time required to complete the cutting pass (in minutes)
a. the depth of cut is 0.625 inches.
b. the material removal rate is 0.003125 cubic inches per minute.
c. the time required to complete the cutting pass is 20 minutes.
How do we calculate?a) The required depth of cut can be determined by :
DOC = (4 in - 2.75 in)/2 = 0.625 in
Therefore, the depth of cut is 0.625 inches.
b) The material removal rate can be found by applying:
MRR = DOC x Width of cut x Feed rate
assuming we are using a standard carbide insert tool with a width of cut of 0.5 inches.
MRR = 0.625 in x 0.5 in x 0.010 in/rev = 0.003125 cubic inches per minute
c) The time required to complete the cutting pass is determined by:
Time = Length of cut / (Cutting speed x Width of cut x Feed rate)
Time = 48 in / (400 ft/min x (0.5 in) x (0.010 in/rev) x (1/12 ft/in)) = 20 minutes
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When current flows through a conductor, it develops a magnetic field of concentric circles expanding ? and outward from the conductor. a. circularly b. parallel c. perpendicular d. wavy
When a current travels through a conductor in a circular motion, a magnetic field with growing concentric circles is created.
What happens when current flows through a conductor?Electromagnetism is established when an electrical current flows through a simple conductor, such as a length of wire or cable.
What magnetic field is created when current travels through a conductor?As magnetic fields produced by moving charges are proportional to the current, a conductor carrying current creates a magnetic field around it. Generally speaking, the sub-atomic particles in the conductor, such as the moving electrons in the atomic orbitals, are responsible for this magnetic field.
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1. I’m in the 2nd column, 4th row, and I’m a metal. Who am I? ________________ 2. I’m a very lonely nonmetal. Who am I? ____________ 3. I’m the only metal who is a liquid at room temperature. Who am I? ____________ 4. I’m named after the person who created the 1st Periodic Table. Who am I? ___________ 5. I have 92 protons. Who am I? _____________ 6. I’m the only nonmetal who is a liquid at room temperature. Who am I? ___________ 7. I’m named after a very famous scientist. Who am I? ___________ 8. I have 46 electrons. Who am I? ____________ 9. My atomic mass is 183. 84. Who am I? _____________ 10. My chemical symbol is Ag. Who am I? ________________ 11. I’m the only metalloid in period 3. Who am I? ___________ 12. I’m the only element that is solid and a nonmetal in group 14. Who am I? _____________ 13. I have 5 neutrons. Who am I? ____________ 14. I’m the only gas at room temperature that is in group 16. Who am I? ___________ 15. I have 68 protons. Who am I? __________ 16. What element has the chemical symbol of Ir? ______________ 17. Which element is in group 7 and has 30 neutrons. Who am I? ___________ 18. I’m the only metal in group 15. Who am I? ____________ 19. I have 88 electrons. Who am I? ___________ 20. I’m the only gas at room temperature and in period 5. Who am I? ____________ 21. My symbol is Am. Who am I? ______________ 22. I’m the only nonmetal in period 6. Who am I? ____________ 23. My atomic number is 69. 723. Who am I? _________________ 24. I have 159 neutrons. Who am I? ________________ 25. I’m the only metalloid in group 17. Who am I? ______________ 26. I have 50 electrons. Who am I? __________________ 27. I’m in the 1st group and the 4th period. Who am I? ________________ 28. I’m a metalloid whose symbol is Sb. Who am I? ______________ ©JFlowers2017 Name: ______________________________ Date: ___________Class: ________ Periodic Table Scavenger Hunt Directions: You will use the Periodic Table to answer the questions. 1. I’m in the 17th column, a nonmetal, & a solid at room temperature. Who am I? ________________ 2. I have 79 electrons. Who am I? ____________ 3. I’m the only gas in period 6. Who am I? ____________ 4. My atomic mass is 257. Who am I? ___________ 5. My chemical symbol is Hs. Who am I? _____________ 6. I have 114 neutrons. Who am I? ___________ 7. I’m in the 18th group and 2 nd period. Who am I? ___________ 8. I have 67 protons. Who am I? ____________ 9. I’m a nonmetal who is solid at room temperature & has 2 letters for my symbol. Who am I? _________ 10. I’m in the 1 st group & 7 th period. Who am I? ________________ 11. I’m the only metalloid in group 13. Who am I? ___________ 12. I have 97 electrons. Who am I? _____________ 13. I am the only gas in column 15. Who am I? ____________ 14. My name is similar to Mickey Mouse’s best friend. Who am I? ___________ 15. I’m in group 11 & period 4. Who am I? __________ 16. I have 62 protons. Who am I? ______________ 17. My name fits really well with doctors because they try to do this. Who am I? ___________ 18. My name reminds me of where we all live. Who am I? ____________ 19. I’m the only nonmetal in period 2. Who am I? ___________ 20. My atomic number is 87. 62. Who am I? ____________ 21. My symbol is Mt. Who am I? ______________ 22. I’m in group 17 & the only metalloid. Who am I? ____________ 23. I have 71 electrons. Who am I? _________________ 24. My symbol is Pd. Who am I? ________________ 25. I’m Dorothy’s friend who needed a heart. Who am I? ______________ 26. I have 41 protons. Who am I? __________________ 27. I have 125 neutrons. Who am I? ________________ 28. My name comes from the 8th planet. Who am I? ______________
The Periodic Table of Elements served as the inspiration for this scavenger hunt. The exercise consists of two sets of questions, each of which has 28 questions that must be answered using the Periodic Table.
