Answer:
B. Radio waves
Explanation:
Radio waves are transmitted easily through air. They do not cause damage if absorbed by the human body, and they can be reflected to change their direction. These properties make them ideal for communications.
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Answer:
B
Explanation:
Radio Waves
Se aplican dos fuerzas concurrentes a un objeto de 4N a la derecha y 5N a la izquierda. ¿Hacia donde se movió y con cuanta fuerza?
The forces move strongly towards the left by 1N
Given the following
Force towards the right = 4N
Force towards the left = 5N
Note that the force acting towards the left is negative, hence the force acting towards the left is -5N
Take the sum of force
Resultant force = -5N + 4N
Resultant force = -1N
This shows that the forces move strongly towards the left by 1N
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What can the magnetic fields influence?
A) It can cause objects to be pulled towards the magnet and pushed away from the magnet.
B) It only causes a repel force between the magnets.
C)It cause only an attraction force.
Explanation:
Magnetic fields are areas where an object exhibits a magnetic influence. The fields affect neighboring objects along things called magnetic field lines. A magnetic object can attract or push away another magnetic object. You also need to remember that magnetic forces are NOT related to gravity.
A car starts from rest and accelerates at 2.5m/s^2 for 2s. What is the final velocity of the car
Answer:
5m/s ez
Explanation:
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What is the disappearance of a wave into a medium.
A. Signal
B. Amplitude
C. Absorption
D. Transmission
Answer:
Absorption
Explanation:
the disappearance of an EM wave into the medium. scattering – the spreading out of light rays in all directions because particles reflect and absorb the light.
A 2kg body is moving a long a horizontal circular path of radius 2m with constant speed of 6m/s . what is the magnitude of the force acting on the body ?
How much force is required to move a tractor 60m, when using 250J of work?
Answer:
Work done,W= 250J
Displacement , s = 60
We know that, Work done = Force x displacement
i.e , W = Fxs
250 J = F x 60m
F = 250/60
=4.16 N
Hence , 4.16 N of Force is applied on the body.
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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.
How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.
From edge
Answer:
like 23 or something
Explanation:
Acceration is a change in motion over time:
True False
When the sum of all the forces acting on a block.
Answer:
finish the question pls
Explanation:
A marble is launched at by dropping it through a marble launcher. The marble took 0.22s to land 0.31m from
where it was launched. Find the horizontal velocity of the marble as it rolls off the table.
A. 1.4m/s
B. 0.53m/s
C. 0.71 m/s
D. 0.07m/s
Hi there!
For projectile motion, the horizontal and vertical components are SEPARATE.
We can use the kinematic equation to solve:
dₓ = vₓt
We can rearrange to solve for vₓ:
dₓ/t = vₓ
0.31/0.22 = vₓ
vₓ = 1.4 m/s ⇒ A
Where does the energy released in a nuclear decay reaction come from
A. Electrons
B. Chemical bonds
C. Positrons
D. The binding energy of the nucleus
An irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 20L. The height of water rose to 30.2mL. If the mass of the stone was 25g what was its density?
Answer:
2.45 g/mL
Explanation:
(assuming that the original volume was 20 mL and not L)
Since you know the amount of water in the cylinder before and after you placed the rock in, you can subtract them to get the volume of the rock itself. [tex]30.2-20=10.2[/tex] mL.
To get the rock's density, use the equation [tex]d=\frac{m}{v}[/tex], where m is mass and v is volume.
[tex]d=\frac{25 g}{10.2mL}\\\\d=2.45 g/mL[/tex]
Help help fast please first answer gets brainiest also needs to be clearly stated
What electromagnetic wave is used in nuclear research and mineral exploration?.
The electromagnetic wave used in nuclear research and mineral exploration are gamma rays.
Electromagnetic waves refer to those rays that are found in the electromagnetic spectrum. They are collectively called light. Electromagnetic waves are used for different purposes.
Gamma rays are useful in nuclear research especially in identifying decaying radionuclides. Also, gamma rays are used for geologic mapping, mineral exploration, and identification of environmental contamination.
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I agree to hire you for 30 days. You can decide between two methods of payment: either (1) $1000 a day, or (2) one penny on the first day, two pennies on the second day and continue to double your daily pay each day up to day 30. Use quick estimation to make your decision, and justify it
Answer:
The second deal.
Explanation:
I had that before, if u pick the second one you will get twice as much in a year as the first one.
A crane lifts a 10000 N load through a distance of 30mins in 40s calculate work done
Given,
Force = 10,000 N
Distance = 30 m
Time = 40 s
Work done = force × distance
Work = 10,000 × 30
Work = 300,000 J
______
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The work done on the object is equal to the power it experiences which is equal to 735 watts.
What is work done?Work done is defined as the product of force applied and the distance over which the force is applied on the object. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.
The time rate of doing work is called as power, which is designated by the symbol P. It is measured in the units of watts, where one watt is equal to one joule energy applied per second time.
Work done on an object is equal to the force (F) multiplied by the distance d in the direction of the force. Where, time interval is Δt.
P = W/Δt = F × d/Δt = m × g × h/Δt = 100 × 9.8 × 30 / 40
Power = 735 watts
The power of the object is 735 watts.
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Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?
The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N
The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.
According to Newton's second Law;
Force = (Tension) = mass × acceleration due to gravity
∴
We can say:
Tension = 4kg × 9.81 m/s²
Tension = 39.24 N
Tension = 40 N (to the nearest whole number)
Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N
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Historia de baloncesto internacional resumen
Answer:
?
