Which Sl units are combined to describe energy?
A. Kilograms and m/s2
B. Kilograms and joules
C. Kilograms and m/s2
D. Kilograms and meters

Answers

Answer 1

Answer:

kilograms and m²/s²

Explanation:

The SI units combined to describe energy is kilograms and m²/s² ;

  Energy can be derived from;

Potential energy  = mgh

   Units               = kg x m/s² x m

                          = kg m²/s²

Even if we use kinetic energy, we still get kg m²/s²


Related Questions

A motorist, traveling east on an open highway, sets his cruise control at 90.0 km/h. How far will he travel in 0.75 hours?

Answers

Answer:

The answer is 67.5 km

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question we have

distance = 90 × 0.75

We have the final answer as

67.5 km

Hope this helps you

Answer: 67.5 km

Explanation:

Distance is the velocity and time.

90 x 0.75 = total distance

The distance is represented as 67.5 km/h.

Hope this helps!

Explain a principal of moments of a force

Answers

The principle of moments states that when a body is balanced the total clockwise moment about a point equals the total anticlockwise moment about the same point.Equation.Moment=Force F×perpendicular distance from the pivot do.

Write an equation of the line in slope-intercept form.
Please explain.

Answers

Answer:

 y =  [tex]-\frac{1}{4}[/tex]x + 3

Explanation:

The equation of a straight line is given as:

              y  =  mx + c

y and x are the coordinates

m is the slope

c is the y -intercept

 The y-intercept = 3;

Slope  = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

x₁ = 0

x₂ = 4

y₁ = 3

y₂ = 2

 Slope = [tex]\frac{2-3}{4 -0 }[/tex]  = [tex]-\frac{1}{4}[/tex]

 

       y = mx + c

       y =  [tex]-\frac{1}{4}[/tex]x + 3

You are twice as likely to become good friends with the person who is in the dorm room next to you than the person two doors down. This is due to:

A. Proximity.
B. Common Interests.
C. Shared Values.
D. Social Background​

Answers

I think A. Proximity
Since the person is closer, you get to see them more often
The correct answer is A

can someone help rn please!! thank you sm!!

Answers

I think it’s weight
Mass is the measure of its resistance to acceleration when net force is applied
Pounds and Kilograms definitely cannot be the answer
So the only logical answer is weight
Hope this helps

Calculate the density of a rock that has a mass of 32 grams and a volume of

4.5 mL.

Answers

Answer:

85.2ml

Explanation:

Which of the following is true regarding mixtures? a. One substance not combined with any other substances. b. Two or more substances physically mixed and can be separated. c. Two or more substances that are impossible to separate d. One substance that forms a compound alone.

Answers

Answer:

aerga

dggzsd

Explanation:

szsdrgzsedg

Annie has 100 mL of honey. The honey has a mass of 145 g. What is the density of the honey?

Answers

Answer:

The answer is 1.45 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

From the question we have

[tex]density = \frac{145}{100} \\ [/tex]

We have the final answer as

1.45 g/mL

Hope this helps you


An object with a mass of 15 kg accelerates 10.0 m/s2 when an unknown force is applied to it. What is the
amount of the force

Answers

Answer:

f=mass × acceleration

=15×10

=150

The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?

Answers

Answer:

this is the answer according to my calculations

Explanation:

0.001.9

Unit 2 kinetic energy mastery test

Answers

Answer: kinetic energy is Energy of motion.

Explanation:

1. Which elements would likely have similar properties: two elements in the same group, or two elements in the same period?

2. Fill in the table below with the correct classification of element.

Left side:
Right side:
Zigzag line:

3. Use the periodic table to answer this question: Are the properties of rubidium (Rb) more like those of cesium (Cs) or those of strontium (Sr)? Explain your answer.

4. Use the periodic table at the bottom of the page to identify the elements in the following compounds:
PBS:

KBr:

Rao:

5. Use the periodic table to determine whether each element is a metal or a nonmetal:

Sodium (Na):

Krypton (Kr):

Phosphorus (P):

Answers

Answer:

3. Cs, they are in the same group, mainly sharing characteristics.

Explanation:

The elements in the same group have similar properties. The properties of rubidium is similar to those of strontium because, both are in second group.

What are groups in  periodic table ?

In periodic table, all elements are classified into different periods and groups. The vertical columns in the table is called groups and the horizontal rows are called periods.

The elements in a group have same number of valence electrons and similar chemical and physical properties. For example rubidium and strontium are second group elements and they show similarity in properties.

The elements in the compound, PbS are lead and sulphur and that in KBr are potassium and bromine. Elements in RaO are radium and oxygen. Among the given elements sodium is a metal and krypton and phosphorus are non metals or gases.

Find more on periodic table:

https://brainly.com/question/28747247

#SPJ2

PLZ EXPLAIN THE EQUATION AND I WILL GIVE BRAINLIST You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very heavy rock into the back of a truck. The truck bed is 3 feet off the ground. Your father pulls out a 5-foot plank and begins to set up a ramp. At the same time, you (who know about mechanical advantage!) have found a plank that is 8 feet long, and you show it to your father. Which plank will give you the most mechanical advantage? Calculate the MA for each plank

Answers

Answer:

The 8 foot long plank

Explanation: hope this helps :)

A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?

Answers

Answer:

His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m

Explanation:

The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water

The net force, F acting on the body falling through the fluid is given as follows;

F = Weight force, W, from gravity - Drag force, D, from the fluid

F = W - D

Given that F = Mass, m × Acceleration, a, we have;

F = m × a

The acceleration, a = F/m = (W - D)/m

His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.

On the moon, the gravity is 1/6 that of Earth. While on the moon, Buzz Aldrin carried on his back a support system that would weigh over 1760 N on Earth. a) What did the backpack weigh on the moon? b) What was its mass on the moon? please show the work

Answers

Answer:

a) 293.[tex]\bar 3[/tex] N

b) Approximately  179.41 kg

Explanation:

The given parameters are;

The gravity (gravitational acceleration) on the moon = 1/6 × The gravity on Earth

The weight of the support system Buzz Aldrin carries = 1760 N

a) Given that the weight  of the support system on Earth = Mass of the support system, m × Gravity, g (Acceleration due to gravity) = m·g

The weight  of the support system on Earth = m·g

We have;

The gravity on the moon = 1/6 × g

∴ The weight of the support system on the moon = Mass of the support system, m ×  1/6 × g = m·g/6

∴ The weight on the of the support system on the moon = m·g/6 = 1/6 × m·g = 1/6 × m·g = 1/6 × The weight  of the support system on Earth

The weight on the of the support system on the moon = 1/6 × 1760 N = 880/3 N = 293.[tex]\bar 3[/tex] N

b) The mass, m, of the support system on the moon = The mass, m, of the support system on Earth

The mass, m, of the support system on Earth = Weight of the support system/(Gravity(acceleration due to gravity))

∴ The mass, m, of the support system on Earth = 1760/9.81 ≈ 179.41 kg

∴ The mass, m, of the support system on the moon ≈ 179.41 kg.

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