Students are tasked with identifying elements in the first set of questions using information from their attributes, such as the element's position on the periodic table, atomic mass, or quantity of electrons, protons, or neutrons. The objectives of the questions are to familiarise students with the properties of various elements and the structure of the Periodic Table. The second series of questions is comparable to the first, but more difficult because it asks students to identify components using less obvious cues, like their chemical symbol or a chemical formula. In order to succeed in their future studies of chemistry and other related sciences, students will benefit from being more familiar with the structure of the periodic table and the characteristics of various elements.
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Ceteris paribus, which of these events would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall?
• A dcrease investor confidance
• A decrease in cosmetic income and wealth • A strengh of time preference
• A decrease in capital productivity
Ceteris paribus, a decrease in capital productivity is the event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. The correct answer is option C.
Ceteris paribus is a Latin expression that means "all other things being equal." Ceteris paribus is a model in which economists use to analyze the effect of one independent variable on a dependent variable while keeping all other independent variables constant. This implies that only one variable is allowed to change while all other variables are held constant at their current level or position.
Therefore, Ceteris paribus, an increase in investor confidence, an increase in cosmetic income and wealth, and a strength of time preference will not cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. However, a decrease in capital productivity is an event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall.
When capital productivity is low, firms are unable to produce goods and services efficiently, and as a result, the demand for investment falls. When the demand for investment falls, the equilibrium quantity of investment will also decrease, leading to a decrease in the equilibrium interest rate.
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Is an object moving with a constany speed around a circular path veloctiy? why? why not?
Answer: The motion of a body with constant speed in a circular path is said to be accelerated, because it is moving with uniform speed, but not with uniform velocity, as velocity is a vector quantity, it can be represented in magnitude as well the direction.
Explanation:
A solar sailplane is going from Earth to Mars. Its sail is oriented to give a solar radiation force of FRad = 7.70 × 102 N. The gravitational force due to the Sun is 173 N and the gravitational force due to Earth is 1.00 × 102 N. All forces are in the plane formed by Earth, Sun, and sailplane. The mass of the sailplane is 14,900 kg. What is the magnitude of the acceleration on the sailplane? Answer in m/s2
The sailplane which is going from Earth to Mars is accelerating at 0.033 m/s² in the direction of solar radiation force.
The force of gravity is a force that arises as a consequence of the mutual attraction of two objects. This gravitational force is usually exerted between two physical objects. Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is proportional to the product of their masses.
Acceleration is the rate at which an object changes its speed or direction. Acceleration is a vector quantity that can be positive or negative. If the acceleration is negative, the object slows down. If the acceleration is positive, the object speeds up.
The acceleration on the sailplane can be determined using the following formula:
[tex]F_{net} = ma[/tex]
Where Fnet is the net force acting on the sailplane, m is the mass of the sailplane a is the acceleration on the sailplane.[tex]F_{net} = ma[/tex]
The net force acting on the sailplane can be calculated as:
[tex]F_{net} = F_{rad} - F_{gravitySun} - F_{gravityEarth}[/tex]
Where [tex]F_{rad}[/tex] is the solar radiation force, [tex]F_{gravitySun}[/tex] is the gravitational force due to the sun, and [tex]F_{gravityEarth}[/tex] is the gravitational force due to Earth.