Explanation:
Can Hotspots can be found at the edges of tectonic plates?
Answer:
No.
Explanation:
Hot spots don't appear at the barriers of tectonic plates, instead, they originate at hot centres known as mantle plumes. Mantle plumes exist below the tectonic plates and may develop a string of volcanoes on the Earths surface.
A block of mass =4.20 kg slides along a horizontal table with velocity 0=3.50 m/s . At =0 , it hits a spring with spring constant =26.00 N/m and it also begins to experience a friction force. The coefficient of friction is given by =0.250 . How far has the spring compressed by the time the block first momentarily comes to rest? Assume the positive direction is to the right.
The distance in which the spring is compressed is 1.065 m.
The given parameters;
mass of the block, m = 4.2 kgvelocity of the block, v = 3.5 m/sspring constant, k = 26 N/mcoefficient of friction, μ = 0.25Apply the principle of conservation of energy to determine the distance in which the spring is compressed.
[tex]K.E = W + U\\\\\frac{1}{2} mv^2 = \mu Fx \ + \ \frac{1}{2} kx^2\\\\\frac{1}{2}(4.2)(3.5)^2 = 0.25(4.2 \times 9.8)(x) \ + \frac{1}{2} (26)(x^2)\\\\25.725 = 10.29x \ + \ 13x^2\\\\13x^2 + 10.29x - 25.725 = 0\\\\[/tex]
solve the quadratic equation using formula method;
a = 13, b = 10.29, c = -25.725
[tex]x = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-(10.29) \ \ +/- \ \sqrt{(10.29)^2 \ - \ 4(13\times 25.725)} }{2(13)} \\\\x = 1.065 \ m, \ \ or \ -1.86 \ m[/tex]
choose positive distance, x = 1.065 m.
Thus, the distance in which the spring is compressed is 1.065 m.
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You get in your car after work and turn on the radio. What type of communication does the radio use?.
Answer:
Radio waves
Explanation:
The radio operates by the principles of radio wave.
Electromagnetic wave is a type of wave which does not require material medium for its propagation. A radio wave is an example of electromagnetic wave.
The radio operates in the principle of electromagnetic wave because it does not require material medium for its propagation and it has one of the longest frequency of electromagnetic spectrum.
Thus, we can conclude that the radio operates by the principles of radio wave.
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Guys plz i need those answers as soon as possible
9) a) formula = h(ρ)g by default g=9.8m/s²
Pressure = 2×1000×9.8 = 19600Pa
b)
why do we believe 90 percent of the mass of the milky way is in the form of dark matter?
Answer:
The orbital speeds of stars far from the galactic center are surprisingly high, suggesting that these stars are feeling gravitational effects from unseen matter in the halo.
5 a
What causes the pressure of air at the Earth's surface?
Answer:
Atmospheric pressure is caused by the gravitational attraction of the planet on the atmospheric gases above the surface and is a function of the mass of the planet, the radius of the surface, and the amount and composition of the gases and their vertical distribution in the atmosphere
Explanation:
How does water temperature affect density?
How do energy transformations occur in a hydroelectric plant?
The potential energy of water is converted to mechanical energy by a turbine.
The kinetic energy of water is converted by a dam into potential energy.
The kinetic energy of water is converted by a generator into electric energy.
The potential energy of water is converted by a transformer into electric energy.
Answer:
The answer is #3: The kinetic energy of water is converted by a generator into electric energy.
Explanation:
Hydropower plants capture the energy of falling water to generate electricity. A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy.
What is the mass, in kilograms, of a large dog that weighs 441 newtons?
Answer:
441 Newtons equals 44.97 kilograms.
A car travelled at a speed of 60 km/hr for thrice as long as it travelled at a speed of 40 km/hr. If the total distance it covered was 440 km, for how long did it travel at a speed of 60 km/hr
Answer:
it traveled 180km
Explanation:
What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod
Answer:
C) 5ML^2
Explanation:
2 Spheres of mass M
Bug's mass 3M
Rod length 2L, radius L
Find Rotational Inertia I
I=Σmr^2
I=(3M+M+M)L^2
I=5ML^2
The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Rotational inertia of the systemThe rotational inertia of the system is determined by summing all the masses together and multiply with the radius.
I(t) = Σmr²
Where;
m is the massr is the radiusI(t) = Inertia of the 2 spheres + inertia of the bug
I(t) = (M + M)L² + (3M)L²
I(t) = 2ML² + 3ML²
I(t) = 5ML²
Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Complete question is below:
There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.
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2. What are the challenges of wind energy that causes decrease in the electrical production?
3. Give two solutions:
1. Modification in the structure of the turbine
2. Modification in the function of the turbine.
4. You must estimate the cost in each solution, and which one is more affordable and efficient for the municipality to go for.
5. You must make sure that there is minimal energy loss.
Levelized production cost is a big challenge in the production of wind energy.
The main challenge in the production of wind energy is the high production cost. It has to minimize the Levelized Production Cost (LPC) which is the ratio between energy production cost and economic lifetime. This problem can be solved by doing modification in the structure of the turbine as well as we must ensure minimal energy loss.
The modification in the structure can produce more electrical energy and reduce the energy loss also provides more profit to the company so we can conclude that levelized production cost is a big challenge in the production of wind energy.
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