Putting the given values in the above formula:
[tex]F_{net} = 7.70 \times 10^2 N - 173 N - 1.00 \times 10^2 N = 497 N[/tex]
The acceleration on the sailplane is given as:
[tex]a = F_{net} / ma = (497\ N) / 14,900 \ kg = 0.033 \ m/s^2[/tex]
The magnitude of the acceleration on the sailplane is 0.033 m/s² (rounded to three significant figures).
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a researcher is studying the distribution of auxin in roots and stems exposed to sunlight. he notices that more auxin collects in the sides of stems and roots that are not exposed to light. why?
The researcher's observation that more auxin collects in the sides of stems and roots that are not exposed to light is likely due to the phenomenon of phototropism.
In the process of phototropism, light influences the direction and rate of growth of plant cells. In particular, light induces the cells on one side of a stem or root to create less auxin than the cells on the shaded side. Less auxin is produced on the lighted side and more auxin is produced on the shaded side as a result. The hormone auxin is essential for controlling the growth and development of plants. Auxin generally promotes cell growth and elongation at greater concentrations while inhibiting cell elongation at lower concentrations. Since the cells on the lighted side of the stem or root will contain less auxin when there is light.
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In which of the following cases does a car have a negative velocity and a positive acceleration? A car that is traveling in the ................. (A) -x direction at a constant 10 m/s. (B) - direction increasing in speed. (C) +x direction increasing in speed. (D) - direction decreasing in speed. (E) +x direction decreasing in speed.
In the case where the car is traveling in the -x direction and decreasing in speed, it has a negative velocity and a positive acceleration. Therefore, option D is the correct answer. In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration.
Let's discuss the given options one by one:
(A) In this case, the car is traveling in the -x direction at a constant speed. Therefore, it has a negative velocity and zero acceleration. This option is incorrect.
(B) In this case, the car is traveling in the - direction and increasing its speed. Therefore, it has a negative velocity and a positive acceleration. However, the given direction is not specified, and thus this option is not accurate.
(C) In this case, the car is traveling in the +x direction and increasing in speed. Therefore, it has a positive velocity and a positive acceleration. This option is incorrect.
(D) In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration. This option is correct.
(E) In this case, the car is traveling in the +x direction and decreasing in speed. Therefore, it has a positive velocity and a negative acceleration. This option is incorrect.
Therefore, Option D ( - direction decreasing in speed) is correct.
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Three identical conducting spheres are charged as follows. Sphere A is positively charged, sphere B is negatively charged with a different magnitude of net charge than that of sphere A, and sphere C is uncharged. Spheres A and B are momentarily touched together and separated, then spheres B and C are briefly touched together and separated. After that series of processes is completed, which of the following interactions, if any, can be used as evidence to determine whether sphere A or sphere B had the initially larger magnitude of charge? A Sphere C is repelled from sphere A. B Sphere C is repelled from sphere B. Sphere A is repelled from sphere B. D It cannot be determined from observing whether the spheres repel, because they all have the same sign of charge.
The answer is C. Sphere A is repelled from sphere B
Step by step explanation:
The question is asking which of the interactions between sphere A, B, and C can be used as evidence to determine which one had the initially larger magnitude of charge. This is because if sphere A has a larger magnitude of charge than sphere B, then when spheres A and B are touched and separated, the charge of sphere A would be transferred to sphere B, causing a conduction of charge.
This means that after the processes are completed, the charge of sphere A and B will have reversed - meaning that sphere A will now have the same, but opposite sign of charge as sphere B. As a result, when sphere A and B are close to each other, their charges will repel, so Sphere A is repelled from sphere B.
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Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.20 m high. Assume it starts from rest and rolls without slipping.
Express your answer using three significant figures and include the appropriate units. Thank you!!
The translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.
We can use conservation of energy to solve this problem. The initial energy of the cylinder is all potential energy, and the final energy is all kinetic energy. The potential energy at the bottom of the incline is zero.
The potential energy of the cylinder at the top of the incline is given by:
PE = mgh
where m is the mass of the cylinder, g is the acceleration due to gravity, and h is the height of the incline. Substituting the given values, we get:
PE = (mass of cylinder) x (acceleration due to gravity) x (height of incline) = mgh
The kinetic energy of the cylinder at the bottom of the incline is given by:
KE = (1/2)mv^2
where v is the translational speed of the cylinder at the bottom of the incline.
According to the conservation of energy, the initial potential energy is equal to the final kinetic energy, so we can set these two expressions equal to each other:
mgh = (1/2)mv^2
We can cancel the mass of the cylinder from both sides, and solve for v:
v = sqrt(2gh)
Substituting the given values, we get:
v = sqrt(2 x 9.81 m/s^2 x 7.20 m) ≈ 9.43 m/s
Therefore, the translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.
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the maximum energy of photoelectrons from aluminium is 2.3 ev for radiation of 2000 a and 0.90 ev for radiation of 3130 a. use this data to calculate plancks constant and the work function of aluminium
The maximum energy of photoelectrons from aluminium is 2.3 eV for radiation of 2000 Å and 0.90 eV for radiation of 3130 Å.
To calculate Planck's constant and the work function of aluminium, we need to use the equation:
h = E2 - E1/ λ2 - λ1
Where h is Planck's constant, E1 and E2 are the maximum energy of photoelectrons for each wavelength, and λ1 and λ2 are the wavelengths.
Using the given data, we have:
h = (2.3 - 0.90) / (2000 - 3130)
Therefore, h = -1.4 eV / -930 Å, which simplifies to h = 0.0015 eVÅ.
The work function of aluminium is equal to the maximum energy of the photoelectrons for the longest wavelength, in this case, 0.90 eV. Therefore, the work function of aluminium is 0.90 eV.
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when a 2.75-kg fan, having blades 18.5 cm long, is turned off, its angular speed decreases uniformly from 10.0 rad/s to 6.30 rad/s in 5.00 s. (a) what is the magnitude of the angular acceleration of the fan?
The angular acceleration of the fan is 0.740 rad/s^2,
Angular acceleration which represents the rate at which the angular velocity changes over time. The unit used to measure angular acceleration is radians per square second (rad/s2), according to the International System of Units. The Greek alphabet symbol alpha (α) is used to denote angular acceleration.
To calculate the angular acceleration of the fan, the formula α = Δω/Δt is used. Here, α represents angular acceleration, Δω represents the change in angular speed, and Δt represents the change in time.
In this scenario, Δω is equal to 10.0 - 6.30 = 3.70 rad/s, and Δt is equal to 5.00 s. By substituting these values into the formula, we obtain α = 3.70/5.00 = 0.740 rad/s^2.
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of the three states of matter, which one has the most kinetic energy?
Of the three states of matter (solid, liquid, and gas), gas has the most kinetic energy. This is because the particles in a gas have the highest average speed compared to the particles in solids and liquids.
In a gas, the particles are in constant motion, colliding with each other and the walls of the container. This motion generates kinetic energy, which is proportional to the speed and mass of the particles. In contrast, solids have the lowest kinetic energy because their particles are tightly packed and have limited movement. The particles in a solid vibrate around a fixed position, and only experience small oscillations. Liquids have an intermediate amount of kinetic energy. The particles in a liquid are less tightly packed than in a solid, and can move more freely, resulting in more kinetic energy. However, liquids have more intermolecular forces between the particles compared to gases, which restricts their movement and reduces their average speed. Therefore, of the three states of matter, gases have the most kinetic energy, followed by liquids and then solids.
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Imagine sitting on a merry-go-round and riding along as it spins. Assuming you are not grabbing it anywhere and are not moving with respect to the platform,
A. static friction (directed inwards) causes you to accelerate.
B. you are not accelerating because you aren't moving on the platform.
C. static friction (directed outwards) causes you to accelerate.
D. sliding friction makes you accelerate inwards.
The correct option is: Static friction (directed outwards) causes you to accelerate. (Option C)
When you sit on a merry-go-round, you are not moving relative to the platform. Therefore, you are not in motion in respect to the reference frame of the platform.
The question is asking you to determine the force that causes you to accelerate as the merry-go-round spins.
Static friction is the force that keeps an object at rest or keeps it moving in a straight line when a force is applied to it.
When you're riding a merry-go-round and it starts to spin, static friction force helps you move outwards. This force opposes the force that pulls you towards the center of the platform, i.e., centripetal force.
So the correct option is C: Static friction (directed outwards) causes you to accelerate.
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